course 3 think smart for the smarter balanced assessment · 2016. 8. 4. · 5. a ball rolls in a...
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Think Smart for the Smarter Balanced Assessment
Thin
k Smart for th
e Smarter Balan
ced Assessm
ent
Course 3
Course 3
www.mheonline.com connectED.mcgraw-hill.com
NAME DATE PERIOD SCORE
8.NS.1
8.EE.7, 8.EE.7a
8.NS.2
Cop
yrig
ht ©
McG
raw
-Hill
Edu
catio
n. P
erm
issi
on is
gra
nted
to r
epro
duce
for
clas
sroo
m u
se.
Course 3 • Countdown • 19 Weeks 15
Program: SBAC Component: Count Down 19
PDF PassVendor: MPS Grade: Course 3
Countdown: 19 Weeks1. A company sells only items that are in the shape of cubes.
Select all of the volumes of cubes with rational number side lengths.
8 in3
33 cm3
1.5 ft3
9 ft3
1,000 m3
(4.12 yd)3
2. Sherron is writing a computer program that solves linear equations and displays a numerical answer for the solution.
Part A: When Sherron inputs the equation 4x + 3 = 4(1 + x) + 1, she gets an error message. Explain why.
Part B: Sherron inputs the equation 5 + 6y = 9y + 2 + 3(1 – y). What is the result and why?
3. A square picture frame encloses an area of 29 square inches. Its owner claims that the frame sides are between 5.25 and 5.35 inches long. Is the owner correct? Why or why not?
Think Smart for SBAC On the actual test, you might be asked to click all of the correct answer choices. In this book, you will be asked to shade a box next to each correct answer choice.
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8.EE.2
8.NS.2
Copyright ©
McG
raw-H
ill Education. Permission is granted to reproduce for classroom
use.
16 Course 3 • Countdown • 19 Weeks
Program: SBAC Component: Count Down 19
PDF PassVendor: MPS Grade: Course 3
4. A cargo ship has a stack of shipping containers. The stack is x containers wide, x containers long, and x containers tall. Circle all of the equations that could represent the total number of containers on the ship.
x3 = 64 x3 = 16 100 = x3
x3 = 9 27 = x3 x3 = 0.125
0.343 = x3 x3 = 8 216 = x3
5. A ball rolls in a straight line roughly 3π yards before stopping. Then someone kicks it backward 0.5π yards.
Part A: On the number line, plot a point to represent the distance from the ball’s initial location at 0 to its final location. Each increment on the number line represents 1 yard.
210 9 10876543
Part B: Explain why you cannot illustrate the distance exactly. Then give the distance rounded to the nearest hundredth.
Think Smart for SBAC On the actual test, you might be asked to click the button to plot a point on the number line. In this book, you will be asked to draw the point on the number line.
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Copyright ©
The McG
raw-H
ill Com
panies, Inc. Permission is granted to reproduce for classroom
8.EE
.2
8.N
S.2
16
Cou
rse
3 •
Cou
ntdo
wn
• 19
Wee
ks
4.
A c
argo
shi
p ha
s a
stac
k of
shi
ppin
g co
ntai
ners
. The
sta
ck is
x c
onta
iner
s w
ide,
x c
onta
iner
s lo
ng, a
nd x
con
tain
ers
tall.
Circ
le a
ll of
the
equa
tions
th
at c
ould
rep
rese
nt th
e to
tal n
umbe
r of
con
tain
ers
on th
e sh
ip.
x3 =
64
x3 =
16
100
= x
3
x3 =
9
27 =
x3
x3 =
0.12
5
0.34
3 =
x3 x3
= 8
216
= x
3
5.
A b
all r
olls
in a
str
aigh
t lin
e ro
ughl
y 3π
yar
ds b
efor
e st
oppi
ng.
Then
som
eone
kic
ks it
bac
kwar
d 0.
5π
yard
s.
Par
t A
: O
n th
e nu
mbe
r lin
e, p
lot a
poi
nt to
rep
rese
nt th
e di
stan
ce
from
the
ball’
s in
itial
loca
tion
at 0
to it
s fin
al lo
catio
n. E
ach
incr
emen
t on
the
num
ber
line
repr
esen
ts 1
yar
d.
21
09
108
76
54
3
Par
t B
: Ex
plai
n w
hy y
ou c
anno
t illu
stra
te th
e di
stan
ce e
xact
ly. T
hen
give
th
e di
stan
ce r
ound
ed to
the
near
est h
undr
edth
.
Th
ink
Sm
art
fo
r S
BA
C
On
the
actu
al te
st, y
ou m
ight
be
ask
ed to
clic
k th
e bu
tton
to p
lot a
poi
nt o
n th
e nu
mbe
r lin
e. In
this
boo
k, y
ou w
ill b
e as
ked
to d
raw
the
poin
t on
the
num
ber l
ine.
Sam
ple
answ
er: B
ecau
se π
is ir
ratio
nal,
any
mul
tiple
of
π is
als
o ir
ratio
nal.
So,
2.5
π is
irra
tiona
l. Ir
ratio
nal
num
bers
nev
er t
erm
inat
e or
rep
eat,
so t
hey
cann
ot b
e ill
ustr
ated
exa
ctly
. The
dis
tanc
e fr
om t
he in
itial
lo
catio
n to
the
fin
al lo
catio
n is
2.5
π y
d ≈
7.8
5 y
d.
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M
NA
ME
D
ATE
P
ERIO
D
SC
OR
E
8.N
S.1
8.EE
.7, 8
.EE.
7a
8.N
S.2
Copyright © McGraw-Hill Education. Permission is granted to reproduce for classroom use.
Cou
rse
3 •
Cou
ntdo
wn
• 19
Wee
ks
15
Cou
ntdo
wn:
19
Wee
ks1.
A
com
pany
sel
ls o
nly
item
s th
at a
re in
the
shap
e of
cub
es.
Sele
ct a
ll of
the
volu
mes
of c
ubes
with
rat
iona
l num
ber
side
leng
ths.
8 in
3
33 c
m3
1.5 ft
3
9 ft
3
1,00
0 m
3
(4.12
yd)
3
2.
Sher
ron
is w
ritin
g a
com
pute
r pr
ogra
m th
at s
olve
s lin
ear
equa
tions
and
di
spla
ys a
num
eric
al a
nsw
er fo
r th
e so
lutio
n.
Par
t A
: W
hen
Sher
ron
inpu
ts th
e eq
uatio
n 4x
+ 3
= 4
(1 +
x) +
1, s
he g
ets
an
erro
r m
essa
ge. E
xpla
in w
hy.
Par
t B
: Sh
erro
n in
puts
the
equa
tion
5 +
6y
= 9
y +
2 +
3(1
– y
). W
hat i
s th
e re
sult
and
why
?
3.
A s
quar
e pi
ctur
e fr
ame
encl
oses
an
area
of 2
9 s
quar
e in
ches
. Its
ow
ner
clai
ms
that
the
fram
e si
des
are
betw
een
5.2
5 a
nd 5
.35
inch
es lo
ng. I
s th
e ow
ner
corr
ect?
Why
or
why
not
?
Th
ink
Sm
art
fo
r S
BA
C
On
the
actu
al te
st, y
ou m
ight
be
ask
ed to
clic
k al
l of t
he
corr
ect a
nsw
er c
hoic
es. I
n th
is b
ook,
you
will
be
aske
d to
sha
de a
box
nex
t to
each
co
rrec
t ans
wer
cho
ice.
The
equa
tion
sim
plifi
es t
o 5
+ 6
y =
5 +
6y,
or
5 =
5,
whi
ch h
as a
n in
finite
num
ber
of s
olut
ions
. So,
She
rron
w
ould
get
an
erro
r m
essa
ge.
No;
Bec
ause
the
fra
me
is a
squ
are,
the
sid
es m
ust
be
the
sam
e le
ngth
. The
are
a A
= s
2 =
29.
So,
the
sid
e le
ngth
mus
t eq
ual √
___
29
≈ 5
.38
5 in
ches
. Thi
s do
es n
ot
fall
betw
een
5.2
5 a
nd 5
.35
, so
the
owne
r is
inco
rrec
t.
The
equa
tion
sim
plifi
es t
o 4x
+ 3
= 4
x +
5, o
r 3
= 5
, w
hich
has
no
solu
tion.
So,
She
rron
get
s an
err
or.
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AC
_A_C
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945.
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17 P
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Program: SBAC Component: CD 19
PDF PassVendor: MPS Grade: Course 3
172 Course 3 • Countdown
Countdown: 19 Weeks
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