ekotek - agung cahyadi - 8
Post on 20-Feb-2016
225 Views
Preview:
DESCRIPTION
TRANSCRIPT
Tugas Ekotek Bab 8Agung Cahyadi
1406606650
8.2 We should select the one with lower initial investment.
8.4a. The increment of investment between the two alternatives is less than 12 %b. We should select alternative X because the ROR on the increment of investment is less than MARR (12%), and alternative X requires a smaller investment than alternative Y
8.6 I infrared 27%I expensive 22%MARR 19%Kita tidak dapat menentukan modelnya, karena meskipun kita tahun bahwa kenaikan investasi kurang dari 22% per tahun, bisa saja nilai ini lebih atau sama atau pun kurang dibandingkan dengan MARR
8.8 Total investment $ 100,000.00 ROR total 30%Total Return $ 30,000.00 Investment Z1 $ 30,000.00 ROR Z1 15%Return Z1 $ 4,500.00
Investment Z2 $ 70,000.00 Return Z2 $ 25,500.00 ROR Z2 36%
8,10
Tahuncash flow
A B0 $ (12,000.00) $ (73,000.00)1 $ (27,000.00) $ (14,000.00)2 $ (39,000.00) $ (14,000.00)3 $ (27,000.00) $ (14,000.00)4 $ (39,000.00) $ (14,000.00)5 $ (27,000.00) $ (14,000.00)6 $ (27,000.00) $ 1,000.00
So we get :a. Tahun 0 $ (61,000.00)
b. Tahun 2 $ 25,000.00
8.12 Tahuncash flow
P Q0 $ (50,000.00) $ (85,000.00)1 $ 13,400.00 $ 43,000.00 2 $ 13,400.00 $ 43,000.00 3 $ (36,600.00) $ 43,000.00 4 $ 13,400.00 $ 43,000.00 5 $ 13,400.00 $ 43,000.00 6 $ 16,400.00 $ 51,000.00
8.14
year gasoline diesel0 $ (150,000.00) $ (110,000.00)
1-14 $ (41,000.00) $ (30,000.00)15 $ 23,000.00 $ 39,000.00
So we get :a. First cost diesel $ (110,000.00)b. Annual cost diesel $ (30,000.00)c. Salvage diesel $ 39,000.00
8.16 year incremental0 -46001 11002 11003 11004 11005 11006 1100
7 11008 11009 1100
10 2000
i 21.93%
> Because I <MARR, alternative P3 should be selected
8.18year treated impregnated
0 $ (50,000.00) $ (95,000.00)1 $ (100,000.00) $ (85,000.00)2 $ (100,000.00) $ (85,000.00)3 $ (145,000.00) $ (85,000.00)4 $ (100,000.00) $ (85,000.00)5 $ (100,000.00) $ (85,000.00)6 $ (95,000.00) $ (74,000.00)
MARR 21%I incremental 45.18%
> Because I > MARR, impregnated should be selected
8,20 year A B0 $ (110,000.00) $ (175,000.00)1 $ (60,000.00) $ (35,000.00)2 $ (60,000.00) $ (35,000.00)3 $ (60,000.00) $ (35,000.00)
So we get :MARR 20%I incremental 7.51%
8.22year incremental
0 $ (900,000.00)1 $ 400,000.00 2 $ 400,000.00 3 $ 400,000.00
> So we get :
Annual cost 2 ($566,422.02)Reduction ($166,422.02)
8.24
year variable dual0 $ (270,000.00) $ (245,000.00)1 $ (135,000.00) $ (139,000.00)2 $ (135,000.00) $ (139,000.00)3 $ (135,000.00) $ (139,000.00)4 $ (135,000.00) $ (139,000.00)5 $ (135,000.00) $ (139,000.00)6 $ (60,000.00) $ (104,000.00)
> So we get :i 23.08%
> Because I > MARR, variable speed should be selected
8.26year HP EMT
0 $ (600,000.00) $ (800,000.00)1 $ (200,000.00) $ (150,000.00)2 $ (200,000.00) $ (150,000.00)3 $ (200,000.00) $ (150,000.00)4 $ (200,000.00) $ (150,000.00)5 $ (130,000.00) $ (20,000.00)
So we get :i 14.52%
> Because I < MARR, HP should be selected
8.28> Do-nothing alternative should be selected
8,30year iGen-1 iGen-2
0 $ (500,000.00) $ (600,000.00)1 $ 100,000.00 $ 160,000.00 2 $ 100,000.00 $ 160,000.00 3 $ 170,000.00 $ 245,000.00
i -12.60% -2.74%
> Because I > MARR, alternative D should be selected
8.32Rank alternatives according to increasing initial investment : DN, D, A, C, E, B
a) A vs B 19%E vs D 24%C vs A 19%C vs DN 7%D vs C 33%
MARR 11.50%
> Therefore, select B
b) MARR 13.50%
A vs B 19%E vs D 24%C vs A 19%DN vs B 13%D vs C 33%
> Therefore, select do-nothing
8.34
D AInitial Cost $ (3,000.00) $ (7,000.00)Cash Flow $ 500.00 $ 3,500.00 ROR (vs DN) 16.70% 14.30%MARR 14.90%
Eliminate DN Eliminate A
I D vs C 15% Eliminate D
I C vs B 15% Eliminate C
> Therefore, B should be selected
8.36 MARR 22%
year machine 1 machine 20 $ (44,000.00) $ (60,000.00)1 $ 10,000.00 $ 16,000.00 2 $ 10,000.00 $ 16,000.00 3 $ 10,000.00 $ 16,000.00 4 $ 10,000.00 $ 16,000.00 5 $ 10,000.00 $ 16,000.00 6 $ 10,000.00 $ 16,000.00 7 $ 10,000.00 $ 16,000.00 8 $ 10,000.00 $ 16,000.00 9 $ 10,000.00 $ 16,000.00
10 $ 10,000.00 $ 16,000.00
year Incremental cash flow (2-1) Incremental cash flow (3-2)0 $ (16,000.00) $ (12,000.00)1 $ 6,000.00 $ 3,000.00 2 $ 6,000.00 $ 3,000.00 3 $ 6,000.00 $ 3,000.00 4 $ 6,000.00 $ 3,000.00 5 $ 6,000.00 $ 3,000.00 6 $ 6,000.00 $ 3,000.00 7 $ 6,000.00 $ 3,000.00 8 $ 6,000.00 $ 3,000.00 9 $ 6,000.00 $ 3,000.00
10 $ 6,000.00 $ 3,000.00 i 35.73% 21.41%
Select 2 2
Comparison 3-2 21.41% < MARR
> Therefore, 2 should be selected
Tugas Ekotek Bab 8Agung Cahyadi
1406606650
We should select alternative X because the ROR on the increment of investment is less than MARR (12%), and alternative X requires a smaller investment than alternative Y
Kita tidak dapat menentukan modelnya, karena meskipun kita tahun bahwa kenaikan investasi kurang dari 22% per tahun, bisa saja nilai ini lebih atau sama atau pun kurang dibandingkan dengan MARR
incremental Cash flow A
$ (61,000.00) $ 13,000.00 0 1 2 3 $ 25,000.00 $ 13,000.00 $12,000.00 $ 25,000.00 $ 13,000.00 $27,000.00 $ 28,000.00 $39,000.00
incrementCash Flow P
$ (35,000.00) $22,000.00 $ 29,600.00 $ 29,600.00 $3,000.00 $ 79,600.00 $ 29,600.00 0 1 2 3 $ 29,600.00 $ 34,600.00 $8,600.00
$50,000.00
incremental Gasoline $ 40,000.00 $ 11,000.00 $ 16,000.00
0 1 2 3
$41,000.00
$150,000.00
Incremental$2,000.00
$1,100.00
0 1 2 3 14 15
4600
Aincremental $5,000.00
$ (45,000.00) $ 15,000.00 $ 15,000.00 0 1 2 3 $ 60,000.00 $ 15,000.00 $ 15,000.00 $50,000.00 $ 21,000.00
$100,000.00
$150,000.00
incremental A $ (65,000.00) $ 25,000.00 0 1 2 3 $ 25,000.00 $ 25,000.00
$60,000.00
$110,000.00
Incremental Cash Flow$400,000.00
0 1 2 3
$900,000.00
incremental Variable $ 25,000.00 $ (4,000.00) $ (4,000.00) $ (4,000.00) 0 1 2 3 $ (4,000.00) $ (4,000.00) $ (44,000.00) $135,000.00
$270,000.00
incremental HP $ (200,000.00) $ 50,000.00 $ 50,000.00 $ 50,000.00 0 1 2 3 $ 50,000.00 $ 110,000.00 $200,000.00
$600,000.00
iGen-3 iGen-4 $ (650,000.00) $ (750,000.00) A $170,000.00 $ 205,000.00 $ 310,000.00 $100,000.00 $ 205,000.00 $ 310,000.00 $ 295,000.00 $ 430,000.00 0 1 2 3
3.92% 17.77%
$500,000.00
Eliminate AEliminate EEliminate CEliminate DNEliminate D
Eliminate AEliminate EEliminate CEliminate BEliminate D
C E B $ (9,000.00) $ (16,000.00) $ (23,000.00) $ 1,400.00 $ 500.00 $ 3,500.00
15.60% 13.80% 15.20%14.90%
Eliminate DN Eliminate E Eliminate DN
machine 3 machine 4 $ (72,000.00) $ (98,000.00) $ 19,000.00 $ 24,000.00 $ 19,000.00 $ 24,000.00 $ 19,000.00 $ 24,000.00 $ 19,000.00 $ 24,000.00 $ 19,000.00 $ 24,000.00 $ 19,000.00 $ 24,000.00 $ 19,000.00 $ 24,000.00 $ 19,000.00 $ 24,000.00 $ 19,000.00 $ 24,000.00 $ 19,000.00 $ 24,000.00
Incremental cash flow (4-3) $ (26,000.00) $ 5,000.00 $ 5,000.00 $ 5,000.00 $ 5,000.00 $ 5,000.00 $ 5,000.00 $ 5,000.00 $ 5,000.00 $ 5,000.00 $ 5,000.00
14.08%3
Kita tidak dapat menentukan modelnya, karena meskipun kita tahun bahwa kenaikan investasi kurang dari 22% per tahun, bisa saja nilai ini lebih atau sama atau pun kurang dibandingkan dengan MARR
Cash flow A Cash flow B
4 5 6
0 1 2 3 4
$27,000.00$39,000.00 $14,000.00
$73,000.00
Cash Flow P Cash Flow Q$22,000.00 $45,000.00
$3,000.00
4 5 6
$8,600.00 0 1 2 3 4$2,000.00
$50,000.00
$85,000.00
Diesel$23,000.00
14 15 0 1 2 3
$41,000.00 $30,000.00
$110,000.00
$2,000.00
B$5,000.00
4 5 60 1 2 3 4
$100,000.00$85,000.00
$150,000.00 $95,000.00
B
0 1 2 3
35000
175000
Dual$75,000.00
4 5 6 0 1 2 3 4
$135,000.00 139000
245000
EMT
$70,000.00
4 5 0 1 2 3 4
$200,000.00 $150,000.00
$800,000.00
$170,000.00 C $295,000.00 B$205,000.00 $150,000.00
1 2 3 1
$650,000.00 $600,000.00
$15,000.00
5 6
$14,000.00
$45,000.00
$8,000.00
5 6$2,000.00
$39,000.00
14 15
$30,000.00
$11,000.00
5 6
$85,000.00
35000
5 6
139000
$130,000.00
5
$150,000.00
D $430,000.00$245,000.00 $310,000.00
$150,000.00
2 3 0 1 2 3
$750,000.00
top related