final jeopardy question gas law concepts gas law problems 500 gas law demos misc. gas laws 100 200...

Post on 31-Dec-2015

222 Views

Category:

Documents

2 Downloads

Preview:

Click to see full reader

TRANSCRIPT

Final Jeopardy QuestionFinal Jeopardy Question

Gas LawConcepts

Gas LawProblems

500

Gas Law

DemosMisc. Gas

Laws

100

200

300

400

500 500 500 500

400 400 400 400

300 300 300300

200 200 200 200

100 100 100100

STP &Temp.

Problems

If temperature is doubled and volume is cut in half, what happens to the

pressure?

Back

Pressure is 4 times the original

Back

At constant temperature, if pressure is quadrupled, what happens to volume?

Back

At constant temperature, if the pressure is quadrupled, what happens to volume?

Pressure – 4x, then Volume – 1/4x

Back

What relationship does John’s Law demonstrate?

Back

Direct relationship between pressure and temperature

P1 = P2

T1 T2

Back

Back

Which gas law can be represented by the following graph?

Boyle’s Law – inverse relationship

Back

What does Charles’ Law state?

Back

At constant pressure, direct relationship between volume and

temperature

Back

A sample of gas has a volume of 23 mL at 39oC and 890 mm Hg. This sample is cooled down to 11oC and now has a volume of 150 mL. What is the new

pressure?

Back

Use the combined gas law since all variables are changing…

P1V1 = P2V2

T1 T2

890 mm Hg ( 23 mL) = P2 (150 mL)312 K 284 K

P2 = 124.22 mm HgBack

A 50 L container is filled with a gas to a pressure of 4.7 atm at 32oC. At what

temperature IN DEGREES CELSIUS will the pressure inside the container be

3.5 atm with a volume of 50 L?

Back

Volume is constant, so use John’s law.

P1 = P2 4.7 atm = 3.5 atmT1 T2 305 K T2

T2 = 227.13 K – 273 = -45.87 oC

Back

A gas occupies a volume of 34 mL at 21.8 oC. To what temperature (in

Kelvin) must the gas be raised to have a volume of 86 mL? Assume constant

pressure.

Back

Pressure is constant, so use Charles’ law.

V1 = V2 34 mL = 86 mLT1 T2 294.8 K T2

T2 = 745.67 K

Back

Back

A balloon has a volume of 6L at 2 atm. If the balloon was brought to a

pressure of 4 atm, what would the new volume be (assume constant temp).

Temp is constant, so use Boyle’s law.

P1V1 = P2V2

2 atm (6L) = 4 atm (V2)

V2 = 3 LBack

Whose law is being used in the following situation…

A sample of gas in a flexible container occupies 46.5 mL at standard pressure.

What volume will it take up if the pressure was increased to 3 atm?

Assume constant temp.

Back

Temp is held constant, so it is Boyle’s law.

Pressure increases while the volume decreases.

Back

At STP, how many liters of space will 8 g of O2 occupy?

Back

Back

8 g O2 x 1 mole O2 x 22.4 L O2 = 1 32 g O2 1 mole O2 5.6 L

What is the Kelvin value for absolute zero, and what theoretically happens at

this temperature?

Back

ZERO Kelvin (0K) and in theory all matter will stop moving at this temperature.

Back

What is 550K in oC?

Back

277 oC

K = 273 + oCoC = K - 273

277 oC = 550K-273

Back

Back

What is 38.5 oC in Kelvin?

311.5 K

K = 273 + 38.5oC

Back

What are the four values for Standard

Pressure?

Back

101.3 kPa = 760 torr = 760 mm Hg = 1 atm

Back

Explain how a straw works – and DO NOT USE THE WORD “SUCK”.

Back

When you inhale, your lungs expand (Volume increases), creating less pressure in the straw or your mouth. Since

the pressure in the straw is less than the pressure outside the straw, the atmospheric pressure PUSHES the

liquid into the straw so you can enjoy it!

Back

Explain the egg in flask demo.

AND REMEMBER SCIENCE NEVER ____!

Back

In the egg demo, water was heated in the flask. Since temp increased in the flask, the pressure also increased.

The flask was then taken away from the heat, and an egg was placed on top.

The flask cools down which causes the pressure inside the flask to decrease.

Since the pressure inside the flask decreased, the atmospheric pressure outside the flask was greater; therefore, it PUSHED the egg into the flask.

Back

A pressure apparatus that contains a sample of gas at a fixed volume is first placed into a container of hot water. It is then plunged into a container of liquid nitrogen (very cold). What happens to the pressure and why?

Back

This is an example of John’s law – when temp goes down, pressure

goes down.

Back

Back

Explain why the Ivory soap expanded in the microwave and which gas law applies

to this situation.

Since temp increased, so does volume. This is Charles’ law.

Back

What will happen to the volume of a balloon if it is placed into a bell jar

(vacuum pump) and the pump is turned on.

Back

The volume of the balloon will increase. This is Boyle’s law… as P decreases, V increases

and vice versa.

Back

Back

At what pressure would 0.150 mole of nitrogen gas at 23.0 °C

occupy 8.90 L?

Back

PV = nRT (Ideal Gas Law)P = nRT V

P = .15 mol x 8.31 L*kPa x 296 K ____ mol K______

8.9L P =41.46 kPa

Back

How many moles of oxygen gas are contained in a 890.0 mL

container at 21.0 °C and 90.3 kPa?

Back

PV = nRT (Ideal Gas Law)n = PV

RT n = 90.3 kPa x .890 L

8.31 L*kPa x 294 Kmol*K

n = .032 moles O2

Back

What is the partial pressure of helium if the total

pressure of a rigid container is 53.1 kPa and oxygen’s

pressure in the tank is 34.3 kPa?

Back

P total = PHe +PO2

53.1 kPa = PHe + 34.3 kPa

PHe = 53.1 – 34.3 = 18.8 kPa

Back

Given the following partial pressures, solve for the total

pressure:PN2 = 22.1 kPaPO2 = 9.4 kPaPCO2 = 2.2 kPa

Back

P total = PN2 +PO2 +PCO2

33.7 kPa = 22.1 + 9.4 + 2.2

2 H2O (l) 2 H2 (g) + O2 (g)

How many liters of H2 are produced if 4 L of oxygen were

produced, at STP?

Back

2 H2O (l) 2 H2 (g) + O2 (g)How many liters of H2 are produced if 4 L of oxygen were

produced, at STP?

4 L O2 x 1 mole O2 x 2 moles H2 x 22.4 L H2 = 8 L

1 22.4 L O2 1 mole O2 1 mole H2

Back

Type Question Here

Back

Type Answer Here

Back

Type Question Here

Back

Type Answer Here

Back

Type question Here

Back

Type Answer Here

Back

Back

Type Answer Here

Type Answer Here

Back

Type Question Here

Back

Type Answer Here

Back

If you are making pasta in Los Angeles and at the same time, your best friend in Colorado Springs is doing the exact same thing, whose pasta will cook first and why?

Back

LOS ANGELES – the boiling point of water in Los Angeles is higher than the boiling point of water in Colorado Springs. WHY?

Water boils when the vapor pressure equals the atmospheric pressure.

Because the atmospheric pressure in L.A. is higher than that in Colorado Springs, so even though the water in L.A. will boil second, it will have a higher temperature providing more heat. THUS, the pasta in L.A. will be done first.

Back

This Jeopardy Game was Created by: SaraFeltman, 5th Grade Teacher

Scott Elementary School1999-2000 School Year

Revised: RLipkowitz 2000

top related