analis de viga t

7232019 Analis de Viga t

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ANAacuteLISIS DE UNA VIGA DESECCIOacuteN T

CONCRETO ARMADO I

a) b)

2804200

b= 75 cm

h= 45 cm

bw= 25 cmSOLUCIOacuteN

a) 254cmAs empty 1 = 50 cm2 N$= 4

4 cm

= amp ($)c D+m Es D+m$ D+m V$ -2d = 3624 cm

0004

Caacutelculo de la cuana nma

00001

000

0004 000 Con$ome

ampnde

()3 cm2 085

+naacutel-- de una -eccn Calcula el momeno con0able de d-e ue -e mue-a en la 0ua con-dee

As = 4empty1

As = 4emptyN10

〖〗_

= =_

As = 4empty1

empty-8

empty1=

empty-8=

=

=

=

310383891103925〖907317〗2310383891103925〖907317〗2

=08_iacute

(〖〗 _ _

6 _

= =14-_iacute

_ _iacute =

there4 = gt _iacute =

=(08 7 _ 5acute (minus ℎ _

_

=

1=0859005(( 9280-0acute

1=




CONCRETO ARMADO I

2()

23

Caacutelculo de la cuana aacutema

(256

0004 00125 Con$ome

Considereando que actua como seccioacuten rectamgular

2028 cm2

418cm

a = 477 cm h$ = 7 cm Usar seccioacuten re

Caacutelculo del momeo 8lmo

0

25)5 9m

b 18 cm2 4 As empty N

18 cm2 05 cm

4 cm


00114 00000114 00125

Clts+)$lt gt) c cltmlt s)cc+ $)cB$

18 cm2

1 =

- _ (_

1=

( _ = 085 1 ( (000-(000 acute +

( _ )

=

=05_aacute _ ( 1(_ +

_aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute=

there4 = 〖 lt _aacute___________=

there4

= -(_lowast_

(085 lowastacutelowast

=

_

=

there4

=_ empty _lowast_7 -2(minus empty=

=_

As = 4emptyN10

empty=

As

=

N$=

=

=

=

empty

-8=

=

_iacute = _aacute =

= -(_lowast_

(085 lowastacutelowast _

=




CONCRETO ARMADO I

45 cm

a = 745 cm h$ = 7 cm Seccn


F )

18

1185cm2

8 cm

3)656 9m

=

there4

=_ empty _1lowast_7 -2(minus empty7 9 _lowast_ ( _ -2

empty=

=_

_ = _+ _

_

=


1 9_ _ _

1_

== 1 -(_ lowast_

(085 lowastacutelowast=




CONCRETO ARMADO I

hf= cm

05 cm

o de la Seccn




CONCRETO ARMADO I

tangular

10= 2 cm2

CltHlt$m)CltHlt$m)




CONCRETO ARMADO I

cm2




CONCRETO ARMADO I

2()

23

Caacutelculo de la cuana aacutema

(256

0004 00125 Con$ome

Considereando que actua como seccioacuten rectamgular

2028 cm2

418cm

a = 477 cm h$ = 7 cm Usar seccioacuten re


0

25)5 9m

b 18 cm2 4 As empty N

18 cm2 05 cm

4 cm


00114 00000114 00125

Clts+)$lt gt) c cltmlt s)cc+ $)cB$

18 cm2

1 =

- _ (_

1=

( _ = 085 1 ( (000-(000 acute +

( _ )

=

=05_aacute _ ( 1(_ +

_aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute_ aacute=

there4 = 〖 lt _aacute___________=

there4

= -(_lowast_

(085 lowastacutelowast

=

_

=

there4

=_ empty _lowast_7 -2(minus empty=

=_

As = 4emptyN10

empty=

As

=

N$=

=

=

=

empty

-8=

=

_iacute = _aacute =

= -(_lowast_

(085 lowastacutelowast _

=




CONCRETO ARMADO I

45 cm



F )

18

1185cm2

8 cm

3)656 9m

=

there4


empty=

=_

_ = _+ _

_

=


1 9_ _ _

1_

== 1 -(_ lowast_





CONCRETO ARMADO I

hf= cm

05 cm

o de la Seccn




CONCRETO ARMADO I

tangular

10= 2 cm2

CltHlt$m)CltHlt$m)




CONCRETO ARMADO I

cm2




CONCRETO ARMADO I

45 cm



F )

18

1185cm2

8 cm

3)656 9m

=

there4


empty=

=_

_ = _+ _

_

=


1 9_ _ _

1_

== 1 -(_ lowast_





CONCRETO ARMADO I

hf= cm

05 cm

o de la Seccn




CONCRETO ARMADO I

tangular

10= 2 cm2

CltHlt$m)CltHlt$m)




CONCRETO ARMADO I

cm2




CONCRETO ARMADO I

hf= cm

05 cm

o de la Seccn




CONCRETO ARMADO I

tangular

10= 2 cm2

CltHlt$m)CltHlt$m)




CONCRETO ARMADO I

cm2




CONCRETO ARMADO I

tangular

10= 2 cm2

CltHlt$m)CltHlt$m)




CONCRETO ARMADO I

cm2




CONCRETO ARMADO I

cm2

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