announcements 3/28/12

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Announcements 3/28/12 Prayer Exam review problems for sign-up Calvin & Hobbes

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Announcements 3/28/12. Prayer Exam review problems for sign-up. Calvin & Hobbes. Reading Quiz. A lens placed after a diffraction aperture causes the Fraunhofer pattern to be produced: before the focal length at the focal length after the focal length (but at a finite distance) at infinity. - PowerPoint PPT Presentation

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Page 1: Announcements 3/28/12

Announcements 3/28/12 Prayer Exam review problems for sign-up

Calvin & Hobbes

Page 2: Announcements 3/28/12

Reading Quiz A lens placed after a diffraction aperture

causes the Fraunhofer pattern to be produced:

a. before the focal lengthb. at the focal lengthc. after the focal length (but at a finite

distance)d. at infinity

Page 3: Announcements 3/28/12

Lenses

Page 4: Announcements 3/28/12

Lenses What it object is not at infinity?

a. What appears at q?b. What appears at f?

“Fourier transform plane”

f f f f

Object at f:

Page 5: Announcements 3/28/12

Lens Fourier Transforms

From Hecht

at focus of lens

Page 6: Announcements 3/28/12

“Fourier Transform smoothing”

From Hecht

Before After

Page 7: Announcements 3/28/12

Reading Quiz

What does the “Rayleigh criterion” tell us?a. The angle at which both light

polarizations have equal reflection coefficients

b. The angle at which p-polarized light has minimum reflection

c. The angular separation resolvable by an imaging system

d. The number of orders produced by a diffraction grating

Page 8: Announcements 3/28/12

Reading Quiz The Rayleigh criterion for resolving two

point light sources comes from:a. Fourier transforms of delta functions.b. Jinc functions’ maxima and minima. c. Lagrange multipliers.d. Parallax of stars.

Page 9: Announcements 3/28/12

Simple Telescope

Page 10: Announcements 3/28/12

Circular Aperture, again

Page 11: Announcements 3/28/12

What do you get in this situation?

What if there’s a lens in the hole?

What if there isn’t a board?

What if you have two light sources?

patt

ern

at in

finity

patt

ern

at f

ocus

supe

rimpo

sed

patt

erns

at

focu

s

f

board with hole

Page 12: Announcements 3/28/12

Rayleigh: 2nd peak at position of first minimum

Page 13: Announcements 3/28/12

Rayleigh Criterion

plotted vs (krb/f), = D/

Mathematica “FindRoot” command: / = 1.21967…

min.resolve 1.22D

(using sin )

Curve is (J1(x)/x)2

Rayleigh Criterion

(= first zero of J1(x))