anova
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STAT 101 Dr. Kari Lock Morgan 11/1/12. ANOVA. SECTION 8.1 Testing for a difference in means across multiple categories. What Next?. If you have enjoyed learning how to analyze data, and want to learn more: take STAT 210 (Regression Analysis) Applied, focused on data analysis - PowerPoint PPT PresentationTRANSCRIPT
Statistics: Unlocking the Power of Data Lock5
STAT 101Dr. Kari Lock Morgan
11/1/12
ANOVA
SECTION 8.1• Testing for a difference in means across
multiple categories
Statistics: Unlocking the Power of Data Lock5
What Next?• If you have enjoyed learning how to analyze data, and want to learn more: • take STAT 210 (Regression Analysis)• Applied, focused on data analysis• Recommended for any major involving data analysis• Only prerequisite is STAT 101
• If you like math and want to learn more of the mathematical theory behind what we’ve learned: • take STAT 230 (Probability) • and then STAT 250 (Mathematical Statistics)• Prerequisite: multivariable calculus
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Two Options for p-valuesWe have learned two ways of calculating p-values:
The only difference is how to create a distribution of the statistic, assuming the null is true:
1)Simulation (Randomization Test): • Directly simulate what would happen, just by
random chance, if the null were true
2)Formulas and Theoretical Distributions: • Use a formula to create a test statistic for which
we know the theoretical distribution when the null is true, if sample sizes are large enough
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Two Options for IntervalsWe have learned two ways of calculating intervals:
1)Simulation (Bootstrap): • Assess the variability in the statistic by
creating many bootstrap statistics
2)Formulas and Theoretical Distributions: • Use a formula to calculate the standard error
of the statistic, and use the normal or t-distribution to find z* or t*, if sample sizes are large enough
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Inference
Which way did you prefer to learn inference?
a) Simulation methodsb) Formulas and theoretical distributions
Statistics: Unlocking the Power of Data Lock5
Inference
Which way gave you a better conceptual understanding of confidence intervals and p-values?
a) Simulation methodsb) Formulas and theoretical distributions
Statistics: Unlocking the Power of Data Lock5
Inference
Which way do you prefer to do inference?
a) Simulation methodsb) Formulas and theoretical distributions
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Pros and Cons1)Simulation Methods
PROS:• Methods tied directly to concepts, emphasizing conceptual
understanding• Same procedure for every statistic• No formulas or theoretical distributions to learn and distinguish
between• Works for any sample size• Minimal math needed
CONS:• Need entire dataset (if quantitative variables)• Need a computer• Newer approach, so different from the way most people do
statistics
Statistics: Unlocking the Power of Data Lock5
Pros and Cons2)Formulas and Theoretical Distributions
PROS:• Only need summary statistics• Only need a calculator• The approach most people take
CONS:• Plugging numbers into formulas does little for conceptual
understanding• Many different formulas and distributions to learn and
distinguish between• Harder to see the big picture when the details are different for
each statistic• Doesn’t work for small sample sizes• Requires more math and background knowledge
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Two Options
• If the sample size is small, you have to use simulation methods
• If the sample size is large, you can use whichever method you prefer
• It is redundant to use both methods, unless you want to check your answers
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Accuracy• The accuracy of simulation methods depends on the number of simulations (more simulations = more accurate)
• The accuracy of formulas and theoretical distributions depends on the sample size (larger sample size = more accurate)
• If the sample size is large and you have generated many simulations, the two methods should give essentially the same answer
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Multiple Categories
•So far, we’ve learned how to do inference for a difference in means IF the categorical variable has only two categories
•Today, we’ll learn how to do hypothesis tests for a difference in means across multiple categories
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Hypothesis Testing
1.State Hypotheses
2.Calculate a statistic, based on your sample data
3.Create a distribution of this statistic, as it would be observed if the null hypothesis were true
4.Measure how extreme your test statistic from (2) is, as compared to the distribution generated in (3)
test statistic
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Cuckoo Birds•Cuckoo birds lay their eggs in the nests of other birds
•When the cuckoo baby hatches, it kicks out all the original eggs/babies
•If the cuckoo is lucky, the mother will raise the cuckoo as if it were her own
http://opinionator.blogs.nytimes.com/2010/06/01/cuckoo-cuckoo/
•Do cuckoo birds found in nests of different species differ in size?
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Notation
•k = number of groups
•nj = number of units in group j
•n = overall number of units = n1 + n2 + … + nk
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Cuckoo Eggs
k = 5n1 = 15, n2 = 60, n3 = 16, n4 = 14, n5 = 15n = 120
Bird Sample Mean
Sample SD
SampleSize
Pied Wagtail 22.90 1.07 15
Pipit 22.50 0.97 60
Robin 22.58 0.68 16
Sparrow 23.12 1.07 14
Wren 21.13 0.74 15
Overall 22.46 1.07 120
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Hypotheses
To test for a difference in means across k groups:
0 1 2: ...: At least one
k
a i j
HH
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Test Statistic
Why can’t use the familiar formula
to get the test statistic?
•More than one sample statistic•More than one null value
We need something a bit more complicated…
sample statistic null valueSE
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Difference in Means
Whether or not two means are significantly different depends on
• How far apart the means are
• How much variability there is within each group
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Difference in Means
group1 group2
02
46
810
group1 group2
02
46
810
1214
group1 group2
4.5
5.0
5.5
6.0
6.5
group1 group2
02
46
810
group1 group2
02
46
810
1214
group1 group2
4.5
5.0
5.5
6.0
6.5
group1 group2
02
46
810
group1 group2
02
46
810
1214
group1 group2
4.5
5.0
5.5
6.0
6.5
1
2
1 2
65
2
X
ssX
1
2
1 2
95
2
X
ssX
1
2
1 2
5
0.6
2s
XXs
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Analysis of Variance
•Analysis of Variance (ANOVA) compares the variability between groups to the variability within groups
Total Variability
VariabilityBetween Groups
VariabilityWithin Groups
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Analysis of Variance
If the groups are actually different, then
a) the variability between groups should be higher than the variability within groups
b) the variability within groups should be higher than the variability between groupsIf the groups are different, there will be high variability between the groups.
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Discoveries for Today
•How to measure variability between groups?
•How to measure variability within groups?
•How to compare the two measures?
•How to determine significance?
Statistics: Unlocking the Power of Data Lock5
Discoveries for Today
•How to measure variability between groups?
•How to measure variability within groups?
•How to compare the two measures?
•How to determine significance?
Statistics: Unlocking the Power of Data Lock5
Sums of Squares
•We will measure variability as sums of squared deviations (aka sums of squares)
•familiar?
Statistics: Unlocking the Power of Data Lock5
Sums of Squares
2
1
n
ii
X X
Total Variability
VariabilityBetween Groups
VariabilityWithin Groups
2
1
k
j jj
n X X
2
,11
jnk
i j jij
X X
overall mean
data value i
overall mean
mean in group j mean in
group j
ith data value in group j
Sum over all data values Sum over all groups Sum over all data values
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Deviations
Group 1
Group 2
X
Total iX X
Overall Mean
1X
Group 1 Mean
,
Within i j jX X
1
BetweenX X
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Sums of Squares
2
1
n
ii
X X
Total Variability
VariabilityBetween Groups
VariabilityWithin Groups
2
1
k
j jj
n X X
2
,11
jnk
i j jij
X X
SST (Total sum of squares)
SSG(sum of squares due to groups)
SSE(“Error” sum of squares)
Statistics: Unlocking the Power of Data Lock5
Cuckoo Birds
2
1
137.19n
ii
SST X X
2
1
35.90k
j jj
SSG n X X
2
,11
101.29jnk
i j jij
X XSSE
Statistics: Unlocking the Power of Data Lock5
Source
Groups
Error
Total
df
k-1
n-k
n-1
Sum ofSquares
SSG
SSE
SST
MeanSquareMSG =
SSG/(k-1)MSE =
SSE/(n-k)
ANOVA TableThe “mean square” is the
sum of squares divided by the degrees of freedom
variability
average variability
Statistics: Unlocking the Power of Data Lock5
ANOVA Table•Fill in the beginnings of the ANOVA table based on the Cuckoo birds data.
Source
Groups
Error
Total
df
k-1
n-k
n-1
Sum ofSquares
SSG
SSE
SST
MeanSquare
MSG = SSG/(k-1)
MSE = SSE/(n-k)
Bird Sample Mean
Sample SD
SampleSize
Pied Wagtail 22.90 1.07 15
Pipit 22.50 0.97 60
Robin 22.58 0.68 16
Sparrow 23.12 1.07 14
Wren 21.13 0.74 15
Overall 22.46 1.07 120
SSG = 35.9SSE = 101.20
Statistics: Unlocking the Power of Data Lock5
Source
Groups
Error
Total
df
4
115
119
Sum ofSquares35.90
101.29
137.19
MeanSquare
35.9/4 = 8.97
101.29/115 = 0.88
ANOVA Table•Fill in the beginnings of the ANOVA table based on the Cuckoo birds data.
Statistics: Unlocking the Power of Data Lock5
Discoveries for Today
•How to measure variability between groups?
•How to measure variability within groups?
•How to compare the two measures?
•How to determine significance?
Statistics: Unlocking the Power of Data Lock5
F-Statistic
•The F-statistic is a ratio of the average variability between groups to the average variability within groups
average between group variabilityaverage within group variability
MSGFMSE
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Source
Groups
Error
Total
df
k-1
n-k
n-1
Sum ofSquares
SSG
SSE
SST
MeanSquareMSG =
SSG/(k-1)MSE =
SSE/(n-k)
FStatistic
MSGMSE
ANOVA Table
Statistics: Unlocking the Power of Data Lock5
Cuckoo Eggs
Source
Groups
Error
Total
df
4
115
119
Sum ofSquares35.90
101.29
137.19
MeanSquare
35.9/4 = 8.97
101.29/115 = 0.88
FStatistic
8.97/0.88= 10.19
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F-statisticIf there really is a difference between the groups, we would expect the F-statistic to be
a) Higher than we would observe by random chance
b) Lower than we would observe by random chance
If the null hypothesis is true, what kind of F-statistics would we observe just by random chance?
The numerator of the F-statistic measures between group variability, and the denominator measures within group. If there is a difference, we expect the between group variability to be higher.
Statistics: Unlocking the Power of Data Lock5
Discoveries for Today
•How to measure variability between groups?
•How to measure variability within groups?
•How to compare the two measures?
•How to determine significance?
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How to determine significance?
We have a test statistic. What else do we need to perform the hypothesis test?
A distribution of the test statistic assuming H0 is true
How do we get this? Two options:1) Simulation2) Distributional Theory
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www.lock5stat.com/statkey Simulation
Because a difference would make the F-statistic higher, calculate proportion in the upper tail
An F-statistic this large would be very unlikely to happen just by random chance if the means were all equal, so we have strong evidence that the mean lengths of cuckoo birds in nests of different species are not all equal.
Statistics: Unlocking the Power of Data Lock5
F-distributionRandomization Distribution
F-statistic
Frequency
0 2 4 6 8 10
0100
200
300
400
500
600
Randomization Distribution
F-statistic
Frequency
0 2 4 6 8 10
0100
200
300
400
500
600
F-distribution
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F-DistributionIf the following conditions hold,
1.Sample sizes in each group are large (each nj ≥ 30) OR the data are relatively normally distributed
2.Variability is similar in all groups
3.The null hypothesis is true
then the F-statistic follows an F-distribution
•The F-distribution has two degrees of freedom, one for the numerator of the ratio (k – 1) and one for the denominator (n – k)
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Equal Variance•The F-distribution assumes equal within group variability for each group
•As a rough rule of thumb, this assumption is violated if the standard deviation of one group is more than double the standard deviation of another group
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F-distributionCan we use the F-distribution to calculate the p-value for the Cuckoo bird eggs?
a) Yesb) Noc) Need more information
The equal variability condition is satisfied, but the sample sizes are small so we can only use the F-distribution if the data is normal.
Bird Sample Mean
Sample SD
SampleSize
Pied Wagtail 22.90 1.07 15
Pipit 22.50 0.97 60
Robin 22.58 0.68 16
Sparrow 23.12 1.07 14
Wren 21.13 0.74 15
Overall 22.46 1.07 120
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F-distribution p-values1.StatKey – simulation or theoretical
2.RStudio:tail.p(“f”,stat,df1,df2,tail=“upper”)
3.TI-83:2nd DISTR 7:Fcdf( lower bound, upper bound, df1, df2
For F-statistics, the p-value (the area as extreme or more extreme) is always the upper tail
Statistics: Unlocking the Power of Data Lock5
Source
Groups
Error
Total
df
k-1
n-k
n-1
Sum ofSquares
SSG
SSE
SST
MeanSquareMSG =
SSG/(k-1)MSE =
SSE/(n-k)
FStatistic
MSGMSE
p-value
Use Fk-1,n-k
ANOVA Table
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Source
Groups
Error
Total
df
4
115
119
Sum ofSquares35.90
101.29
137.19
MeanSquare
8.97
0.88
FStatistic10.19
p-value
4.3 × 10-7
ANOVA Table
We have very strong evidence that average length of cuckoo eggs differs for nests of different species
Equal variability Normal(ish) data
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Can we use the F-distribution to calculate the p-value for whether there is a difference in average hours spent studying per week by class year at Duke?
a) Yesb) Noc) Need more information
Study Hours by Class Year
Year Sample Mean
Sample SD
SampleSize
First Year 16.06 10.33 72
Sophomore 17.51 9.29 74
Upperclass 19.31 14.74 52The equal variability condition is satisfied, and the sample sizes are large enough (>30)
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Study Hours by Class Year
Is there a difference in the average hours spent studying per week by class year at Duke?
(a)Yes(b)No(c)Cannot tell from this data(d)I didn’t finish
31824984
SSGSSE
The p-value is 0.29, which means we cannot reject the null, so cannot determine whether there is a difference.
Year Sample Mean
Sample SD
SampleSize
First Year 16.06 10.33 72
Sophomore 17.51 9.29 74
Upperclass 19.31 14.74 52
Statistics: Unlocking the Power of Data Lock5
Source
GroupsErrorTotal
df
2195197
Sum ofSquares
31824984
20013.4
MeanSquare
159128.1
F-Statistic
1.24
ANOVA Table
p-value
0.29
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Summary• Analysis of variance is used to test for a difference in means between groups by comparing the variability between groups to the variability within groups
• Sums of squares are used to measure variability
• The F-statistic is the ratio of average variability between groups to average variability within groups
• The F-statistic follows an F-distribution, if sample sizes are large (or data is normal), variability is equal across groups, and the null hypothesis is true
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To DoRead Section 8.1
Complete the anonymous midterm evaluation by Monday, 11/5, 5pm
Do Homework 6 (due Tuesday, 11/6)