any combination of the prime factorization. find the number that “gazinta” all the numbers. 6...
TRANSCRIPT
262 xx 212 xx 234 xxxxx 322
Any combination of the prime factorization.
)Find the number that “GAZINTA” all the numbers.
62 3
6 goes into 12, 2 times and into 18, 3 times.
The only number that divides into 2 and 3 is 1…the number on the left side is the GCF.GCF = 6
)46 8)23 4
The product of the numbers on the left side is the GCF.GCF = 4 * 2 = 8
)44 6 9
There are no common factors in the remaining factors of 4, 6, and 9. The GCF = 4
The 6 and the 8 can still be divided by 2.
From the previous examples.
3626 x
326 xLeftovers
ba 4838
ba 438 Leftovers
946444 2 xx
9644 2 xxLeftovers
Distributive Property.
1343 x 143 x
babaab 1044
When variables are a GCF, it will always be to the smallest power.
baab 104 26x 3x x4 3
223 yx 3x xy5 32xy 23y yx a2 b3
Group the terms in half.
Factor each side by GCF’s _________ _________ 2x x5 1
Since the 1st two terms are subtracting, both ( )’s will have minus signs.
3 x5 1
In fact, both sets of ( )’s must be the same for this to factor. If not the same, prime.Factor the same binomials as a GCF.
____15 x 2x 3
Factor by grouping
482 23 xxx 212868 34 xxx
byaybxax 2436 2135106 xwxw
_________ _________ 22x x 4 1 x 4
____4x 22x 1
_________ _________ x2 34x 3 7 34x 3
____34 3 x x2 7
_________ _________ x3 a2 b y2 a2 b
____2 ba x3 y2
_________ _________ w2 3 x5 7 3 x5
____35 x w2 7
There is another pattern. Find the product of the F & L terms and O & I terms.
Make up any two binomials, with no GCF, and FOIL them.
F.O.I.L.
When the “c” term is positive it means that the binomials have the same signs, and the sign on the “b” term determines the signs of the binomials.
When the “c” term is negative it means that the binomials have the opposite signs, and the sign on the “b” term determines the signs of the largest value in the binomials.
210xLF 210xIO
210xLF 210xIO
210xLF 210xIO
210xLF 210xIO
This pattern gives us the a, b, c rule for finding our factors. Number Sense!
Factor the trinomials.
1282 xx 2082 xx 652 xx
cbxax 2
b
ca
______
______
O Ix xcIxOxax 2
bx
ca
______
______
_________ _________
O I
Factor by Grouping
8______
121______
b
ca
________
Answer looks like.
________
6 26 2
12262 xxx
_________ _________ 26x x 6x
6x 2x
8______
201______
b
ca
________ BigAnswer looks like.
10 2
10 2
202102 xxx
_________ _________ 210x x 10x
2x10x
Did you just notice that the numbers in the binomial answers are the same numbers that were our factors?
This will always happen when a = 1!
Answer looks like.
5______
61______
b
ca
2323
3x 2x
Number Sense Rules.Odd + Even = OddEven + Even = EvenOdd + Odd = Even2 is a factor every Even.(Odd)*(Odd) = Odd
Factor the trinomials.
____ xx 6 1
5______
61______
b
ca6 16 1
____ xx 3 7
4______
211______
b
ca3 73 7
____ xx 4 6
10______
241______
b
ca4 64 6
____ xx 2 12
___ ___ 24
___ ___ 10
c
b
2 122 12
____ xx 3 8
___ ___ 24
___ ___ 5
c
b
3 83 8
____ xx 3 8
___ ___ 24
___ ___ 11
c
b
3 83 8
____ xx 5 15
___ ___ 75
___ ___ 20
c
b
5 155 15
____ xx 4 12
___ ___ 48
___ ___ 8
c
b
4 124 12
____ xx
___ ___ 60
___ ___ 7
c
b
5 125 12
5(-12) = -60 not 60!
Prime
even + odd
odd
odd + odd
even
(odd)*(odd) = odd
even + even
even
(odd)(even)=even
even + even
even
even
odd + even
odd
odd + even
odd
odd + odd
even
odd
even + even
even
even
Prime doesn’t happen too often, so make sure you check everything!
____ xx 2 18
___ ___ 36
___ ___ 20
c
b
2 182 18
____ xx 4 5
___ ___ 20
___ ___ 1
c
b
4 54 5
____ xx 1 6
___ ___ 6
___ ___ 7
c
b
1 61 6
____ xx
___ ___ 8
___ ___ 7
c
b
1 81 8
1(-8) = -8 not 8!
Prime yxyx ____ 15 3
___ ___ 45
___ ___ 12
c
b
15 3
15 3
nmnm ____ 3 8
___ ___ 24
___ ___ 5
c
b
3 83 8
even + even
even
even
odd + odd
even
odd
These directions means more than one factoring…Watch for GCF!
65 2 xxGCF of 5
____5 xx 2 3
___ ___ 6
___ ___ 1
c
b
2 32 3
13222 xxx
GCF of x2
____2 xxx 12 11
___ ___ 132
___ ___ 1
c
b
12 1112 11
543 26 xxx
GCF of -3x6
____3 6 xxx 1 5
___ ___ 5
___ ___ 4
c
b
1 51 5
1862 2 xxGCF of -2
____2 xx
___ ___ 18
___ ___ 6
c
b
? ?
? ?
1862 2 xx
Not Prime…factored -2 out!
3223 1224 yyxx
GCF of 4
Can’t go any further because of the variables cubed.even + even
even
even
F.O.I.L.
When the “c” term is positive it means that the binomials have the same signs, and the sign on the “b” term determines the signs of the binomials.
When the “c” term is negative it means that the binomials have the opposite signs, and the sign on the “b” term determines the signs of the largest value in the FACTORS not the binomials.
260xLF 260xIO
260xLF 260xIO
260xLF 260xIO
260xLF 260xIO
The author actually suggested guessing what the binomials are and FOILing them out to test if the middle term is correct. 8 tries to get the right answer!?!
7______
1210______
b
ca
________
Answer looks like.
1281510 2 xxx
_________ _________ 43x5 x2 3x2
Refers to the middle term. ODD + EVEN = ODD
odd even
Since we have an odd + even, we need odd factors. Break the 10 and 12 down to odd factors.
4253
5 432Isolate the odd factors and multiply all possible odd combinations.
15 8___3 ___5 ___15
7403 Not the factors
4235 2440
7245 Not the factors
4235 8
7815 Right factors
15 8
3x2 4x5
It should still factor if we switch the 15x and -8x.
________
1215810 2 xxx
_________ _________ 34x2 x5 4x5
4x5 3x2
I can see a pattern! When you look at the left side of each factoring by grouping, I see the two binomials in the answer!Do you see that? Say YES! What terms are generating these binomials? Look above each step.
It is the leading term and the two factors! Can we all agree that we will always factor out at least an x as the GCF? Yep.
Here is a shortcut. Always put the “a” in both binomials.
__10__10 xxPut in the factors.
158
Take out GCF’s
2
45 x
5
32 x
Refers to the middle term. EVEN + EVEN = EVEN
__8__8 xx
Answer looks like this using the new short cut. Use 8x twice.
14__________
158__________
b
ca
even evenBecause a = 8
Since we have an even + even, we factor out a 2 from our factors. Break the 8 down to get factors of 2’s. Put a 2( ) in each blank as a factor because we know that the two factors are even.
53222
22( ) 2( )Factor 2 out of the -14. The sum of the two red ( )’s must = (– 7).
Since – 7 is odd. Isolate the odd factors and multiply all possible odd combinations.
___3 523
10
7103 Right factors! Put them in the red ( )’s!
___5 ___15
3 10
6 20
6 and -20 are the two factors that add up to -14. Place them in our answer.
6 20 Now we know we are not finished because we used the 8 twice. We have to divide out the extra 8 by finding the GCF of each binomial.2
34 x
4
52 x
( – 7 )
EVEN RULE ( odd + odd )
Factor. 63343 2 xx
Refers to the middle term. ODD + ODD = EVEN
__3__3 xx
Answer looks like this using new short cut. Use 3x twice.
34__________
633__________
b
ca
odd oddBecause both a & c are odd
Since a and c as odd factors we have an odd + odd = -34. This is going to take some time because all the factors will be odd. Break 63 down.
733
Isolate each odd factor, from smallest to largest, and then multiply all possible odd combinations to create more odd factors.
___3 ___7 ___9 ___21 ___27 7333 63
34633 Wrong factors!
3337 27
34277 Right factors!
7 27
7 27
-7 and -27 are the two factors that add up to -34. Place them in our answer.
7 27 Now we know we are not finished because we used the 3 twice. We have to divide out the extra 3 by finding the GCF of each binomial. 73 x
3
9x
NO GCF
These directions means more than one factoring…Watch for GCF!
__3__3 xx
10__________
83__________
b
ca
even evenBecause c = -8
42 The 2 or 4 must be multiplied to the 32 12
2 12
2 12 23 x3
4xNO
GCF Remember this example 2 pages ago, where the author FOILed it out 8 times? Which way is easier?
__5__5 xx
7__________
65__________
b
ca
odd even
The 5 and -6 doesn’t work, so try 3 and 10!-3 and 10 work.
3 103 10
10 3 2x5
35 xNO
GCF
32
GCF of 2x. 31142 2 xxx
__4__42 xxx
11__________
34__________
b
ca
Because 11 is much bigger than 4 and 3, multiply 4 and 3 to get 12.
1 121 12
112 32 xx4
14 xNO GCF
__4__4 xx
12__________
54__________
b
ca
odd even
even evenBecause a = 4
2 2
One of the 2’s must be multiplied to the 5. 2 and 10
2 102 10
2 10 12 x2 2
52 x
Factor completely.
xyyx 1946 22 186310 2 xx
20236 2 xx 968 2 xx
22 4196 yxyx
Need to have x powers in descending order.
yxyx __6__6
19__________
46__________
b
ca1 243 8
odd even odd
32
No possible factors.
PRIME __10__10 xx
63__________
1810__________
b
ca
332
3 603 60
3 60 310 x 6x10NO
GCF
odd even odd
52
63 is a big value… factors must be far apart.
__6__6 xx
23__________
206__________
b
ca
522
15 8
15 8
15 8 52 x 43 x3
odd even odd
32
3*_____5*_____15*____
40
24
8
2
__8__8 xx
6__________
98__________
b
ca
222
6 12
3 6
12 6 32 x 34 x4
even even even
33
2( ) 2( )
2
32
One of the 3’s must be mult. to the 2, 6 and 3 subtract to be the 3 in the ( )’s.
3*_____5*_____9* ____15*____45*____
60
Factor completely.234 302830 xxx 183918 2 xx
22 28176 yxyx 152812 2 xx
GCF of 2x2. 1514152 22 xxx
__15__152 2 xxx
14__________
1515__________
b
ca
odd odd even
53 53
3*_____5*_____9*____
75
45
25
1514152 22 xxx
GCF of -3.
61363 2 xx
__6__63 xx
13__________
66__________
b
ca
23 23
odd even odd
9 49 4
9 4
323 x 23 x3 2
yxyx __6__6
17__________
286__________
b
ca
odd even odd
72232
3*_____7*_____21*____
56
24
8
7 247 24
24 7NO
GCF
yx 76 yx 4
6
__12__12 xx
28__________
1512__________
b
ca
322
18 109 5
18 10
32 x 56 x
6
even even even
53
2( ) 2( )
2
142
The two 3’s mult. together, 9 and 5 add up to be the -14 in the ( )’s.
It is important to know that x2, x4, xeven, etc. are all perfect squares
442 xxPer.Sqr.
Per.Sqr.
Let’s try a ( )2
22xWe must test the middle term!
xxx 422 It Factors!
25x
xxx 1055
Done!
24x
xxx 844
Done!
23x
xxx 633
NOT Done!
ERASE
____ xx 1 9Done!
4 and 36 are perfect squares, but 4 is a GCF!
964 2 xx
234 x
xxx 633
Done!
234 x
xxx 241212
Done!
273 x
xxx 422121
Done!
HIDE inside other polynomials!
55 xx 88 xx 49 2 x
GCF of 9, 1st!
229 xx
Factor completely.
8116 4 x 42 x 7512 2 x
22 2536 yx 2864 121100 yxca
9494 22 xx
323294 2 xxxAnother Diff. of Per. SQ!
NOT Diff. of Per. SQ! PRIME
GCF of 3, 1st!
2543 2 x
52523 xx
22 3625 xy
22 25361 yx GCF of -1, 1st!
yxyx 56561
Or put the 25y2 in front.
xyxy 6565
yxcayxca 432432 11101110
Even powers on the variables are still perfect squares. Divide the powers by 2 to take the square root.
Middle terms exist!
Binomial Trinomial
_______________33 ba
Same sign as given
Opposite sign as given
Always Plus
3 3 a b
2a
ab 2b
_________________
3 3
y3 x2
29y
xy6 24x __________________
3 3
x4 5
216x
x20 25
_________________
3 3
yx2 6
24 yx
yx26 36 __________________
3 3
x10 7
2100x
x70 49
3382 txa
______________2 a
3 3
x2 t
24x
xt2 2t
Both Diff. of Per. Sq. and Perfect Cubes
1st
2nd
1818 33 xx
____________
3 3
x2 1
24x
x2 1 ____________ x2 1 24x x2 1
GCF( LEFTOVERS )The number of terms in the leftovers determines which step we go to.
bababa 221st
2nd
Remember these like to hide inside of other polynomials.
_______________33 ba
Same sign as given
Opposite sign as given
Always Plus
3 3 a b
2a
ab 2b
Remember the sign rules for what your answer looks like.
____ axaxb
ca
__________
__________d e
d ed e
GCF GCF
_________ _________
dcxbxax 23
GCFLT
GCFRT
SAME SAME
____________ SAME
GCFLT
GCFRT
2222 2 ybabxxa
3 to 1 SPLIT
22 ybax Difference of
Perfect Squares
1 to 3 SPLITis the same concept, but watch for signs!
GCF of 5 165 4 x
Step 2D.P.S. 445 22 xx
Step 2D.P.S.Again
2245 2 xxx
GCF of 2x 4518522 23 xxxx
Step 4F. by G. 529522 2 xxxx
9522 2 xxxStep 2D.P.S. 33522 xxxx
GCF of 3 883 235 xxx
Step 4F. by G. 1813 223 xxx
813 32 xxStep 2D.P.S.& P.C.
422113 2 xxxxx
Step 2D.P.S. 88 33 xx
Step 2& P.C. twice 422422 22 xxxxxx
Factor completely.
GCF of 7 657 2 xx
Step 3 237 xx
GCF of 3x2 24103 22 xxx
Step 3 2123 2 xxx
3 to 1 SPLIT
2 23x y
Step 4F. by G.
yxyx 33
Difference of Per. Squares
yxyx 33
1 to 3 SPLIT
22 3 xy
Step 4F. by G.
33 xyxy
Difference of Per. Squares
33 xyxy
9622 xxyGCF of -1 first.
Distribute the minus!
Remember the product of -8(10)(3)(5)(0)(7)(11) = 0.
05 x 02 xSolve each for x.
5 5
0x
22
2x2,0x
07 08 x 032 x07 8x 32 x
2
3x
2
3,8x
02 x0x
01x1x
01x1x
1,1,0 x
064 xx04 x 06 x
4x 6x6,4x
0212 xx
12x 2x
2,12 x
Solve the equations by factoring.
01682 xx xx 62 254 2 x
044 xx
4xWe don’t have to list the same number twice, but just know that there were two answers that were the same value.
Never divide by the variable!Set the equation = 0.
062 xx 06 xx
0x 6x
6,0x
0254 2 x
05252 xx
052 x
52 x
2
5x
2
5x
2
5,
2
5x
No reason to work out the 2nd binomial because the only difference will be the sign.
Solve the equations by factoring.
063162 xx 28122 xx
02482 23 xxx 0356 2 xx
097 xx
7x 9x
9,7 x
028122 xx 0214 xx
14x 2x2,14x
01242 2 xxx
0622 xxx
6x2x0x
6,2,0 x
0__6__6 xx
1__________
356__________
b
ca
57
15 14
15 14
1514 73 x 052 x2
odd even odd
32
3
The factors have to
differ by 1, so 2(7)=14
and 3(5)=15
073 x73 x
3
7x
052 x52 x
2
5x
Solve the equations by factoring.
027308 2 xx012832 23 xxx
0__8__8 xx
30__________
278__________
b
ca
222
36 6
18 3
36 6
even even even
333
2( ) 2( ) 152
One of the 3’s must be isolated, 3 and 18 will subtract to be 15 in the ( )’s.
092 x
92 x
2
9x
034 x
34 x
4
3x
0324322 xxx
0432 2 xx
02232 xxx
032 x
32 x
2
3x
2x 2x
4
3,
2
9x
2
3,2,2 x
4 2
Solve the equations by factoring.
9123 xx xxx 543 Will need to FOIL and set = 0
9362 2 xxx01252 2 xx
0__2__2 xx
5__________
122__________
b
ca
322
odd even odd
33 8
8
8 3
04 x
4x
032 x
32 x
2
3x
4,2
3x
xxxx 512342
01242 xx
026 xx
6x 2x
2,6 x
2
xxx 51212
The cutting board is a rectangle because of the reference to “long and wide.” Build a rectangle.
W
LWe know that the Length is twice the Width.
W2
The Area formula is L * W and the Area equals 800.
AreaWL
8002 WW
8002 2 W
08002 2 W
04002 2 W
020202 WW
20W 20W WL 240202 L
The dimensions are 40 cm by 20 cm.
Means that the numbers differ by 1. The First number is unknown, call it x.The Second number must be 1 bigger… x + 1
1561 xx
Multiply the two numbers and set = 156
15612 xx
015612 xx
01213 xx
13x 12x
Assuming the racing number must be positive, the first number is 12 and the consecutive second number is 13.
4402 xx44022 xx
044022 xx
Means that the numbers differ by 2. The First number is unknown call it x.The Second number must be 2 bigger… x + 2
02022 xx
22x 20x
There are two sets of answers!
-22 and -20
20 and 22
Right triangles have a special relationship called The Pythagorean Theorem. 222 cba a
b
c
The legs of the right triangle are the sides of the right angle, labeled a and b. The hypotenuse is the longest side and is labeled c.
x
3x
15222 cba
222 153 xx
22593322 xxxx
021662 2 xx
010832 2 xx
09122 xx
12x 9x
9
1239
The other two sides are 9 ft and 12 ft.
210N
21010010 2 tt
021010010 2 tt
0211010 2 tt
07310 tt
3t 7t
There will be 210 micrograms in the bloodstream at 3 minutes and 7 minutes.
135
100120
35
222 12035 c2144001225 c
215625 c
156250 2 c 1251250 cc
125c
c
The minimum length of the cable is 125 ft.
50h
10h
222 5010 hh
2500100101022 hhhh
02400202 2 hh
01200102 2 hh
030402 hh
30h
The two distances are 30 ft. and 40 ft.
A number is 6 less than its square. Find all such numbers.
x 62 x
60 2 xx
320 xx
2x 3x
62 xx
642
622 2
62 xx
693
633 2