b production 181015 me gh1-sol

7/25/2019 B Production 181015 ME GH1-Sol

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ME Production EngineeringDate : 18/10/2015

Mechanical Engineering

CLASS TEST - 2015

Serial No. : B__Production_181015_ME_GH1

ANSWERS

1.1.1.1.1. (b)(b)(b)(b)(b)

2.2.2.2.2. (b)(b)(b)(b)(b)

3.3.3.3.3. (a)(a)(a)(a)(a)

4.4.4.4.4. (a)(a)(a)(a)(a)

5.5.5.5.5. (a)(a)(a)(a)(a)

6.6.6.6.6. (c)(c)(c)(c)(c)

7.7.7.7.7. (c)(c)(c)(c)(c)

8.8.8.8.8. (a)(a)(a)(a)(a)

9.9.9.9.9. (c)(c)(c)(c)(c)

10.10.10.10.10. (d)(d)(d)(d)(d)

11.11.11.11.11. (c)(c)(c)(c)(c)

12.12.12.12.12. (b)(b)(b)(b)(b)

13.13.13.13.13. (c)(c)(c)(c)(c)

14.14.14.14.14. (d)(d)(d)(d)(d)

15.15.15.15.15. (b)(b)(b)(b)(b)

16.16.16.16.16. (b)(b)(b)(b)(b)

17.17.17.17.17. (d)(d)(d)(d)(d)

18.18.18.18.18. (a)(a)(a)(a)(a)

19.19.19.19.19. (a)(a)(a)(a)(a)

20.20.20.20.20. (c)(c)(c)(c)(c)

21.21.21.21.21. (c)(c)(c)(c)(c)

22.22.22.22.22. (a)(a)(a)(a)(a)

23.23.23.23.23. (a)(a)(a)(a)(a)

24.24.24.24.24. (b)(b)(b)(b)(b)

25.25.25.25.25. (d)(d)(d)(d)(d)

26.26.26.26.26. (d)(d)(d)(d)(d)

27.27.27.27.27. (a)(a)(a)(a)(a)

28.28.28.28.28. (d)(d)(d)(d)(d)

29.29.29.29.29. (c)(c)(c)(c)(c)

30.30.30.30.30. (a)(a)(a)(a)(a)


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6 MECHANICAL ENGINEERING

EXPLANAEXPLANAEXPLANAEXPLANAEXPLANATIONSTIONSTIONSTIONSTIONS

1.1.1.1.1. (b)(b)(b)(b)(b)

Backward cold extrusion or impact extrusion or backward impact extrusion.

2.2.2.2.2. (b)(b)(b)(b)(b)

3.3.3.3.3. (a)(a)(a)(a)(a)

4.4.4.4.4. (a)(a)(a)(a)(a)

5.5.5.5.5. (a)(a)(a)(a)(a)

6.6.6.6.6. (c)(c)(c)(c)(c)

7.7.7.7.7. (c)(c)(c)(c)(c)

8.8.8.8.8. (a)(a)(a)(a)(a)

9.9.9.9.9. (c)(c)(c)(c)(c)

10.10.10.10.10. (d)(d)(d)(d)(d)

11.11.11.11.11. (c)(c)(c)(c)(c)

12.12.12.12.12. (b)(b)(b)(b)(b)

13.13.13.13.13. (c)(c)(c)(c)(c)

Brazing fluxes are generally made of borax, boric acid, borates, fluorides and chlorides.

14.14.14.14.14. (d)(d)(d)(d)(d)

15.15.15.15.15.

(b)(b)(b)(b)(b)

Given:

D= 10 mm, N= 1000 rpm, v= 31.41 m/min, L= 100 mm, f= 0.7 mm/rev.

From Taylors tool life expression, we have

Substituting the values, we get

31.41 T1.2 = 180

or T = 4.28 min

Machining time/piece

=

=

= 0.142 min

Machining time for 1000 workpieces

= 1000 0.142

= 142.86 min

Number of resharpenings

=

= 33.37

or 34 resharpenings


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7CTME15 | Production Engineering

16.16.16.16.16. (b)(b)(b)(b)(b)

Heat supplied = I2Rt

= 300002 100 106 0.005

= 450 J

Volume of the joint

=

= 29.452 mm3

Heat required for melting

= 29.452 10

= 294.52 J

Melting efficiency,

=

100 %

= 65.45 %

17.17.17.17.17. (d)(d)(d)(d)(d)

Surface area of cube = 6l2

Surface area of sphere = 4 r2

According to Chorinovs relation

Solidification time

as volume of cube and sphere are equal

=

=

=

l

18.18.18.18.18. (a)(a)(a)(a)(a)

19.19.19.19.19. (a)(a)(a)(a)(a)

We know that

tan i= tan bsin tan

scos

For orthogonal cutting operation

i = 0

= tan

s

b

= 7

tan s

=

= 90 30 = 60tan

s= 0.213

s

= 12.00


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20.20.20.20.20. (c)(c)(c)(c)(c)

We know that

=

+

= 10FT

= 560

FC

= 1177

+

= 0.712

21.21.21.21.21. (c)(c)(c)(c)(c)

We know that shear angle of work material

=

+

= tan1(0.5)= 26.57

Shear angle

= 37.715 = 12

=

( )( )

+

Fs

= 0.632 Fc

Fc

= 567 N

Ft

= 227 N

Fs

= 567 0.632 358.34 N

=

= 438.4176438 MPa

22.22.22.22.22. (a)(a)(a)(a)(a)

VTn = Constant

V1T1n = VT2

n

=

=

n =( )

=


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9CTME15 | Production Engineering

23.23.23.23.23. (a)(a)(a)(a)(a)

Time taken to drill 10 holes at 250 m

T1

=

Time taken to drill 50 holes at 200 rpm

T2 =

V1T

1n = V

2T

2n

But V =

V N N1T1

n = N2T2n

n log

=

n =

=

24.24.24.24.24. (b)(b)(b)(b)(b)

Cutting speed,

v =

=

= 2.51 m/sec.

25.25.25.25.25. (d)(d)(d)(d)(d)

0 = 10, r = 0.3

tan =

tan

= tan1(0.312) = 17.33 = cot + tan(

0)

= cot 17.33 + tan(7.33)= 3.2041 + 0.1286

= 3.34


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26.26.26.26.26. (d)(d)(d)(d)(d)

Q =====( )

=

= 125000 W/cm2

or 125 KW/cm2

27.27.27.27.27. (a)(a)(a)(a)(a)

D ===== +

===== ( ) ( )

+

= 184.4 mm

28.28.28.28.28. (d)(d)(d)(d)(d)

F = A0K

l

= ( )

l

= 1.26 MN

29.29.29.29.29. (c)(c)(c)(c)(c)

Given that ; V1

= 50 m/min, T1= 100 min, n = 0.26

For 25% higher speed, V2= 1.25

V2= 62.5 m/min

We know that, V1

T1

n= V2

T2

n

Substituting the values, we get

T2 = 42.39 min

30.30.30.30.30. (a)(a)(a)(a)(a)

Fc = 500 N

Fx

= 200 N (axial component)

Ft

=

=

= 207.055 N

F = Fcsin + Ftcos = 500 sin 10 + 207.055 cos 10

F = 290.733 NN = Fccos Ftsin

= 500 cos 10 207.055 sin 10

= 456.449 N

=

=

= 0.6369

0.64

b production 181015 me gh1-sol

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