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  • 7/26/2019 Backup calcus

    1/2

    > a:=exp(x)/2;

    :=a1

    2ex

    >b:= 15*ln(x^2);

    :=b 15 ( )ln x2

    > fsolve(a=b,x);-1.006112566

    > evalf(a=b);

    =0.5000000000 ex

    15. ( )ln x2

    > a=b;

    =

    1

    2ex

    15 ( )ln x2

    > c:=a=b;

    :=c =1

    2ex

    15 ( )ln x2

    > solve(c,x);

    ( )RootOf e_Z

    30 ( )ln _Z2

    > fsolve(c,x);

    -1.006112566

    > d:=b-a;

    :=d 15 ( )ln x2

    1

    2ex

    > int(d,x=0..4.5);

    23.54188291

    > %/2;

    11.77094146

    > int(d,x=0..u);

    +

    1

    215 ( )ln u

    2u 30u

    1

    2eu

    > fsolve(%,u);

    5.416292883

    > int(d,x=1..4.5);

    54.40102383

    > e:=int(d,x=1..u)=(int(d,x=1..4.5))/2;

    :=e =+ + 301

    2e 15 ( )ln u

    2u 30u

    1

    2eu

    27.20051192

    > fsolve(%,u);

    5.472653137

  • 7/26/2019 Backup calcus

    2/2

    > (int(d,x=1..4.5))/2

    > ;

    27.20051192

    >m:= int(d,x=1..p)=(int(d,x=1..4.5))/2;

    :=m =+ + 301

    2e 15 ( )ln p

    2p 30p

    1

    2ep

    27.20051192

    > fsolve(m,p);

    5.472653137

    > solve(m,p);Warning, solutions may have been lost

    > solve(m,p);Warning, solutions may have been lost

    > evalf(m,p);Error, invalid input: evalf expects its 2nd argument, n, to be of type posint, but

    received p

    >