basic block diagram of op-amp an op-amp can be conveniently divided in to four main blocks 1.an...
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Basic Block Diagram of Op-AmpAn Op-Amp can be conveniently divided in to four main blocks1. An Input Stage or Input Diff. Amp.2. The Gain Stage3. The Level Translator4. An Out put Stage Note: It can be used to perform various mathematical operations such
as Addition, Subtraction, Integration, Differentiation, log etc.
Input Stage(Diff. Amp.)
Gain Stage (C E Amp.)
Level Shifter
Out put Stage (Buffer)
V1
V2
VO
Op-Amp IC
I/P
An IDEAL OP AMP
An ideal op amp has the following characteristics:1. Infinite open-loop voltage gain, AV ≈ ∞.
2. Infinite input resistance, Ri ≈ ∞.
3. Zero output resistance, Ro ≈ 0.
4. Infinite CMRR, ρ =∞
5. The output voltage Vo=0; when Vd = V2-V1 = 0
6. Change of output with respect to input, slew rate = ∞
7. Change in out put voltage with Temp., ∂Vo/∂Vi=0
• i(+), i(-) : Currents into the amplifier on the inverting and non-inverting lines respectively
• vid : The input voltage from inverting to non-inverting inputs• +VS , -VS : DC source voltages, usually +15V and –15V• Ri : The input resistance, ideally infinity• A : The gain of the amplifier. Ideally very high, in the 1x1010 range.• RO: The output resistance, ideally zero• vO: The output voltage; vO = AOLvid where AOL is the open-loop voltage gain
The Operational Amplifier+VS
-VS
vid
Inverting
Noninverting
Output
+
_i(-)
i(+)
vO = AdVid
RO
ARi
• An operational amplifier circuit is designed so that
1) Vout = Av (V1-V2) (Av is a very large gain)
2) Input resistance (Rin) is very large
3) Output resistance (Rout) is very low
Operational Amplifier Model
V1
V2
VoutRin
+-
Rout
Av(V1- V2)
Practical Op-Amp Circuits
These Op-amp circuits are commonly used:– Inverting Amplifier– Noninverting Amplifier– Unity Follower– Summing Amplifier– Integrator– Differentiator
Notice the output formula is similar to Inverting Amplifier, but they are not the same.
Noninverting Amplifier
V1)R1
Rf1(Vo
Summing Amplifier
Because the op-amp has a high input impedance the multiple inputs are treated as separate inputs.
3
3
f2
2
f1
1
fV
R
RV
R
RV
R
RVo
Inverting Amplifier: Input and Output Resistances
Rinvsis
R1 since v 0
11i
22iov RR
But i1=i2)
12(
1iv RRo
Since v- = 0, i1=0. Therefore vo
= 0 irrespective of the value of io
. 0 outR
Rout is found by applying a test current (or voltage) source to the amplifier output and determining the voltage (or current) after turning off all independent sources. Hence, vs = 0
Differential Amplifier Using Op Amp
v v
11
1
v vi
R
I/P Current to op amp is zero
01
2
v vi
R
+
-1R
2R
1vovv
v1i
1i
2v1R
2R
22
1 2
Rv v
R R
01
1 2
v vv v
R R
2 21 2 2 0
1 2 1 2
1 2
R Rv v v v
R R R R
R R
Differential Amplifier Using Op Amp
+
-1R
2R
1vovv
v1i
1i
2v1R
2R
2 21 2 2 0
1 2 1 2
1 2
R Rv v v v
R R R R
R R
2
2 2 20 1 2 2
1 1 2 1 1 2
R R Rv v v v
R R R R R R
2 2 20 1 2
1 1 2 1
1R R R
v v vR R R R
20 2 1
1
Rv v v
R
The Unity-Gain Amplifier or “Buffer”
• This is a special case of the non-inverting amplifier, which is also called a voltage follower, with infinite R1 and zero R2.
Hence Av = 1.• It provides an excellent electrical isolation while maintaining the signal voltage
level.• The “ideal” buffer requires no input current and can drive any desired load
resistance without loss of signal voltage.• Such a buffer is used in many sensor and data acquisition system applications.
1oF
i
vA
v
i ov v v v
+
-ov
v
viv
oF
i
vA
v
i ov v v v
Closed-loop voltage gain
Used as a "line driver" that transforms a high input impedance (resistance) to a low output impedance. Can provide substantial current gain.
Unity-Gain Buffer
Since the inverting input is at virtual ground
dt
dvCi o
2
R
vi in1
Applying KCL at the inverting input
i1+i2 = 0
0R
v
dt
dvC ino
)initial(vdtvRC
1v oino
Op-Amp Integrator Cont…
dt
dvCi in
1
R
vi o
2
i1+i2 = 0
0R
v
dt
dvC oin
dt
dvRCv in
o
Since the inverting input is at virtual ground
Applying KCL at the inverting input
Differentiators are avoided in practice as they amplify noise
Op-Amp Differentiator Cont…
Instrumentation Amplifier
Combines 2 non-inverting amplifiers with the difference amplifier to provide higher gain and higher input resistance. Gain can be varied by varying single resistor R1
)b
va(v
3
4v R
Ro
bv
2i)
1i(2
2iav RRR
12
2v
1v
iR
)2
v1
(v
1
21
3
4v
R
R
R
Ro
NOTE
Ideal input resistance is infinite because input current to both op amps is zero. The CMRR is determined only by Op Amp 3.
Finite Open-loop Gain and Gain Error
21
1
ovov
21
11
v
RR
R
RR
R
is called the feedback factor.
AA
vA
AAA
1svov
)ovsv()1
vsv(id
vov
Av1
1R
2R1
This is the “ideal” voltage gain of the amplifier. If Ab is not >>1, there will be “Gain Error”.
• Gain Error is given by
GE = (ideal gain) - (actual gain)
For the non-inverting amplifier,
• Gain error is also expressed as a fractional or percentage error.
)1(1
11
AAAGE
FGE
1
A1A1
11A
1A
PGE 1A
100%
io 5V500
10mA
)21
(
ov
12
ovovF
iL
ioi
RRLR
EQR
EQRRR
LR
For the inverting amplifier,
2RLREQ
R
Practical op amps have limited output voltage and current ranges.
Voltage: Usually limited to a few volts less than power supply span.
Current: Limited by additional circuits (to limit power dissipation or protect against accidental short circuits).
The current limit is frequently specified in terms of the minimum load resistance that the amplifier can drive with a given output voltage swing. Eg:
Output Voltage and Current Limits