bjt amplifiers (cont’d) common-base topology. outline common-base topology – cb core – cb...
TRANSCRIPT
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BJT Amplifiers (cont’d)
Common-base topology
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OUTLINE
• Common-base topology– CB core– CB stage with source resistance– Impact of base resistance
• CB stage with biasing– Emitter follower (Common-collector amplifier)– Analysis of emitter follower core– Impact of source resistance– Impact of Early effect
• Emitter follower with biasing
Reading: Chapter 5.3.2, 5.3.3-5.4
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Common Base (CB) Amplifier
The base terminal is biased at a fixed voltage; the input signal is applied to the emitter, and the output signal sensed at the collector.
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Small-Signal Analysis of CB Core
The voltage gain of a CB stage is gmRC, which is identical to that of a CE stage in magnitude and opposite in phase.
Cmv RgA
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Tradeoff between Gain and Headroom
To ensure that the BJT operates in active mode, the voltage drop across RC cannot exceed VCC-VBE.
T
BECCC
T
Cv V
VVR
V
IA
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Simple CB Stage Example
2.172230130
1 Cmv RgA
VCC = 1.8VIC = 0.2mAIS = 5x10-17 A = 100
k7.67 ,k3.22
2010 Choose
if 354.1
21
211
121
2
RR
RR
VAII
IIVRR
RVV
CCB
BCCb
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Input Impedance of a CB Stage
The input impedance of a CB stage is much smaller than that of a CE stage.
Am
in Vg
R if 1
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CB Stage with Source Resistance
With the inclusion of a source resistance, the input signal is attenuated before it reaches the emitter of the amplifier; therefore, the voltage gain is lowered. This effect is similar to CE stage emitter degeneration.
S
m
Cv
Rg
RA
1
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Practical Example of a CB Stage
An antenna usually has low output impedance; therefore, a correspondingly low input impedance is required for the following stage.
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Output Impedance: CE vs. CB Stages
The output impedances of emitter-degenerated CE and CB stages are the same. This is because the circuits for small-signal analysis are the same when the input port is grounded.
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Output Impedance of a CB Stage
The output impedance of a CB stage is equal to RC in parallel with the impedance looking into the collector.
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1
||
||)||(1
outCout
EOEmout
RRR
rRrrRgR
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Av of CB Stage with Base Resistance (VA = ∞)
With base resistance, the voltage gain degrades.
BC
outP
BCm
outBP
Cm
outCmout
RrR
vv
RrRgr
vRr
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Rg
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inBC
out
Cm
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E
inPm R
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v
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vg
rR
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1 :P nodeat KCL
1
11
BE
m
C
BE
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in
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RR
g
R
RRr
R
v
v
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Voltage Gain: CE vs. CB Stages
The magnitude of the voltage gain of a CB stage with source and base resistances is the same as that of a CE stage with base resistance and emitter degeneration.
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Rin of CB Stage with Base Resistance (VA = ∞)
The input impedance of a CB stage with base resistance is equal to 1/gm plus RB divided by (+1). This is in contrast to a degenerated CE stage, in which the resistance in series with the emitter is multiplied by (+1) when seen from the base.
1
1
1
1
B
m
B
x
xin
xxB
m
xm
R
g
Rr
i
vR
ivRr
rg
r
ivgr
vKCL
xB
vRr
rv
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Input Impedance Seen at Emitter vs. Base
Common Base Stage Common Emitter Stage
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Input Impedance Example
To find RX, we have to first find Req, treat it as the base resistance of Q2 and divide it by (+1).
1
1
1
11
12 B
mmx
R
ggR
1
1
1
B
meq
R
gR
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Biasing of CB Stage
SEmE
ECm
in
out
in
X
X
out
in
outv
RRgR
RRg
v
v
v
v
v
v
v
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1
inSEmE
Ein
Sin
inX v
RRgR
Rv
RR
Rv
1
RE is necessary to provide a path for the bias current IE to flow, but it lowers the input impedance.
Em
E
Em
Em
Em
in Rg
R
Rg
Rg
Rg
R
11
1
||1
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Reduction of Input Impedance Due to RE
The reduction of input impedance due to i1 is undesirable because it shunts part of the input current to ground instead of to Q1 (and RC).
Choose RE >> 1/gm , i.e. ICRE >> VT
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Creation of Vb
A resistive voltage divider lowers the gain. To remedy this problem, a capacitor is inserted
between the base and ground to short out the resistive voltage divider at the frequency of interest.
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Example of CB Stage with Bias
Design a CB stage for Av = 10 and Rin = 50.
Rin = 50≈ 1/gm if RE >> 1/gm
Choose RE = 500
Av = gmRC = 10 RC = 500 IC = gm·VT = 0.52mA VBE=VTln(IC/IS)=0.899V
Vb = IERE + VBE = 1.16V Choose R1 and R2 to provide Vb
and I1 >> IB, e.g. I1 = 52A CB is chosen so that (1/(+1))(1/CB) is small compared to 1/gm at the
frequency of interest.
VCC = 2.5VIS = 5x10-16 A= 100VA = ∞
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BJT Amplifiers (cont’d)
Emitter Follower
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Emitter Follower (Common Collector Amplifier)
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Emitter Follower Core
When the input voltage (Vin) is increased by Vin, the collector current (and hence the emitter current) increases, so that the output voltage (Vout) is increased.
Note that Vin and Vout differ by VBE.
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Unity-Gain Emitter Follower
In integrated circuits, the follower is typically realized as shown below. The voltage gain is 1 because a constant collector current
(= I1) results in a constant VBE; hence Vout = Vin .
1vA
AV
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Small-Signal Model of Emitter Follower
The voltage gain is less than 1 and positive.
mE
E
E
in
out
E
outoutinm
outin
E
outm
outin
gR
R
Rrv
v
R
vvvg
r
vv
R
vvg
r
v
vvv
111
1
1
:emitterat KCL
AV
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Emitter Follower as a Voltage Divider
AV
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Emitter Follower with Source Resistance
11
S
mE
E
in
out
Rg
R
R
v
v
AV
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Input Impedance of Emitter Follower The input impedance of an emitter follower is the
same as that of a CE stage with emitter degeneration (whose input impedance does not depend on the resistance between the collector and VCC).
Ex
xin Rr
i
vR )1(
AV
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Effect of BJT Current Gain
There is a current gain of (+1) from base to emitter. Effectively, the load resistance seen from the base
is multiplied by (+1).
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Emitter Follower as a Buffer The emitter follower is suited for use as a buffer
between a CE stage and a small load resistance, to alleviate the problem of gain degradation.
speaker221 )1( RrRin
1inCmv RRgA speakerRRgA Cmv
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Output Impedance of Emitter Follower
An emitter follower effectively lowers the source impedance by a factor of +1, for improved driving capability.
The follower is a good “voltage buffer” because it has high input impedance and low output impedance.
Es
mout R
R
gR ||
1
1
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Emitter Follower with Early Effect Since rO is in parallel with RE, its effect can be easily
incorporated into the equations for the voltage gain and the input and output impedances.
OE
m
sout
OEin
m
SOE
OEv
rRg
RR
rRrR
gR
rR
rRA
||||1
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||1
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||
||
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Emitter Follower with Biasing
A biasing technique similar to that used for the CE stage can be used for the emitter follower.
Note that VB can be biased to be close to VCC because the collector is biased at VCC.
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Supply-Independent Biasing By putting an independent current source at the
emitter, the bias point (IC, VBE) is fixed, regardless of the supply voltage value.
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Summary of Amplifier Topologies The three amplifier topologies studied thus far have
different properties and are used on different occasions.
CE and CB stages have voltage gain with magnitude greater than one; the emitter follower’s voltage gain is at most one.
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Amplifier Example #1 The keys to solving this problem are recognizing the
AC ground between R1 and R2, and using a Thevenin transformation of the input network.
SE
m
S
C
in
out
RRR
Rg
RRRR
vv
1
1
1
2
11
||||
CE stage Small-signal equivalent circuit
Simplified small-signal equivalent circuit
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Amplifier Example #2 AC grounding/shorting and Thevenin transformation
are needed to transform this complex circuit into a simple CE stage with emitter degeneration.
S
m
S
C
in
out
RRR
Rg
RRR
v
v
1
1
21 1
1
||
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Amplifier Example #3 First, identify Req, which is the impedance seen at
the emitter of Q2 in parallel with the infinite output impedance of an ideal current source.
Second, use the equations for a degenerated CE stage with RE replaced by Req.
1
1 1
2
R
gR
meq
111 1
21
121
Rgg
RA
RrrR
mm
Cv
in
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Amplifier Example #4
Sm
Cv
Rg
RRA
1|| 1
Note that CB shorts out R2 and provides a ground for R1, at the frequency of interest.
R1 appears in parallel with RC; the circuit simplifies to a simple CB stage with source resistance.
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Note that the equivalent base resistance of Q1 is the parallel connection of RE and the impedance seen at the emitter of Q2.
Amplifier Example #5
ES
mmin R
R
ggR ||
1
1
1
11
21