c puzzles by raju(srk)

8/9/2019 c Puzzles by Raju(Srk)

1/40

simple

C Puzzles


2/40

main(){int i=400,j=300;

printf("%d%d");

}ans:


3/40

Answer:400300

Explanation:

printf takes the values of the first two

assignments of the program.

Any number of printf's may be given. All

of them take only the first two values.

If more number of assignments given in

the program,then printf will take garbage

values.


4/40

#define ABC 200

#define XYZ 10#define XXX ABC / XYZ

void main()

{

int a;

a = XXX * 10;printf("%d ", a);

}ans:


5/40

Ans:2

a = xxx * 10which is => a = ABC/XYZ * 10

=> a = 200 /10 * 10

=> a = 200 / 100

=> a = 2


6/40

main()

{printf("\nab");

printf("\bsi");

printf("\rha");

}ans:


7/40

Answer:hai

Explanation:

\n - newline

\b - backspace

\r - linefeed


8/40

main()

{

int c=- -2;

printf("c=%d",c);

}ans:


9/40

Ans: c=2

Explanation:

Here unary minus (or

negation) operator is used

twice. Same maths rules

applies, ie. minus * minus=plus.


10/40

#define square(x) x*x

main(){

int i;

i = 64/square(4);

printf("%d",i);

}ans:


11/40

Answer:

64i=64/x*x

i=64/4*4

i=16 *4

i=64


12/40

main()

{int i;

printf("%d",scanf("%d",&i));

// value 10 is given as

input here

}ans:


13/40

ans:1

Scanf returns number ofitems successfully read.

Here 10 is given as input

which should have been

scanned successfully. So

number of items readis 1.


14/40

#define int char

main(){

int i=65;

printf("sizeof(i)=%d",sizeof

(i));

}ans:


15/40

Ans:sizeof(i)=1

Since the #define replaces

the string int by the macro

char and 65 treated as

single.


16/40

Void main()

{int x=4,y,z;

y=--x;

z=x--;

printf(%d %d %d,x,y,z);

}ans:


17/40

Ans:2 3 3

y=--x (x=3,y=3)

z=x-- (z=3,x=2)


18/40

void main()

{

printf(%c,abcdef[4]);

}ans:


19/40

Ans:e


20/40

void main()

{int x=4,y=2,z;

z=x-- -y;

printf(%d %d %d,x,y,z);}ans:


21/40

Ans:3 2 2


22/40

#include

void main (){ int i=1;

switch(i-2)

{ case -1:printf(a);case 0:printf(b);

case 1:printf(c);

default:printf(none);

}

}ans:


23/40

Ans:abcnone


24/40

#include

void main (){ int i=1;

switch(i)

{ printf(b);case 1:printf(a);break;

case 2:printf(aa);break;

}

}ans:


25/40

Output:a


26/40

#include

void main(){

float a=3.15555;

printf(\n%5.4f,a);printf(\n%0.0f,a);

}ans:


27/40

Output:

3.15553


28/40

#include

void main(){

int a=500,b=100,c;

if(!a>=400)b=300;

c=200;

printf(b=%d c=%d,b,c);

}ans:


29/40

Output:b=100 c=200

(!a>=400)==(a


30/40

Void main()

{int x;

for(x=-1;x


31/40

Ans:0 times


32/40

#include

void main(){ int a[5]={5,1,15,20,25};

int i,j,k;

i=++a[1];j=a[1]++;

k=a[i++];

printf(\n%d %d %d,i,j,k);

}ans:


33/40

Output:

3 2 15++a[1]=2=i

a[1]=2=j& ++ a[1]=3

m=a[2]=15 & i++ ie,i=3


34/40

#include

main()

{

int a = 5;

printf("%d %d\n", a++, ++a);

} ans:


35/40

Output:5 7


36/40

What is the output of the following

code?# include

#define a 10

main()

{ printf("%d..",a);foo();

printf("%d",a);

}

void foo(){

#undef a

#define a 50

}ans:


37/40

Output:10..10


38/40

#include

void main(){

int I=3,*j,**k;

j=&I;k=&j;

printf("%d%d%d",*j,**k,*(*k)

);

}ans:


39/40


40/40

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