cct 226-final
TRANSCRIPT
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By:
Eric N. Madan
Arqam Iqbal Pasha
CCT 226: PRESENTATION
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Joke!
A statistician can have his head in an oven and his feet in ice, and he will say that on the average he feels fine.
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QUESTION 108(a)
Refer to the real estate data from the Central Area of Edmonton, which reports information on listed homes.
a. Select the variable size (Sq. Ft.) 1. Find the mean, median and the standard
deviation.2. Determine the coefficient of skewness, is the
distribution positively or negatively skewed?3. Develop a box plot. Are there any outliers?
Estimate the first and third quartiles.4. Summarize the results.
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*unless you are sure of what you are doing!
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Data Set
Class Distribution Mid-Points (X) Frequency (f) f * X X^2 f * (X^2)
672 - 997 834.50 19 15,855.50 696,390.25 581,137,663.63
998 - 1323 1,060.50 34 36,057.00 1,124,660.25 1,192,702,195.13
1324 - 1649 1,486.50 15 22,297.50 2,209,682.25 3,284,692,664.63
1650 - 1975 1,812.50 10 18,125.00 3,285,156.25 5,954,345,703.13
1976 - 2301 2,138.50 12 25,662.00 4,573,182.25 9,779,750,241.63
2302 - 2627 2,464.50 4 9,858.00 6,073,760.25 14,968,782,136.13
2628 - 2953 2,790.50 2 5,581.00 7,786,890.25 21,729,317,242.63
96 133,436.00 57,490,727,846.88
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Result
Mean = 1,389.96 Median = 1239.5Mode = 1119
Standard Deviation = 24560.39974Coefficient of Skewness = 0.018378162
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Let’s Get Serious
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Arithmetic Mean
n
iiX
NMean
1
1
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Arithmetic Mean (cont.)
1.414,196
754,135Mean
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Median
thMedian
thN
Median
2
196
2
1
Median = 48.5th term = 1239.5
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Mode
1119Mode
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Standard Deviation
1
2
2
nn
XX
s
568.497s
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Coefficient of Skewness
s
MedianMeansk
3
568.497
5.239,11.414,13 sk
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Coefficient of Skewness (cont.)
93816.0skewness
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First Quartile
L25 = 24.25th term
P25 = 1050.25
4
1)196(
4
11
25
25
L
nL
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Third Quartile
L75 = 72.75th term
P75 = 1793
4
3)196(
4
31
75
75
L
nL
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Box Plot
There is one outlier = 2947
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Summary
Mean = 1,414.10 Median = 1239.5Mode = 1119
Standard Deviation = 497.568Coefficient of Skewness = 0.93816
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Excel Overview
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