ch03 mine.pptjohnston/me204/ee204... · title: microsoft powerpoint - ch03 mine.ppt [compatibility...
TRANSCRIPT
![Page 1: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/1.jpg)
Effect on the current of changing the voltage with the resistance at a constant value.
Ohm’s Law
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
•I = V/R
•V = RI
•R = V/I
![Page 2: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/2.jpg)
Effect on the current of changing the resistance with the voltage at a constant value.
Ohm’s Law
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
•I = V/R
•V = RI
•R = V/I
![Page 3: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/3.jpg)
Graph of current versus voltage
Linear Relationships
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
![Page 4: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/4.jpg)
A graphic aid for the Ohm’s law formulas.
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
![Page 5: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/5.jpg)
Determine IT
IT = 50V/1.0k Ohms
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
I = 50mA
![Page 6: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/6.jpg)
Determine RL
RL = 12V/3A
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
RL = 4 Ohms
![Page 7: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/7.jpg)
Determine VS
Vs = (100 Ohms)(5A)
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
Vs = 500V
![Page 8: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/8.jpg)
Power in Electric Circuits
P = VI
•1 Watt of Power is 1 Joule of Energy/Second
•Rate of Work Being Done
•Heat being Produced
•Source has to Generate Enough Votage & Current for Circuit Load
P = VI
P = I2 R
P = V2/R
High Power Circuits have:
A. High Voltage
B. High Current
C. A & B
![Page 9: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/9.jpg)
Power dissipation in an electric circuit is seen as heat given off by the resistance.
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
![Page 10: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/10.jpg)
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
(a) P = (10V)(2A) = 20W
(b) P = (2A)2(47Ohms) = 188W
(c) P = (5V)2/(1Ohms) = 2.5W
Unknown Source Voltage Unknown CurrentUnknown Resistance
![Page 11: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/11.jpg)
Ohm’s Law and Power Wheel
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
![Page 12: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/12.jpg)
All Circuits have a certain amount of Power Loss – Generally Through Heat
Power EfficiencyOften stated as a Percentage
Thomas L. Floyd
Electronics Fundamentals, 6e
Electric Circuit Fundamentals, 6e
Copyright ©2004 by Pearson Education, Inc.
Upper Saddle River, New Jersey 07458
All rights reserved.
Efficiency = Pout/Pin
49W/50W = 98%
Pout = Pin – Ploss
49W = 50W - 1W
![Page 13: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/13.jpg)
Kilowatt Hour
Kilowatt Hour = How Power Company computes your Bill
Watts over Hours:
Refrigerator: 500W for 18 Hours = 9Kwh
Air Conditioner: 3.8KW for 10 Hours = 38KWh
![Page 14: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/14.jpg)
Ampere Hour Battery Ratings
• How long the battery is rated to last
• 1 Ampere Hour (Ah) = Can Deliver:
– 1 Amp for 1 Hour– 1 Amp for 1 Hour
– 500Ma for 2 Hours
• Generally tested at a Certain Current
– Car Battery – 70 Ah @ 3.5A
– D Battery – 4.5 Ah @ 100mA
– 9V Battery – 400Ah @ 8uA
![Page 15: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/15.jpg)
Troubleshooting – Open Resistor
•Full Source Voltage Across Resistor/Component
•Low Total Current
•Little or No Voltage Across Other Resistors/Components
![Page 16: CH03 Mine.pptjohnston/ME204/EE204... · Title: Microsoft PowerPoint - CH03 Mine.ppt [Compatibility Mode] Author: johnstonht Created Date: 2/2/2011 11:01:01 AM](https://reader036.vdocument.in/reader036/viewer/2022071211/6023cca6ef38dd2a81682ca7/html5/thumbnails/16.jpg)
Troubleshooting – Shorted Resistor
•Low Voltage Across Shorted Resistor/Component
•High Total Current
•Higher Voltages Across Other Resistors/Components