chapter 14 review page 1 - blue valley schools · chapter 14 review page 1 1 the result of the...

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Chapter 14 Review Page 1 The result of the following cross indicates the orange eyes are _____ black eyes. 1 A larger than B dominant to C recessive to D co-dominant to E incompletely dominant to If O represents the allele for black eyes (dominant) and o represents the allele for orange eyes (recessive), what would be the genotypic ratio of a cross between a heterozygous black-eyed MendAlien and an orange-eyed MendAlien? 2 A 1 homozygous black (OO): 1 heterozygote (black) (Oo): 1 homozygous orange (oo) B 2 homozygous black (OO): 1 heterozygote (black) (Oo): 1 homozygous orange (oo) C 1 homozygous black (OO): 0 heterozygote (black) (Oo): 1 homozygous orange (oo) D 0 homozygous black (OO): 1 heterozygote (black) (Oo): 1 homozygous orange (oo) E 0 homozygous black (OO): 0 heterozygote (black) (Oo): 1 homozygous orange (oo) Which of these is a testcross? 3 A A? x aa B A? x AA C A? x Aa D A? x A? E aa x aa 11/19/2010 8:01:19 AM

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Page 1: Chapter 14 Review Page 1 - Blue Valley Schools · Chapter 14 Review Page 1 1 The result of the following cross indicates the orange eyes are _____ black eyes. A larger than B dominant

Chapter 14 Review Page 1

The result of the following cross indicates the orange eyes are _____ black eyes.1

A larger thanB dominant toC recessive toD co-dominant toE incompletely dominant to

If O represents the allele for black eyes (dominant) and o represents the allele for orangeeyes (recessive), what would be the genotypic ratio of a cross between a heterozygousblack-eyed MendAlien and an orange-eyed MendAlien?

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A 1 homozygous black (OO): 1 heterozygote (black) (Oo): 1 homozygousorange (oo)

B 2 homozygous black (OO): 1 heterozygote (black) (Oo): 1 homozygousorange (oo)

C 1 homozygous black (OO): 0 heterozygote (black) (Oo): 1 homozygousorange (oo)

D 0 homozygous black (OO): 1 heterozygote (black) (Oo): 1 homozygousorange (oo)

E 0 homozygous black (OO): 0 heterozygote (black) (Oo): 1 homozygousorange (oo)

Which of these is a testcross?3

A A? x aaB A? x AAC A? x AaD A? x A?E aa x aa

11/19/2010 8:01:19 AM

Page 2: Chapter 14 Review Page 1 - Blue Valley Schools · Chapter 14 Review Page 1 1 The result of the following cross indicates the orange eyes are _____ black eyes. A larger than B dominant

Chapter 14 Review Page 2

That each MendAlien gamete contains a single allele of the eye color gene is an illustrationof

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A Mendel's law of segregation only.B Darwin's theory of natural selection.C Mendel's law of independent assortment only.D Beadle and Tatum's one gene/­one enzyme hypothesis.E both Mendel's law of segregation and Mendel's law of independent

assortment.

What is the genotype of the parent with orange eyes and white skin? (Note: orange eyesand white skin are recessive.)

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A oowwB ooWwC ooWWD OoWwE OOWW

Black eyes are dominant to orange eyes, and green skin is dominant to white skin. Sam, aMendAlien with black eyes and green skin, has a parent with orange eyes and white skin.Carole is a MendAlien with orange eyes and white skin. If Sam and Carole were to mate,the predicted phenotypic ratio of their offspring would be (enter the numbers sequentially):__ black eyes, green skin :__ black eyes, white skin :__ orange eyes, green skin :__ orange eyes, white skin

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11/19/2010 8:01:19 AM

Page 3: Chapter 14 Review Page 1 - Blue Valley Schools · Chapter 14 Review Page 1 1 The result of the following cross indicates the orange eyes are _____ black eyes. A larger than B dominant

Chapter 14 Review Page 3

A cross between an individual with orange eyes and green skin and an individual with blackeyes and white skin is an example of a _____ cross.

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A testB difficultC dihybridD trihybridE monohybrid

In a two-factor cross, a phenotypic ratio of 9:3:3:1 in the offspring of a cross indicates that8

A both parents are homozygous dominant.B both parents are heterozygous for both genes.C one parent is homozygous dominant and one parent is heterozygous.D one parent is heterozygous and one parent is homozygous recessive.E one parent is homozygous dominant and one parent is homozygous

recessive.

The observed distribution of alleles into gametes is an illustration of9

A Eimer's principle.B Thienemann's rule.C Mendel's law of segregation only.D Mendel's law of independent assortment only.E Mendel's laws of segregation and independent assortment.

A OoWw x ooww cross yields a phenotypic ratio of approximately 5 black eyes, green skin :5 orange eyes, white skin : 1 black eyes, white skin : 1 orange eyes, green skin. Which ofthe following best explains these results?

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A Mendel's law of segregation is being violated.B The genes for eye color and skin color are co-dominant.C Mendel's law of independent assortment is being violated.D Mendel's laws of segregation and independent assortment are being

violated.E The heterozygous individual is male, and the homozygous individual is

female.

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Page 4: Chapter 14 Review Page 1 - Blue Valley Schools · Chapter 14 Review Page 1 1 The result of the following cross indicates the orange eyes are _____ black eyes. A larger than B dominant

Chapter 14 Review Page 4

In the following cross the genotype of the female parent is OoWw. What is the genotype ofthe male parent? [Hint: O = black eyes, o = orange eyes, W = green skin, w = white skin]

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A OoWwB OOWWC OOWwD OoWWE ooWW

In a situation in which genes assort independently, what is the ratio of the gametesproduced by an AaBB individual?

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A 1 A : 1 BB 3 A : 1 BC 3 AB : 1 abD 1 AB : 1 aBE 3 AA : 1 BB

Andalusian chickens with the genotype CBCB are black, those with the genotype CWCW arewhite, and those with the genotype CBCW are gray. What is the relationship between theCB and CW alleles?

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A CB is dominant to CWB CB is recessive to CWC CW is dominant to CBD CB and CW are co-dominantE The relationship between the alleles is one of incomplete dominance.

Andalusian chickens with the genotype CBCB are black, those with the genotype CWCW arewhite, and those with the genotype CBCW are gray. What is the expected phenotypic ratioof a CBCW x CBCW cross?

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A 1 black : 1 grayB 3 gray : 1 whiteC 1 black : 1 whiteD 3 black : 1 whiteE 1 black : 2 gray : 1 white

11/19/2010 8:01:19 AM

Page 5: Chapter 14 Review Page 1 - Blue Valley Schools · Chapter 14 Review Page 1 1 The result of the following cross indicates the orange eyes are _____ black eyes. A larger than B dominant

Chapter 14 Review Page 5

The A, B, AB, and O blood types found in humans refer to the15

A genotype.B phenotype.C quality of the blood.D frequency of the alleles.E size of the red blood cells.

A woman with type AB blood marries a man with type O. What is the probability that theirfirst child will have either of the parents' blood types?

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A 0%B 25%C 50%D 75%E 100%

As shown in this diagram, eye color in fruit flies is an example of a(n)17

A polygenic trait.B sex-linked trait.C codominant trait.D intermediate trait.E multifactorial trait.

Coat color in Labrador retrievers is an example of epistasis, in which a single trait isinfluenced by two separate genes. What is this dog's genotype?

B=black melanin, b=brown melaninE=full deposition, e=reduced deposition

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A BbEEB BbeeC bbEeD bbeeE BbEe

11/19/2010 8:01:19 AM

Page 6: Chapter 14 Review Page 1 - Blue Valley Schools · Chapter 14 Review Page 1 1 The result of the following cross indicates the orange eyes are _____ black eyes. A larger than B dominant

Chapter 14 Review Page 6

Freckles (F) and a widow's peak (W) are dominant human traits. John and Sarah haveboth, but their son Casey has neither. What are John and Sarah's genotypes?

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A Ff and WwB FfWw and FfWWC FfWw and FfWwD FFWW and ffwwE FFff and WWww

Skin color and height in humans are influenced by the combined effects of multiple genes.This is called

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A epistasis.B codominance.C polygenic inheritance.D incomplete dominance.E sex-linked inheritance.

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Page 7: Chapter 14 Review Page 1 - Blue Valley Schools · Chapter 14 Review Page 1 1 The result of the following cross indicates the orange eyes are _____ black eyes. A larger than B dominant

Chapter 14 Review Page 7

Answer Key :

Question: Answer

Chapter 14 Review

C1D2A3A4A51111 (+/- 0.0%)6C7B8E9D10C11D12E13E14B15A16B17D18C19C20

11/19/2010 8:01:19 AM