chem instructions

80
Chem Instructions Before class starts, get a piece of paper and title it Ch 11 Notes – The Mole

Upload: etenia

Post on 24-Feb-2016

18 views

Category:

Documents


0 download

DESCRIPTION

Chem Instructions. Before class starts, get a piece of paper and title it Ch 11 Notes – The Mole. Chapter 11: The Mole. 11.1 Measuring Matter. 11.1 Measuring Matter Roses and eggs are conveniently packaged as a dozen . Sheets of paper are packaged as a ream. - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Chem  Instructions

Chem Instructions• Before class starts, get a piece of paper

and title it Ch 11 Notes – The Mole

Page 2: Chem  Instructions

Chapter 11: The Mole

Page 3: Chem  Instructions

11.1 Measuring Matter

Page 4: Chem  Instructions

11.1 Measuring MatterRoses and eggs are conveniently packaged as a dozen. Sheets of paper are packaged as a ream.

Small item are packaged in large amounts to make life easier. The same is true for atoms. However, because atoms are really, really, really small, the amounts of them that are packaged together are really, really, really big

Page 5: Chem  Instructions

A package of atoms or compounds that chemists use is called the Mole (from the Greek word for “pile”).

Page 6: Chem  Instructions
Page 7: Chem  Instructions

A package of atoms or compounds that chemists use is called the Mole (from the Greek word for “pile”). A mole (abbreviated “mol”) contains

602,200,000,000,000,000,000,000 of anything. This really large number is often called Avogadro’s Number and is abbreviated 6.022 × 1023.

Page 8: Chem  Instructions

If you know the number of moles, then the amount of atoms or molecules can be calculated.

How many atoms are in 2 moles of Al?

In a calculator, you would put in 2 × 6.022 EE 23. Pushing the button that says EE takes the place of the “ × 10 ” and is the way calculators are meant to be used.

2 mols Al 6.022 × 1023 atoms= 1.20 × 1024 atoms Al

1 mol

Page 9: Chem  Instructions

How many molecules of HCl are in 3.57 moles of HCl?

In a calculator, you would put in 3.57 × 6.022 EE 23. When stating the answer don’t forget to include the “× 1024”.

3.57 mols HCl 6.022 × 1023 molecules

= 2.15 × 1024 molecules HCl

1 mol

Page 10: Chem  Instructions

The opposite can also be done.How many moles is 9.03 × 1023 atoms of K?

9.03 × 1023 atoms K 1 mol

= 1.50 mols K 6.022 × 1023 atoms

Page 11: Chem  Instructions
Page 12: Chem  Instructions

Notice, in both cases you use that fact that 1 mol = 6.022 × 1023 (this is called a conversion factor). Whether the 6.022 × 1023 is on the top or bottom of

the railroad tracks depends on what you start the problem with.

Page 13: Chem  Instructions

How would you set up the railroad tracks to find out how many atoms is 2.9 moles of Fe?

Page 14: Chem  Instructions

How would you set up the railroad tracks to find out how many atoms is 2.9 moles of Fe?

=

Page 15: Chem  Instructions

How would you set up the railroad tracks to find out how many atoms is 2.9 moles of Fe?

2.9 mols Fe=

Page 16: Chem  Instructions

How would you set up the railroad tracks to find out how many atoms is 2.9 moles of Fe?

2.9 mols Fe=

1 mol

Page 17: Chem  Instructions

How would you set up the railroad tracks to find out how many atoms is 2.9 moles of Fe?

2.9 mols Fe 6.022 × 1023 atoms

= 1 mol

Page 18: Chem  Instructions

How would you set up the railroad tracks to find out how many atoms is 2.9 moles of Fe?

2.9 mols Fe 6.022 × 1023 atoms = 1.75 × 1024

atoms Fe1 mol

Page 19: Chem  Instructions

How would you set up the railroad tracks to find out how many moles is 4.9 × 1023 molecules of Rb3P?

=

Page 20: Chem  Instructions

How would you set up the railroad tracks to find out how many moles is 4.9 × 1023 molecules of Rb3P?

4.9 × 1023 molecules Rb3P =

Page 21: Chem  Instructions

How would you set up the railroad tracks to find out how many moles is 4.9 × 1023 molecules of Rb3P?

4.9 × 1023 molecules Rb3P

1 mol=

6.022 × 1023 molecules

Page 22: Chem  Instructions

How would you set up the railroad tracks to find out how many moles is 4.9 × 1023 molecules of Rb3P?

4.9 × 1023 molecules Rb3P

1 mol= 0.814 mols Rb3P

6.022 × 1023 molecules

Page 23: Chem  Instructions

11.2 Masses and the Mole

Page 24: Chem  Instructions

11.2 Masses and the MoleThe mole is not only handy to counting a large amount of atoms or molecules, it is even more

useful when measuring out amounts of elements or compounds. The masses on the periodic table have been designed to be the amount of grams in a mole of that element.

Page 25: Chem  Instructions

For example, look at sulfur.

The information shown for sulfur tells us that 1 mol of sulfur = 32.066 grams of sulfur. Likewise, 2 mols of sulfur = 2 × 32.066 or 64.132 grams of sulfur, etc. This allows for amounts of elements to be easily measured in the laboratory and turned into moles.

16S

32.066

Page 26: Chem  Instructions

A student measures out 12 g of Mg in lab. How many moles does this student have?

12 g Mg 1 mol = 0.49 mols Mg

24.31 g

Page 27: Chem  Instructions
Page 28: Chem  Instructions

A student measures out 12 g of Mg in lab. How many moles does this student have?

In the calculator you would put in 12 ÷ 24.31. Notice the conversion factor is unique for each element and must come from the periodic table.

12 g Mg 1 mol = 0.49 mols Mg

24.31 g

Page 29: Chem  Instructions

The opposite can also be done.A student needs 2.3 mols of B for an experiment. How many grams should this student measure out?

In the calculator you would put in 2.3 × 10.81.

2.3 mols B 10.81 g = 24.86 g B

1 mol

Page 30: Chem  Instructions

How would you set up the railroad tracks to find out how many grams is 2.9 moles of Fe?

=

Page 31: Chem  Instructions

How would you set up the railroad tracks to find out how many grams is 2.9 moles of Fe?

2.9 mols Fe=

Page 32: Chem  Instructions

How would you set up the railroad tracks to find out how many grams is 2.9 moles of Fe?

2.9 mols Fe=

1 mol

Page 33: Chem  Instructions

How would you set up the railroad tracks to find out how many grams is 2.9 moles of Fe?

2.9 mols Fe 55.847 g=

1 mol

Page 34: Chem  Instructions

How would you set up the railroad tracks to find out how many grams is 2.9 moles of Fe?

2.9 mols Fe 55.847 g= 161.96 g Fe

1 mol

Page 35: Chem  Instructions

How would you set up the railroad tracks to find out how many moles is 4.3 grams of P?

=

Page 36: Chem  Instructions

How would you set up the railroad tracks to find out how many moles is 4.3 grams of P?

4.3 g P=

Page 37: Chem  Instructions

How would you set up the railroad tracks to find out how many moles is 4.3 grams of P?

4.3 g P=

30.974 g

Page 38: Chem  Instructions

How would you set up the railroad tracks to find out how many moles is 4.3 grams of P?

4.3 g P 1 mol=

30.974 g

Page 39: Chem  Instructions

How would you set up the railroad tracks to find out how many moles is 4.3 grams of P?

4.3 g P 1 mol= 0.14 mols P

30.974 g

Page 40: Chem  Instructions

Sections 11.1 and 11.2 can be put together into one big calculation.

Page 41: Chem  Instructions

A student needs 2.6 × 1023 atoms of fluorine for an experiment. How many grams of fluorine should the student measure out?

In the calculator you would put in 2.6 EE 23 ÷ 6.022 EE 23 × 18.998.

2.6 × 1023 atoms F 1 mol 18.998 g

= 8.20 g F6.022 × 1023

atoms 1 mol

Page 42: Chem  Instructions

Moles will always be in the middle of these kinds of calculations!

Page 43: Chem  Instructions
Page 44: Chem  Instructions

The opposite can also be done.A student has 56.7 grams of aluminum. How many atoms of aluminum does the student have?

In the calculator you would put in 56.7 ÷ 26.982 × 6.022 EE 23.

56.7 g Al 1 mol 6.022 × 1023 atoms = 1.27 × 1024

atoms Al 26.982 g 1 mol

Page 45: Chem  Instructions

How would you set up railroad tracks to calculate how many grams of Rb are 9.4 × 1023 atoms of Rb?

=

Page 46: Chem  Instructions

How would you set up railroad tracks to calculate how many grams of Rb are 9.4 × 1023 atoms of Rb?

9.4 × 1023 atoms Rb

=

Page 47: Chem  Instructions

How would you set up railroad tracks to calculate how many grams of Rb are 9.4 × 1023 atoms of Rb?

9.4 × 1023 atoms Rb

= 6.022 × 1023

atoms

Page 48: Chem  Instructions
Page 49: Chem  Instructions

How would you set up railroad tracks to calculate how many grams of Rb are 9.4 × 1023 atoms of Rb?

9.4 × 1023 atoms Rb 1 mol

= 6.022 × 1023

atoms

Page 50: Chem  Instructions

How would you set up railroad tracks to calculate how many grams of Rb are 9.4 × 1023 atoms of Rb?

9.4 × 1023 atoms Rb 1 mol

= 6.022 × 1023

atoms 1 mol

Page 51: Chem  Instructions

How would you set up railroad tracks to calculate how many grams of Rb are 9.4 × 1023 atoms of Rb?

9.4 × 1023 atoms Rb 1 mol 85.468 g

= 133.41 g Rb6.022 × 1023

atoms 1 mol

Page 52: Chem  Instructions

how many atoms of Rb are 17.8 grams of Rb?

=

Page 53: Chem  Instructions

how many atoms of Rb are 17.8 grams of Rb?

17.8 g Rb=

Page 54: Chem  Instructions

how many atoms of Rb are 17.8 grams of Rb?

17.8 g Rb=

85.468 g

Page 55: Chem  Instructions
Page 56: Chem  Instructions

how many atoms of Rb are 17.8 grams of Rb?

17.8 g Rb 1 mol=

85.468 g

Page 57: Chem  Instructions

how many atoms of Rb are 17.8 grams of Rb?

17.8 g Rb 1 mol=

85.468 g 1 mol

Page 58: Chem  Instructions

how many atoms of Rb are 17.8 grams of Rb?

17.8 g Rb 1 mol 6.022 × 1023 atoms

=85.468 g 1 mol

Page 59: Chem  Instructions

how many atoms of Rb are 17.8 grams of Rb?

17.8 g Rb 1 mol 6.022 × 1023 atoms = 1.25 × 1023

atoms Rb85.468 g 1 mol

Page 60: Chem  Instructions

11.3: Moles of Compounds

Page 61: Chem  Instructions

A properly written compound shows the ratio of atoms in the compound. For example, sodium carbonate (Na2CO3) shows that for every 1

compound there are 2 atoms of Na, 1 atom of C, and 3 atoms of O.

Page 62: Chem  Instructions

This also works with the mole.

Page 63: Chem  Instructions
Page 64: Chem  Instructions

This also works with the mole. For 1 mole of the compound, there are 2 moles of Na, 1 mole of C, and 3 moles of O. This information allows us to

calculate the molar mass of the entire compound, often called the formula mass or molecular mass.

Page 65: Chem  Instructions

2 mols Na 22.99 g = 45.98 g Na1 mol

1 mol C 12.011 g = 12.011 g C

1 mol

3 mols O 15.999 g= 47.997 g O

1 mol

Page 66: Chem  Instructions

The total molar mass of Na2CO3 is 45.98 g + 12.011 g + 47.997 g = 105.988 g.Once it is known that 1 mol of Na2CO3 = 105.998 g,

conversion factors can be made of this information:

These conversion factors can then be used in calculations just like in sections 11.1 and 11.2.

105.988 g Na2CO3or

1 mol

1 mol 105.988 g Na2CO3

Page 67: Chem  Instructions

What is the molar mass for potassium oxide (K2O)?

Page 68: Chem  Instructions

What is the molar mass for potassium oxide (K2O)?

2 mols K =

1 mol O =

Page 69: Chem  Instructions

What is the molar mass for potassium oxide (K2O)?

2 mols K 39.098 g =

1 mol

1 mol O 15.999 g =

1 mol

Page 70: Chem  Instructions

What is the molar mass for potassium oxide (K2O)?

2 mols K 39.098 g = 78.196 g K

1 mol

1 mol O 15.999 g = 15.999 g O

1 mol

Page 71: Chem  Instructions

What is the molar mass for potassium oxide (K2O)?

K2O = 78.196 g + 15.999 g = 94.195g

2 mols K 39.098 g = 78.196 g K

1 mol

1 mol O 15.999 g = 15.999 g O

1 mol

Page 72: Chem  Instructions

If you have 560 grams of K2O, how many moles do you have?

Page 73: Chem  Instructions

If you have 560 grams of K2O, how many moles do you have?

560 g K2O =

Page 74: Chem  Instructions

If you have 560 grams of K2O, how many moles do you have?

560 g K2O 1 mol =

94.195 g

Page 75: Chem  Instructions

If you have 560 grams of K2O, how many moles do you have?

560 g K2O 1 mol = 5.95 mol K2O94.195 g

Page 76: Chem  Instructions
Page 77: Chem  Instructions

If you have 3.4 moles of K2O, how many grams do you have?

Page 78: Chem  Instructions

If you have 3.4 moles of K2O, how many grams do you have?

3.4 mols K2O =

Page 79: Chem  Instructions

If you have 3.4 moles of K2O, how many grams do you have?

3.4 mols K2O 94.195 g =

1 mol

Page 80: Chem  Instructions

If you have 3.4 moles of K2O, how many grams do you have?

3.4 mols K2O 94.195 g = 320.26 g K2O1 mol