computer communication & networks

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Computer Communication & Networks Lecture 10 Datalink Layer: Error Correction http://web.uettaxila.edu.pk/CMS/coeCCNbsSp0 9/index.asp Waleed Ejaz [email protected]

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Computer Communication & Networks. Lecture 10 Datalink Layer: Error Correction http://web.uettaxila.edu.pk/CMS/coeCCNbsSp09/index.asp. Waleed Ejaz [email protected]. Data Link Layer. Data Link Layer Topics to Cover. Error Detection and Correction. - PowerPoint PPT Presentation

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Page 1: Computer Communication & Networks

Computer Communication & Networks

Lecture 10

Datalink Layer: Error Correction

http://web.uettaxila.edu.pk/CMS/coeCCNbsSp09/index.asp

Waleed [email protected]

Page 2: Computer Communication & Networks

Data Link Layer

Page 3: Computer Communication & Networks

Data Link Layer Topics to CoverError Detection and Correction

Data Link Control and ProtocolsMultiple Access

Local Area Networks

Wireless LANs

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Error Correction

1. By retransmission flow and error control protocols

2. Forward Error Correction (FEC) require more redundancy bits should locate the invalid bit or bits n-bit code word contains m data bits + r

redundancy bitsn=m+r

m+r+1 bits discoverable by r bits 2r>=m+r+1

Page 5: Computer Communication & Networks

Data and redundancy bitsData and redundancy bits

Number ofdata bits

m

Number of redundancy bits

r

Total bits

m + r

11 2 3

22 3 5

33 3 6

44 3 7

55 4 9

66 4 10

77 4 11

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Hamming Code

Hamming codes provide for FEC using a “Block Parity” i.e, instead of one parity bit send a block of parity

bits Allows correction of single bit errors This is accomplished by using more than one

parity bit Each computed on different combination of

bits in the data

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Hamming code (Contd.)

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Positions of Redundancy Bits

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Redundancy Bits Calculation

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Example

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Error Correction using Hamming Code

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Burst Error Correction

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Hamming Distance The Hamming distance between two words is

the number of differences between corresponding bits.

Let us find the Hamming distance between two pairs of words.1. The Hamming distance d(000, 011) is 2 because

2. The Hamming distance d(10101, 11110) is 3 because

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To guarantee the detection of up to s errors in all cases, the minimum

Hamming distance in a block code must be dmin = s + 1.

Note

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Example

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To guarantee correction of up to t errors in all cases, the minimum Hamming

distance in a block code must be dmin = 2t + 1.

Note

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A code scheme has a Hamming distance dmin = 4. What is the error detection and correction capability of this scheme?

SolutionThis code guarantees the detection of up to three errors(s = 3), but it can correct up to one error. In other words, if this code is used for error correction, part of its capability is wasted. Error correction codes need to have an odd minimum distance (3, 5, 7, . . . ).

Example

Page 18: Computer Communication & Networks

Readings

Chapter 10 (B.A Forouzan) Section 10.2,10.5 (Cover only those contents which are related to topics

covered in class)

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