connect with maths webinar "beyond the tip of the iceberg mathematics"
DESCRIPTION
'Tip of the Iceberg' Maths Problems A constant challenge for teachers is to cater for the diversity of students in my classes. Matt Skoss is always looking to incorporate rich Maths tasks that are easy for students to make a start on the problem, but once students are engaged in the problem, they are exposed to the deeper, richer Mathematics lurking beneath the surface, hence the use of the 'iceberg' metaphor. to support the professional growth of teachers. Connect with Maths ~ supporting teachers of mathematics ONLINE http://connectwith.indigenous.aamt.edu.auTRANSCRIPT
Exploring mathematical problems
beyond the tip of the iceberg
Exploring mathematical problems
beyond the tip of the iceberg
Pick problems...
Pick problems...
Challenges in my classroom...
Arithmagons
Strategy Board
Learning outcomes and related concepts•basic addition•difference between•algebraic representation•problem posing and solving•the Working Mathematically process
Arithmagons
Pen Pen thicknessthickness
Pen colourPen colour
t1 = a + bt2 = b + ct3 = a + c
t1 = a + bt2 = b + ct3 = a + c
The number on the edge is The number on the edge is the sum of the two the sum of the two
numbers on the vertices.numbers on the vertices.
t1 = a + bt2 = b + ct3 = a + c
t1 - t2 = (a + b) - (b - c)
this becomest1 - t2 = a - c
t1 = a + bt2 = b + ct3 = a + c
t1 - t2 = (a + b) - (b - c)
this becomest1 - t2 = a - c
Put your finger near the top circle to highlight the difference between 13 and 8, which is 5.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Put your finger near the top circle to highlight the difference between 13 and 8, which is 5.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Zero is not being used. The only pairs of numbers which sum to 9 are: (8, 1), (7, 2), (6, 3), (5, 4)
Put your finger near the top circle to highlight the difference between 13 and 8, which is 5.
Put your finger near the top circle to highlight the difference between 13 and 8, which is 5.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Zero is not being used. The only pairs of numbers which sum to 9 are: (8, 1), (7, 2), (6, 3), (5, 4)
Put your finger near the top circle to highlight the difference between 13 and 8, which is 5.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Zero is not being used. The only pairs of numbers which sum to 9 are: (8, 1), (7, 2), (6, 3), (5, 4)
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Another approach...
Pick any numberPick any number
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Pick any numberPick any number
Complete the other Complete the other other two verticesother two vertices
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Pick any numberPick any number
Total needs to be 9, but Total needs to be 9, but 10 + 5 = 15...over by 6.10 + 5 = 15...over by 6.
Complete the other Complete the other other two verticesother two vertices
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Pick any numberPick any number
Total needs to be 9, but Total needs to be 9, but 10 + 5 = 15...over by 6.10 + 5 = 15...over by 6.
Complete the other Complete the other other two verticesother two vertices
6 needs to be shared 6 needs to be shared between two verticesbetween two vertices
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Total needs to be 9, but Total needs to be 9, but 10 + 5 = 15...over by 6.10 + 5 = 15...over by 6.
6 needs to be shared 6 needs to be shared between two verticesbetween two vertices
Add 3Add 3
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Total needs to be 9, but Total needs to be 9, but 10 + 5 = 15...over by 6.10 + 5 = 15...over by 6.
6 needs to be shared 6 needs to be shared between two verticesbetween two vertices
Add 3Add 3
Take 3Take 3
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Total needs to be 9, but Total needs to be 9, but 10 + 5 = 15...over by 6.10 + 5 = 15...over by 6.
6 needs to be shared 6 needs to be shared between two verticesbetween two vertices
Add 3Add 3
Take 3Take 3
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Total needs to be 9, but Total needs to be 9, but 10 + 5 = 15...over by 6.10 + 5 = 15...over by 6.
6 needs to be shared 6 needs to be shared between two verticesbetween two vertices
Add 3Add 3
Take 3Take 3
Extensions...
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Extensions...
Challenge older kids to program a SS
So, the opposite circle numbers must have a difference of 5 AND sum to 9.
Challenge older kids to program a SS