data of doll
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considerpowersof2..takeanocloserto17say2^4=16;Now2^256=(2^4)642^256/17=(2^4)64/17=(17-1)^64/17expandingbybionamialtheorem17^64..17^63*1..17^62*1^2...........17.1^63...1^64(Iamleaving+-signs)Ifyouconsidertheseexpn..everytermisamultipleof17exceptlast(1^64)thatis(17-1)^64/17->remainderis(-1)^64==1Quote
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(#67)
santarocksItsnowMoreofLife@HDFCBankHardcorePaGaLSIESMumbai
Posts:265JoinDate:May2006Age:28Thanks:87Thanked230Timesin133PostsGroans:10Groanedat4Timesin4PostsRe:MathsTakingTricks-26-12-2006,05:20PM
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Quote:OriginallyPostedbygsnindiaLetstake1stcase
When(2)^256isdividedby17Whatistheremainder?
WeWillmakeiseasybythewayof256=8*32
Hence2^256=[[2^8]]^32meanwecanwrite2^832times
Now2^8=256Now256/17willgiveusremainder1Hencetheremainderof2^256isalso1
ItlooksComplicatedinitiallyButifwebreakitinsmallertermswegetthesolution
ThanksaTon!!!!.
Ihavesearchedallpossiblethreadsandhaveseenallkindaexplanations.OFal
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lthisisthemosteasiestwayforalaymantounderstand..
ThanksagainsantarocksQuote
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(#68)
san.rahul99SBIPO2010..HardcorePaGaL
Posts:445JoinDate:Jan2009Location:Delhi
Age:24Thanks:1,078Thanked381Timesin132PostsGroans:34Groanedat11Timesin11PostsRe:MathsTakingTricks-06-08-2009,01:03AM
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nicetriks...willsurelyhelpaCATtakerlikeme...thnxQuote
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(#69)
gsnindiaWorkingexceutiveTraineePaGaL
Posts:77JoinDate:May2006Location:AJMERThanks:1Thanked132Timesin31PostsGroans:0Groanedat13Timesin8PostsRe:MathsTakingTricks-20-08-2009,01:31PM
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7/31/2019 Data of Doll
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HiGuys,
Iwasoutandbusywithworking,NowithinkineedtotaketherealtestofOnlineCAT.
CouldnotmakeinpreviousCAT,MytargetisExecutiveMBAwithIIMIndore.Hopetomakethistime.
WellEnoughsayingletgettothework.Today'stricktosharewithyou
Howtorememberthefractions
1/2=0.5---1/4=0.25(0.5/2)---1/8=0.125(0.25/2or0.5/4)
1/3=0.33---1/6=0.165(.33/2)---1/9=0.111(0.33/3)
1/5-easy1/15=0.2/3=0.066thiswaywecancalculatethequickfraction
weneednotmugthefractions.Quote
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(#70)
nehaghodkehasnostatus.NewbiePaGaL
Posts:2JoinDate:Sep2009Location:PuneAge:23Thanks:0Thanked0Timesin0PostsGroans:0Groanedat0Timesin0PostsRe:MathsTakingTricks-21-09-2009,12:26PM
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veryfirstaddingupthe3givenequations:
a+b+c+d=17d+e+f+g=17g+h+i=17weget,a+b+c+2d+e+f+2g+h+i=51-----------------(1)
weknowthat,a+b+c+d+e+f+g+h+i=45-------------------(2)
subtractingequation(2)from(1),weget:
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d+g=6
asthevaluesarebetween1-9,dandgcantakefollowingvalues:
1](d,g)=(1,5)2](d,g)=(2,4)3](d,g)=(3,3)
butthe2ndoptionisnotpossibleasa=4andeachalphabetholdsauniquevalue.the3rdoptiontoo,isnotpossibleasdandgcannothavethesamevalues.hencethecorrectansweris(d,g)=(1,5).