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considerpowersof2..takeanocloserto17say2^4=16;Now2^256=(2^4)642^256/17=(2^4)64/17=(17-1)^64/17expandingbybionamialtheorem17^64..17^63*1..17^62*1^2...........17.1^63...1^64(Iamleaving+-signs)Ifyouconsidertheseexpn..everytermisamultipleof17exceptlast(1^64)thatis(17-1)^64/17->remainderis(-1)^64==1Quote

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(#67)

santarocksItsnowMoreofLife@HDFCBankHardcorePaGaLSIESMumbai

Posts:265JoinDate:May2006Age:28Thanks:87Thanked230Timesin133PostsGroans:10Groanedat4Timesin4PostsRe:MathsTakingTricks-26-12-2006,05:20PM

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Quote:OriginallyPostedbygsnindiaLetstake1stcase

When(2)^256isdividedby17Whatistheremainder?

WeWillmakeiseasybythewayof256=8*32

Hence2^256=[[2^8]]^32meanwecanwrite2^832times

Now2^8=256Now256/17willgiveusremainder1Hencetheremainderof2^256isalso1

ItlooksComplicatedinitiallyButifwebreakitinsmallertermswegetthesolution

ThanksaTon!!!!.

Ihavesearchedallpossiblethreadsandhaveseenallkindaexplanations.OFal

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lthisisthemosteasiestwayforalaymantounderstand..

ThanksagainsantarocksQuote

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(#68)

san.rahul99SBIPO2010..HardcorePaGaL

Posts:445JoinDate:Jan2009Location:Delhi

Age:24Thanks:1,078Thanked381Timesin132PostsGroans:34Groanedat11Timesin11PostsRe:MathsTakingTricks-06-08-2009,01:03AM

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nicetriks...willsurelyhelpaCATtakerlikeme...thnxQuote

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(#69)

gsnindiaWorkingexceutiveTraineePaGaL

Posts:77JoinDate:May2006Location:AJMERThanks:1Thanked132Timesin31PostsGroans:0Groanedat13Timesin8PostsRe:MathsTakingTricks-20-08-2009,01:31PM

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7/31/2019 Data of Doll

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HiGuys,

Iwasoutandbusywithworking,NowithinkineedtotaketherealtestofOnlineCAT.

CouldnotmakeinpreviousCAT,MytargetisExecutiveMBAwithIIMIndore.Hopetomakethistime.

WellEnoughsayingletgettothework.Today'stricktosharewithyou

Howtorememberthefractions

1/2=0.5---1/4=0.25(0.5/2)---1/8=0.125(0.25/2or0.5/4)

1/3=0.33---1/6=0.165(.33/2)---1/9=0.111(0.33/3)

1/5-easy1/15=0.2/3=0.066thiswaywecancalculatethequickfraction

weneednotmugthefractions.Quote

TheFollowingUserSaysThankYoutogsnindiaForThisUsefulPost:acumind

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(#70)

nehaghodkehasnostatus.NewbiePaGaL

Posts:2JoinDate:Sep2009Location:PuneAge:23Thanks:0Thanked0Timesin0PostsGroans:0Groanedat0Timesin0PostsRe:MathsTakingTricks-21-09-2009,12:26PM

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veryfirstaddingupthe3givenequations:

a+b+c+d=17d+e+f+g=17g+h+i=17weget,a+b+c+2d+e+f+2g+h+i=51-----------------(1)

weknowthat,a+b+c+d+e+f+g+h+i=45-------------------(2)

subtractingequation(2)from(1),weget:

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d+g=6

asthevaluesarebetween1-9,dandgcantakefollowingvalues:

1](d,g)=(1,5)2](d,g)=(2,4)3](d,g)=(3,3)

butthe2ndoptionisnotpossibleasa=4andeachalphabetholdsauniquevalue.the3rdoptiontoo,isnotpossibleasdandgcannothavethesamevalues.hencethecorrectansweris(d,g)=(1,5).