diffraction - kekconference.kek.jp/jass02/pdf_ppt/9_ishikawa.pdf · 11/15/2002 jass02 14 two-wave...
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11/15/2002 JASS02 2
Introduction
In the 1st part, we dealt with “Kinematical Theory” where the scattered x-rays suffer no additional scattering.The 2nd part is designed to give basic ideas of “Dynamical Diffraction” observed with perfect crystals as a result of multiple scattering.
11/15/2002 JASS02 4
Maxwell Equation (1/2)
E: electric fieldD: electric displacementH: magnetic fieldB: magnetic inductionρ: charge densityj: current densityP: polarizationM: magnetizationε0: permittivity of vacuumµ0: permeability of vacuumχ: electric susceptibilityc: speed of light in vacuum
0true
true
t
t
ρ∇ ⋅ =∇ ⋅ =
∂∇× = −
∂∂
∇× = +∂
DB
BE
DH j
o
o
ε
µ
= +
= −
D E PBH M
oε χ=P E
2
1o o cε µ =
11/15/2002 JASS02 5
Maxwell Equation (2/2)For periodically oscillating electromagnetic field;
jtrue = 0, ρtrue = 0.
For non-magnetic materials, M=0 so that B = µ0H.
00
o t
t
µ
∇⋅ =∇ ⋅ =
∂∇× = −
∂∂
∇× =∂
DH
HE
DH
11/15/2002 JASS02 6
PolarizationPolarization P = electric dipole moment in unit volume
( ) ( ) ( )2
2
o
er e r rm
ε χ
ρ ρ ρω
=
= = − = −
P E
P p x E
( ) ( ) ( ) ( )2 2 2 2
2 2 24 oo o
e e rm mc
λ λχ ρ ρ ρω ε π ε π
= − = − = −r r r r
χ(r) have the periodicity of crystal lattice
( ) ( )
( ) ( ) ( )
( )2
exp
1 exp
g
c
o
c
i
F iv
r Fv
χ χ
ρ
λχπ
= ⋅
= ⋅
⇒ = −
∑
∑
g
g
g
r g r
r g g r
g
11/15/2002 JASS02 7
Electromagnetic Wave in Periodic Medium
Incident Plane Wave in Vacuum ( ){ }exp i tω⋅ −oK rBloch Theorem
Waves inside Periodic Medium ( ){ } ( )expE i t uω= ⋅ −oK r r
u(r) has periodicity of crystal lattice
u(r) can be expanded in a Fourier Series with reciprocal lattice vector, g.
( ){ } ( )
( )
exp exp
expi t
E i t E i
e E iω
ω
−
= ⋅ − ⋅
= ⋅
= +
∑
∑
o gg
g gg
g o
K r g r
K r
K K g
Bloch Wave
11/15/2002 JASS02 8
Some Mathematic....
, i it t
ω ω∂ ∂= − = −
∂ ∂D HD H ( )
( )( )( )
( )( )( )( )
2
2
2
2
1
1
1
o
o
o o
i
i i
cK
ωµ
ωµ ω
ω µ ε χ
ω χ
χ
∇× ∇× = ∇×
= −
= +
= +
= +
E H
D
r E
r E
r E
2 ; X ray wavenumber in vacuumKcω π
λ= = −
( ){ } ( )( ){ } ( ) ( )
exp exp
exp exp
i i i
i i
∇× ⋅ = × ⋅
∇×∇× ⋅ = − × × ⋅
g g g g g
g g g g g g
E K r K E K r
E K r K K E K r
11/15/2002 JASS02 9
Mathematics (cont’d)( )
( ){ } ( )
[ ] 2
2[ ]
1
exp expg
g g
K
E ig r K ig r
⊥
⊥
= − × ×
⇒∇×∇× ⋅ = ⋅
g
g
g K g g g
g K
E K K E
E
( ) ( ) ( ) ( )
( )
''exp exp
exp
E i i
i
χ χ
χ′
= ⋅ ⋅
= ⋅
∑∑
∑∑
h hhh h
g-h h gg h
r r h r E K r
E K r
, ′ ′+ = + =h gh h g h K K
( )2 2 2[ ] exp 0g
gK K K iχ⊥ −
− − ⋅ =
∑ ∑gg K g g h h g
hE E E K r (*)
11/15/2002 JASS02 10
Basic Equations for Dynamical TheoryCondition for the equation (*) should be valid for arbitrary r gives the basic equation for dynamical diffraction theory:
2 2[ ]
2
gK KK
χ⊥−
−=∑gg K g
g h hh
E EE
6[ ]10χ −⊥⇒ ≅
gg g k gE ESince
the basic equation is well approximated by
2 2
2gK KK
χ −
−=∑g g h h
hE E
11/15/2002 JASS02 11
Boundary Conditions (1/3)z
vacuum
crystal
z=H
Fields in vacuum: (Ea, Da)
Fields in crystal: (E, D)
Boundary conditions from Maxwell Equations:
Continuity of tangential components of Electric Fields
Et =Eat
Continuity of normal components of Electric Displacements
Dz =Daz
t: tangential component, z: z(=normal) component
11/15/2002 JASS02 12
Boundary Conditions (2/3)Wavefield : Superposition of plane waves
( ) ( )exp expi t iω= − ⋅∑ g gg
E E K r
Km
Kg
Wave Vector in Crystal: KgWave Vector in Vacuum: Km
Kgt = Kmt
crystal wave
( ) ( )exp , expi i= ⋅ = ⋅∑ ∑g g g gg g
E E K r D D K r
vacuum wave
( ) ( )exp , expi i= ⋅ = ⋅∑ ∑a a a am m m m
m mE E K r D D K r
11/15/2002 JASS02 13
Boundary Conditions (3/3)ˆunit vector normal to the surface:
ˆunit vector tangential to the surface: z
tˆˆˆˆ
z t
z t
K K
K K
= +
= +g g g
m m m
K z t
K z t
Boundary Condition at z=H (Crystal Surface)( ) ( )
( ) ( )
exp exp
exp expgt mt gt mt
gt mt gt mt
agt gz mt mz
K K K K
agz gz mz mz
K K K K
E iK H E iK H
D iK H D iK H
= =
= =
=
=
∑ ∑
∑ ∑
( ) ( )1 exp expgt mt gt mt
g gz mzK K K K
iK H iK Hχ= =
⇒ =∑ ∑ ag mE E
11/15/2002 JASS02 14
Two-Wave Approximation (1/3)Under usual experimental conditions, only two waves with K0 (incident direction) and Kg (diffracted direction) are strong inside the crystal.
Wavefield in crystal:
( ) ( )exp expi i= ⋅ + ⋅0 0 g gE E K r E K r
Basic Equation:
( )( )
2 2 2
2 2 2
0
0
K k E K P E
K P E K k E
χ
χ
− − =
− − =
o o g g
g o g g
Averaged refractive index of crystal:
1 12 2
o on k Kχ χ = + ⇒ = +
Polarization Factor
B
1 for polarizationcos 2 for polarization
PP
σθ π
= −= −
11/15/2002 JASS02 15
Two-Wave Approximation (2/3)Condition for the basic equation,
( )( )
2 2 2
2 2 2
0
0
K k E K P E
K P E K k E
χ
χ
− − =
− − =
o o g g
g o g g
to have non-trivial solutions is2 2 2
2 2 2 0K k K PK P K k
χχ−
=−
o g
g g
= +g oK K g O G
dispersion sphere
dispersion surface
Ko Kg
g
By introducing new parameters:
o o
g g
K kK k
ξξ
= −= −
2 214
K Pξ ξ χ χ=o g g g
11/15/2002 JASS02 16
Two Wave Approximation (3/3)For non-absorbing crystals,
* (complex conjugateof )χ χ χ=g g g
2χ χ χ=g g g
When we introduce a new parameter Λ as2 cos cosB B
K P Pπ θ λ θ
χ χΛ = =
g g,
2 2
2
cos Bπ θξ ξ =Λo g
x
y
Lo
To
Tg
Near the point Lo,sin cos
sin cosB B
B B
x yx y
ξ θ θξ θ θ
= − +
= +o
g
Dispersion surfaces formHyperbolla
2 22 2 2 2
2
cossin cos BB Bx y π θθ θ− + =
Λ
11/15/2002 JASS02 17
Amplitude Ratio2 0
2 0o o g
o g g
E KP EKP E Eξ χ
χ ξ
− =
− =g
g
Amplitude Ratio
22
gj oj gj
oj g gj
E KPr
E KPξ χχ ξ
= = =
j = 1, 2
11/15/2002 JASS02 19
Symmetric Laue Case
Dispersion sphere of vacuum wave (radius K)
Starting point of wave vector Ko: P
Laue point: L
Deviation from Bragg Condition
LPK
θ∆ =
( )
2sincos2 sin
g oo g B
B
B B
p p LP
K
ξ ξθ
θθ θ θ
−= = ⋅
= −
11/15/2002 JASS02 20
Symmetric Laue Case: Deviation Parameter
Deviation Parameter W
( )
( )1 2
2 sin
sin 2
o g BB
B B
g
p pW
L L
P
θ θ θλ
θ θ θχ
Λ= = −
−=
cos 2 B
polarization Wpolarization W
W W
σ
π
σ π
σ
π
θ
−
−
=
2 2
2
2 cos
cos
g o B
Bg o
Wπξ ξ θ
π θξ ξ
− =Λ
=Λ
Solving above equations, we can get
( )( )
2
2
cos 1
cos 1
Boj
Bgj
W W
W W
π θξ
π θξ
= − ± +Λ
= ± +Λ
upper sign: j=1, lower sign: j=2Usually W=Wσ
11/15/2002 JASS02 21
Symmetric Laue Case: Amplitude Ratio
( )( )2exp 1
upper sign 1, lower sign 2
gjj g
oj
E Pr i W W
E Pj j
α= = − ± +
= =
Here, ( )expg g giχ χ α=
For non-absorbing crystals,
( )
* , ,
exp
g g g g g g
gg
g
i
χ χ α α χ χ
χα
χ
= = − =
=
11/15/2002 JASS02 22
Symmetric Bragg Case (1/2)Between L1 and L2, z has no intersections with dispersion surfaces.
Total Reflection Region
Deviation from Bragg Condition
( )cos
2sin 2 sin
B
g oo g
B
B B o B
LPK
p p
L P K
θ θ
ξ ξθ
θ θ θ θ θ
− =
− −=
′= ⋅ = − − ∆
11/15/2002 JASS02 23
Symmetric Bragg Case (2/2)∆θo : Deviation from geometrical Bragg angle by refraction
( )2 1sin 2 sin 2
oo
B B
nχθθ θ
−−∆ = =
Deviation parameter, W
( )1 2
2 sino g BB o
p pW
L Lθ θ θ θ
λΛ
= = − −∆
2 cosg o BWπξ ξ θ+ = −Λ
( )( )
2
2
cos 1
cos 1
Boj
Bgj
W W
W W
π θξ
π θξ
= − −Λ
= ± −Λ
m
upper sign: j=1, lower sign: j=2
Amplitude Ratio
( )( )2exp 1gjj g
oj
E Pr i W W
E Pα= = − ± −
upper sign: j=1, lower sign: j=2
11/15/2002 JASS02 24
Rocking CurvesUse monochromatic plane wave as an incident beam;
Rocking the sample crystal around the Bragg angle;
We can observe so-called rocking curve.
11/15/2002 JASS02 25
Rocking Curve: Symmetric Laue Case (1/3)
Ka,Eoa
Ko2, E02
Ko1, Eo1
Ka,Eda
Kg2, Eg2
Kg1, Eg1
Kga,Eg
a
Incident Wave
z=0
z=H
( )expaoE i ⋅aK r
Crystal Waveo-wave ( )
( )1
2
exp
expo
o
E i
E i
⋅
⋅o1
o2
K r
K r
g-wave ( )( )
1
2
exp
exp
g
g
E i
E i
⋅
⋅
g1
g2
K r
K r
Outgoing Wave
o-wave ( )expadE i ⋅aK r
g-wave ( )expagE i ⋅a
gK r
11/15/2002 JASS02 26
Rocking Curve: Symmetric Laue Case (2/3)Boundary condition at z = 0 (incident surface)
1 2
1 20
ao o o
g g
E E EE E
= +
= +
( )
2
2
1 12 11 1exp2 1
aoj o
gj g
WE EW
PE iP W
α
= ±
+ ±
=+
upper sign: j=1, lower sign: j=2
At W=0 (exact Bragg condition),
oj gjE E=
Boundary condition at z = H(exit surface)
( ) ( ) ( )( ) ( ) ( )
1 1 2 2
1 1 2 2
exp exp exp
exp exp exp
ao o o o d z
a ag g g g g gz
E iK H E iK H E iK H
E iK H E iK H E iK H
+ =
+ =
j
j
ˆPP
ˆPPˆ:inner normal vector at the incident surface
= −
= − +
aoj
agj
K z + K
K z + K gz
oj
j
-2PP
cos
o
B
Kχξ
θ
+ =
jPP aojz gjz zK K K= = − +
11/15/2002 JASS02 27
Rocking Curve: Symmetric Laue Case (3/3)
( )
( )
2 22
2
2 2 22
2
sin 1
1
cos 1
1
W ag g
ao o
W ad d
ao o
H WI EI E W
W H WI EI E W
π
π
+ Λ= =
+
+ + Λ= =
+
11/15/2002 JASS02 28
Rocking Curve: Symmetric Bragg Case (1/3)
Ka,Eoa Kg
a,Ega
Ko1, Eo1: W<-1
Ko2, Eo2: W>1
Kg1, Eg1: W<-1
Kg2, Eg2: W>1
Boundary condition at z = 0
z = 0
1 2
1 2
( 1), ( 1)
( 1), ( 1)
ao o oag g g
E E W E WE E W E W
= ≤ − ≥
= ≤ − ≥
( )( )2exp 1a ag g o
PE i W W E
Pα= − −m
upper sign: W<-1, lower sign: W>1
11/15/2002 JASS02 29
Rocking Curve: Symmetric Bragg Case (2/3)1 z-componentsof and arecomplexW ≤ ⇒ o gK K
ˆPP
ˆPP
2PP sin
j
j
ooj
jB
Kχξ
θ
= −
= −
+ = −
oj
gj
K z + K
K z + K + g
( )21Im
tani ioz oz gz
B
WK K K πθ
−= = =
Λ
( )2cos 1Bo W i Wπ θξ = − + −
Λ
Another solution will give a divergent solution
( )( )2exp 1a ag g o
PE i W i W E
Pα= − + −
11/15/2002 JASS02 30
Rocking Curve: Symmetric Bragg Case (3/3)Rocking curve (Darwin Curve)
( )222
2
1 ( 1)
1 ( 1)
aWgg
ao o
EI W W WI E W
− − ≥= = ≤
|W|<1: All incident energies are reflected back.
Total Reflection
sin 2 sin 2g o
BB B
PW
χ χθ θ
θ θ− = +
Center of total reflectiuon, W=0, is deviated from geometrical Bragg angle θBby
sin 2o
B
χθ
Range of total reflection (-1<W<1)
2
2sin 2 sin
2sin 2
g
B B
og g g
c B
P
Pr F or Fv
χ λωθ θ
λ χπ θ
= =Λ
= ∝
Darwin Width, ~microradian order
11/15/2002 JASS02 31
Absorbing CrystalAbsorption: Anomalous dispersion term into atomic scattering factor
( ) ( )
( )
2 2
2 2
exp
exp
g g g
oo og g j j j
jc c
o og g j j
jc c
i
r rF f f iv v
r rF f iv v
χ χ χ
λ λχπ π
λ λχπ π
′ ′′= +
′ ′ ′= − = − + − ⋅
′′ ′′ ′′= − = − − ⋅
∑
∑
g r
g r
, :complexg gχ χ′ ′′
* *,g g g gχ χ χ χ′ ′ ′′ ′= =
Centrosymmetric Crsyatls
, :realg gχ χ′ ′′
,g g g gχ χ χ χ′ ′ ′′ ′′= =
g gχ χ=
2 2g g g g g g giχ χ χ χ χ χ χ′′ ′ ′ ′ ′′⇒ ≈ +
A new parameter κ is defined as
g
g
χκ
χ′′
=′
11/15/2002 JASS02 32
Symmetric Laue Case: Absorbing Crystal (1/2)
2 22 2
2
exp cos 1 1sin sinh1
Wg B
o
HI H W H WI W
µθ π κπ
− + + = + + Λ Λ
( )sin 2cos , B BB
g g
WP P
θ θ θλ θχ χ
−Λ = =
′ ′
22 1sin H Wπ + Λ
Oscillating Term, Hardly to be observed experimentally without very good plane wave
averaging( )2 2 2
1 exp 1 exp 1cos cos4 1 1 1
Wg
o B B
I P PH HI W W W
ε εµ µθ θ
= − − + − + + + +
g
o
χε
χ′′
=′′
Bloch Wave αsmall absorption
Bloch Wave βlarge absorption
Anomalous Transmission (Borrman Effect)
11/15/2002 JASS02 33
Symmetric Laue Case: Absorbing Crystal (2/2)Forward Diffraction
2 2
2 2 2 2
1 1 exp 1 1 exp 14 cos cos1 1 1 1
Wd
o B B
P PI W H W HI W W W W
ε εµ µθ θ
= + − − + − − + + + + +
Thin Crystal Thick Crystal
11/15/2002 JASS02 34
Symmetric Bragg Case: Absorbing Crystal
Rocking curve for a symmetric Bragg case diffraction from a semi-infinite absorbing crystal(with centrosymmetry)
( ) ( )
2
2 22 2 2 2 2
2
1
1 4
1
Wg
o
o
g
IL L
I
W g W g gWL
gP
κ κ
κχχ
= − −
+ + − − + + −=
+′′
=′
κ = 0
κ = 0.1
11/15/2002 JASS02 35
SummaryVery quick scan of x-ray diffraction theory was attempted.You may need reference text books.References
Dynamical Theory of X-Ray Diffraction,A. Authie, Oxford University Press, 2001Handbook on Synchrotron Radiation Vol. 3, North-Holland, 1991.
11/15/2002 JASS02 36
Thank you for your Thank you for your attention.attention.
Acknowledgement
Some materials presented here are originally prepared by Prof. Seishi Kikuta for his textbook written in Japanese. Some ppt materials have been prepared by Dr. Shunji Goto. Discussion in preparing the lecture with Drs. Shunji Goto, Kenji Tamasaku and Makina Yabashi is appreciated.