distance around the circle 2 r = c or d = c
TRANSCRIPT
Distance around the circle
2 r = Cor
d = C
Find the circumference.
in. 6.28 C m 33in.8.89C
Portion of the circumference
P
A
B3602
mAB
r
ABlength
3.82 m60º50º
5cm
3602
mAB
r
ABlength
360
50
52
length
38.1
360
60
2
82.3
r
647.3r
647.32 C
A = r2
ANSWERS WILL BE IN SQUARE UNITS
6.8
Find the area.
If S has a circumference of 10 inches, find the area of the circle to the nearest hundredth.
C = 2r10 = 2r
5 = r
A = r2
A = 52A = 25A =
in2
Find the area of the shaded region.
188.49in2
6 in
2 in
A = 22A = 82
A = 4
A = 12.57in2
A = 64
A = 201.06in2
A shaded = A – A= 201.06 - 12.57 =
SECTOR: region bounded by two radii of the circle and their
intercepted arcR
O
Q
Area of a Sector
2
sec
360
Area of tor RQ mRQ
r
60°
120 °
6 cm
7 cm
Q
R
Q
R
218.85cm
251.31cm
2
60
(6) 360
Area
2
sec
360
Area of tor QR mQR
r
2
sec
360
Area of tor QR mQR
r
2
120
(7) 360
Area
A SEGMENT is a region bounded by a chord and its intercepted
arc
A segment is a minor segment if the
intercepted arc is less than 180
degrees
Area of minor segment =
(Area of sector) – (Area of triangle)
Area of minor segment =
(Area of sector) – (Area of triangle)
12 yd
2 1
*360 2
mRQr b h
R
Q290 1
(12) (12)*(12)360 2
113.10 72
241.10yd
CW/ HW
• Book page 226 #8-10, 17-21
• Book page 232 #10-15, 22, 23, 29