distance around the circle

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Page 1: Distance around the circle
Page 2: Distance around the circle

Distance around the circle

Page 3: Distance around the circle

2 p r = Cor

dp = C

Page 4: Distance around the circle

Find the circumference.

in. 6.28 pC m 33pin.8.89C

Page 5: Distance around the circle

Portion of the circumference

P

A

B3602

mAB

r

ABlength

p

Page 6: Distance around the circle

60º50º

3602

mAB

r

ABlength

p

360

50

52

p

length

p38.1

360

60

2

82.3

rp

647.3r

647.32 pC

Page 7: Distance around the circle

A = p r2

ANSWERS WILL BE IN SQUARE UNITS

6.8

Page 8: Distance around the circle

Find the area.

Page 9: Distance around the circle

If S has a circumference of 10p inches, find the area of the circle to the nearest hundredth.

C = 2pr

10p = 2pr

5 = r

A = pr2

A = p 52

A = p 25

A = 78.54 in2

Page 10: Distance around the circle

Find the area of the shaded region.

188.49in2

6 in

2 in

A = p22A = p82

A = p4

A = 12.57 in2

A = p64

A = 201.06 in2

A shaded = A –A= 201.06 - 12.57 =

Page 11: Distance around the circle

SECTOR: region bounded by two radii of the circle and their intercepted arc

R

O

Q

Area of a Sector

2

sec

360

Area of tor RQ mRQ

rp

Page 12: Distance around the circle

60°

120 °Q

R

Q

R

218.85cm

251.31cm

2

60

(6) 360

Area

p

2

sec

360

Area of tor QR mQR

rp

2

sec

360

Area of tor QR mQR

rp

2

120

(7) 360

Area

p

Page 13: Distance around the circle

A SEGMENT is a region bounded by a chord and its intercepted arc

A segment is a minor segment if the intercepted arc is less than

180 degrees

Area of minor segment =

(Area of sector) – (Area of triangle)

Page 14: Distance around the circle

Area of minor segment =

(Area of sector) – (Area of triangle)

12 yd

2 1*

360 2

mRQr b hp

R

Q290 1

(12) (12)*(12)360 2

p

113.10 72

241.10yd