Download - Power Plants and Processes EEN-E1010, E1
![Page 1: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/1.jpg)
Power Plants and
Processes
EEN-E1010, E1.
Shouzhuang Li
Energy Conversion research
group
![Page 2: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/2.jpg)
![Page 3: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/3.jpg)
Today’s program
•12:30 Energy conversion and performance parameters of steam power plant
•13:00 Example
•13:30 Exercise in group work, Q&A
![Page 4: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/4.jpg)
Energy conversion of steam power plants
Boiler
Net electrical power output Pel,net
![Page 5: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/5.jpg)
Performance parameters of steam power plants
Heat Rate HR
The amount of heat in kJ that is required to produce a unit power output kWh
Electrical (Overall) efficiency
Capacity factor CF
![Page 6: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/6.jpg)
Example
• In a Rankine cycle steam power plant, the turbine receives 490 kg/s of steam at 200 bars and 550°C and the condenser pressure is 0.04 bar. The turbine and pump isentropic efficiencies are 0.92 and 0.83, respectively.
• Calculate: (a) the plant power output, (b) the plant thermal efficiency and (c) the plant heat rate.
![Page 7: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/7.jpg)
P1 = 200 bars, T1= 550°C
P3 =0.04 bar
𝜂𝑖𝑠= 0.92
𝜂𝑝𝑢𝑚𝑝= 0.83
h1 = 3400 kJ/kg
h2s = 1920 kJ/kg
h2 = 2038.4 kJ/kg
![Page 8: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/8.jpg)
Textbook Page 559
![Page 9: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/9.jpg)
Group Work
• In a steam power plant, the turbine receives 700 kg/s of live steam at
• Group 1,4,7,10: 250 bars and 560 °C
• Group 2,5,8,11: 250 bars and 600 °C
• Group 3,6,9,12: 300 bars and 600 °C.
• The condenser pressure is 0.04 bar. The turbine isentropic efficiency is 0.92. The work of the feedwater pump can be neglected.
• 1. Draw the cycles in the T-s diagram
• 2. Calculate the plant’s thermal efficiency
• 3. Calculate the power plant net power output
![Page 10: Power Plants and Processes EEN-E1010, E1](https://reader031.vdocument.in/reader031/viewer/2022012505/617f8e0dde8fe23564671bca/html5/thumbnails/10.jpg)
Solutions
h1
[kJ/kg]
h2is
[kJ/kg]
h2
[kJ/kg]
h3
[kJ/kg] ηth
Net power
output [MW]
Group I 3380 1880 2000 121.41 0.423496 966
Group II 3490 1920 2045.6 121.41 0.428785 1011.08
Group III 3440 1860 1986.4 121.41 0.438017 1017.52