dr. fowler ccm solving systems of equations by elimination – harder

15
Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Upload: briana-beasley

Post on 13-Jan-2016

216 views

Category:

Documents


1 download

TRANSCRIPT

Page 1: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Dr. Fowler CCM

Solving Systems of EquationsBy Elimination – Harder

Page 2: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Solving a system of equations by elimination using addition and subtraction.

Step 1: Put the equations in Standard Form.

Step 2: Determine which variable to eliminate.

Step 3: Add or subtract the equations.

Step 4: Plug back in to find the other variable.

Step 5: Check your solution.

Standard Form: Ax + By = C

Look for variables that have the

same coefficient.

Solve for the variable.

Substitute the value of the variable

into the equation.

Substitute your ordered pair into

BOTH equations.

ALREADY IN NOTES – Read Only for Review

Page 3: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Elimination using Multiplication

1) Solve the system. Adding or subtracting will not eliminate

x + 2y = 6

3x + 3y = -6

But, we can multiply the first equationby -3 to eliminate the x term

Page 4: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Elimination using Multiplication

x + 2y = 6

3x + 3y = -6

-3 ( )

1) Solve the system.

Page 5: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Elimination using Multiplication

-3x + -6y = -18

3x + 3y = -6+-3y = -24

y = 8

ANS: (x, 8)

Be sure to distribute the -3to ALL in the equation.

1) Solve the system.

Page 6: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Elimination using Multiplication

x + 2y = 6

3x + 3y = -6

ANS: (x, 8)

Substitute y = 8 into equation

y =8

x + 2(8) = 6x + 16 = 6

x = -10

1) Solve the system.

Page 7: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Elimination using Multiplication

x + 2y = 6

3x + 3y = -6

Answer: ( -10 , 8)

Substitute y = 8 into equation

y =8x + 2(8) = 6

x + 16 = 6

x = -10

1) Solve the system.

Page 8: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

2) Solve the system:

2(2) + 2y = 6

4 + 2y = 6

2y = 2

y = 1

2x + 2y = 6

3x – y = 5

If we multiply the bottom

equation by 2 we can eliminate y:

2x + 2y = 6

(2)(3x – y = 5) 2x + 2y = 6(+) 6x – 2y = 10 8x = 16 x = 2

(2, 1)

Substitute x = 2 into either original equation:

Page 9: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

More complex Problems

3x + 4y = -25

2x - 3y = 6

Multiply by 2

Multiply by -3.

This will get X’s to MATCH

3) Solve the system

Page 10: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

More complex Problems

3x + 4y = -25

2x - 3y = 6

2( )

-3( )

3) Solve the system

Page 11: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

More complex Problems

6x + 8y = -50

-6x + 9y = -18+17y = -68

y = -4

Answer: (x, -4)

3) Solve the system

Page 12: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

More complex Problems

3x + 4y = -25

2x - 3y = 6 Substitute y = -4

2x - 3(-4) = 62x - -12 = 6

2x + 12 = 6

2x = -6

x = -3 Answer: (-3, -4)

3) Solve the system

Page 13: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

3x + 4y = -14x – 3y = 7

4) Solve the system using elimination.

3(1) + 4y = -1

3 + 4y = -1

4y = -4

y = -1

Multiply both equations

(3)(3x + 4y = -1)

(4)(4x – 3y = 7)

9x + 12y = -3 (+) 16x – 12y = 28

25x = 25 x = 1

(1, -1)

Page 14: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Excellent Job !!!Well Done

Page 15: Dr. Fowler CCM Solving Systems of Equations By Elimination – Harder

Stop NotesDo Worksheet