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    Ashwin Kumar.S

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    #include

    struct node

    {

    int element[5];

    int next[5];

    }s;

    static int i=0;

    void create()

    {

    int x,cont;

    do

    {

    printf("\nenter the element:");

    scanf("%d",&x);

    s.element[i] = x;

    s.next[i]=i+1;

    i++;

    if(i

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    s.next[i+1]='\0';

    i++;

    }

    else

    {

    printf("\nthe position before the given position is vacant");

    }

    }

    else

    printf("\nno space for insertion");

    }

    void display()

    {

    int y;

    for(y=0;y

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    else

    return 0;

    }

    int find(int x)

    {

    int y=0;

    while(y

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    scanf("%d",&x);

    y=retreive(x);

    if(y!=0)

    printf("\nthe element is %d",y);

    else

    printf("\nthere is no element in the given position");

    }

    if(choice==4)

    {

    printf("\nenter the element to be found:");

    scanf("%d",&x);

    y=find(x);

    if(y!=0)

    printf("\nthe given element is in position no: %d",y);

    else

    printf("\nthe given element is not present");

    }

    printf("\ncontinue?\n1.yes\n2.no: ");

    scanf("%d",&cont);

    }while(cont==1);

    printf("\nelements in the list are:");

    display();

    getch();

    }

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    SAMPLE INPUT AND OUTPUT

    Enter the element: 3

    Continue?

    1.yes

    2.no: 1

    Enter the element: 4

    Continue?

    1.yes

    2.no: 2

    Enter your choice:

    1.insert

    2.delete

    3.retreive

    4.find

    1

    Enter the element and the position : 8

    4

    The position before the given position is vacant

    Continue?

    1.yes

    2.no:1

    Enter your choice:1.insert

    2.delete

    3.retreive

    4.find

    1

    Enter the element and the position : 5

    1

    Continue?

    1.yes2.no:1

    Enter your choice:

    1.insert

    2.delete

    3.retreive

    4.find

    3

    Enter the position of the element to be retrieved : 3

    The element is 4

    Continue?

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    1.yes

    2.no:1

    Enter your choice:

    1.insert

    2.delete

    3.retreive

    4.find

    2

    Enter the position of the element to be deleted : 1

    Continue?

    1.yes

    2.no:1

    Enter your choice:

    1.insert

    2.delete

    3.retreive

    4.find

    4

    Enter the element to be found : 3

    The given element is in position no : 1

    Continue?

    1.yes

    2.no: 2

    The elements in the list are:

    3

    4

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    #include

    #include

    #include

    struct node

    {

    int element;

    struct node * next;

    };

    struct node *ptr;

    struct node *header;

    static int count=0;

    void create(int z)

    {

    int i,x;

    struct node *temp,*temp1;

    temp=(struct node *)malloc(sizeof(struct node));

    header=(struct node *)malloc(sizeof(struct node));

    header->next=temp;

    for(i=0;ielement = x;

    if (inext=temp1;

    temp=temp->next;}

    else

    temp->next=NULL;

    }

    }

    int find(int x)

    {

    int i=0;ptr=header->next;

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    while(ptr!=NULL)

    {i++;

    if(ptr->element==x)

    return i;

    else

    ptr=ptr->next;

    }

    return 0;

    }

    int retreive(int p)

    {

    int i=1;

    ptr=header->next;

    if(p==1)

    return ptr->element;

    while(ptr->next!=0)

    {

    i++;

    ptr=ptr->next;

    if(i==p)

    {

    return ptr->element;

    }

    }

    return 0;

    }

    void insert(int x,int p)

    {

    int i=1;struct node * insert;

    insert=(struct node *)malloc(sizeof(struct node));

    insert->element=x;

    ptr=header->next;

    if(p==1)

    {

    insert->next=ptr;

    header->next=insert;

    count++;}

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    else

    {

    while(inext;

    i++;

    }

    if(countnext=ptr->next;

    ptr->next=insert;

    count++;

    }

    }

    }

    void delete(int p)

    {

    int i=1;

    struct node * temp;

    if(count!=0&&count>=p)

    {

    ptr=header->next;

    temp=ptr->next;

    if(p==1)

    {

    header->next=temp;

    free(ptr);

    count--;}

    else

    {

    while(inext;

    temp=ptr->next;

    printf("\n%d\t%d",ptr,temp);

    i++;}

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    if(count!=p)

    {

    ptr->next=temp->next;

    printf("\n%d\t%d",temp->next,ptr->next);

    free(temp);

    count--;

    }

    if(count==p)

    {

    ptr->next=NULL;

    free(temp);

    count--;

    }

    }

    }

    else

    printf("\ndeletion is not possible");

    }

    void display()

    {

    printf("\nelements in the list and their addresses are:");

    ptr=header->next;

    while(ptr!=NULL)

    {

    printf("\n%d\t%d",ptr->element,ptr);

    ptr=ptr->next;

    }

    }

    void empty(){

    ptr=header->next;

    struct node * temp;

    while(ptr!=NULL)

    {temp=ptr;

    ptr=ptr->next;

    temp->element='\0';

    }

    printf("\nthe list is empty");}

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    void reverse()

    {

    ptr=header->next;

    struct node *q = NULL,*r;

    while (ptr!= NULL)

    {

    r = q;

    q = ptr;

    printf("\n%d\t%d",ptr->element,ptr->next);

    ptr = ptr->next;

    q->next = r;

    }

    header->next=q;

    }

    void sort()

    {

    int swap=1,temp;

    while(swap==1)

    {

    swap=0;

    ptr=header->next;

    while(ptr->next!=NULL)

    {

    if(ptr->element>ptr->next->element)

    {

    temp=ptr->element;

    ptr->element=ptr->next->element;

    ptr->next->element=temp;

    swap=1;}

    ptr=ptr->next;

    }

    }

    }

    main()

    {

    int choice,cont,x,y,z;printf("enter the no of nodes to be created in the list :");

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    scanf("%d",&z);

    create(z);

    do

    {

    printf("\nenter your

    choice:\n1.insert\n2.delete\n3.retreive\n4.find\n5.sort\n6.reverse:");

    scanf("%d",&choice);

    if(choice==1)

    {

    printf("\nenter the element and the position:");

    scanf("%d%d",&x,&y);

    insert(x,y);

    display();

    }

    if(choice==2)

    {

    printf("\nenter the position of the element to be deleted:");

    scanf("%d",&x);

    delete(x);

    display();

    }

    if(choice==3)

    {

    printf("\nenter the position of the element to be retrieved:");

    scanf("%d",&x);

    y=retreive(x);

    if(y!=0)

    printf("\nthe element is %d",y);

    else

    printf("\nthere is no element in the given position");

    }if(choice==4)

    {

    printf("\nenter the element to be found:");

    scanf("%d",&x);

    y=find(x);

    if(y!=0)

    printf("\nthe given element is in position no: %d",y);

    else

    printf("\nthe given element is not present");}

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    if(choice==5)

    {

    sort();

    printf("\nthe elements have been sorted");

    display();

    }

    if(choice==6)

    {

    reverse();

    printf("\nthe elements have been reversed");

    display();

    }

    printf("\ncontinue?\n1.yes\n2.no:");

    scanf("%d",&cont);

    }while(cont==1);

    getch();

    }

    SAMPLE INPUT AND OUTPUT

    Enter the number of nodes to be created in the list: 2

    Enter the element : 5Enter the element : 2

    Enter your choice :

    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    1Enter the element and the position: 3

    2

    The elements in the list and their addresses are:

    5 4751008

    3 4751104

    2 4751072

    Continue?

    1.yes

    2.no: 1

    Enter your choice :

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    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    2

    Enter the position of the element to be deleted: 1

    The elements in the list and their addresses are:

    3 4751104

    2 4751072

    Continue?

    1.yes

    2.no: 1

    Enter your choice :

    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    3

    Enter the position of the element to be retrieved: 3

    There is no element in the given position

    Continue?

    1.yes

    2.no: 1

    Enter your choice :

    1.insert

    2.delete

    3.retreive4.find

    5.sort

    6.reverse

    4

    Enter the element to be found: 2

    The given element is in position no: 2

    Continue?

    1.yes

    2.no: 1Enter your choice :

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    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    5

    The elements have been sorted

    Elements in the list and their addresses are:

    2 4751104

    3 4751072

    Continue?

    1.yes

    2.no: 1

    Enter your choice :

    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    6

    The elements have been reversed

    Elements in the list and their addresses are:

    3 4751072

    2 4751104

    Continue?

    1.yes

    2.no: 2

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    #include

    #include

    #include

    struct node

    {

    int element;

    struct node * next,*previous;

    };

    struct node *header,*front,*back;

    static int count=0;

    void create(int z)

    {

    int i,x;

    struct node *temp,*temp1;

    temp=(struct node *)malloc(sizeof(struct node));

    header=(struct node *)malloc(sizeof(struct node));

    header->next=temp;

    header->previous=NULL;

    temp->previous=header;

    for(i=0;ielement = x;

    if (inext=temp1;temp1->previous=temp;

    temp=temp->next;

    }

    else

    temp->next=NULL;

    }

    }

    int find(int x){

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    int i=0;

    front=header->next;

    while(front!=NULL)

    {i++;

    if(front->element==x)

    return i;

    else

    front=front->next;

    }

    return 0;

    }

    int retreive(int p)

    {

    int i=1;

    front=header->next;

    if(p==1)

    return front->element;

    while(front->next!=0)

    {

    i++;

    front=front->next;

    if(i==p)

    {

    return front->element;

    }

    }

    return 0;

    }

    void insert(int x,int p){

    int i=1;

    struct node * insert;

    insert=(struct node *)malloc(sizeof(struct node));

    insert->element=x;

    front=header->next;

    if(p==1)

    {

    insert->next=front;header->next=insert;

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    insert->previous=header;

    front->previous=insert;

    count++;

    }

    else

    {

    while(inext;

    i++;

    }

    if(countnext=front->next;

    insert->previous=front;

    front->next=insert;

    count++;

    if(count!=p-1)

    insert->next->previous=insert;

    }

    }

    }

    void delete(int p)

    {

    int i=1;

    struct node * temp;

    if(count!=0&&count>=p)

    {front=header->next;

    temp=front->next;

    if(p==1)

    {

    header->next=temp;

    temp->previous=header;

    free(front);

    count--;

    }else

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    {

    while(inext;

    temp=front->next;

    printf("\n%d\t%d",front,temp);

    i++;

    }

    if(count!=p)

    {

    front->next=temp->next;

    temp->next->previous=front;

    free(temp);

    count--;

    }

    if(count==p)

    {

    front->next=NULL;

    free(temp);

    count--;

    }

    }

    }

    else

    printf("\ndeletion is not possible");

    }

    void display()

    {

    printf("\nelement\tprevious address\tnext address ");

    front=header->next;while(front!=NULL)

    {

    printf("\n%d\t\t%d\t\t%d",front->element,front->previous,front->next);

    front=front->next;

    }

    }

    void empty()

    {front=header->next;

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    struct node * temp;

    while(front!=NULL)

    {temp=front;

    front=front->next;

    temp->element='\0';

    }

    printf("\nthe list is empty");

    }

    void reverse()

    {

    front=header->next;

    struct node *q = NULL,*r;

    while (front!= NULL)

    {

    r = q;

    q = front;

    printf("\n%d\t%d\t\t%d",front->element,front->previous,front->next);

    front = front->next;

    q->next = r;

    q->previous=front;

    }

    header->next=q;

    }

    void sort()

    {

    int swap=1,temp;

    while(swap==1)

    {

    swap=0;front=header->next;

    while(front->next!=NULL)

    {

    if(front->element>front->next->element)

    {

    temp=front->element;

    front->element=front->next->element;

    front->next->element=temp;

    swap=1;}

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    front=front->next;

    }

    }

    }

    main()

    {

    int choice,cont,x,y,z;

    printf("enter the no of elements to be created :");

    scanf("%d",&z);

    create(z);

    do

    {

    printf("\nenter your

    choice:\n1.insert\n2.delete\n3.retreive\n4.find\n5.sort\n6.reverse:");

    scanf("%d",&choice);

    if(choice==1)

    {

    printf("\nenter the element and the position:");

    scanf("%d%d",&x,&y);

    insert(x,y);

    display();

    }

    if(choice==2)

    {

    printf("\nenter the position of the element to be deleted:");

    scanf("%d",&x);

    delete(x);

    display();

    }

    if(choice==3){

    printf("\nenter the position of the element to be retrieved:");

    scanf("%d",&x);

    y=retreive(x);

    if(y!=0)

    printf("\nthe element is %d",y);

    else

    printf("\nthere is no element in the given position");

    }if(choice==4)

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    {

    printf("\nenter the element to be found:");

    scanf("%d",&x);

    y=find(x);

    if(y!=0)

    printf("\nthe given element is in position no: %d",y);

    else

    printf("\nthe given element is not present");

    }

    if(choice==5)

    {

    sort();

    printf("\nthe elements have been sorted");

    display();

    }

    if(choice==6)

    {

    reverse();

    printf("\nthe elements have been reversed");

    display();

    }

    printf("\ncontinue?\n1.yes\n2.no:");

    scanf("%d",&cont);

    }while(cont==1);

    getch();

    }

    SAMPLE INPUT AND OUTPUT

    Enter the number of nodes to be created in the list: 2

    Enter the element : 5

    Enter the element : 2Enter your choice :

    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    1

    Enter the element and the position: 3

    2

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    Element previous address next address

    5 3112640 3112704

    3 3112608 3112672

    2 3112704 0

    Continue?

    1.yes

    2.no: 1

    Enter your choice :

    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    2

    Enter the position of the element to be deleted: 1

    Element previous address next address

    3 3112640 3112672

    2 3112704 0

    Continue?

    1.yes

    2.no: 1

    Enter your choice :

    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    3

    Enter the position of the element to be retrieved: 3There is no element in the given position

    Continue?

    1.yes

    2.no: 1

    Enter your choice :

    1.insert

    2.delete

    3.retreive

    4.find5.sort

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    6.reverse

    4

    Enter the element to be found: 2

    The given element is in position no: 2

    Continue?

    1.yes

    2.no: 1

    Enter your choice :

    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    5

    The elements have been sorted

    Element previous address next address

    2 3112640 3112672

    3 3112704 0

    Continue?

    1.yes

    2.no: 1

    Enter your choice :

    1.insert

    2.delete

    3.retreive

    4.find

    5.sort

    6.reverse

    6

    The elements have been reversedElement previous address next address

    3 0 3112704

    2 3112672 0

    Continue?

    1.yes

    2.no: 2

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    #include

    #include

    struct poly

    {

    int coeff,degree;

    struct poly *next;

    };

    struct poly * create()

    {

    int i,x,y,z;

    printf("\nenter the no of terms: ");

    scanf("%d",&z);

    struct poly *temp,*temp1,*header;

    temp=malloc(sizeof(struct poly));

    header=malloc(sizeof(struct poly));

    header->next=temp;

    for(i=0;icoeff = x;

    temp->degree=y;

    if (inext=temp1;

    temp=temp->next;

    }

    elsetemp->next=NULL;

    }

    return header;

    }

    void sort(struct poly * p)

    {

    struct poly * ptr;

    int swap=1,tempc,tempd;while(swap==1)

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    {

    swap=0;

    ptr=p->next;

    while(ptr->next!=NULL)

    {

    if(ptr->degreenext->degree)

    {

    tempc=ptr->coeff;

    tempd=ptr->degree;

    ptr->coeff=ptr->next->coeff;

    ptr->degree=ptr->next->degree;

    ptr->next->coeff=tempc;

    ptr->next->degree=tempd;

    swap=1;

    }

    ptr=ptr->next;

    }

    }

    }

    struct poly* addpoly(struct poly *p1,struct poly *p2)

    {

    struct poly *p3,*p4;

    p1=p1->next;

    p2=p2->next;

    p3=(struct poly *)malloc(sizeof(struct poly));

    p4=(struct poly *)malloc(sizeof(struct poly));

    p4->next=p3;

    while( p1!=NULL && p2!=NULL )

    {

    if( p1->degree > p2->degree ){

    p3->degree = p1->degree;

    p3->coeff = p1->coeff;

    p1 = p1->next;

    }

    else if( p1->degree < p2->degree )

    {

    p3->degree = p2->degree;

    p3->coeff = p2->coeff;p2 = p2->next;

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    }

    else

    {

    p3->degree = p1->degree;

    p3->coeff = p1->coeff + p2->coeff;

    p1 = p1->next;

    p2 = p2->next;

    }

    if(p1!=NULL&&p2!=NULL)

    {

    p3->next = (struct poly*)malloc(sizeof(struct poly));

    p3 = p3->next;

    }

    p3->next = NULL;

    }

    while( p1!= NULL || p2!= NULL )

    {

    p3->next = (struct poly*)malloc(sizeof(struct poly));

    p3 = p3->next;

    if( p1!= NULL )

    {

    p3->degree = p1->degree;

    p3->coeff = p1->coeff;

    p1 = p1->next;

    }

    if( p2!= NULL )

    {

    p3->degree = p2->degree;

    p3->coeff = p2->coeff;

    p2 = p2->next;

    }p3->next = NULL;

    }

    return p4;

    }

    struct poly * subpoly(struct poly * p1,struct poly * p2)

    {

    struct poly *p3,*p4;

    p3=p2;p2=p2->next;

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    while(p2!=NULL)

    {

    p2->coeff=-p2->coeff;

    p2=p2->next;

    }

    p4=addpoly(p1,p3);

    return p4;

    }

    struct poly * difpoly(struct poly *p)

    {

    struct poly *p1,*p2;

    p1=p;

    p=p->next;

    while(p!=NULL)

    {

    if(p->degree!=0)

    {

    p->coeff=p->coeff*p->degree;

    p->degree--;

    p2=p;

    p=p->next;

    }

    else

    {

    p2->next=NULL;

    free(p);

    p=p2->next;

    }

    }

    return p1;}

    struct poly * multipoly(struct poly *p1,struct poly *p2)

    {

    int swap=1;

    struct poly *temp,*p4,*p5,*p6;

    struct poly *p3=malloc(sizeof(struct poly));

    p4=p3;

    p5=p3;p6=p2;

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    for(p1=p1->next;p1!=NULL;p1=p1->next)

    {

    for(p2=p2->next;p2!=NULL;p2=p2->next)

    {

    temp=malloc(sizeof(struct poly));

    p3->next=temp;

    temp->coeff=p1->coeff*p2->coeff;

    temp->degree=p1->degree+p2->degree;

    p3=p3->next;

    }

    p2=p6;

    }

    p3->next=NULL;

    sort(p4);

    while(p4->next!=NULL)

    {

    temp=p4->next;

    if(p4->degree==temp->degree)

    {

    p4->coeff=p4->coeff+temp->coeff;

    p4->next=temp->next;

    free(temp);

    }

    else

    p4=p4->next;

    }

    return p5;

    }

    void display(struct poly *p)

    {struct poly *ptr;

    printf("\nthe polynomial is:\n");

    ptr=p->next;

    while(ptr!=NULL)

    {

    printf("%d^%d ",ptr->coeff,ptr->degree);

    ptr=ptr->next;

    }

    }

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    main()

    {

    struct poly *p1,*p2,*p3;

    int choice;

    do

    {

    printf("\nenter your

    choice\n1.addition\n2.subtraction\n3.multiplication\n4.differentiation\n");

    scanf("%d",&choice);

    if(choice==1)

    {

    p1=create();

    p2=create();

    sort(p1);

    sort(p2);

    display(p1);

    display(p2);

    p3=addpoly(p1,p2);

    printf("\nafter addition ");

    display(p3);

    }

    if(choice==2)

    {

    p1=create();

    p2=create();

    sort(p1);

    sort(p2);

    display(p1);

    display(p2);

    p3=subpoly(p1,p2);

    printf("\nafter subtraction ");display(p3);

    }

    if(choice==3)

    {

    p1=create();

    p2=create();

    sort(p1);

    sort(p2);

    display(p1);display(p2);

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    p3=multipoly(p1,p2);

    printf("\nafter multiplication ");

    display(p3);

    }

    if(choice==4)

    {

    p1=create();

    sort(p1);

    display(p1);

    p3=difpoly(p1);

    printf("\nafter differentiation ");

    display(p3);

    }

    printf("\nperform another operation?\n1.yes\n2.no\n");

    scanf("%d",&choice);

    }while(choice==1);

    }

    SAMPLE INPUT AND OUTPUT

    enter your choice

    1.addition

    2.subtraction

    3.multiplication

    4.differentiation

    1

    enter the no of terms: 3

    enter the coefficient and the degree:

    4

    3

    Enter the coefficient and the degree:6

    5

    enter the coefficient and the degree:

    1

    2

    enter the no of terms: 2

    enter the coefficient and the degree:

    6

    2enter the coefficient and the degree:

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    4

    5

    the polynomial is:

    6^5 4^3 1^2

    the polynomial is:

    4^5 6^2

    after addition

    the polynomial is:

    10^5 4^3 7^2

    perform another operation?

    1.yes

    2.no

    1

    enter your choice

    1.addition

    2.subtraction

    3.multiplication

    4.differentiation

    2

    enter the no of terms: 2

    enter the coefficient and the degree:

    3

    4

    enter the coefficient and the degree:

    6

    0

    enter the no of terms: 3

    enter the coefficient and the degree:

    1

    2

    enter the coefficient and the degree:5

    4

    enter the coefficient and the degree:

    2

    1

    the polynomial is:

    3^4 6^0

    the polynomial is:

    5^4 1^2 2^1after subtraction

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    the polynomial is:

    -2^4 -1^2 -2^1 6^0

    perform another operation?

    1.yes

    2.no

    1

    enter your choice

    1.addition

    2.subtraction

    3.multiplication

    4.differentiation

    3

    enter the no of terms: 2

    enter the coefficient and the degree:

    5

    3

    enter the coefficient and the degree:

    4

    1

    enter the no of terms: 2

    enter the coefficient and the degree:

    6

    2

    enter the coefficient and the degree:

    8

    0

    the polynomial is:

    5^3 4^1

    the polynomial is:

    6^2 8^0

    after multiplicationthe polynomial is:

    30^5 64^3 32^1

    perform another operation?

    1.yes

    2.no

    1

    enter your choice

    1.addition

    2.subtraction3.multiplication

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    4.differentiation

    4

    enter the no of terms: 4

    enter the coefficient and the degree:

    2

    4

    enter the coefficient and the degree:

    7

    5

    enter the coefficient and the degree:

    4

    8

    enter the coefficient and the degree:

    2

    9

    the polynomial is:

    2^9 4^8 7^5 2^4

    after differentiation

    the polynomial is:

    18^8 32^7 35^4 8^3

    perform another operation?

    1.yes

    2.no

    2

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