ece 875: electronic devices
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ECE 875: Electronic Devices. Prof. Virginia Ayres Electrical & Computer Engineering Michigan State University [email protected]. Course Content: Core: Part I: Semiconductor Physics Chapter 01: Physics and Properties of Semiconductors – a Review Part II: Device Building Blocks - PowerPoint PPT PresentationTRANSCRIPT
ECE 875:Electronic Devices
Prof. Virginia AyresElectrical & Computer EngineeringMichigan State [email protected]
VM Ayres, ECE875, S14
Course Content: Core:
Part I: Semiconductor PhysicsChapter 01: Physics and Properties of Semiconductors – a Review
Part II: Device Building BlocksChapter 02: p-n JunctionsChapter 03: Metal-Semiconductor ContactsChapter 04: Metal-Insulator-Semiconductor Capacitors
Part III: TransistorsChapter 06: MOSFETs
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Course Content: Beyond core:
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Lecture 02, 10 Jan 14
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Electronics: Transport: e-’s moving in an environment
Correct e- wave function in a crystal environment: Block function:(R) = expik.a (R) = (R + a)
Correct E-k energy levels versus direction of the environment: minimum = Egap
Correct concentrations of carriers n and p
Correct current and current density J: moving carriersI-V measurementJ: Vext direction versus internal E-k: Egap direction
Fixed e-’s and holes:C-V measurement
Crystal Structures: Motivation:
x Probability f0 that energy level is occupied
q n, p velocity Area
(KE + PE) = E
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Unit cells:
Non-cubic
A Unit cell is a convenient but not minimal volume that contains an atomic arrangement that shows the important symmetries of the crystal
Why are Unit cells like these not good enough?
Compare: Sze Pr. 01(a) for fcc versus Pr. 03
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fcc lattice, to match Pr. 03
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14 atoms needed
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Crystal Structures: Motivation:Electronics: Transport: e-’s moving in an environment
Correct e- wave function in a crystal environment: Block function: (R) = expik.a (R) = (R + a)
Periodicity of the environment:Need specify where the atoms are
Unit cell a3 for cubic systems sc, fcc, bcc, etc.ORPrimitive cell for sc, fcc, bcc, etc.ORAtomic basis
Most atoms
Fewer atoms
Least atoms
Think about: need to specify:
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A primitive Unit cell is the minimal volume that contains an atomic arrangement that shows the important symmetries of the crystal
Example:What makes a face-centered cubic arrangement of atoms unique?Hint: Unique means unique arrangement of atoms within an a3 cube.
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Answer:Atoms on the faces
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Answer:Atoms on the faces
Also need two corner atoms that give maximum dimension of volume of a3 cubic Unit cell
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Answer:Atoms on the faces
Also need two corner atoms that give maximum dimension of volume of a3 cubic Unit cell
This arrangement of 8 atoms does represent the fcc primitive cell
But: specifying the arrangement of 8 atoms is a complicated description.
There is a simpler way.
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Switch to a simpler example:
How many atoms do you need to describe this simple cubic structure?
Want to specify:• atomic arrangement• minimal volume: a3 for this
structure
Start: 8 atoms,1 on each corner.Do you need all of them?
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Simpler Example:
Answer: 4 atoms and 3 vectors between them give the minimal volume = l x w x h.
4 red atoms
Specify 3 vectors:a = l = a x + 0 y + 0 z b = w = 0 x + a y + 0 z c = h = 0 x + 0 y + a z
Minimal Vol = a . b x c
Specify the atomic arrangement as: one atom at every vertex of the minimal volume.
h
lw
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Return to fcc primitive cell example: 8 atoms:
Simpler description:4 atoms and 3 vectors between them give the volume of a non-orthogonal solid (parallelepiped) p.11: Volume = a . b x c
Specify the atomic arrangement as: one atom at every vertex.
rotate
a
b
c
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Better picture of the fcc parallelepiped:
Ashcroft & Mermin
rotate tilt
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This is what Sze does in Chp.01, Pr. 03:
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Picture and coordinate system for Pr. 03:
For a face centered cubic, the volume of a conventional unit cell is a3.Find the volume of an fcc primitive cell with three basis vectors:(000) -> (a/2,0,a/2): a = a/2 x + 0 y + a/2 z(000) -> (a/2,a/2,0): b = a/2 x + a/2 y + 0 z(000) -> (0,a/2,a/2): c = 0 x + a/2 y + a/2 z
(000)
z
y
x
a
b
c
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= Volume of fcc primitive cell
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Sze, Chp.01, Pr. 03:
For a face centered cubic, the volume of a conventional unit cell is a3.Find the volume of an fcc primitive cell with three basis vectors:(000) -> (a/2,0,a/2): a = a/2 x + 0 y + a/2 z(000) -> (a/2,a/2,0): b = a/2 x + a/2 y + 0 z(000) -> (0,a/2,a/2): c = 0 x + a/2 y + a/2 z
a, b and c are the primitive vectors of the fcc Bravais lattice.
P. 10:“Three primitive basis vectors a, b, and c of a primitive cell describe a crystalline solid such that the crystal structure remains invariant under translation through any vector that is the sum of integral multiples of these basis vectors. In other words, the direct lattice sites can be defined by the setR = ma + nb + pc.”
Translational invariance is great for describing an e- wave function acknowledging the symmetries of its crystal environment: Block function: (R) = expik.a (R) = (R + a)
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Formal definition of a Primitive cell, Ashcroft and Mermin:
“A volume of space that when translated through all the vectors of a Bravais lattice just fills all the space without either overlapping itself of leaving voids is called a primitive cell or a primitive Unit cell of the lattice.”
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a = a/2 x + 0 y + a/2 zb = a/2 x + a/2 y + 0 zc = 0 x + a/2 y + a/2 z
(000)
z
y
x
a
b
c
1. four atoms
2. three vectors between themAnywhere: R = ma + nb + pc
3. minimal Vol = a3/4 (parallelepiped)atom at each vertex of the minimal volume
Steps for fcc were:
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Typo, p. 08:
No! Figure 1 shows conventional Unit cells!
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Conventional Unit CellsVol. = a3
Primitive Unit Cells:Smaller Volumes
Vol = a3/4
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Primitive cell for fcc is also the primitive cell for diamond and zincblende:
Conventional cubic Unit cell Primitive cell for: fcc, diamond and zinc-blende
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P. 08: the diamond (and zinc-blende) lattices can be considered as two inter-penetrating fcc lattices.
The two interpenetrating fcc lattices are displaced (¼, ¼, ¼) x a
Note: also have pairs of atoms displaced (¼, ¼, ¼) x a:
a =
lattice co
nsta
nt
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P. 08: the diamond (and zinc-blende) lattices can be considered as two inter-penetrating fcc lattices.
The two interpenetrating fcc lattices are displaced (¼, ¼, ¼) x a
Note: also have pairs of atoms displaced (¼, ¼, ¼) x a:
a =
lattice co
nsta
nt
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Example:
What are the three primitive basis vectors for the diamond primitive cell?(000) -> (a/2,0,a/2): a = a/2 x + 0 y + a/2 z(000) -> (a/2,a/2,0): b = a/2 x + a/2 y + 0 z(000) -> (0,a/2,a/2): c = 0 x + a/2 y + a/2 z
How to make it diamond: two-atom basis
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Picture and coordinate system for example problem:
(000)
z
y
x
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Make it diamond by specifying the atomic arrangement as: a two-atom basis at every vertex of the primitive cell.
Pair a 2nd atom at (¼ , ¼, ¼) x a with every fcc atom in the primitive cell:
Answer:
Three basis vectors for the diamond primitive cell:(000) -> (a/2,0,a/2): a = a/2 x + 0 y + a/2 z(000) -> (a/2,a/2,0): b = a/2 x + a/2 y + 0 z(000) -> (0,a/2,a/2): c = 0 x + a/2 y + a/2 z
(000)
Same basis vectors as fccSame primitive cell volume a3/4
z
y
x
z
y
x
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Rock salt
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Rock salt can be also considered as two inter-penetrating fcc lattices.
Discussion: Lec 03 13 Jan 14
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Conventional cubic Unit cell Primitive cell for: fcc, diamond, zinc-blende, and rock salt
Direct space (lattice) Direct space (lattice)
Rock salt
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Conventional cubic Unit cell Primitive cell for: fcc, diamond, zinc-blende, and rock salt
Reciprocal space = first Brillouin zone for: fcc, diamond, zinc-blende, and rock salt
Direct space (lattice) Direct space (lattice) Reciprocal space (lattice)
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Direct lattice
HW01:
Reciprocal lattice
Reciprocal lattice
Reciprocal lattice
Needed for describing an e- wave function in terms of the symmetries of its crystal environment: Block function: (R) = expik.a (R) = (R + a)