em 324 session 9 thermal effects - iowa state university...em 324 session 9 – thermal effects 1)...

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EM 324 Session 9 Thermal Effects 1) The assembly has the diameters and material indicated. If it fits securely beween its fixed supports when the temperature is T 1 = 70 oF , determine the average normal stress in each material when the temperature reaches T 2 = 110 oF . AB: E = 10.6*10 6 psi, α = 12.8 BC: E = 15*10 6 psi, α = 9.6 CD: E = 28*10 6 psi, α = 9.6

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Page 1: EM 324 Session 9 Thermal Effects - Iowa State University...EM 324 Session 9 – Thermal Effects 1) The assembly has the diameters and material indicated. If it fits securely beween

EM 324 Session 9 – Thermal Effects

1) The assembly has the diameters and material indicated. If it fits securely beween its

fixed supports when the temperature is T1 = 70oF, determine the average normal stress

in each material when the temperature reaches T2 = 110oF.

AB: E = 10.6*106 psi, α = 12.8

BC: E = 15*106 psi, α = 9.6

CD: E = 28*106 psi, α = 9.6

Page 2: EM 324 Session 9 Thermal Effects - Iowa State University...EM 324 Session 9 – Thermal Effects 1) The assembly has the diameters and material indicated. If it fits securely beween

2) The two cylindrical rod segments are fixed to the rigid walls such that there is a gap of

0.01 in between them when T1 = 60 °F . Each rod has a diameter of 1.25 in. Determine

the average normal stress in each rod if T2 = 400 °F and Calculate the new length of the

aluminum segment. Take αal = 13(10-6) /°F , Eal = 10(103) ksi , (σY)al = 40 ksi , αcu =

9.4(10?6) / °F , (σY)cu = 50 ksi , and Ecu = 15(103) ksi .