envision math topic 2: lesson 2-2 estimating sums and differences 2010-11
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EnVision Math Topic 2: Lesson 2-2 Estimating Sums and Differences 2010-11. Rocket Math. Rocket Math Partners. Ryan and Ariana Chelsie and Allison Maryan and Brandon Saul and Jayla Meadow and Mikayla Cameron, Jadyn & Ryan V. - PowerPoint PPT PresentationTRANSCRIPT
EnVision Math
Topic 2:
Lesson 2-2
Estimating Sums and Differences
2010-11
Ryan and Ariana Chelsie and Allison
Maryan and Brandon Saul and Jayla
Meadow and Mikayla Cameron, Jadyn & Ryan V.
Matthew and Nicholas
Elijah and Chase
How can I estimate sums and differences?
645 + 253 =600 300
900
398 + 121 =400 100
500
563 + 375 =600 400
1,000
5,317 + 1,734 =5,000 2,000
7,000
6,324 + 3,842 =6,000 4,000
10,000
72,694 + 17,789 =70,000 20,000
90,000
1,250 + 204 =1,300 200
1,500
542 + 27 =540 30
570
288 - 171 =300 200
100
5,323 – 2,611 =5,000 3,000
2,000
73,088 – 44,444 =70,000 40,000
30,000
892 - 35 =890 40
850
1,724 - 731 =1,700 700
1,000
1,931 – 1,884 =2,000 2,000
0
1,931 – 1,884 =
0
1,900 1,900
1,931 – 1,884 =
50
1,930 1,880
How can I estimate sums and differences?
$4.95 + $8.39 =$5.00 $8.00
$13.00
$9.45 - $6.72 =$9.00 $7.00
$2.00
$24.66 + $72.19 =$20.00 $70.00
$90.00
Let’s Practice
!
219 + 544 =200 500
700
86,128 – 28,017 =90,000 30,000
60,000
$8.79 + $9.13 =$9.00 $9.00
$18.00
1,576 - 910 =1,600 900
700
7,299 + 5,846 =7,000 6,000
13,000
8,112 – 1,511 =8,000 2,000
6,000
1,415 + 337 =1,400 300
1,700
$78.50 - $31.99 =$80.00 $30.00
$50.00
84,735 + 58,175 =80,000 60,000
140,000
This year, 35,658 people ran in a marathon. Last year, 8,683 fewer people ran. About how many people ran last year?
35,658 – 8,683 =36,000 9,000
27,000 people
There are 152 students in grade 4 and 144 students in grade 5. About how many students are in grade 4 and 5?
152 + 144 =200 100
300 students
Alex sold 86 tickets to a school talent show on Thursday and 103 tickets on Friday. About how many tickets did Alex sell altogether?
86 + 103 =90 100
190 tickets
Estimate 463 + 896. The sum is between which two numbers?
A. 500 and 1,000B. 1,000 and 1,500C. 1,500 and 2,000D. 2,000 and 2,500
500 = 1,400+ 900
Estimate 963 + 751. The sum is between which two numbers?
A. 500 and 1,000B. 1,000 and 1,500C. 1,500 and 2,000D. 2,000 and 2,500
1,000 = 1,800+ 800