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EPR paradox and Bell inequality
Antonın Cernoch
RCPTM, Joint Laboratory of Optics of Palacky University and Physical Institute of Academyof Sciences of the Czech Republic
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 1 / 12
Quantum physics
MilestonesPlanc - black-body radiation
Einstein - photoelectric effectHeisenberg - uncertainty principle
Compton, Raman, Zeeman, Millikan, Bohr, Moseley, Debye,Sommerfeld, de Broglie, Schrodinger, Born, von Neumann, Dirac,Fermi, Pauli, von Laue, Dyson, Hilbert, Wien, Bose, Sommerfeld, . . .
Two main principlesrandomnesssuperposition principle
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 2 / 12
Copenhagen interpretationNiels Bohr and Werner Heisenberg
Wavefunctionphysical systems have not definite propertiesbefore they are measuredquantum mechanics only predict the probabilitiesof measurements outputswavefunction is non-localmeasurement changes the system→ collapse ofwavefunction
Other theoriesmany-worlds interpretationthe De Broglie-Bohm (pilot-wave) interpretationquantum decoherence theorie
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 3 / 12
EPR paradox
Albert Einstein, Boris Podolsky and Nathan RosenCan quantum-mechanical description of physical reality beconsidered complete? Phys. Rev. 47, 777 (1935)
wave function does not provide a completedescription of physical reality”element of reality” determines the measurementresultsthese hidden variables are local
”God does not play dice withthe universe”
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 4 / 12
Bell inequality
John Stewart Bell ”On the Einstein Podolsky Rosen Paradox”.Physics 1, 195–200 (1964)
local realism cannot reproduce all the predictionsof quantum mechanical theory
If EPR are rightdifferent measurements (a, b, c) on two distant particles (A and B)measurement results on A is not affected by setting ofmeasurement on B and vice versameasurement result ±1statistics over many realizations→ correlation Cthen C(a, c)− C(b,a)− C(b, c) ≤ 1
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 5 / 12
CHSH inequality
John Clauser, Michael Horne, Abner Shimony and Richard A. Holt”Proposed experiment to test local hidden-variable theories”. Phys. Rev. Lett. 23,880–4 (1969)
generalization of Bell inequality – works also for not-perfectlycorrelated (anti-correlated) pair
−2 ≤ C(a,b)− C(a,b′) + C(a′,b) + C(a′,b′) ≤ 2 ∀a,b
C =N++ − N+− − N−+ + N−−N++ + N+− + N−+ + N−−
1 2
1. photon 2. photon
PBS PBS
+1
−1
+1
−1
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 6 / 12
Proof
four random independent variables a,a′,b,b′
with possible values ±1B = ab + ab′ + a′b − a′b′
a +1 +1 +1 +1 +1 +1 +1 +1 −1 −1 −1 −1 −1 −1 −1 −1a′ +1 +1 +1 +1 −1 −1 −1 −1 +1 +1 +1 +1 −1 −1 −1 −1b +1 +1 −1 −1 +1 +1 −1 −1 +1 +1 −1 −1 +1 +1 −1 −1b′ +1 −1 +1 −1 +1 −1 +1 −1 +1 −1 +1 −1 +1 −1 +1 −1B +2 +2 −2 −2 +2 −2 +2 −2 −2 +2 −2 +2 −2 −2 +2 +2
B = ±2
statistical outcomes⇒
−2 ≤ 〈B〉 ≤ +2
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 7 / 12
Previous measurements
quantum limit
2√
2 ≈ 2.8284271
Poh et al., Singapore
2.82759± 0.00051
my yesterdays value
2.599± 0.015
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 8 / 12
Standard deviation σ
longer accumulation of data→ higher precision (µ/σ)
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 9 / 12
Bell states
Maximally entangled states
|Φ+〉 = 1√2
(|HH〉+ |VV 〉) |Ψ+〉 =1√2
(|HV 〉+ |VH〉)
|Φ−〉 = 1√2
(|HH〉 − |VV 〉) |Ψ−〉 =1√2
(|HV 〉 − |VH〉)
Angles which maximize Bell inequality violation→ Bmax
−C(0◦,22.5◦) + C(0◦,67.5◦) + C(45◦,22.5◦) + C(45◦,67.5◦)4 coincidence measurement for each correlation⇒ 16 measurementsif you change measurement basis by HWP – rotate it by half angle!
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 10 / 12
Table of HWP settings
C(0◦,22.5◦)
ϑ1 ϑ2N++ 0◦ 11.25◦
N+− 0◦ 56.25◦
N−+ 45◦ 11.25◦
N−− 45◦ 56.25◦
C(45◦,22.5◦)
ϑ1 ϑ2N++ 22.5◦ 11.25◦
N+− 22.5◦ 56.25◦
N−+ 67.5◦ 11.25◦
N−− 67.5◦ 56.25◦
C(0◦,67.5◦)
ϑ1 ϑ2N++ 0◦ 33.75◦
N+− 0◦ 78.75◦
N−+ 45◦ 33.75◦
N−− 45◦ 78.75◦
C(45◦,67.5◦)
ϑ1 ϑ2N++ 22.5◦ 33.75◦
N+− 22.5◦ 78.75◦
N−+ 67.5◦ 33.75◦
N−− 67.5◦ 78.75◦
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 11 / 12
Bell factor calculation
Bmax
Nu = N++ − N+− − N−+ + N−−Nl = N++ + N+− + N−+ + N−−
C =Nu
Nl
Bmax = −C1 + C2 + C3 + C4
σ(Bmax )
σ2(Nu) = σ2(Nl) =∑
σ2(N±±)
σ2(C) =1
N4l
(N2u + N2
l )σ2(Nu)
σ2(Bmax ) =4∑
n=1
σ2(Cn)
A. Cernoch (RCPTM/JLO) EPR & Bell inequality 31.8.2016 12 / 12