example 1

9
EXAMPLE 1 Solving an Equation Using Subtraction ANSWER The solution is –23. 8 8 Original equation Subtract 8 from each side to undo addition. Simplify. x is by itself. = –15 + 8 x = –15 + 8 x x –23 =

Upload: leo-larson

Post on 30-Dec-2015

24 views

Category:

Documents


0 download

DESCRIPTION

= –15. x. x. + 8. + 8. = –15. – 8. – 8. –23. x. =. ANSWER. The solution is –23. Solving an Equation Using Subtraction. EXAMPLE 1. Original equation. Subtract 8 from each side to undo addition. Simplify. x is by itself. ?. 13. 17.5 – 4.5. =. 13 = 13 ✓. - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: EXAMPLE 1

EXAMPLE 1 Solving an Equation Using Subtraction

ANSWER

The solution is –23.

– 8 – 8Original equation

Subtract 8 from each side to undo addition.

Simplify. x is by itself.

= –15 + 8x

= –15 + 8x

x –23=

Page 2: EXAMPLE 1

EXAMPLE 2 Solving an Equation Using Addition

c – 4.5 = 13

c – 4.5 + 4.5 = 13 + 4.5

c = 17.5

Original equation

Add 4.5 to each side to undo subtraction.

Simplify. c is by itself.

Check Substitute 17.5 for c

in original equation.13 = 13 ✓

c – 4.5 = 13

=? 1317.5 – 4.5

Page 3: EXAMPLE 1

EXAMPLE 3 Using a Model

Rock Climbing

SOLUTION

Use the diagram to help you write an algebraic model. Let x represent the distance left to climb.

A cliff has a height of about 1500 feet. If you have already climbed 675 feet, how much farther do you have to climb to reach the top?

Page 4: EXAMPLE 1

EXAMPLE 3 Using a Model

1500 = x + 675

1500 – 675 = x + 675 – 675

825 = x

Write an algebraic model.

Subtract 675 from each side.

Simplify. x is by itself.

ANSWER

You have about 825 feet left to climb.

Page 5: EXAMPLE 1

GUIDED PRACTICE for Examples 1, 2, and 3

Solve the equation. Check your solution.

1. x + 9 = 20

x + 9 = 20

c + 9 – 9 = 20 – 9

x = 11

Original equation

Subtract 9 from each side.

Simplify. x is by itself.

Check Substitute 11 for x

in original equation.11 = 11 ✓

=? 1311 + 9

Page 6: EXAMPLE 1

GUIDED PRACTICE for Examples 1, 2, and 3

2. –10 = 3 + y

–10 = 3 + y

–10 – 3 = 3 + y – 3

–13 = y

Original equation

Subtract 3 from each side.

Simplify. y is by itself.

Check Substitute –13 for y

in original equation.–10 = –10 ✓

3 – 13 =?

–10

Page 7: EXAMPLE 1

GUIDED PRACTICE for Examples 1, 2, and 3

3. m – 14 = –15

m – 14 = –15

m – 14 + 14 = –15 +14

m = –1

Original equation

Add 14 from each side.

Simplify. m is by itself.

Check Substitute –1 for m

in original equation.–1 = – 1 ✓

=? –15–1 – 14

Page 8: EXAMPLE 1

GUIDED PRACTICE for Examples 1, 2, and 3

2 = z – 6.4

2 + 6.4 = z – 6.4 + 6.4

8.4 = z

Original equation

Subtract 6.4 from each side.

Simplify. z is by itself.

Check Substitute 8.4 for z

in original equation.2 = 2 ✓

4. 2 = z – 6.4

=? 8.4 – 6.4 2

Page 9: EXAMPLE 1

GUIDED PRACTICE for Examples 1, 2, and 3

s + 49 = 162

s + 49 – 49 = 162 – 49

s = 113

Write an algebraic model.

Subtract 49 from each side.

Simplify. s is by itself.

SOLUTION

Let s represent Jerry’s seashells

5. Seashells

Lucinda combines her 49 seashells with Jerry’s seashells, for a total of 162. Write and solve an addition equation to find how many seashells Jerry had before their collections were combined.

ANSWERJerry had 113 seashells before their collections were combined