exp1 fallingsphereviscometer madrazo,rolandallen

Upload: jclolz15

Post on 06-Apr-2018

229 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    1/12

    Mapua Institute of TechnologySchool of Civil Engineering Environmental and Sanitary Engineering

    Hydraulics Laboratory

    Name: MADRAZO, Roland Allen T.

    Student #: 2008106905

    Program & Year: CE-3

    Course code & Sec: CE140-OP / B2 (Fluid mechanics)

    Group #: 1

    Group Members: ANTONIO, Alvin Kim

    COLUMNA, Regor Leuric

    VIRAY, Jervis Jewel

    Date Performed: October 21, 2010

    Date Submitted: October 27, 1010 Ratings

    Engr. Fibor J. Tan

    Instructor

    Experiment No.1

    Title: FALLING SPHERE VISCOMETER

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    2/12

    EXPERIMENT NO. 1

    FALLING SPHERE VISCOMETER

    Commercial Falling Sphere viscometers are non-available. One type of which isshown on the sketch. The one available is not of the commercial type this viscometermakes use of the principles in case of flow around a small sphere.

    For laminar flow vd/2 1in which d is the diameter of the sphere. The friction orthe deformation drag Fd of the sphere moving at a constant velocity V through a fluid ofinfinite extend is given by Stokes Law with the following assumptions:

    1. The particle must be a sphere.2. The surface of the particle must be smooth.

    3. The resistance to fall or drag force Fd is due to the viscosity of the fluid.4. The terminal velocity must be constant.

    Fd = 3 Vt d ------------------------------------------------ (1)

    A free body diagram of the sphere after it has acquired constant velocity or terminal velocity is

    shown on the sketch where W is the weight of the sphere. Fb is the buoyant force and Fd is the

    deformation drag.

    + = 0 (2)

    Or 3 + 3/6 3/6 (3)

    Solving for :

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    3/12

    = 2( ) (4)

    18V

    Equation (4) has to be corrected in actual practice because the extent of the fluid is not infinite

    and the influence of the boundary proximity on the sphere is large. The correction is usually affected

    by multiplying the observed velocity of fall VSby a certain constant K which is a function of d/Dm the

    diameter of the sphere and medium ratio, such that

    V = VS K (5)

    Where

    K = 1 + 9d/ 4 Dm (9d/4 Dm)2

    The equation for viscosity then becomes

    = d2(SL) / 18VSK

    for which the viscosity can be computed.

    OBJECTIVE:

    The purpose of this experiment is to determine the viscosity of a certain fluid.

    APPARATUS:

    Viscometer stopwatch caliper steel balls

    Hydrometer thermometer

    LABORATORY PROCEDURE:

    Determine the temperature and specific gravity of the liquid whose viscosity is desired. Drop cautiously

    one of the spheres noting whether the sphere is guided correctly or is off center. Determine the time

    required for the sphere to travel a certain distance. Repeat the procedure for each sphere.

    REPORT:

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    4/12

    From the data obtained in the laboratory, compute for each run

    1. (a) Ratio of sphere diameter to diameter of medium, d/Dm

    (b) Correction constant, K

    (c) The observed velocity of fall, VS

    (d) Dynamic Viscosity,

    2. Using the computed value of dynamic viscosity , compute for the Kinematic Viscosity v.

    v = / L

    3. Plot VS versus d/Dm

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    5/12

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    6/12

    FINAL COMPUTATION SHEET

    TRIAL NO. 1

    VS = Y/t = 1m/ 3.42s = 0.29m/s

    d/Dm =0.0063/ 0.09285 = 0.07

    K = 1 + 9d/ 4 Dm (9d/4 Dm)2

    K = 1 + (9*0.0063/ 4*0.09285) (9*0.0063/ 4*0.09285 )2

    K = 1.19

    s = 7350*9.81= 72103.5

    l = 1280*9.81 = 12556.8

    V = VS K = 0.29*(1.19) = 0.35m/s

    = d2(SL) / 18VSK

    = 0.006632(72103.512556.8) / 18*0.35

    = 0.42 Pa-s

    = vp ; v ; /p = 0.42/1280 = 3.28 x 10^-4

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    7/12

    0

    0.05

    0.1

    0.15

    0.2

    0.25

    0.3

    0.35

    0.03 0.05 0.09

    Vs Vs d/Dm

    Vs versus d/Dm

    ANSWERS TO THE QUESTIONS

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    8/12

    RESULTS AND DISCUSSIONS

    The experiment was about testing of the viscosity of a certain fluid which is glycerine. The small steel

    balls with differtent sizes was used to be submerged in the fluid. Each ball have their respective time

    ith their different corresponding sizes.

    The steel balls have different sizes. The smaller the ball, the slower it will sink to the bottom of the

    tube. It is directly proportional. The results for both dynamic and kinematic viscosity have a little

    discrepancy.

    Sources of error must be the incorrect reading of the diameter by using the calibre. Inaccurate start

    and stop times may have a small error. I suggest to use an instrument like a photogate to get the exact

    time when it passes the mark.

    Some practical applications seen is when the speed of the submerging ball is slower due to viscosity of

    the glycerine. Viscosity is commonly perceived as the thicknes or resistance to flow. A good application

    of this is designing a pipeline of a certain fluid in order to counter the shear force it produces and for

    the fluid to flow smoothly.

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    9/12

    CONCLUSION

    Viscosity is the measure of the resistance of a fluid to being in a deformed position by either shear

    stress or extensional stress. In this experiment, we determined the viscosity of a ball in glycerine. f a

    specific layer of a liquid is taken, the layer below it moving with lesser velocity, tries to decrease the

    velocity of upper layer due to cohesive forces between the molecules of adjacent layers. In turn the

    upper layer which is moving with greater velocity tries to increase the velocity of the lower layer. Thus

    between parallel, successive layers of a liquid in motion, opposing force comes into play tending to

    decrease the relative velocity between the layers. The force is called viscous drag. It looks like a

    tangential shearing force is acting between the layers. To overcome these forces and for maintaining

    constant velocity between layers, an external force need to be applied. If there is no external force,

    the velocity of flow decreases and becomes zero. From the results that we have attained, we therefore

    conclude that the values for dynamic and kinematic viscosity were that the dynamic had a lager value

    than the kinetic one. The steel balls have different sizes. The smaller the ball, the slower it will sink to

    the bottom of the tube. It is directly proportional. The results for both dynamic and kinematic viscosity

    have a little discrepancy.

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    10/12

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    11/12

  • 8/3/2019 Exp1 FallingSphereViscometer MADRAZO,RolandAllen

    12/12

    REFERENCE:

    en.wikipedia.org/wiki/Viscosity

    www.britannica.com/.../fluid-mechanics/.../Measurement-of-shear- viscosity -

    www.tutorvista.com/physics/fluid-mechanics-viscosity - United States

    www.engineeringtoolbox.com/fluid-mechanics-t_21.html

    www.efm.leeds.ac.uk/CIVE/CIVE1400/.../Fluid_mechanics.htm -