experts and accuracy
TRANSCRIPT
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EXPERTS AND ACCURACY
Jim Joyce
Department of Philosophy
The University of Michigan
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EXPERT NORMS
Some evidential norms are expressed as expert principles.
Principal Principle: Your credence in H should be your best
estimate of H’s current objective chance (provided you have
no “inadmissible” evidence).
c(H | CHANCEnow(H) = x) = x
Equivalently, c(H) = ∫ 𝒄1
0(CHANCEnow(H) = x)x dx
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SOME NORMS OF EPISTEMIC DEFERENCE
Principal Principle. One should defer to the current CHANCES
as an expert (ceteris paribus)
Reflection Principle. One should defer to ONE’s FUTURE SELF
as an expert (ceteris paribus)
Alethic Principle. One should defer to TRUTH as an expert.
Note the ceteris paribus clauses!
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TWO QUESTIONS
What is involved in treating a potential expert as an expert?
Are there potential experts that should be treated as experts?
I will focus mainly on the first question, but will have a little to
say about the second at the very end.
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GOAL FOR TODAY’S TALK
I plan to explain the normative force of expert principles like PP
by showing that aligning one’s credences with those of an expert
promotes expected credal accuracy.
Expert credences can be used as proxies or surrogates for
Truth. Aligning one’s credences with those of an expert is as
an effective way of holding credences that approximate Truth.
Plan: (a) The basics of expert norms (brief)
(b) The basics of accuracy measurement (brief)
(c) Divergence from experts can be used as a as proxy
for divergence from Truth
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THE SET-UP
W is a set of “possible worlds.”
H = {H1, H2,…, HN} is a partition of hypotheses (each a set of
possible worlds fromW).
Q, R will denote random variables that map elements of W to
coherent credence functions over H.
o These are potential experts (about the Hn).
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THE SET-UP
c is a coherent ceredence function defined over propositions of
form [Hn & Q S], for Q a potential expert and S a set of
coherent credence functions defined over H.
o Q = q means that Q has q as its value.
o Q(Hm) = x means that Q(Hm) S where S is the set of all
coherent credence functions that assign credence x to Hm.
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SIMPLIFYING ASSUMPTIONS (I think)
All potential experts are “data base” experts for c (as well as
“analyst” experts) so that c(E) = 1 implies q(E) = 1 for all q
with c(Q = q) > 0.
A potential expert Q knows everything c knows.
Each potential expert has only finitely many possible values,
so that c(Q = q) > 0 for only finitely many q.
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Learn Q(H1) = 0.2, then Q = q1 or Q = q2
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DEFERENCE TO AN EXPERT
Q is an expert for c if c (completely) defers to Q about the
credences over H.
c(H | Q = q) = q(H), H.
Equivalently, c(H | Q(H) = x) = x, x, H.
This entails that c’s credence for H is its expectation of Q’s
credence for H.
c(H) = q c(Q(H) = q)q(H)
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EMULATION OF EXPERTS
If you defer to Q as an expert, you align your credences with
your expectations of Q’s credences, and your expectations are
your expectations of the Q’s expectations.
Key Fact: If f is any real-valued function of the Hn, then c’s
estimate of f is c’s estimate of Q’s estimate of f.
Expc(ExpQ(f )) = q c(Q = q)n q(Hn)f(Hn)
= q c(Q = q)n c(Hn | Q = q)f(Hn)
= n [q c(Hn & Q = q)]f(Hn)
= n c(Hn)f(Hn) = Expc(f )
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AGREEMENT AMONG EXPERTS
If c defers to Q and R as experts, then c’s expectation of their
credences must agree for all H:
c(H) = q c(Q(H) = q)q(H) = r c(R(H) = r)r(H)
Even though your experts agree about H in expectation, you
recognize that they can disagree in their value assignments.
o You might even know they will disagree, and yet they
can still agree in expectation!
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DISAGREEMENT AMONG EXPERTS
What should your updated credence be if you learn Q(H) = x
and R(H) = y where x y?
The answer depends on which expert carries most epistemic
weight with you.
Definition: Q overrides R about H for c just when
c(H | R(H) = r & Q(H) = q) = q(H), H, x, y
Why would one expert carry more weight than another?
Hold that thought!
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INADMISSIBLE EVIDENCE
Any expert norm that tells you to align your credences with
your expectations of R’s expectations comes with a ceteris
paribus clause
provided you do not possess any ‘inadmissible’ evidence
about an expert Q of higher rank that is not be screened
off by knowledge of R’s value.
o I see this as a definition of admissibility.
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SCREENING CONDITION
You have information about Q that undermines R’s expert status
when
x ∫ 𝒄1
0(Q(H) = y | R(H) = x)y dy, x, y.
Roughly, you take yourself to know more about Q’s values
than what is indicated about them by R.
o Example: Q is the reclusive Queen and R is her spokesman.
If all you know about Q’s opinions comes to you via R, then
R can be an expert for you despite ranking below the Queen.
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THE PECKING ORDER
There is a “pecking order” among experts.
Truth overrides everything: c(H | R(H) = r & H) = 1
c(H | R(H) = r & ~H) = 0
Later chances override earlier chances.
o What else can be usefully said here?
This is a (very) partial order. Often neither Q nor R overrides
the other.
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TWO QUESTIONS
When will c regard Q as an expert?
What accounts for the pecking order?
Considerations of credal accuracy answer both questions!
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EPISTEMIC SCORING RULES
An epistemic scoring rule is a real-valued function Iv(c) that
expresses the inaccuracy of holding credences c in world where
the truth-values for the Hn are as described by v.
Iv(c) 0, with a perfect score of Iv(c) = 0 iff c = v on H.
Think of Iv(c) as a “penalty” for having inaccurate credences.
We will be interested in accuracy over H, and In gives the
inaccuracy of credence functions on H when Hn is true.
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PROPERTIES OF SCORING RULES
TRUTH-DIRECTEDNESS. If all c’s values are closer to the truth
than b’s are, then c earns a strictly lower (= better) score.
EXTENSIONALITY. Iv(c) is a function solely of the credences
that c assigns and the truth-values that v assigns.
CONTINUITY. Iv(c) is a continuous function of c’s values.
STRICT PROPRIETY. Each coherent credence function c uniquely
minimizes expected inaccuracy when expectations are taken
relative to c itself:
Expc(I(b)) = v c(v)Iv(b) > v c(v)Iw(c) = Expc(I(c))
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TWO PLEASING FACTS ABOUT EXPERTS AND ACCURACY
We regard Q as an expert only if we expect that learning its
value will increase our accuracy: Expc(|Q = q)(I(c) – I(q)) > 0
when q c.
If Q overrides R for c then c’s estimate of R’s inaccuracy
exceeds c’s estimate of Q’s inaccuracy.
o c’s estimate of R’s inaccuracy is
Expc(I(R)) = r c(R = r)n c(Hn | R = r)In(r)
= r c(R = r)n r(Hn)In(r)
= r c(R = r)M(r) r’s “modesty”
Note: The converses of these do not hold. Nor should they.
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EXPERT CREDENCES AS PROXIES FOR TRUTH
We can show that aligning credences as closely as possible
with those of an expert serves a kind of proxy or surrogate for
aligning credences with Truth (or any higher-ranking expert).
If you cannot emulate God, emulate a saint!
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DIVERGENCE FROM A CREDENCE FUNCTION
Given two probability functions b and q defined on H the I-
divergence of b from q is the amount by which q expects b to be
less accurate than itself:
Div(b, q) = Expq(I(b)) – Expq(I(q)) > 0 by SP.
Expq(I(q)) is q’s modesty M(q). higher = more modesty
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DIVERGENCE FROM AN EXPERT
Div(b, Q) is b’s divergence from Q. This is a random variable
with values Div(b, q) = Expq(I(b)) – M(q), for variable q.
Div(b, Q) measures how well b does, according to Q, at
approximating Q.
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TWO NICE FEATURES OF Div(b, Q)
1. If you know Q’s value is q, so that c(Q = q) = 1, you will be
certain that Div(b, Q) is minimized at b = q.
2. If Q = @ then Div(b, @) is a random variable with values
Exp@(I(b) – I(v)) = Iv(b)
For any truth-value assignment v, Div(b, v) = Iv(c), i.e.,
inaccuracy = divergence from truth.
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EXPECTED DIVERGENCE FROM AN EXPERT
If Q is an expert for you, then your estimate of the degree to
which an arbitrary credal state b accurately approximates Q
should be your expectation of the divergence of b from Q.
ExpcDiv(b, Q)
To the extent that you are striving to emulate Q you should be
aiming to have credences that minimize this quantity.
We will see that ExpcDiv(b, Q) > ExpcDiv(c, Q) when b c, which
means a coherent believer who defers to Q always (immodestly)
expect herself to be doing better that anyone else at emulating Q.
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THE MASTER FORMULA
Degree to which c expects b to diverge from Q
ExpcDivI(b, Q)
= Expc(I(b)) – q c(Q = q)M(q)
c’s estimate of b’s accuracy. c’s estimate of Q’s modesty.
Minimized at b = c, where it Less than c’s modesty.
equals c’s modesty. Not a function of b!
Not a function of Q’s value!
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DIFFERENCE IN EXPECTED DIVERGENCE FROM AN EXPERT
= DIFFERENCE IN EXPECTED DIVERGENCE FROM TRUTH
ExpcDivI(b1, Q) – ExpcDivI(b2, Q) = Expc(I(b1)) – Expc(I(b2))
When Q is an expert for c, c expects b1 to be inferior to b2
as an approximation of Q to the same degree as c expects b1
to be inferior to b2 as an approximation of Truth.
When Q is an expert for you, seeking to align your credences
with Q’s values is tantamount, in your estimation, to seeking
to align them with Truth (or any expert that overrides Q).
o This explains why you should set your credence for H to
q(H) when you learn Q = q.
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THE q c(Q = q)M(q) TERM
If Q and R are experts for c, and Q overrides R, then c’s
estimate of R’s modesty exceeds c’s estimate of Q’s
modesty (proof of “the 2nd pleasing fact”).
Expected modesty is a kind of measure of departure from
Truth for expert random variables: the higher Q’s modesty
the less well Q approximates Truth.
For Truth, v c(@ = v)M(v) = 0 since M(v) = 0 for every
truth-value assignment.
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TAKE-HOME POINTS
Minimizing expected divergence from expert Q is tantamount
to minimizing expected inaccuracy!
Divergence from an expert can be used as a proxy or surrogate
for divergence from Truth.
Q-PROXY. If c expects b1 to diverge less from Q than b2 does,
then c also expects b1 to diverge less from Truth than b2 does,
and by the same amount.
So, the policy of minimizing expected divergence from an
expert will also minimize expected inaccuracy!
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WHEN SHOULD WE DEFER?
What makes potential expert worthy of expert status?
I have no general answer, but there must be a tie to truth.
o There is such a tie with chance: barring complications (of
inadmissible evidence) chance manifests itself in frequency
of truth.
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The Master Equation: ExpcDiv(b, Q) = Expc(I(b)) – Expc(M(Q))
ExpcDiv(b, Q) = q c(Q = q)Expq(I(b) – I(q)) (> 0 if b q)
= q c(Q = q)n q(Hn)(In(b) – In(q))
= q c(Q = q)n c(Hn | Q = q)(In(b) – In(q))
= q n c(Hn & Q = q)(In(b) – In(q))
= q n c(Hn & Q = q)In(b) – q n c(Hn & Q = q)In(q)
= n c(Hn)In(b) – q n c(Q = q)q(Hn) In(q)
= n c(Hn)In(b) – q c(Q = q)n q(Hn) In(q)
= Expc(I(b)) – q c(Q = q)M(q)
= Expc(I(b)) – Expc(M(Q))
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2nd Pleasing Fact: If Q and R are both experts for c, then Q overrides R for
c only if c’s estimate of R’s inaccuracy exceeds c’s estimate of Q’s
inaccuracy: Expc(I(R)) > Expc(I(Q)).
Expc(I(R)) = n,r c(Hn & R = r)In(r)
= n,r,q c(Hn & R = r & Q = q)In(r)
= r,q c(R = r & Q = q)n c(Hn | R = r & Q = q)In(r)
= r,q c(R = r & Q = q)n q(Hn)In(r)
= r,q c(R = r & Q = q)n q(Hn)In(r)
Expc(I(Q)) = n,q c(Hn & Q = q)In(q)
= n,q,r c(Hn & Q = q & R = r)In(q)
= q,r c(Q = q & R = r)n c(Hn | Q = q & R = r)In(q)
= q,r c(Q = q & R = r)n q(Hn)In(q)
By Propriety, n q(Hn)In(r) > n q(Hn)In(q) for every q and r. From this the
desired result follows.