f5 c5 trigonometric functions new

Upload: aaron-laja

Post on 14-Apr-2018

217 views

Category:

Documents


0 download

TRANSCRIPT

  • 7/30/2019 f5 c5 Trigonometric Functions New

    1/8

    CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5

    PAPER 1

    106

    1. Given is an acute angle andsin p = . Express each of the following in

    terms ofp.

    [3 marks]

    a) tan

    b) ( )cos 90oec

    2. Given cos p = and 270 360o o .Express each of the following interms ofp.

    [3 marks]

    a) sec

    b) ( )cot 90o

    3. Given tan r = , where r is a constant and 180 270o o . Find interms ofr.

    [3 marks]

    a) cot

    b) tan 2

    4. Solve the equation 26cos 13cot 0ec x x = for 0 360o ox

    [4 marks]5. Solve the equation 2 22sin cos sin 1A A A = + for 0 360o oA

    [4 marks]

    6. Solve the equation 2sin7cos2 2 = yy for 0 360o oy

    [4 marks]

    7. Solve the equation 2 015cos cos 4cos 60x x= + for 0 360o oA [4 marks]

    8. Solve the equation 3cot 2sin 0x x+ = for 0 360o ox [4 marks]

  • 7/30/2019 f5 c5 Trigonometric Functions New

    2/8

    CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5

    PAPER 2

    107

  • 7/30/2019 f5 c5 Trigonometric Functions New

    3/8

    CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5

    108

    1. (a) Sketch the graph of sin2y x= for 0 180o ox [4 marks]

    (b) (b) Hence, by drawing suitable straight line on the same axes, find the

    number of solution to the equation1

    sin cos2 360o

    xx x = for

    0 180o ox

    [3 marks]

    2. (a) Sketch the graph of 3cosy x= for 0 2x [4 marks]

    (b) (b) Hence, by using the same axes, sketch a suitable graph to find the

    number of solution to the equation2

    3cos 0xx

    + = for 0 2x .

    State number of solutions.

    [3 marks]

    3. (a) Sketch the graph of 3sin2y x= for 0 2x [4 marks]

    (b) Hence, by using the same axes, sketch a suitable straight line to find

    the number of solution to the equation 2 3sin 22

    xx

    = for

    0 2x

    [3 marks]

    4.(a) Prove that

    cot tancos 22

    x xec x

    +=

    [2 marks]

    (b) (i) Sketch the graph of3

    2sin2

    y x= for 0 2x [6 marks]

    (ii) Find the equation of a suitable straight line to solve the equation

    3 3 1sin

    2 2 2x x

    = .

    Hence, on the same axes, sketch the straight line and state the

    number of solutions to the equation3 3 1

    sin2 2 2

    x x

    = for

    0 2x .5. (a) Prove that 2 2 2sec 2cos tan cos 2x x x x = [2 marks]

    (b) (i) Sketch the graph of cos2y x= for 0 2x [6 marks]

    (ii) Hence, using the same axes, draw a suitable straight line to find

    the number of solutions to the equation22cos 1

    xx

    = for

    0 2x .

    6. (a) Prove that 2 22 2sin 2cosx x = [2 marks]

    (b) Sketch the graph of 12tan += xy for 20 x . By using the same

    axes, draw the straight line9

    32

    y x

    = and state the number of solution to

    equation9

    tan 2 22

    x x

    + = for 20 x

    [6 marks]

    7. (a) Prove that 2 2 2 2cot cos tan secx ec x x x= + [2 marks]

    (b) Sketch the graph3

    cos2

    y x= and 2siny x= for 0 2x . State

    the number of solution to e uation1 3

    sin cosx x = for

    [6 marks]

  • 7/30/2019 f5 c5 Trigonometric Functions New

    4/8

    CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5

    ANSWERS (PAPER 1)

    109

  • 7/30/2019 f5 c5 Trigonometric Functions New

    5/8

    CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5

    110

    1 a)

    2

    tan1

    p

    p =

    1

    b)( )cos 90oec = ( )

    1

    sin 90o 1

    = 21 p 1

    2 a)sec =

    1

    cos

    =1

    p

    1

    b) ( )cot 90o = tan 1

    =21 p

    p

    1

    3 a)cot =

    1

    tan

    =1

    r

    1

    b)tan 2 =

    2

    2tan

    1 tan

    1

    =2

    2

    1

    r

    r1

    4 ( )26 1 cot 13cot 0x x+ = 1

    26cot 13cot 6 0x x + =

    ( ) ( )3cot 2 2cot 3 0x x = 1

    3cot 2 0x = OR 2cot 3 0x =

    3tan

    2x = OR

    2tan

    3x =

    ' 056 19 or 56.31

    ox = and '33 41 or 33.69o ox = 1

    ' o ' ' o '56 19 , 236 19 33 41 , 213 41o ox = Or 56.31 , 236.31 ,33.69 ,213.69

    o o o o

    1

    5 ( )2 22sin 1 sin sin 1A A A = + 1

    2 22sin 1 sin sin 1A A A + = +

    23sin sin 2 0A A =

    ( ) ( )3sin 2 sin 1 0A A+ = 1

    ( )3sin 2 0A + = OR ( )sin 1 0A =

    2

    sin3

    A = OR sin 1A =

    90 and 41.81o oA = 1

    90 ,221.81 , 318.19o o o

    A = 16 22cos 7sin 2 0y y + =

    22(1 sin ) 7sin 2 0y y + = 1

    22sin 7sin 4 0y y+ =

  • 7/30/2019 f5 c5 Trigonometric Functions New

    6/8

    CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5

    (ANSWERS)PAPER 2

    111

  • 7/30/2019 f5 c5 Trigonometric Functions New

    7/8

    45o

    135o

    1

    0.5

    0.5

    1

    x

    y

    1180

    o

    xy =

    180o

    sin 2y x=

    CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5

    112

    1 1 ( shape)

    1(max/min)

    1(one

    period)

    1(complete

    from 0 to

    180o)

    1 (straight

    line)

    1sin cos

    2 360ox

    x x =

    1

    2 2 360oy x

    =

    1 180ox

    y = 1Number of solutions= 3

    1

    2 a) 1 ( shape)

    1(max/min)

    1(one

    period)

    1(complete

    from 0 to2 or

    360 o)

    1(for line

    2y

    x

    =

    b) 2 3cos 0xx

    + =

    20y

    x

    =

    (b)

    2y

    x

    =

    1

    Number of solution =2

    1

    3 1 ( shape)

    1(max/min)1(one

    period)

    1(complete

    from 0o to

    2 )

    2

    3

    2

    2

    2

    1

    2

    x

    y

    31y x

    =

    32sin

    2y x=

    y=2sinx2

    2

    3

    2

    2

    2

    1

    1

    2?

    x

    y

    2

    3

    2

    2

    2

    x

    y

    tan 2 1y x= +

    2y

    x

    =

    3cosy x=

    -2

  • 7/30/2019 f5 c5 Trigonometric Functions New

    8/8

    CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5

    113