f5 c5 trigonometric functions new
TRANSCRIPT
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CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5
PAPER 1
106
1. Given is an acute angle andsin p = . Express each of the following in
terms ofp.
[3 marks]
a) tan
b) ( )cos 90oec
2. Given cos p = and 270 360o o .Express each of the following interms ofp.
[3 marks]
a) sec
b) ( )cot 90o
3. Given tan r = , where r is a constant and 180 270o o . Find interms ofr.
[3 marks]
a) cot
b) tan 2
4. Solve the equation 26cos 13cot 0ec x x = for 0 360o ox
[4 marks]5. Solve the equation 2 22sin cos sin 1A A A = + for 0 360o oA
[4 marks]
6. Solve the equation 2sin7cos2 2 = yy for 0 360o oy
[4 marks]
7. Solve the equation 2 015cos cos 4cos 60x x= + for 0 360o oA [4 marks]
8. Solve the equation 3cot 2sin 0x x+ = for 0 360o ox [4 marks]
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CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5
PAPER 2
107
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CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5
108
1. (a) Sketch the graph of sin2y x= for 0 180o ox [4 marks]
(b) (b) Hence, by drawing suitable straight line on the same axes, find the
number of solution to the equation1
sin cos2 360o
xx x = for
0 180o ox
[3 marks]
2. (a) Sketch the graph of 3cosy x= for 0 2x [4 marks]
(b) (b) Hence, by using the same axes, sketch a suitable graph to find the
number of solution to the equation2
3cos 0xx
+ = for 0 2x .
State number of solutions.
[3 marks]
3. (a) Sketch the graph of 3sin2y x= for 0 2x [4 marks]
(b) Hence, by using the same axes, sketch a suitable straight line to find
the number of solution to the equation 2 3sin 22
xx
= for
0 2x
[3 marks]
4.(a) Prove that
cot tancos 22
x xec x
+=
[2 marks]
(b) (i) Sketch the graph of3
2sin2
y x= for 0 2x [6 marks]
(ii) Find the equation of a suitable straight line to solve the equation
3 3 1sin
2 2 2x x
= .
Hence, on the same axes, sketch the straight line and state the
number of solutions to the equation3 3 1
sin2 2 2
x x
= for
0 2x .5. (a) Prove that 2 2 2sec 2cos tan cos 2x x x x = [2 marks]
(b) (i) Sketch the graph of cos2y x= for 0 2x [6 marks]
(ii) Hence, using the same axes, draw a suitable straight line to find
the number of solutions to the equation22cos 1
xx
= for
0 2x .
6. (a) Prove that 2 22 2sin 2cosx x = [2 marks]
(b) Sketch the graph of 12tan += xy for 20 x . By using the same
axes, draw the straight line9
32
y x
= and state the number of solution to
equation9
tan 2 22
x x
+ = for 20 x
[6 marks]
7. (a) Prove that 2 2 2 2cot cos tan secx ec x x x= + [2 marks]
(b) Sketch the graph3
cos2
y x= and 2siny x= for 0 2x . State
the number of solution to e uation1 3
sin cosx x = for
[6 marks]
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CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5
ANSWERS (PAPER 1)
109
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CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5
110
1 a)
2
tan1
p
p =
1
b)( )cos 90oec = ( )
1
sin 90o 1
= 21 p 1
2 a)sec =
1
cos
=1
p
1
b) ( )cot 90o = tan 1
=21 p
p
1
3 a)cot =
1
tan
=1
r
1
b)tan 2 =
2
2tan
1 tan
1
=2
2
1
r
r1
4 ( )26 1 cot 13cot 0x x+ = 1
26cot 13cot 6 0x x + =
( ) ( )3cot 2 2cot 3 0x x = 1
3cot 2 0x = OR 2cot 3 0x =
3tan
2x = OR
2tan
3x =
' 056 19 or 56.31
ox = and '33 41 or 33.69o ox = 1
' o ' ' o '56 19 , 236 19 33 41 , 213 41o ox = Or 56.31 , 236.31 ,33.69 ,213.69
o o o o
1
5 ( )2 22sin 1 sin sin 1A A A = + 1
2 22sin 1 sin sin 1A A A + = +
23sin sin 2 0A A =
( ) ( )3sin 2 sin 1 0A A+ = 1
( )3sin 2 0A + = OR ( )sin 1 0A =
2
sin3
A = OR sin 1A =
90 and 41.81o oA = 1
90 ,221.81 , 318.19o o o
A = 16 22cos 7sin 2 0y y + =
22(1 sin ) 7sin 2 0y y + = 1
22sin 7sin 4 0y y+ =
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CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5
(ANSWERS)PAPER 2
111
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45o
135o
1
0.5
0.5
1
x
y
1180
o
xy =
180o
sin 2y x=
CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5
112
1 1 ( shape)
1(max/min)
1(one
period)
1(complete
from 0 to
180o)
1 (straight
line)
1sin cos
2 360ox
x x =
1
2 2 360oy x
=
1 180ox
y = 1Number of solutions= 3
1
2 a) 1 ( shape)
1(max/min)
1(one
period)
1(complete
from 0 to2 or
360 o)
1(for line
2y
x
=
b) 2 3cos 0xx
+ =
20y
x
=
(b)
2y
x
=
1
Number of solution =2
1
3 1 ( shape)
1(max/min)1(one
period)
1(complete
from 0o to
2 )
2
3
2
2
2
1
2
x
y
31y x
=
32sin
2y x=
y=2sinx2
2
3
2
2
2
1
1
2?
x
y
2
3
2
2
2
x
y
tan 2 1y x= +
2y
x
=
3cosy x=
-2
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CHAPTER 5 TRIGONOMETRIC FUNCTIONS FORM 5
113