fe review – mechanics of materials...11 fe review mechanics of materials 21 v & m diagrams w...

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1 1 FE Review – Mechanics of Materials FE Review Mechanics of Materials 2 Resources You can get the sample reference book: www.ncees.org – main site http://www.ncees.org/exams/study_ma terials/fe_handbook Multimedia learning material web site: http://web.umr.edu/~mecmovie/index. html

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Page 1: FE Review – Mechanics of Materials...11 FE Review Mechanics of Materials 21 V & M Diagrams w dV dx V = M V dM dx = FE Review Mechanics of Materials 22 Six Rules for Drawing V & M

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FE Review – Mechanics of Materials

FE Review Mechanics of Materials 2

ResourcesYou can get the sample reference book:www.ncees.org – main sitehttp://www.ncees.org/exams/study_materials/fe_handbookMultimedia learning material web site:http://web.umr.edu/~mecmovie/index.html

Page 2: FE Review – Mechanics of Materials...11 FE Review Mechanics of Materials 21 V & M Diagrams w dV dx V = M V dM dx = FE Review Mechanics of Materials 22 Six Rules for Drawing V & M

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FE Review Mechanics of Materials 3

Normal Stress (normal to surface)

Shear Stress (along surface)

First Concept – Stress

FE Review Mechanics of Materials 4

Normal Strain – length change

Mechanical

Thermal

Shear Strain – angle change

Second Concept – Strain

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FE Review Mechanics of Materials 5

Material PropertiesHooke’s Law

Normal (1D)

Normal (3D)

Shear

FE Review Mechanics of Materials 6

Material PropertiesPoisson’s ratio

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FE Review Mechanics of Materials 7

Axial Loading

Stress

Deformation

FF

PLAEδ =∑

xPAσ = F σx

FE Review Mechanics of Materials 8

Torsional Loading

Stress

Deformation TLJGθ =∑

TJρτ =

TT

maxTcJτ =

ρ

τ

τmax

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FE Review Mechanics of Materials 9

Bending Stress

Stress

Find centroid of cross-sectionCalculate I about the Neutral Axis

rxM y

Iσ =− max rM cIσ =

MM

σx

FE Review Mechanics of Materials 10

Transverse Shear Equation

ave VAτ = Average over entire cross-section

aveVQIbτ = Average over line

V = internal shear forceb = thicknessI = 2nd moment of areaQ = 1st moment of area of partial section

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FE Review Mechanics of Materials 11

Partial 1st Moment of Area (Q)

FE Review Mechanics of Materials 12

Max. Shear Stresses on Specific Cross-Sectional Shapes

Rectangular Cross-Section

max32VAτ =

τCircular Cross-Section

max43VAτ =

τ

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FE Review Mechanics of Materials 13

Max. Shear Stresses on Specific Cross-Sectional Shapes

Wide-Flange Beam

maxweb

VAτ ≈

τ

FE Review Mechanics of Materials 14

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FE Review Mechanics of Materials 21

V & M Diagrams

dVwdx

=V

M dMVdx

=

FE Review Mechanics of Materials 22

Six Rules for Drawing V & M Diagrams

1. w = dV/dxThe value of the distributed load at any point in the beam is equal to the

slope of the shear force curve.2. V = dM/dx

The value of the shear force at any point in the beam is equal to the slope of the bending moment curve.

3. The shear force curve is continuous unless there is a point force on the beam. The curve then “jumps” by the magnitude of the point force (+ for upward force).

4. The bending moment curve is continuous unless there is a point moment on the beam. The curve then “jumps” by the magnitude of the point moment (+ for CW moment).

5. The shear force will be zero at each end of the beam unless a point force is applied at the end.

6. The bending moment will be zero at each end of the beam unless a point moment is applied at the end.

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FE Review Mechanics of Materials 23

Deflection Equation

22

d y MEIdx

=y = deflection of midplaneM = internal bending momentE = elastic modulusI = 2nd moment of area with

respect to neutral axis

To solve bending deflection problems (find y):1. Write the moment equation(s) M(x)2. Integrate it twice3. Apply boundary conditions4. Apply matching conditions (if applicable)

FE Review Mechanics of Materials 24

Method of Superposition

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FE Review Mechanics of Materials 25

Stress TransformationPlane Stress Transformation Equations:

cos2 sin22 2x y x y

n xyσ σ σ σσ θ τ θ+ −

= + +

sin2 cos22x y

xyntσ σ

τ θ τ θ⎛ ⎞⎜ ⎟⎝ ⎠

−=− +

τxy

σx

σy

FE Review Mechanics of Materials 26

Stress TransformationPrincipal Stresses:

22

1, 2 2 2 xyx y x y

p pσ σ σ σσ τ

⎛ ⎞⎜ ⎟⎜ ⎟⎜ ⎟⎝ ⎠

+ −= + +

( )tan 2

2

xyp

x y

τθ

σ σ=

−⎛ ⎞⎜ ⎟⎝ ⎠

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FE Review Mechanics of Materials 27

Stress TransformationMax Shear Stress:

1 2max 2

p pσ στ

−= 1

max 2pσ

τ =2

max 2pσ

τ =

FE Review Mechanics of Materials 28

Stress Transformation

Mohr’s Circle

σ

τ

C

( ),x xyσ τ−

( ),y xyσ τ

R

τxy

σx

σy

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FE Review Mechanics of Materials 29

Combined LoadingWe have derived stress equations for four different loading types:

xPA

σ =

maxVkA

τ =

FE Review Mechanics of Materials 30

xMcI

σ = −

xMcI

σ = +

TcJ

τ =

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FE Review Mechanics of Materials 31

Method for Solving Combined Loading Problems1. Find internal forces and moments at

cross-section of concern.2. Find stress caused by each individual

force and moment at the point in question.

3. Add them up.

FE Review Mechanics of Materials 32

Thin-Walled Pressure Vessels

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FE Review Mechanics of Materials 33

Column Buckling

FE Review Mechanics of Materials 34

σY

σY

−σY

−σY

Failure occurs when:

1p Yσ σ>

where σp1 is the largest principal stress.

if σp1 and σp2 have the same sign

1 2p p Yσ σ σ− > if σp1 and σp2 have different signs

σp1

σp2

Maximum Shear Stress Theory

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FE Review Mechanics of Materials 35

σY

σY

−σY

−σY

Failure occurs when:2 2 21 1 2 2p p p p Yσ σ σ σ σ− + >

σp1

σp2

Maximum Distortion Energy Theory

This theory assumes that failure occurs when the distortion energy of the material is greater than that which causes yielding in a tension test.

FE Review Mechanics of Materials 36

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