final stats my(2)
TRANSCRIPT
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PRESENTATION ON :
Group members :
Dilraj kohli 22
Harsh Thakkar 29
Hiren Badani 32
Jigar Vora 39
Krunal Trivedi 49
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LUX soap was launched in INDIA in 1930
Popularly known as beauty soap of film star, Lux has
been a favourate with generations for the experience of
luxurious bathing.
The brand name, Lux has been taken from the word,
luxury.
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Contd..
Lux is the largest personal wash brand in the country
Lux stands for promise of beauty and glamour as one
of the indias most trusted personal care brands
Its world-class fragrances and nourishing ingredients
have made a strong product differentiation for Lux,
making the Lux bath a pleasurable experience.
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Name:
Gender:
1. Age:
20-22
22-25
25-35
35 and above
2. Which bathing soap brand come to your mind first?
Lux
Dove
Lifeboy
Others(specify)
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3. Which are the factors you take into consideration before buyingthe soap?
Celebrity Endorsement Fragrance
Price Brand name
4. You came to know about Lux soap from Newspaper advertisements
TV advertisements Word of mouth Others
5. Which of the offers available influence you the most to purchaseSoap?
Discounts offer Buy one get one Combo pack Other
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6. From where do you prefer to purchase Soap?
Departmental Store
Retail Store
Grocery store Super Market
7. Which type of Lux Soap you like the most( if you have used lux)?
Peach Milk
Cream Milk Pink Cream
Badam Milk
8. What is the size of the Soap you usually purchase?
70 gms 90 gms
125 gms
Other
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9. How frequently you purchase Lux Soap?
Every Week
Every fortnight
Every month
Occasionally
10. Based on the following experience rank lux from the scale of
1(excellent) - 5(poor)
1
2
3
4
5
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18
22
Gender
Male
Female
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The mean or average is a method to derive thecentral tendency of a sample space.
Advantages: Finds the most accurate averageof the set of numbers.
Disadvantages: Outliers can change the mean alot... making it much lower/higher than itshould be.
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15
19
6
Age Group(yrs)
20-24
24-28
28-32
32 &Above
Data F x Fx20-24 15 22 33024-28 19 26 49428-32 6 30 180
32 & above 0 34 0TOTAL 40 1004
MEAN = fx /n
= 1004/40
=25.1
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Median is a measure of central tendency
Data F Cumulativefrequency
20-24 15 1524-28 19 3428-32 6 40
32 & above 0 40Total 40
N/2 = 40/2 = 20th observation
24-28 median class.
Median = L + N/2 Pcf-------------------------- * i
cf
= 24 + 20 15-------------------- * 4
19= 25.05
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18
12
7
30
2
4
6
8
10
12
14
16
18
20
Lux Dove Lifeboy Others
Brand UsedThe most-common or most-frequently occurring value in aseries of data
As, 18 is the higest value So, lux
refers to the most-common ormost-frequently soap usedamong people surveyed
http://www.businessdictionary.com/definition/value.htmlhttp://www.businessdictionary.com/definition/data.htmlhttp://www.businessdictionary.com/definition/data.htmlhttp://www.businessdictionary.com/definition/value.html -
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7
125
16
Factor leads to buy
Celebrity Endorsement
Fragnance
Price
Brand
0
5
10
15
20
25
6
25
72
Information Channel
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0
2
4
6
8
10
12
14
4
9
1314
Offer Influence
16
12
4
8
Place to buy
Departmental Store
Retail Store
Grocery Store
Supermarket
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2
6
17
15
0
2
4
6
8
10
12
14
16
18
frequency of purchase
2
6
17
15
Frequency of Purchase
Every WeekEvery Fortnight
Every Month
Occasionally
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The term SKEWNESS refers to the lack of symmetric. When
the distribution is asymmetrical, it is called as a SKEWED
DISTRIBUTION
If the value of mean, median & mode are alike, it issymmetrical distribution.
In a positively skewed distribution, Mean > Mode & the
Median lies in between Mean & Mode.
In a negatively skewed distribution, Mean < Mode & Median
lies between the two.
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Data F m d fd0-2
8
1
-2
4
-16
256
2-4 15 3 -1 1 -15 2254-6 13 5 0 0 0 06-8 4 7 1 1 4 168-10
0
9
2
4
0
0
Total -27 497
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It shows how much variation or "dispersion"there is from the average
Low standard deviation indicates that the datapoints tend to be very close to the mean
High standard deviation indicates that the data
points are spread out over a large range ofvalues
http://en.wikipedia.org/wiki/Statistical_dispersionhttp://en.wikipedia.org/wiki/Meanhttp://en.wikipedia.org/wiki/Meanhttp://en.wikipedia.org/wiki/Statistical_dispersion -
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After applying, Standard Deviation Formula, we get
Standard Deviation () = [(fd2 /N) (fd/N)2 ] * i
= 6.9192Skewness = mean-mode
= 0.0159
Interpretation: Mean is greater than Mode by anamount equal to 52.75% of the value of StandardDeviation. Thus it is the case of positive skewed
distribution
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Co-relation analysis is defined as analysis of co-variationof 2 or more variables
Assumed mean1 = 7 Assumed mean2 = 4
Serial
numberX Y Dx = X-
ADy =
Y-ADx2 Dy2 Dx Dy
1 5.03 3.14 -1.97 -0.86 3.88 0.74 1.692 5.72 3.24 -1.28 -0.76 1.63 0.58 0.973 5.42 3.6 1.58 -0.40 2.49 0.16 0.634 6.18 3 -0.83 -1.06 0.68 1 0.835 6.22 3.79 -0.78 -021 0.60 0.04 0.166 8.77 4.27 1.77 0.27 3.13 0.07 0.487 8.12 3.89 1.12 -0.02 1.25 0 0.028 8.73 4.17 1.73 0.17 3 0.03 0.299 9.02 5.03 2.02 1.03 4.08 1.06 2.0810 9.48 5.16 2.48 1.16 6.15 1.35 2.88
x =
72.68y =
39.17Dx =
3.47Dy =
-0.62Dx2 = 26.89 Dy2 = 5.03 DxDy =
10.01
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X = 72.68 = 7.2610
Y = 39.17 = 3.9110
r = N dx dy - dx dy
2 ()2 2 ()2
r = 10(10.01) - (3.47) (-.62)
(10 26.89 (3.47)2 (10 0.62 (5.03)2
r = 0.89Since the co-relation is very close to 1, there is a strong positive correlationbetween sales and advertising.
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Regression is the effect of one variable on another.X = X Y = Y
n nv(x) = 2 - x2 v(y) = y2 - y2n ncov(x, y) = xy - x y
nbyx = cov(x, y) bxy = cov(x, y)v(x) v(y)
y on x:y y = byx (x x)x on y:x x = bxy (y-y)
Serial X Y X2 Y2 XY
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Serial
numberX Y X Y XY
1 5.03 3.14 25.3 9.85 15.792 5.72 3.24 32.7 10.49 18.533 5.42 3.6 29.3 12.96 19.514 6.18 3 38.19 9 18.545 6.22 3.79 38.68 14.36 23.576 8.77 4.27 75.69 18.23 37.447 8.12 3.89 65.93 15.13 31.588 8.73 4.17 76.21 17.39 36.409 9.02 5.03 81.36 25.30 45.3710 9.48 5.16 89.87 26.62 48.91
x = 72.68 y = 39.17 X2 = 552.93 Y2 = 159.33 XY = 295.7
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X = 72.68 = 7.26 Y = 39.17 = 3.91
10 10V(x) = 552.93 - (7.26)2 = 2.78
10V(y) = 160.03 - (3.93)2 = 0.5610
cov (x, y) = 296.47 - (7.26 x 3.93) = 1.1110
Byx = 1.11 = 0.39 Bxy = 1.11 = 1.982.78 0.56
Taken x = 50Y 3.93 = 0.39 (50 7.26)
Y = 20.59
Taken y = 45X 7.26 = 1.98 (453.93)X = 88.57