gladish 2009 - derham cohology essentials

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  • 7/30/2019 Gladish 2009 - DeRham Cohology Essentials

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    de Rham cohomology essentials

    de Rham cohomology essentials

    Carl Gladish

    CIMS

    October 10, 2008

    http://find/
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    de Rham cohomology essentials

    Outline of Talk

    History

    Contents

    Outline of TalkHistoryPhysical ExamplesIdea of De Rham cohomologyExterior Calculus

    Generalized Stokes Theorem and De Rhams Theorem

    http://find/
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    de Rham cohomology essentials

    Outline of Talk

    History

    (1899) First general proof of Stokes theorem by HenriPoincare

    (1869-1951) Exterior calculus on manifolds is due to ElieCartan

    (1903 - 1990) Georges de Rham gave a rigorous proof of DeRhams Theorem in 1931

    http://find/
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    de Rham cohomology essentials

    Outline of Talk

    History

    In differential geometry there are two ways to learn things:

    Operationally: ie Calculate like this

    d(cos(xy)dx) = xsin(xy)dy dx

    http://find/
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    de Rham cohomology essentials

    Outline of Talk

    History

    In differential geometry there are two ways to learn things:

    Operationally: ie Calculate like this

    d(cos(xy)dx) = xsin(xy)dy dx

    Rigorous Definitions: ie A cotangent vector is an equivalence

    class of germs of C

    -functions ...

    http://find/
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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    Contents

    Outline of TalkHistoryPhysical ExamplesIdea of De Rham cohomologyExterior Calculus

    Generalized Stokes Theorem and De Rhams Theorem

    http://find/
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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    Solar energy flux

    Let M = {(x, y, z) R3|x2 + y2 + z2 R2sun}.

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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    Solar energy flux

    Let M = {(x, y, z) R3|x2 + y2 + z2 R2sun}.

    The flux of energy from the sun through any surface S M isdetermined by integrating the following 2-form over S:

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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    Solar energy flux

    Let M = {(x, y, z) R3|x2 + y2 + z2 R2sun}.

    The flux of energy from the sun through any surface S M isdetermined by integrating the following 2-form over S:

    f =E

    4

    x(x2 + y2 + z2)3/2

    dy dz

    +y

    (x2 + y2 + z2)3/2dz dx

    +z

    (x2 + y2 + z2)3/2dx dy

    d Rh h l l

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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    Picture of solar energy flux

    d Rh h l i l

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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    This flux is divergence-free (think physically!) everywhere in M soperturbing the surface S by a little (keeping boundary fixed)doesnt change the total flux through it.

    de Rh h l esse ti ls

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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    This flux is divergence-free (think physically!) everywhere in M soperturbing the surface S by a little (keeping boundary fixed)doesnt change the total flux through it.

    Stokes theorem hints that f is the curl of some vector potential A.

    de Rham cohomology essentials

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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    This flux is divergence-free (think physically!) everywhere in M soperturbing the surface S by a little (keeping boundary fixed)doesnt change the total flux through it.

    Stokes theorem hints that f is the curl of some vector potential A.Indeed, in any small open ball U, this flux is the curl of somevector potential AU:

    f|U= AU

    But we can not patch together the local potentials AU to get aglobal potential because ...

    de Rham cohomology essentials

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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    Irrotational 2-d fluid

    Let M = {(x, y) R2|x2 + y2 1}.

    de Rham cohomology essentials

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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    Irrotational 2-d fluid

    Let M = {(x, y) R2|x2 + y2 1}.Consider the flow depicted here:

    de Rham cohomology essentials

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    de Rham cohomology essentials

    Outline of Talk

    Physical Examples

    To get the circulation of V along a path M we must integratethe 1-form

    y

    x2 + y2dx +

    x

    x2 + y2dy

    along .

    de Rham cohomology essentials

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    gy

    Outline of Talk

    Physical Examples

    To get the circulation of V along a path M we must integratethe 1-form

    y

    x2 + y2dx +

    x

    x2 + y2dy

    along . Greens theorem says that the circulation along a loop L is

    C =

    L

    v dr =

    U

    x(

    x

    x2 + y2)

    y(

    y

    x2 + y2)dx dy

    =

    U

    0 dx dy

    = 0

    if L bounds a disk-like region U.

    de Rham cohomology essentials

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    Outline of Talk

    Physical Examples

    This means: If we just consider a disk-like neighbourhood N then

    v is given by a gradient N in that neighbourhood.

    de Rham cohomology essentials

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    Outline of Talk

    Physical Examples

    This means: If we just consider a disk-like neighbourhood N then

    v is given by a gradient N in that neighbourhood.

    But this fails globally because ...

    de Rham cohomology essentials

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    Outline of Talk

    Physical Examples

    Notice that we can easily make up another velocity field that iscurl-free but doesnt have a potential:

    v2 = v + d(xy/2)

    de Rham cohomology essentials

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    Outline of Talk

    Physical Examples

    Notice that we can easily make up another velocity field that iscurl-free but doesnt have a potential:

    v2 = v + d(xy/2)

    de Rham cohomology essentials

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    Outline of Talk

    Physical Examples

    Notice that we can easily make up another velocity field that iscurl-free but doesnt have a potential:

    v2 = v + d(xy/2)

    Question: what other curl-free flows on M lack a potential?De Rhams answer: essentially v is the only one

    de Rham cohomology essentials

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    Outline of Talk

    Idea of De Rham cohomology

    Contents

    Outline of Talk

    HistoryPhysical ExamplesIdea of De Rham cohomologyExterior Calculus

    Generalized Stokes Theorem and De Rhams Theorem

    de Rham cohomology essentials

    O l f lk

    http://find/
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    Outline of Talk

    Idea of De Rham cohomology

    The De Rham cohomology of a space M identifies the differentialforms on M where:

    is closed (ie d = 0), which is the same as saying that has an anti-derivative in any disk-like neighbourhood

    = d for any ( is not exact, it has no globalanti-derivative).

    The derivative we are talking about here is the exterior derivative.For now, think of it as a generalization of div, grad and curl.

    de Rham cohomology essentials

    O li f T lk

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    Outline of Talk

    Idea of De Rham cohomology

    The De Rham cohomology of a space M identifies the differentialforms on M where:

    is closed (ie d = 0), which is the same as saying that has an anti-derivative in any disk-like neighbourhood

    = d for any ( is not exact, it has no globalanti-derivative).

    The derivative we are talking about here is the exterior derivative.For now, think of it as a generalization of div, grad and curl.Specifically,

    Hkde Rham(M) ={ k(M)|d = 0}

    { k(M)| = d for some }

    de Rham cohomology essentials

    O tli e f T lk

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    Outline of Talk

    Idea of De Rham cohomology

    De Rhams Theorem shows that

    Hkde Rham(M)= Linear(Hk(M),R)

    where Hk(M) is the k-dimensional singular homology.

    de Rham cohomology essentials

    Outline of Talk

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    Outline of Talk

    Idea of De Rham cohomology

    De Rhams Theorem shows that

    Hkde Rham(M)= Linear(Hk(M),R)

    where Hk(M) is the k-dimensional singular homology.The upshot is that,modulo the addition of exact forms d, thenumber of linearly independent k-forms on M that are closed butnot exact is exactly the number of independent k-dimensionalholes in the space M.

    de Rham cohomology essentials

    Outline of Talk

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    Outline of Talk

    Idea of De Rham cohomology

    De Rhams Theorem shows that

    Hkde Rham(M)= Linear(Hk(M),R)

    where Hk(M) is the k-dimensional singular homology.The upshot is that,modulo the addition of exact forms d, thenumber of linearly independent k-forms on M that are closed butnot exact is exactly the number of independent k-dimensionalholes in the space M.Looking back at our two examples ...

    de Rham cohomology essentials

    Outline of Talk

    http://find/
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    Outline of Talk

    Exterior Calculus

    Contents

    Outline of Talk

    HistoryPhysical ExamplesIdea of De Rham cohomologyExterior Calculus

    Generalized Stokes Theorem and De Rhams Theorem

    de Rham cohomology essentials

    Outline of Talk

    http://find/
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    Outline of Talk

    Exterior Calculus

    Exterior calculus (due to Cartan) on a manifold M deals with thealgebra of differential forms on M

    (M) = 0(M) 1(M) . . . n(M).

    The exterior derivative is the mysterious map

    d : k(M) k+1(M)

    that has appeared already as a generalization of div, grad and curl.

    de Rham cohomology essentials

    Outline of Talk

    http://find/
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    Exterior Calculus

    Exterior calculus (due to Cartan) on a manifold M deals with thealgebra of differential forms on M

    (M) = 0(M) 1(M) . . . n(M).

    The exterior derivative is the mysterious map

    d : k(M) k+1(M)

    that has appeared already as a generalization of div, grad and curl.

    de Rham cohomology essentials

    Outline of Talk

    http://find/
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    Exterior Calculus

    Here is a sketch of what d : k(M) k+1(M) is:

    de Rham cohomology essentials

    Outline of Talk

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    Exterior Calculus

    Here is a sketch of what d : k(M) k+1(M) is:

    By definition, 0(M) is just the smooth functions on M.

    If f 0(M) then df is a dual-vector field on M.In particular ...

    de Rham cohomology essentials

    Outline of Talk

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    Exterior Calculus

    Here is a sketch of what d : k(M) k+1(M) is:

    By definition, 0(M) is just the smooth functions on M.

    If f 0(M) then df is a dual-vector field on M.In particular ...If vp is a tangent vector at p represented by the path where(0) = p then

    dfp(v) =

    d

    dtt=0f((t))

    de Rham cohomology essentials

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    Exterior Calculus

    In general, a differential k-form k(M) is something which, foreach p M, provides a multi-linear, alternating function

    TpM TpM . . . TpM R.

    Intuitively, this provides a way to measure the volume ofinfinitesimal k-dimensional boxes with one corner at p.

    de Rham cohomology essentials

    Outline of Talk

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    Exterior Calculus

    In general, a differential k-form k(M) is something which, foreach p M, provides a multi-linear, alternating function

    TpM TpM . . . TpM R.

    Intuitively, this provides a way to measure the volume ofinfinitesimal k-dimensional boxes with one corner at p.

    A bit of pure algebra shows that for any (finite-dimensional) vectorspace V there is an isomorphism

    : V V . . . V {alt. k-linear forms on V}

    where

    (v1 v2 . . . v

    k)(w1, w2, . . . , wk) =

    Sk

    (1)sign()v(1)(w1)v(2)(w2) . . . v

    (k)(wk)

    de Rham cohomology essentials

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    Exterior Calculus

    Therefore, given local coordinate functions x1, x2, . . . , xn definednear p, any k-form can be written as

    =

    1i1

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    Exterior Calculus

    Therefore, given local coordinate functions x1, x2, . . . , xn definednear p, any k-form can be written as

    =

    1i1

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    Exterior Calculus

    Formal properties of d

    If f is a smooth function, df is defined as stated above(function on tangent vectors)

    de Rham cohomology essentials

    Outline of Talk

    E terior Calc l s

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    Exterior Calculus

    Formal properties of d

    If f is a smooth function, df is defined as stated above(function on tangent vectors)

    If p(M) and q(M) then

    d( ) = d + (1)p d

    de Rham cohomology essentials

    Outline of Talk

    Exterior Calculus

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    Exterior Calculus

    Formal properties of d

    If f is a smooth function, df is defined as stated above(function on tangent vectors)

    If p(M) and q(M) then

    d( ) = d + (1)p d

    d2 = 0

    de Rham cohomology essentials

    Outline of Talk

    Exterior Calculus

    http://find/
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    Exterior Calculus

    Formal properties of d

    If f is a smooth function, df is defined as stated above(function on tangent vectors)

    If p(M) and q(M) then

    d( ) = d + (1)p d

    d2 = 0

    If U M is open, then

    dU

    = d(U

    )

    If : M N is smooth map between manifolds, then

    d = d

    de Rham cohomology essentials

    Outline of Talk

    Generalized Stokes Theorem and De Rhams Theorem

    http://find/
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    Generalized Stokes Theorem and De Rham s Theorem

    Contents

    Outline of Talk

    HistoryPhysical ExamplesIdea of De Rham cohomologyExterior CalculusGeneralized Stokes Theorem and De Rhams Theorem

    de Rham cohomology essentials

    Outline of Talk

    Generalized Stokes Theorem and De Rhams Theorem

    http://find/
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    Ge e a ed Sto es eo e a d e a s eo e

    General Stokes Theorem (first proved by Poincare 1899)

    M

    d =M

    .

    Proof is quite straightforward but requires careful use of technicaldefinitions.

    de Rham cohomology essentials

    Outline of Talk

    Generalized Stokes Theorem and De Rhams Theorem

    http://find/
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    General Stokes Theorem (first proved by Poincare 1899)

    M

    d =M

    .

    Proof is quite straightforward but requires careful use of technicaldefinitions.

    The important part is that we see that, for the bilinear pairing ofk-forms and k-dimensional submanifolds, d is the adjoint of theboundary operator .

    de Rham cohomology essentials

    Outline of Talk

    Generalized Stokes Theorem and De Rhams Theorem

    http://find/
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    General Stokes Theorem (first proved by Poincare 1899)

    M

    d =M

    .

    Proof is quite straightforward but requires careful use of technicaldefinitions.

    The important part is that we see that, for the bilinear pairing ofk-forms and k-dimensional submanifolds, d is the adjoint of theboundary operator . In fact, Stokes theorem allows us to define abilinear pairing

    Hkde Rham(M) Hk(M) R

    where

    ([], [])

    .

    de Rham cohomology essentialsOutline of Talk

    Generalized Stokes Theorem and De Rhams Theorem

    http://find/http://goback/
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    General Stokes Theorem (first proved by Poincare 1899)

    M

    d =M

    .

    Proof is quite straightforward but requires careful use of technicaldefinitions.

    The important part is that we see that, for the bilinear pairing ofk-forms and k-dimensional submanifolds, d is the adjoint of theboundary operator . In fact, Stokes theorem allows us to define abilinear pairing

    Hkde Rham(M) Hk(M) R

    where

    ([], [])

    .

    Check well-definedness ...

    de Rham cohomology essentialsOutline of Talk

    Generalized Stokes Theorem and De Rhams Theorem

    http://find/
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    This pairing immediately gives us a map

    Hkde Rham(M) Hom(Hk(M),R).

    de Rham cohomology essentialsOutline of Talk

    Generalized Stokes Theorem and De Rhams Theorem

    http://find/
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    This pairing immediately gives us a map

    Hkde Rham(M) Hom(Hk(M),R).

    De Rhams theorem shows that this map is actually anisomorphism. If Hk(M) is finite-dimensional, then

    dim(Hkde Rham(M)) = dim(Hk(M))

    = number of k dimensional holes.

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