hotel management system project report
DESCRIPTION
Project report with Oracle FormsTRANSCRIPT
HOTEL MANAGEMENT SYSTEM COLLEGE NAME: BENGAL COLLEGE OF ENGINEERING AND TECHNOLOGY
BIDHANNAGAR ,DURGAPUR , WESTBENGAL
PIN-713201
GROUP MEMBERS
Student NAME:- STUDENT_ID:- NITESH KUMAR 29522
VIJAY PRATAP 29525
SINGH
SANDIP KUMAR 29521
BAISHALI MUKHERJEE 28195
ACKNOWLEDGEMENT We take upon this opportunity endowed upon us by the grace of the almighty, to thank all those who have been part of this endeavour.
Firstly, we would like to thank GLOBSYN FINISHING SCHOOL for giving us the opportunity as well as lending us the resources to fulfil our work.
We would like to thank our mentor PROF. ARNAB CHAKRABORTY for giving us the right direction to follow and proper guidance regarding the topic. Without his active involvement and the right guidance this would not have been possible .we sincerely thank him for giving us the chance as well as the support for all the time being.
Last but not the least, we heartily appreciate all those people who have helped us directly or indirectly in making these task a success
INDEX 1.INTRODUCTION 1.1 Scope of work
2. REQUIREMENT SPECIFICATION
2.1 Domain description
2.2 Problem definition
2.3 Functional requirements
2.4 Hardware & Software requirements
3. DATABASE DESIGN
3.1 ER diagram
3.2 Table description
4. SCREEN SHOTS
5. FUTURE SCOPE OF IMPROVEMENTS
6. CODE
This is a project work undertaken during SUMMER TRAINING at GLOBSYN FINISHING SCHOOL. We have tried our best to make this project which is HOTEL MANAGEMENT SYSTEM using ORACLE 10g and ORACLE DEVELOPER SUITE as simple as possible which could help the administrators and ticket counter personnel to use and to manipulate different field values easily .Further expansion is possible without much effort.There are four forms:-
1.CUSTOMER
2.STAFF
3.ROOM
4.ALLOCATION
REQUIREMENT SPECIFICATION DOMAIN DESCRIPTION HOTEL MANAGEMENT SYSTEM reservation system is needed to ROOMS on the HOTEL where the customer can choose the ROOM that is currently being in the hotel which has been not allotted.
The main actors in the hotel management system are the administrator….
PROBLEM DEFINITION Nowadays it is very difficult for a person to maintain records manually, so in order to provide the hotels with such a system that helps them severely in maintaining the records of the hotel transactions, we are going with this project. The operations performed by this project are maintenance of the information of the transactions that are performed by the hotels.
Data redundancy and inconsistency.
Difference in accessing data.
Data isolation
Security problem
Communication gap
Updating problem
FUNCTIONAL REQUIREMENTS The functions that the hotel management system provides are as follows:
Activities that only the administrator can perform are:
1. CREATION OF A NEW ACCOUNT FOR customer and staff.
2. ADDING OF A NEW customer WITH ALL THE RELEVANT DETAILS (FOR e.g. customer name, customer_id, customer identification).
3. DELETING OR UPDATING OF A customer AND HENCE, UPDATING OF THE DATABASE.
4. MODIFICATION OR UPDATION OF The hotel related
facilities.
5. booking of rooms for the customer.
Activities that only the admin or receptionist can perform are:
1. BOOKING OF rooms FOR CUSTOMERS. 2. Allotting staff to the customer.
HARDWARE/ SOFTWARE REQUIREMENTS HARDWARE REQUIREMENTS
MOTHERBOARD
PROCESSORS
RAM (64MB MINIMUM)
HARD DISK
MONITOR
KEYBOARD
MOUSE
PRINTER
SOFTWARE REQUIREMENTS
OPERATING SYSTEM :- WINDOWS XP/ WINDOWS 7/WINDOWS 8
PLATFORM :- ORACLE 10G EXPRESS EDITION
FILE SYSTEM :- ORACLE DEVELOPER SUITE
BROWSER :-MOZILLA FIREFOX 2.0.0.2, 3 or 3.5
MICROSOFT WOR
Snapshots
FUTURE SCOPE OF IMPROVEMENTS The limited time and resources have restricted us to incorporate in this project. Only main activities that can be performed in a hotel management system are shown but at most care has been taken to make the system efficient and user friendly. In future, certain improvements can be brought upon like:
1. Developing an interface so that customers can book hotel online, choosing their room of preference.
2. In our project, only one room can be booked at a time. This can be overcome in the future where an interface would be developed which will support booking of multiple rooms at a time.
Codes
Table creating codes
Customer:- create table customer(cid number(10) primary key,cname varchar(10),phno number(10),address varchar(10),pancard number(10));
insert into customer values (rollseq.nextval,'aaa',1111, 'patna',1234);
insert into customer values (rollseq.nextval,'bbb',1121,'ranchi',2345);
insert into customer values (rollseq.nextval,'ccc',1131,'kolkata',3456);
insert into customer values (rollseq.nextval,'ddd',1141,'asansol',4567);
insert into customer values (rollseq.nextval,'eee',1151,'durgapur',5678);
insert into customer values (rollseq.nextval,'fff',1161,'mumbai',6789);
satff
create table staff(Sid number(10),sname varchar(10),address varchar(10),desigination varchar(20),phno number(10));
insert into staff values (sidseq.nextval,'ram','lohardaga','receptionist',2222);
insert into staff values (sidseq.nextval,'shyam','bokaro','waiter',3333);
insert into staff values (sidseq.nextval,'gopal','tata','shef',4444);
insert into staff values (sidseq.nextval,'hari','muri','housekeeping',5555);
insert into staff values (sidseq.nextval,'radha','dhanbad','cleaner',6666);
room
create table room(Room_no number(10) primary key,room_type varchar(10),rent number(15),block varchar(10),floor varchar(10));
insert into room values(01,'single',3000,'A','ground');
insert into room values(02,'single',3000,'A','ground');
insert into room values(03,'single',3000,'A','ground');
insert into room values(04,'single',3000,'A','ground');
insert into room values(05,'single',3000,'A','ground');
insert into room values(06,'Double',4000,'A','ground');
insert into room values(07,'Double',4000,'A','ground');
insert into room values(08,'Double',4000,'A','ground');
insert into room values(09,'Double',4000,'A','ground');
insert into room values(10,'Twin',4000,'A','ground');
insert into room values(11,'Twin',5000,'B','ground');
insert into room values(12,'Twin',5000,'B','ground');
insert into room values(13,'Interconnective',7000,'C','first');
insert into room values(14,'Interconnective',7000,'C','first');
ALLOCATION
create table allocation(cid number(20) ,room number(20),start_date date, end_date date, cost_status varchar(20));
insert into allocation values(1001,421,'20-mar-2010','20-dec-2010','notnull');
insert into allocation values(1002,422,'20-apr-2010','20-dec-2010','notnull');
insert into allocation values(1003,423,'20-may-2010','20-dec-2010','notnull');
insert into allocation values(1004,424,'20-jun-2010','20-dec-2010','notnull');
insert into allocation values(1005,425,'20-jul-2010','20-dec-2010','notnull');
PROGRAMME CODES
Login page:-
For customer:-
Open form(‘c:\new folder\customer.fmx’,activate,no_session)
For staff
Open form(‘c:\new folder\staff.fmx’,activate,no_session)
Customer
Load:- declare a number; begin if :ti1 is null then a := show_alert('nodeptno'); else select count(*) into a from emp where deptno=:ti1; if a=0 then a := show_alert('norecord'); else a := populate_group('rg1'); populate_list('li1','rg1'); end if; end if; end;
move last:-
declare
a number;
cust_id customer.cid%type;
cust_name customer.cname%type;
mobile customer.phno%type;
city customer.address%type;
pan_no customer.pancard%type;
begin
select count(*) into a
from customer;
if (a=0) then
:global.reccount:=0;
:global.currecno:=0;
message('I m in the then block...');
else
message('I m in the else block...');
:global.reccount:=1;
:global.currecno:=a;
:di7:=:global.currecno||'/'||:global.reccount;
select cid,cname,phno,address,pancard into cust_id,cust_name,mobile,city,pan_no
from
(
select rownum rn,cid,cname,phno,address,pancard
from customer
order by rownum
)
where rn=:global.currecno;
:di6:=cust_id;
:ti1:=cust_name;
:ti2:=mobile;
:ti3:=city;
:ti4:=pan_no;
:di7:=:global.reccount||'/'||:global.currecno;
end if;
end;
move previous:- declare a number; cust_id customer.cid%type; cust_name customer.cname%type; mobile customer.phno%type; city customer.address%type; pan_no customer.pancard%type; begin select count(*) into a from customer; if (a=0) then :global.reccount:=0; :global.currecno:=0; else if (:global.reccount=1) then a := show_alert('firsttrecord'); else :global.reccount:=:global.reccount - 1; select cid,cname,phno,address,pancard into cust_id,cust_name,mobile,city,pan_no
from ( select rownum rn,cid,cname,phno,address,pancard from customer order by rownum ) where rn=:global.reccount; :di6:=cust_id; :ti1:=cust_name; :ti2:=mobile; :ti3:=city; :ti4:=pan_no; :di7:=:global.reccount||'/'||:global.currecno; end if; end if; end;
end;
move first:-
declare
a number;
cust_id customer.cid%type;
cust_name customer.cname%type;
mobile customer.phno%type;
city customer.address%type;
pan_no customer.pancard%type;
begin
select count(*) into a
from customer;
if (a=0) then
:global.reccount:=0;
:global.currecno:=0;
message('I m in the then block...');
else
message('I m in the else block...');
:global.reccount:=1;
:global.currecno:=a;
:di7:=:global.reccount||'/'||:global.currecno;
select cid,cname,phno,address,pancard into cust_id,cust_name,mobile,city,pan_no
from
(
select rownum rn,cid,cname,phno,address,pancard
from customer
order by rownum
)
where rn=1;
:di6:=cust_id;
:ti1:=cust_name;
:ti2:=mobile;
:ti3:=city;
:ti4:=pan_no;
:di7:=:global.reccount||'/'||:global.currecno;
end if;
end;
move last:-
declare a number; cust_id customer.cid%type; cust_name customer.cname%type; mobile customer.phno%type; city customer.address%type; pan_no customer.pancard%type; begin select count(*) into a from customer; if (a=0) then :global.reccount:=0; :global.currecno:=0; message('I m in the then block...'); else message('I m in the else block...'); :global.reccount:=1; :global.currecno:=a; :di7:=:global.currecno||'/'||:global.reccount; select cid,cname,phno,address,pancard into cust_id,cust_name,mobile,city,pan_no from ( select rownum rn,cid,cname,phno,address,pancard from customer order by rownum ) where rn=:global.currecno; :di6:=cust_id; :ti1:=cust_name; :ti2:=mobile; :ti3:=city; :ti4:=pan_no; :di7:=:global.reccount||'/'||:global.currecno; end if;
end;
update:- declare a number; begin if :ti2 is null or :ti3 is null or :ti4 is null then a:=show_alert('blankfield'); else insert into mystu values (rollseq.nextval,:ti2,:ti3,:ti4); standard.commit; :global.reccount:=:global.reccount+1; :global.currecno:=:global.reccount; :di3:=:global.currecno||'/'||:global.reccount; end if; end;
insert:-_ :di2 := :global.reccount+1; :ti2:=''; :ti3:=''; :ti4:=''; go_item('ti2');
move next:- declare a number; cust_id customer.cid%type; cust_name customer.cname%type; mobile customer.phno%type; city customer.address%type; pan_no customer.pancard%type; begin select count(*) into a from customer; if (a=0) then :global.reccount:=0; :global.currecno:=0; else if (:global.currecno=:global.reccount) then a := show_alert('lastrecord');
else :global.reccount:=:global.reccount + 1; select cid,cname,phno,address,pancard into cust_id,cust_name,mobile,city,pan_no from ( select rownum rn,cid,cname,phno,address,pancard from customer order by rownum ) where rn=:global.reccount; :di6:=cust_id; :ti1:=cust_name; :ti2:=mobile; :ti3:=city; :ti4:=pan_no; :di7:=:global.reccount||'/'||:global.currecno; end if; end if;
move previous:- declare a number; cust_id customer.cid%type; cust_name customer.cname%type; mobile customer.phno%type; city customer.address%type; pan_no customer.pancard%type; begin select count(*) into a from customer; if (a=0) then :global.reccount:=0; :global.currecno:=0; else if (:global.reccount=1) then a := show_alert('firsttrecord'); else :global.reccount:=:global.reccount - 1; select cid,cname,phno,address,pancard into cust_id,cust_name,mobile,city,pan_no from ( select rownum rn,cid,cname,phno,address,pancard from customer
order by rownum ) where rn=:global.reccount; :di6:=cust_id; :ti1:=cust_name; :ti2:=mobile; :ti3:=city; :ti4:=pan_no; :di7:=:global.reccount||'/'||:global.currecno; end if; end if; end;
end;
staff table:- insert:- :di2 := :global.reccount+1; :ti2:=''; :ti3:=''; :ti4:=''; go_item('ti2');
update:- update declare a number; begin if :ti2 is null or :ti3 is null or :ti4 is null then a:=show_alert('blankfield'); else insert into mystu values (rollseq.nextval,:ti2,:ti3,:ti4); standard.commit; :global.reccount:=:global.reccount+1; :global.currecno:=:global.reccount; :di3:=:global.currecno||'/'||:global.reccount; end if; end;
exit:-
exit form;
room table:-
least button:-
:DI1:=:LI1;
allocation:-
Certificate THIS IS TO CERTIFY THAT NITESH KUMAR OF
Bengal college of engineering and technology HAS
SUCCESSFULLY COMPLETED THE PROJECT
ON hotel management system
THE GUIDANCE OF PROF. ARNAB CHAKRABORTY
USING ORACLE 10g FROM GLOBSYN
FINISHING SCHOOL IN SUMMER TRAINING
PROGRAM 2015-2016.
___________________ ___________________________ Signature and date PROF.ARNAB CHAKRABORTY
Certificate THIS IS TO CERTIFY THAT VIJAY PRATAP SINGH OF
Bengal college of engineering and technology HAS
SUCCESSFULLY COMPLETED THE PROJECT
ON hotel management system
THE GUIDANCE OF PROF. ARNAB CHAKRABORTY
USING ORACLE 10g FROM GLOBSYN
FINISHING SCHOOL IN SUMMER TRAINING
PROGRAM 2015-2016.
___________________ ___________________________ Signature and date PROF.ARNAB CHAKRABORTY
Certificate THIS IS TO CERTIFY THAT BAISHALI MUKHERJEE OF
Dr.sudhir Chandra sur degree engineering college HAS
SUCCESSFULLY COMPLETED THE PROJECT
ON hotel management system
THE GUIDANCE OF PROF. ARNAB CHAKRABORTY
USING ORACLE 10g FROM GLOBSYN
FINISHING SCHOOL IN SUMMER TRAINING
PROGRAM 2015-2016.
___________________ ___________________________ Signature and date PROF.ARNAB CHAKRABORTY
Certificate THIS IS TO CERTIFY THAT SANDIP KUMAR OF
Bengal College of engineering and technology HAS
SUCCESSFULLY COMPLETED THE PROJECT
ON hotel management system
THE GUIDANCE OF PROF. ARNAB CHAKRABORTY
USING ORACLE 10g FROM GLOBSYN
FINISHING SCHOOL IN SUMMER TRAINING
PROGRAM 2015-2016.
___________________ ___________________________ Signature and date PROF.ARNAB CHAKRABORTY
CONCLUSION The HOTEL MANAGEMENT SYSTEM is a step in the direction to ease the structure of ticket booking and reservation system. Some of the advantages that it enjoys over Manual System are:
Data retrieval process becomes easy when it is needed, if we use computer management instead of manually.
Storage capacity of the computer is also excellent.
Updating of data is easy in computerized system
. Data consistency is required for neat and proper management that is achieved by computer easily.
Time is precious and speed is the order of today. Our software supports this statement
. With the help of software, data redundancy reduces as compared to manual.