introduction to the sm (1+2)yuvalg/teshep/tes-2015-1.pdfintro to qft intro to the sm a bit about bsm...
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Introduction to the SM (1+2)
Yuval Grossman
Cornell
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 1
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General remarks
Please ask questions!
Email: [email protected]
Do your “homework.” This is the best way to learnhttp://lepp.cornell.edu/∼yuvalg/TESHEP/
The plan:
Intro to QFT
Intro to the SM
A bit about BSM
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 2
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What is HEP?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 3
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What is HEP
Find the basic laws of Nature
More formally
L = ?
We have quite a good answer
It is very elegant, it is based on axioms and symmetries
The generalized coordinates are fields
We use particles to answer this question
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 4
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What is mechanics?
Answer the question: what is x(t)?
A system can have many DOFs, and then we seek tofind ~x(t) ≡ x1(t), x2(t),...
Once we know ~x(t) we know any observable
Solving for q1 ≡ x1 + x2 and q2 ≡ x1 − x2 is the same assolving for x1 and x2
The idea of generalized coordinates is very important
How do we solve mechanics?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 5
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How do we find x(t)?
x(t) minimizes the action, S. This is an axiom
There is one action for the whole system
S =∫ t2
t1
L(x, x)dt
The solution is given by the E-L equation
d
dt
(
∂L
∂x
)
=∂L
∂x
Once we know L we can find x(t) up to initial conditions
Mechanics is reduced to the question “what is L?”
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 6
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An example: Newtonian mechanics
We assume particle with one DOF and
L =mv2
2− V (x)
We use the E-L equation
d
dt
(
∂L
∂x
)
=∂L
∂xL =
mv2
2− V (x)
The solution is −V ′(x) = mv, aka F = ma
Here F = ma is the output, not the starting point!
Input is L. We need to measure the parameters
So how do we find what is L?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 7
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What is L?
L is the most generalone that is invariant undersome symmetries
We (again!) rephrase the question. Now we ask whatare the symmetries of the system that lead to L
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 8
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What is field theory
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 9
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What is a field?
In math: something that has a value in each point. Wecan denote it as φ(x, t)
Temperature (scalar field)
Wind (vector field)
Mechanical string (?)
Density of people (?)
Electric and magnetic fields (vector fields)
How good is the field description of each of these?
In physics a field used to be associated with a source,but now we know that fields are fundamental
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 10
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A familiar example: the EM field
Consider E(x, t). It obeys the wave equation
∂2E(x, t)
∂t2= c2∂
2E(x, t)
∂x2
The solution is (ϕ0 depends on IC)
E(x, t) = A cos(ωt− kx+ ϕ0), ω = ck
Some important implications of the result
Each mode has it own amplitude, A(ω)
The energy in each ω is conserved
The superposition principle
Are the statements above exact?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 11
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How to deal with generic field theories
φ(x, t) has an infinite number of DOFs. It can be anapproximation for many (but finite) DOFs
To solve mechanics of fields we need to find φ(x, t)
Here φ is the generalized coordinate, while x and t aretreated the same (nice!)
We still need to minimize S
S =∫
Ldxdt L[φ(x, t), φ′(x, t), φ(x, t)]
We usually require Lorentz invariant (and use c = 1)
S =∫
Ld4x L[φ(x, t), ∂µφ(xµ)]
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 12
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Solving field theory
We also have an E-L equation for field theories
∂µ
(
∂L∂ (∂µφ)
)
=∂L∂φ
We have a way to solve field theory, just likemechanics. Give me L and I can know everything!
Just like in Newtonian mechanics, we want to get Lfrom symmetries!
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 13
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Free field theory
The “kinetic term” is promoted
T ∝(
dx
dt
)2
⇒ T ∝(
dφ
dt
)2
−(
dφ
dx
)2
≡ (∂µφ)2
Free particles, and thus free fields, only have kineticterms
L = (∂µφ)2 ⇒ ∂2φ
∂x2=∂2φ
∂t2
An L of a free field gives a wave equation
As in Newtonian mechanics, what used to be thestarting point, here is the final result
Why did we get it?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 14
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Harmonic oscillator
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 15
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The harmonic oscillator
Why do we care so much about harmonic oscillators?
Because we really care about springs?
Because we really care about pendulums?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 16
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The harmonic oscillator
Why do we care so much about harmonic oscillators?
Because we really care about springs?
Because we really care about pendulums?
Because almost any function around its minimum can beapproximated as a harmonic function!
Indeed, we usually expand the potential around one ofits minima
We identify a small parameter, and keep only fewterms in a Taylor expansion
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 16
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Classic harmonic oscillator
V =kx2
2
We solve the E-L equation and get
x(t) = A cos(ωt) k = mω2
The period does not depend on the amplitude
Energy is conserved
Which of the above two statements is a result of theapproximation of keeping only the harmonic term in theexpansion?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 17
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Coupled oscillators
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 18
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Coupled oscillators
There are normal modes
The normal modes are not “local” as in the case of oneoscillator
The energy of each mode is conserved
This is an approximation!
Once we keep non-harmonic terms energy movesbetween modes
V (x, y) =k1x
2
2+k2y
2
2+ αx2y
What determines the rate of energy transfer?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 19
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Things to think about
Relations between harmonic oscillators and free fields
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 20
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The quantum SHO
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 21
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What is QM?
Many ways to formulate QM
For example, we promote x → x
We solve QM if we know the wave function ψ(x, t)
How many wave functions describe a system?
The wave function is mathematically a field
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 22
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The quantum SHO
H =p2
2m+mω2x2
2En = (n+ 1/2)~ω
We also like to use
H = (a†a+ 1/2)~ω a, a† ∼ x± ip x ∼ a+ a†
We call a† and a creation and annihilation operators
E = a|n〉 ∝ |n− 1〉 a†|n〉 ∝ |n+ 1〉
So far this is abstract. What can we do with it?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 23
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Couple oscillators
Consider a system with 2 DOFs and same mass with
V (x, y) =kx2
2+ky2
2+ αxy
The normal modes are
q± =1√2
(x± y) ω2± =
k ± α
m
What is the QM spectrum of this system?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 24
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Couple oscillators
Consider a system with 2 DOFs and same mass with
V (x, y) =kx2
2+ky2
2+ αxy
The normal modes are
q± =1√2
(x± y) ω2± =
k ± α
m
What is the QM spectrum of this system?
(n+ + 1/2)~ω+ + (n− + 1/2)~ω− |n+, n−〉
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 24
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Couple oscillators and Fields
With many DOFs, a → ai → a(k)
And the states
|n〉 → |ni〉 → |n(k)〉
And the energy
(n+ 1/2)~ω →∑
(ni + 1/2)~ωi →∫
[n(k) + 1/2]~ωdk
Just like in mechanics, we expand around the minimumof the fields, and to leading order we have SHOs
In QFT fields are operators while x and t are not
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 25
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SHO and photons
I have two questions:
What is the energy that it takes to excite a SHO by onelevel?
What is the energy of the photon?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 26
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SHO and photons
I have two questions:
What is the energy that it takes to excite a SHO by onelevel?
What is the energy of the photon?
Same answer
~ω
Why the answer to both question is the same? Can welearn anything from it?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 26
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What is a particle?
Excitations of SHOs are particles
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 27
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More on QFT
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 28
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What about masses?
A “free” Lagrangian gives massless particle
L =1
2(∂µφ)
2 ⇒ ω = k (or E = P )
We can add “potential” terms (without derivatives)
L =1
2(∂µφ)
2+
1
2m2φ2
Here m is the mass of the particle. Still free particle
(HW) Show that m is a mass of the particle by showing
that ω2 = k2 +m2
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 29
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What about other terms?
How do we choose what terms to add to L?
Must be invariant under the symmetries
We keep some leading terms (usually, up to φ4)
Lets add λφ4
L =1
2(∂µφ)
2+
1
2m2φ2 +
1
4λφ4
We get the non-linear wave equation
∂2φ
∂x2− ∂2φ
∂t2= m2φ+ λφ3
We do not know how to solve it
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 30
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What about fermions?
We saw how massless and massive bosons arerelated to SHO
The spin of the particle is related to the polarization ofthe classical field
Scalar field : spin zero paricles
vector field : spin one paricles
We can construct a fermion SHO
[a, a†] = 1 → {b, b†} = 1
No classical analogue since b2 = 0
We can then think of fermionic fields. They cangenerate only one particle in a given state
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 31
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A short summary
Particles are excitations of fields
The fundeumental Lagrangian is giving in term of fields
Our aim is to find LWe can only solve the linear case, that is, theequivalent of the SHO
What can we do with higher order temrs?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 32
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Perturbation theory
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 33
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Perturbation theory
H = H0 +H1 H1 ≪ H0
In many cases pertubation theory is a mathematicaltool
There are cases, however, that PT is a better way todescribe the physics
Many times we prefer to work with EV of H (why?)
Yet, at times it is better to work with EV of H0 (why?)
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 34
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1st and 2nd order PT
H = H0 +H1 H1 ≪ H0
In first order we care only about the states with thesame energy
〈f |H1|i〉 Ef = Ei
2nd order pertubation theory probe the whole spectrum
∑
n
〈f |H1|n〉〈n|H1|i〉En − Ef
Ef = Ei En 6= Ei
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 35
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PT for 2 SHOs
V (x, y) =kx2
2+
4ky2
2+ αx2y
Classically α moves energy between the two modes
How it goes in QM?
Recall the Fermi golden rule
P ∝ |A|2 × P.S. A ∼ 〈f |αx2y|i〉
The relevant thing to calculate is the transitionamplitude, A.
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 36
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Transitions
V (x, y) =kx2
2+
4ky2
2+ αx2y
Recall
x ∼ ax + a†x y ∼ ay + a†
y
When A is non-zero?
A ∼ 〈f |αx2y|i〉
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 37
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Transitions
V (x, y) =kx2
2+
4ky2
2+ αx2y
Recall
x ∼ ax + a†x y ∼ ay + a†
y
When A is non-zero?
A ∼ 〈f |αx2y|i〉
Since H1 ∼ x2y we see that ∆ny = ±1 and ∆nx = 0,±2
What could you say if the perturbation was x2y3?
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 37
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Two SHOs with small α
V (x, y) =kx2
2+
4ky2
2+ αx2y ωy = 2ωx
Consider |i〉 = |0, 1〉Since ωy = 2ωx only f = |2, 0〉 is allowed by energyconservation and by the perturbation
A ∼ 〈2, 0|αx2y|0, 1〉 ∼ α〈2, 0|(ax+a†x)(ax+a†
x)(ay+a†y)|0, 1〉
ay in y annihilates the y “particle” and (a†x)2 in x2
creates two x “particles”
It is a decay of a particle y into two x particles with
width Γ ∝ α2 and thus τ = 1/Γ
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 38
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Even More PT
H1 = αx2z + βxyz ωz = 10, ωy = 3, ωx = 1
Calculate y → 3x using 2nd order PT
A ∼ 〈3, 0, 0|O|0, 1, 0〉 O ∼∑ 〈3, 0, 0|V ′|n〉〈n|V ′|0, 1, 0〉
En − E0,1,0
Which intermediate states? |1, 0, 1〉 and |2, 1, 1〉A1 = |0, 1, 0〉 β−→ |1, 0, 1〉 α−→ |3, 0, 0〉A2 = |0, 1, 0〉 α−→ |2, 1, 1〉 β−→ |3, 0, 0〉
The total amplitude is then
A ∝ αβ
(
#
∆E1
+#
∆E2
)
∝ αβ
(
#
8+
#
12
)
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 39
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Closer look
V ′ = αx2z + βxyz ωz = 10, ωy = 3, ωx = 1
We look at A = |0, 1, 0〉 β−→ |1, 0, 1〉 α−→ |3, 0, 0〉
y
β
x
α
x
xz A ∝ αβ
∆Ez
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 40
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Feynman diagrams
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 41
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Using PT for fields
For SHOs we have xi ∼ ai + a†i
For fields we then have
φ ∼∫
[
a(k) + a†(k)]
dk
Quantum field = creation and annihilation operators
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 42
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Feynman diagrams
A graphical way to do perturbation theory with fields
Unlike SHOs before, a particle can have any energy aslong as E ≥ m
Operators with 3 or more fields generate transitionsbetween states. They give decays and scatterings
Decay rates and scattering cross sections arecalculated using the Golden Rule
Amplitudes are calculated from LWe generate graphs where lines are particles andvertices are interactions
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 43
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Examples of vertices
φ1
φ2
φ1
λL = λφ21φ2 :
φ φ
φ φ
λL = λφ4 :
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 44
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Calculations
We usually care about 1 → n or 2 → n processes
We need to make sure we have energy conservation
External (Internal) particles are called on(off)–shell
On-shell: E2 = p2 +m2
Off-shell: E2 6= p2 +m2
A = the product of all the vertices and internal lines
Each internal line with qµ gives suppression
1
m2 − q2
There are many more rules to get all the factors right
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 45
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Examples of amplitudes
L = λ1XY Z + λ2X2Z Γ(Z → XY )
Energy conservation condition
Draw the diagram and estimate the amplitude
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 46
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Examples of amplitudes
L = λ1XY Z + λ2X2Z Γ(Z → XY )
Energy conservation condition mZ > mX +mY
Draw the diagram and estimate the amplitude
Z
λ1
X
Y
A ∝ λ1
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 46
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Examples of amplitudes (2)
L = λ1XY Z + λ2X2Z Γ(Y → 3X)
Energy conservation condition
Draw the diagram and estimate the amplitude
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 47
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Examples of amplitudes (2)
L = λ1XY Z + λ2X2Z Γ(Y → 3X)
Energy conservation condition mY > 3mX
Draw the diagram and estimate the amplitude
Y
λ1
X
λ2
X
XZ A ∝ λ1λ2 × 1
∆E2Z
= λ1λ2 × 1
m2Z − q2
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 47
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Examples of amplitudes (HW)
L = λ1XY Z + λ2X2Z σ(XX → XY )
Energy conservation condition
Draw the diagram and estimate the amplitude
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 48
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Some summary
Quadratic terms describe free fields. Free particlescannot be created nor decay
We use perturbation theory were terms with 3 or morefields in L are consider small
These terms can generate and destroy particles andgive dynamics
Feynman diagrams are a tool to calculate transitionamplitudes
Many more details are needed to get calculation done
Once calculations and experiments to check them aredone, we can test our theory
Y. Grossman The SM (1) TES-HEP, July 9, 2015 p. 49