itb (institut teknologi brunei) engineering materials lecture 3 - structure of crystalline solids...
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ITB (Institut Teknologi Brunei) Engineering Materials Lecture 3 - Structure of Crystalline Solids PCE1ENM 2013TRANSCRIPT
13/8/2011
Eng. Mat/ITB/UHH 1
Structure of Crystalline Solids
Types of Solids
• Crystalline Material
• Atoms self-organize in a periodic
• Atoms arranged in repetitive 3-Dimensional pattern, in long rangeorder (LRO) give rise to crystalstructure.
• Amorphous (Non-Crystalline)
• Lacks a systematic atomic arrangement
• Atoms are arranged in short range order
Crystalline Structure
Non-Crystalline
Structure
2
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Eng. Mat/ITB/UHH 2
Single Crystals and Polycrystalline Materials
• Single Crystal
• Atoms are in a repeating or periodic array over the entire
extent of material
3
• Polycrystalline material
• Comprised of many small crystals or grains
• The grains have different crystallographic orientation
• Atomic mismatch where grains meet (grain boundaries)
Crystal Structure
• When describing crystalline structures, atoms (or
ions) are thought of as being solid spheres with well-
defined diameters.
• Atomic hard sphere model
• Spheres representing
nearest-neighbor atoms
touch one another.
4
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Eng. Mat/ITB/UHH 3
Unit Cell
• Space Lattice
• An imaginary network of lines, with atoms at intersection of
lines, representing the arrangement of atoms
• Unit Cell
• The smallest structural unit or building block that can
describe the crystal structure
• Repetition of the unit cell generates the entire crystal
Space Lattice
Unit Cell
5
Crystal Systems and Bravais Lattice
• Different types of unit cells can be constructed,
depending on values of the lattice parameters.
Lattice parameters
(or Lattice Constants)axial lengths: a, b, c
interaxial angles: α, β, γ
In general: a ≠ b ≠ c
α ≠ β ≠ γ6
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Crystal Systems and Bravais Lattice
• Only seven different types of unit cells are necessary to
create all space lattices.
• Many of the seven crystal systems have variation of the
basic unit cells:
• Bravais (1811 -1863) showed that fourteen standard unit cells
can describe all possible lattice networks
• These Bravais lattices are illustrated in the next few slides.
• The Four basic types of unit cells are:
1. Simple
2. Body Centered
3. Face Centered
4. Base Centered
7
Types of Unit Cells
1.
1.
8
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Principal Metallic Crystal Structures
• Metals tend to be densely packed
• Typically, only one element is present, so all atomic radii
are the same
• Metallic bonding is not directional
• No restriction on number or positions of nearest
neighbour atoms: large number of nearest neighbours
and dense atomic packing.
• The densely packed structures are in lower and more
stable energy.
• Energy is released as the atoms come closer together
and bond more tightly with each other
• Have simplest crystal structures
11
Principal Metallic Crystal Structures
• 90% of the metals have either Body Centered Cubic
(BCC), Face Centered Cubic (FCC) or Hexagonal Close
Packed (HCP) crystal structure
• HCP is denser version of simple hexagonal crystal
structure
12
The unit cell
is shown by
solid lines
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Eng. Mat/ITB/UHH 7
Body Centered Cubic (BCC) Crystal Structure
• Represented as one atom at each corner of cube and
one at the center of cube
• Each atom has 8 nearest neighbors
• Therefore, coordination number is 8
Atomic-site
unit cell
Hard-sphere
unit cell
Isolated
unit cell
13
Body Centered Cubic (BCC) Crystal Structure
• In isolated unit cell, each of these
cells has the equivalent of two
atoms per unit cell.
• Each unit cell has eight ⅛ atom at
corners and 1 full atom at the center
• (8 × ⅛) + 1 = 2 atoms
• Atoms contact each other at cube
diagonal.
• Therefore, lattice constant:
a =4R
3
14
Ra 43 = or
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Atomic Packing Factor of BCC Structure
• If the atoms in the BCC are considered to be spherical:
• Since there are two atom per BCC unit cell:
• Volume of the BCC unit cells is:
• Therefore:
Atomic Packing Factor =Volume of atoms in unit cell
Volume in unit cell
15
Face Centered Cubic (FCC) Crystal Structure
• Represented as one atom each at the corner of cube
and at the center of each cube face
• Coordination number for FCC structure: 12
• Atomic Packing Factor is 0.74
Atomic-site
unit cell
Hard-sphere
unit cell
Isolated
unit cell
16
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Face Centered Cubic (FCC) Crystal Structure
• In isolated unit cell, each of these
cells has the equivalent of four
atoms per unit cell.
• Each unit cell has eight ⅛ atom at
corners and six ½ atoms at the
center of six faces.
• (8 × ⅛) + (6 × ½) = 4 atoms
• Atoms contact each other across
cubic face diagonal
• Therefore, lattice constant:
2
4Ra =
17
Ra 42 = Or
Hexagonal Close-Packed (HCP) Crystal Structure
• Represented as an atom at each of 12 corners of a
hexagonal prism, 2 atoms at top and bottom face and 3
atoms in between top and bottom face
• Atoms attain higher APF (0.74) by attaining HCP Structure
than simple hexagonal structure
• The coordination number: 12
Atomic-site
unit cell
Hard-sphere
unit cellIsolated
unit cell
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• In isolated unit cell, each of thesecells has the equivalent of six atomsper unit cell.
• Each unit cell has six ⅙ atoms ateach of top and bottom layer, twohalf atoms at top and bottom layerand 3 full atoms at the middle layer.
• (2 × 6 × ⅙) + (2 × ½) + 3 = 6 atoms
• Ideal c/a ratio is 1.633
• Ratio of the height c of the hexagonalprism of the HCP structure to itsbasal side a.
Hexagonal Close-Packed (HCP) Crystal Structure
19
HCP Crystal Structure (Example)
• Calculate the volume of the zinc crystal structure unit cell by
using the following data: pure zinc has the HCP structure with
lattice constant a = 0.2665 nm and c = 0.4947.
Solution:
Volume of Zn HCP unit cell = Area of the base × height
20• Area of base =
Area of ABDEFG
• Area of ABDEFG:
Total areas of 6 equivalent triangles of area
ABC
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Atom Positions in Cubic Unit Cells
• Cartesian coordinate system is use to locate atoms (x, y, z)
• In a cubic unit cell
• y-axis: direction to the right
• x-axis: direction coming out of the paper
• z-axis: direction towards top
• Negative directions are to the opposite of positive directions
• Atom positions are
located using unit
distances along the
axes.21
Directions in Cubic Unit Cells
• In cubic crystals, Direction Indices [uvw] are vector
components of directions resolved along each axes,
resolved to smallest integers.
• Direction indices are position coordinates of unit cell
where the direction vector emerges from cell surface,
converted to integers.
• Some directions in cubic unit cells:
22
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Procedure to Find Direction Indices
Produce the direction vector till it
emerges from the surface of cubic cell
Determine the coordinates of point of
emergence and origin
Subtract coordinates of point of
emergence by that of origin
Are all are integers?
Are any of the direction vectors negative?
Represent the indices in a square
bracket without comas with a bar
(_) over a negative index
Represent the indices in a square
bracket without comas
Convert them to smallest
possible integer by
multiplying by an integerYES
YES
NO
NO
23
For Cubic Unit
Cells
For Cubic Unit
Cells
Direction Indices Cubic Unit Cells(Example)
• Determine direction indices of the given vector.
• Origin coordinates are (3/4, 0, 1/4)
• Emergence coordinates are (1/4, 1/2, 1/2)
Solution:
• Subtracting origin coordinates
from emergence coordinates:
• Multiply by 4 to convert all
fractions to integers:
24
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Miller Indices in Cubic Unit Cells
• Used to refer to specific lattice planes of atoms
• They are reciprocals of the fractional intercepts (with
fractions cleared) that the plane makes with the
crystallographic x, y and z axes of three non-parallel
edges of the cubic unit cell.
25
Procedure to Find Miller Indices
Choose a plane that does not pass
through origin
Determine the x, y, and z intercepts of
the plane
Find the reciprocals of the intercept
Fractions?
Place a ‘bar’ over the negative indices
Enclose in parenthesis (hkl) where
h, k, l are miller indices of cubic
crystal place for x, y and z. Eg: (111)
Clear fractions by
multiplying by an integer to
determine smallest set of
whole numbers
No
Yes
26
For Cubic Unit
Cells
For Cubic Unit
Cells
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Miller Indices for Cubic Unit Cells(Example)
• Intercepts of the plane at x, y and
z are 1, ∞ and ∞
• Taking reciprocals we get (1, 0, 0)
• Miller indices are (100):
• one-zero-plane
1.
2. • Intercepts are 1/3, 2/3 and 1
• Taking reciprocals we get (3,
3/2, 1)
• Multiplying by 2 to clear
fractions, we get (6,3,2)
• Miller indices are (632)
27
Miller Indices for Cubic Unit Cells (Example)
• Taking reciprocals of the
indices we get (1, ∞, 0)
• The intercepts of the plane
are x = 1, y = ∞ (parallel to y)
and z = 1
3. Plot the plane (101)
4. Plot the plane (221)
• Taking reciprocals of the
indices we get (1/2, 1/2, 1)
• The intercepts of the plane are
x = ½, y = ½ and z = 1
28
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Miller Indices for Cubic Unit Cells(Example)
• Taking reciprocals of the indices we get (1, -1, ∞)
• The intercepts of the plane are x = 1, y = -1 and z = ∞
(parallel to z axis)
5. Plot the plane (1 1 0)_
• To show this plane in a
single unit cell, the origin
is moved along the
positive direction of y
axis by 1 unit
29
Miller Indices (Important Relationship)
• This is only for the CUBIC SYSTEM:
• Direction indices of a direction perpendicular to a crystal
plane are same as miller indices of the plane.
• Example:
• Interplanar spacing (dhkl) between parallel closest
planes with same miller indices is given by
dhkl =a
h2 + k 2 + l2
30a = lattice constant
h, ,k, l = miller indices of cubic
planes being considered)
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Indices for Crystal Planes in
Hexagonal (HCP) Unit Cells
• Four indices are used (hkil) called as Miller-Bravals
indices.
31
• Four axes are used (a1, a2,a3 and c)
• Reciprocal of the intercepts
that a crystal plane makes
with the a1, a2, a3 and caxes give the h, k, i and l
indices respectively.
Indicesfor Crystal Planesin HCP Unit Cells (Examples)
• Basal Planes:
• Prism Planes: For plane ABCD
32
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Comparison of FCC and HCP Crystals
• Both FCC and HCP are close packed and have APF 0.74
• FCC crystal is close packed in (111) plane while HCP is
close packed in (0001) plane.
FCC Crystal Structure
showing a close-packed
(111) plane
HCP Crystal Structure
showing a close-packed
(0001) plane
33
Structural Difference between HCP and FCC
34
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Volume Density
• Since the entire crystal can be generated by the
repetition of the unit cell, the density of a crystalline
material
• Example:
• Copper (FCC) has atomic mass of 63.54 g/mol and
atomic radius of 0.1278 nm.
• Volume of unit cell,
ρv =Mass /Unit cell
Volume /Unit cell
35
Densities of Material Classes
• In general
ρmetals > ρceramics > ρpolymers
• Reasons:
• Metals have close-packing (metallic bonding) and often
large atomic masses.
• Ceramics have less dense packing and often lighter
elements
• Polymers have low packing density (often amorphous)
and lighter elements (C, H, O)
36
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Polymorphism or Allotropy
• Polymorphism
• Materials exist in more than one crystalline form under
different conditions of temperature and pressure.
• If the material is an elemental solid, it is called allotropy
• Example: Iron exists in both BCC and FCC form
depending on the temperature.
37
• Another example: Carbon, which can exist as diamond,
graphite and amorphous carbon.
Polymorphism or Allotropy
38
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Non-Crystalline (Amorphous) Solids
• Solids lack of a systematic and regular arrangement of
atoms over relatively large atomic distances.
• Two-dimensional schematic diagrams for:
• Rapid cooling of metals (108 K/s) can give rise to
amorphous structure since little time is allowed for
ordering process.
39
Crystalline SiO2Non Crystalline SiO2
Much more
disordered and
irregular