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January 22 Review questions

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January 22. Review questions. Math 307 Spring 2003 Hentzel Time: 1:10-2:00 MWF Room: 1324 Howe Hall Instructor: Irvin Roy Hentzel Office 432 Carver Phone 515-294-8141 E-Mail: [email protected] Office Hours: 9:00-10:00 MWF 2:00- 3:00 MWF. - PowerPoint PPT Presentation

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Page 1: January 22

January 22

Review questions

Page 2: January 22

• Math 307• Spring 2003• Hentzel• Time: 1:10-2:00 MWF• Room: 1324 Howe Hall• Instructor: Irvin Roy Hentzel• Office 432 Carver• Phone 515-294-8141• E-Mail: [email protected]• Office Hours: 9:00-10:00 MWF• 2:00- 3:00 MWF

Page 3: January 22

We apply the ideas we have learned

• We go over the 36 true false questions so that we learn how to use the facts we have learned so far to get really nice results.

Page 4: January 22

1 The following matrix is in RREF. | 1 2 0 | | 0 0 1 | | 0 0 0 |

True. | |_1__ 2_ 0 | | 0 0 |_ 1 _| | 0 0 0 | Find the: (a) Stairs (b) Stair step ones (c) Zeros below the stairs (d) Zeros above the stair step ones.

Page 5: January 22

2. A system of four equations in three unknowns is always inconsistent.

False: x + y + z = 3 x = 1 y = 1 z = 1Is consistent.

Page 6: January 22

3. There is a 3x4 matrix with rank 4.

False: A matrix with 3 rows can have at most three stair step ones. Thus the matrix can have rank at most 3.

Page 7: January 22

4. If A is a 3x4 matrix and vector V is in R^4, then vector AV is in R^3.

True: A V = (AV) 3x4 4x1 3x1

Page 8: January 22

5. If the 4x4 matrix A has rank 4, then any linear system with coefficient matrix A will have a unique solution.

True: The Row Canonical Form of [A | B] will always reduce to [ I | B* ] for some

B*. There is no stair step one in the last column so there is an answer. There are no parameters so the answer is unique.

Page 9: January 22

6. There exists a system of three linear equations with three unknowns that has exactly three solutions.

False: If there is more than one solution, then there is at least one parameter and there will be an infinite number of solutions.

Page 10: January 22

7. There is a 5x5 matrix A of rank 4 such that the system AX = 0 has only the solution X = 0.

False: Rank 4 means four stair step ones. One of the variables will not be above a stair step one. Therefore, there is at least one parameter. There may be no solutions at all, but if there are any solutions at, there are infinitely many of them.

Page 11: January 22

8. If matrix A is in RREF, then at least one of the entries in each column must be 1.

False: Consider this matrix in RREF. | |_1_ 0 0 0 | | 0 |_1_ 0_ 0 | | 0 0 0 |_1_|

Page 12: January 22

9. If A is an nxn matrix and X is a vector in R^n, then the product AX is a linear combination of the columns of the matrix A.

True: The columns of AB are linear combinations of the columns of A.

Page 13: January 22

10. If vector U is a linear combination of vectors V and W, then we can write U = aV+bW for some scalars a and b.

True: This is exactly what we mean when we say that a vector is a linear combination of two vectors.

Page 14: January 22

11. The rank of the following matrix is 2. | 2 2 2 | | 2 2 2 | | 2 2 2 |

False: Reduce it to Row Canonical Form and count the non zero rows. The rank is 1.

| 1 1 1 | | 0 0 0 | | 0 0 0 |

Page 15: January 22

12. | 11 13 15| | -1 | | 13 | | 17 19 21| | 3 | = | 19 | | -1 | | 21 |

False. It cannot possibly be correct sincea 2x3 matrix times a 3x1 matrix will be a2x1 matrix, not a 3x1 matrix.

Page 16: January 22

13. There is a matrix A such that

| -1 | | 3 | A | 2 | = | 5 | . | 7 |

True: | 0 3/2 | | 0 5/2 | | 0 7/2 |Is such a matrix.

Page 17: January 22

14. | 1 | Vector | 2 | is a linear combination of | 3 | | 4 | | 7 |Vectors | 5 | and | 8 | . | 6 | | 9 |

True: | 4 | | 7 | | 1 | 2 | 5 | - 1 | 8 | = | 2 | | 6 | | 9 | | 3 |

Page 18: January 22

15. The system below is inconsistent.

| 1 2 3 | | x | | 1 | | 4 5 6 | | y | = | 2 | | 0 0 0 | | z | | 3 |

True: The last equation requires that0x + 0 y + 0 z = 3 which cannot possiblebe true.

Page 19: January 22

16.There exists a 2x2 matrix A such that

A | 1 | = | 3 |. | 2 | | 4 |

True: | 1 1 | | 1 | = | 3 | | 2 1 | | 2 | | 4 |

Page 20: January 22

17. If A is a nonzero matrix of the form | a -b | | b a |Then the rank of A must be 2.

True: If a = 0, then the RCF = I and the rank is 2. If a =/= 0, then

| a -b | ~ | 1 -b/a | ~ | 1 -b || b a | | b a | | 0 (b^2)/a +a |

If (b^2)/a + a = 0, the rank is 1. If (b^2)/a =/= 0, the rank is 2.Since (b^2)/a + a = 0 requires a^2 + b^2 = 0 which cannothappen for real numbers a and b, we know that the rank isalways 2.

Page 21: January 22

18. The rank of this matrix is 3. | 1 1 1 | | 1 2 3 | | 1 3 6 |

True:| 1 1 1 | | 1 1 1 | | 1 0 -1 | | 1 0 0 || 1 2 3 | ~ | 0 1 2 | ~ | 0 1 2 | ~ | 0 1 0 || 1 3 6 | | 0 2 5 | | 0 0 1 | | 0 0 1 |

Page 22: January 22

19. The system is inconsistent for any (4x3) matrix A. | 0 | A X = | 0 | | 0 | | 1 |

False: | 0 0 0 | | 1 | | 0 | | 0 0 0 | | 1 | | 0 | | 0 0 0 | | 1 | = | 0 | | 1 0 0 | | 1 |

Page 23: January 22

20.There exists a 2x2 matrix A such that A | 1 | = | 1 | and A | 2 | = | 2 |

| 1 | | 2 | | 2 | | 1 |

False: A| 2 | = 2 A| 1 | = 2 | 1 | = | 2| =/= | 2 |

| 2 | | 1 | | 2 | | 4| | 1 |

Page 24: January 22

21. There exist scalars a and b such that this matrix has rank 3.

| 0 1 a || -1 0 b || -a -b 0 |

False: | 0 1 a | | -1 0 b | | 1 0 -b | | 1 0 –b | | 1 0 –b |

| -1 0 b |~| 0 1 a |~| 0 1 a |~| 0 1 a |~| 0 1 a ||-a -b 0 | | -a –b 0 | |-a –b 0 | | 0 –b –ab | | 0 0 0 |

The Row Canonical Form has exactly 2 non zero rows.

Page 25: January 22

22. If V and W are vectors in R^4, then V must be a linear combination of V and W.

True. V = 1 V + 0 W.

Page 26: January 22

23. If U, V, and W are nonzero vectors in R^2, then W must be a linear combination of U and V.

False. U = | 1 | V = | 1 | W = | 0 | | 0 | | 0 | | 1 |

Page 27: January 22

24. If V and W are vectors in R^4, then the zero vector in R^4 must be a linear combination of V and W.

True: 0 V + 0 W = 0.

Page 28: January 22

25. If A and B are any two 3x3 matrices of rank 2, then A can be transformed into B by means of elementary row operations.

False. Since Row Canonical Forms are unique, we simply display two rank two 3x3 matrices in Row Canonical Form.

| 1 0 0 | | 0 1 0 | | 0 1 0 | | 0 0 1 | | 0 0 0 | | 0 0 0 |

Page 29: January 22

26. If vector U is a linear combination of vectors V and W, and V is a linear combination of vectors P, Q and R, then U is a linear combination of P, Q, R, and W.

True: U = aV + b W and V = cP+dQ+eR, then U = a(cP+dQ+eR)+bW = acP+adQ+aeR+bW.

Page 30: January 22

27.A system with fewer unknowns than equations must have infinitely many solutions or none.

False: x = 1 has exactly one solution y = 1 x+y = 2

Page 31: January 22

28. The rank of any upper triangular matrix is the number of non zeros on the

diagonal.

False: | 0 1 0 0 | | 0 0 1 0 | | 0 0 0 1 | | 0 0 0 0 |

This matrix has rank 3 and no non zeros on the diagonal.

Page 32: January 22

29.If the system AX = B has a unique solution then A must be a square matrix.

False. | 1 0 0 | | x | | 1 | | 0 1 0 | | y | = | 1 | | 0 0 1 | | z | | 1 | | 1 1 1 | | 3 |

This has a unique solution and A is not square.

Page 33: January 22

30.If A is a 4x3 matrix, then there exists a vector B in R^4

such that the system AX = B is inconsistent.

True. The system

| 1 0 0 | 0 | | 0 1 0 | 0 | | 0 0 1 | 0 | | 0 0 0 | 1 |

is inconsistent. If we use inverse elementary row

operations, we can backwards transform this system to

any system [ A | B ] where A is a 4x3 matrix with rank 3.

The backwards transformed system will still be

inconsistent.

Page 34: January 22

31.If A is a 4x3 matrix of rank 3 and AV = AW for two vectors V and W in R^3, then the vectors V and W must be equal.

True: If A V = A W, then A(V-W) = 0. Since A has rank three,

the only solution to AX = 0 is X = 0. Thus V-W = 0 and V = W..

Page 35: January 22

32. If A is a 4x4 matrix and the system

| 2 |A X = | 3 | has a unique solution, | 4 | | 5 |then the system AX = 0 has only the solutionX = 0.

True. If any system has exactly one solution, thenthere will be no parameters. Thus every solution isunique.

Page 36: January 22

33. If vector U is a linear combination of vectors V and W, then W must be a linear combination of U and V.

False: | 1 | | 0 | | 2 | 2 | 0 | + 0 | 1 | = | 0 | | 0 | | 0 | | 0 |

v w u

2V+ 0 W = U, but W is not a linear combination of U and V

.

Page 37: January 22

| 1 0 2 |34 If A = [ U V W ] and RREF(A) = | 0 1 3 | | 0 0 0 |

then the equation W = 2U + 3 V must hold..

| -2 |True. The vector | -3 | must be in the null space of A | 1 |

So -2 U -3 V + W = 0. Thus W = 2 U + 3 V.

Page 38: January 22

35.If A and B are matrices of the same size, then the formula rank(A+B) = rank(A) + rank(B) must hold.

False

| 1 0 0 | | 0 1 0 | = | 1 1 0 | | 0 1 0 | + | 0 0 1 | | 0 1 1 |

The rank of all three of these matrices is two.

Page 39: January 22

36.If A and B are any two nxn matrices of rank n, then A can be transformed into B by elementary row operations.

True. Since A and B are both equivalent to the identity matrix I, we can transform either one of them into the other.

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