january 25, 2010
DESCRIPTION
January 25, 2010. Do Now Take out your study guide. Matching Set 1. 1. b 2. c 3. f 4. g 5. d 6. a 7. e 8. h. Matching Set 2. 1. G 2. F 3. C 4. E 5. A 6. B 7. D. Set 3. 11. D 12. C 13. A 14. B. Fill in blank Set 1. 1. repel, attract 2. friction, conduction, induction - PowerPoint PPT PresentationTRANSCRIPT
January 25, 2010
Do Now Take out your study guide
Matching Set 1 1. b 2. c 3. f 4. g 5. d 6. a 7. e 8. h
Matching Set 2
1. G 2. F 3. C 4. E 5. A 6. B 7. D
Set 3
11. D 12. C 13. A 14. B
Fill in blank Set 1
1. repel, attract 2. friction, conduction, induction 3. increase 4. parallel 5. series
Fill in blank Set 2
1. Newton’s third law. 2. terminal velocity, projectile 3. centripetal force 4. static friction 5. air resistance 6. Newton’s second law 7. momentum
Fill in blank Set 2
8. conservation of momentum 9. Gravity 10. weight 11. distance 12. Newton 13. static friction 14. Sliding friction
Multiple Choice Questions
1. E. 2. B 3. B 4. E 5. D 6. D 7. F 8. A 9. E 10. B 11. G 12. H
True or False
1. F 2. T 3. F 4. T 5. F 6. T 7. F 8. T 9. F 10. T 11. F
Determine Types of matter
1. Hom 2. C 3. E 4. Het 5. E 6. Het 7. Hom 8. C 9. E 10. Hom
Open Ended Questions
1.
2. V = IR = 10 x 7 = 70 V 3. I = V/R = (7x1.5)/5 = 2.1 A 4. I = P/V = 90/(4x1.5) = 15A 5. V = P/I = 3400/18 = 188.8 V 6. W = Fxd = 100 x 1 = 100 J
7. P = W/t = 1500 / 30 = 50 W 8. To lift the first object, the kinetic
energy is ½ 2kg x 22=4 J To lift the second object, the kinetic
energy is ½ 4kg x 32=18 JTherefore, the second object has
more kinetic energy.
9. The potential energy for the first object is mgh = 2 x 9.8 x 10 = 196 J
The potential energy for the first object is mgh = 4 x 9.8 x 10 = 392 J
Therefore, the second object has more potential energy.
Corrections
10. Calculate the momentum of a 100-kg football player, a fullback, moving at a velocity of 3.5 m/sec.
Momentum = mass x velocity = 100 x 3.5 = 3500 kg m/sec
10b. Calculate the acceleration of a 10 kg mass when a 40 N force is applied to it. Acceleration = F/m = 40/10 = 4 m/s2
11. Thickness of one business card is
1.95 cm / 62 = 0.031 cm
12. Mass of one staple is
7.2 g / 323 = 0.02 g