HAf FA IZ;AH Billogy I'aper 3 li{{ell Scorr

7,1 MASTERING GROUP 1 SKILLS

SAMPLE ANSWERS

GROUP 1

sctENcE PROCESS SKTLLS (SPS)

SP$ 3- Measuring and Using Numbers

SPS 1- Ohserving

SPS 4- trnferring ar Making an Inference

SPS 9 - Defining Operationally

HAFFA IZZAH Biotogy papsr3 Exceil score

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7.1.1 SAMPLE AN9WERS FoR EXERGISES GROUP I { sP$ 3.I.4 and g} ;

QUESI/ON 1:CHAPTER 3 : MOVEMENI OF SUBSTANCES AcRoSS THE PLASMA

MEMBRANE

3A. Study the effect of isotonic, hypotonic, and hypertonic solution onanimal cell or plant cell

(a) $tudents should be abte toglven:

GroupP:13.0cmGroup Q :11.4 cmGroupR:9.5cmGroupS:8.6cm

1- Obseruing

4- Inferring or Making an lnference(b) (i) Students should Oe aOte t(b) (ii) students.should be able to state any two inferences which conlsponalo*leobservationsconectly. ' - :-'l

Sample answer:

SPS 1 Observations SPS4 lnferenceegbeervafion Iln 0% of sucrose solution, the finallength of the potato discs after beingimmersed is 13.0 crn.

lnference 1The final length of potato discs incrcasebecaase the water molecules from thedistilled water diffuse into the cell sap of thepotato discs by osmosis.

ebseruation 2ln 370 of sucrose solution, the finallength of the potato discs after b€ingimmersed is 1 1.4 cm.

lnference 2The final length of potato discs increasebecaase the water molecules from the 3%of sucrose solution diffuse into the cell sapof tfre potato discs by osmosis

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IIAFFA IZZAH Biotogy Paper J Erc€$ Score

| !n s.. zo -of.

sucrose sdution, the final I me Rnat length of potato discs does not I

I length of the potato discs after being I change because the rate of diffusion of I

I lmmersed is 9.5 crn. I water molecules into the cell sap is the I

I I same as the rate of diffusion of water I

I I molecules out of the cell sap. IrtI

lfn t9 7o-of sucrose solution, the final lrnernal tength of potato discs decrease I

I length of the potato discs afier being I because the water molecules diffuse out I

I immersed is 8.6 cm. j from the cell sap of the potato discs to the II | 15 % of sucrose solution by osmosis.

Iltl

$P$ 9 - Defining Operationally

3 Students should be able to descdbe theinfurences

Sample answer:

Osmosis is the movement of water molecules from distilled water into the cell sap of potatodiscs through the plasma membrane of potato Jiscs anO increase its length .

or

osmosls is the movement of water molecules from the cell sap of potato discs into15 % of sucrose solution through the plasma membrane of potato discs anddecrease its length.

AAFFA IZZAH Biohgy paper 3 Exceil score

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38' Study the movement of substances across the semi permeabremembrane

sPS 3- Measuriig aiiTiin$

Time (min) The rise in the sucrose soiili6n'iEGt l6ij

SPS 1- ObservingSPs4-tnterri@

Students snostudents shourd be abre to state any tr"o i"i"*""."

"nich correspond to theobservations correclly.

I ObservationG

At first 10 minutes, the 30o/o SUCToS€ solution levelis 4.5 ml

The level of sucrose solution in the scaled glass tubeincrease because at the tenth ,iiil,j", -,i"tl, vrior""ut""

move .from distilled water.to tfre gO -"/"

s,iiose"sofutionthrough the Visking tubing due d;.;;#p;;;;;Observation 2

At 20s minutes, the 30 %sucrose solution level is9.5 ml

IT-l:*l of sucrose sotution in the scated gtass tuberncrease because at the twentietr minute, wllr"rioleculesmove from distified water.to tn" S0;;'suliise'sofutionthrough the Visking tubing due to o"ro"i" pioJ"lrl

Observation 3

At 30h minutes, the 30 %sucrose solution level is9.9 ml

lnterence

IT-!y{ of sucrose solylign in the scated stass tube::i:jT^:yuse at the thirtieth minute,

-;;ier"iolecute"move from distiued water.to tn" Co-"2"';il;'"ffiifi;through the Visking tubing due 6;.;;.i" p;;"";

llAFFA, IZZAH Biolagy pep€r 3 Excelt score

sPsi-@3 Siudents should be able to describe tha

inferencee

Sample ans\/er:

Osmosis is a process where water molecules move from the distilled water to the 30 yosucrose solution through the Visking tubing and increase the level of sucrose solution in thescaled glass tube

or

Osmosis is a process where water molecules enter the Visking tubing at the tenth minute /the twentieth minute / the thirtieth minute and the level of sucroie solution in the scaled glasstube is raised at 4.5 ml i 9.5 ml and 9.9 ml.

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3C. Study thE effect of isotonic, hypotonic, and hypertonic solution onanimal cell and plant cell

SCOre I Sample answensSPS 3- Measuring and Using Numbers

3 Studenls should be able to record the finat reading Uy using thE?ffiEtusgiven:

Sucroseconcentration (o/o)

Volume of the solution in the visking tubeafter 15 minutes (ml)

10 't7.0

30 't8.0

50 20.0

SPS 1- Observing

SPS 4- lnferring or Making an lnfeience3 (b) (i)

(b) (ii)Students should be ableto state anytwo o@students should be able to state any two inferences which coriespond to theobservations correclly.

INAFFA IZZAH Biology paper 3 Erceil Scqre

Ob*rvation 1

At first 10 minutes, the 30% sucrose solution levelis 4.5 ml

It^l:y"t. of sucrose sotution in the scatd glass tuberncrease because at the tenth minrte, -raGr omolecules

move from distified warer. to tne io -ii"

;;;;* sotutionthrough the Viskins tubing due 6 il;#fi;;.Obeervation7

At 20s minutes, the 30 %sucrose solution level is9.5 ml

lnferenceThe level of sucrose soluticin in the scaled glass tube::r_,"^"::^f ":,:::_1jth".t*"nti"tiirnin-rtJlirr'ror""rr*"move Jrom distiued water.to the 30t;'s;;;-#Hffi;throush the Visking tubing due tJ

".,i1*. prJ[E.

Obseruation 5

At 30m minutes, the 30 %sucrose solution level is9.9 ml

IT_!"-"t of sucrose solution in the scaled gtass tuberncrease because at the thirtietn rinute,-wif,r"moleculesmove .from distified water. to tf," aO-"rt' ;;;;* sorutionthrough the Visking tubing due d ;;;#fi;:;

sPse_D@i",#:1,:""J"rrd

be abre,o o"

Sample answer:

osmosis is a process of water molecules movement from distilled water into loyol 30o/ol 5oo/oorsucrose sor ution throush th" ;ilG;;#iv'J"',o o"i" il-il;;;;;=ir,J.!ir" or rhe viskins

+IAFFA, IZZAH Btotog5r paper3 Erce[S{ore

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3D' Study the effect of isotonic, hypotonic, and hypertonic sorution onanimal cell and plant cell

and Using NumbersStudents

"nor'O *

given;

Solution (M) Final mass of potato striD (q)Distilled water 64.0

Sucrose 0.2 58.0

Sucrose 0.4 52.0

Sucrose 0,6 36.0

Sucrose 0.8 32.0

SPs4-tnferringffi(b) (i) Students s(b) (ii) students shourd be abre to state

"ny t*o infeiences which conespond to the

ln distilled waler, the finalmass of the potato stripafter being immersed is 64

The final mass of potato strip increase iecause thewater molecules from the distilled water diffuse into thecell sap of the potato strip by osmosis.

Obcervation 2ln 0.2 M sucrose solution,the final mass ofthe polatostrip afrer being immersedis58g

The final mass of potato strip increase because thewater molecules from the 0.2 M sucrose solution diffuseinto the cell sap of the potato strip by osmosis.

Observation 3ln 0.4 M sucrose solution,the final mass of the potatostrip after being immersedis52g

The final maes of potato strip increase because thewaier molecules from the 0.4 M sucrose solution diffuseinto the cell sap of ihe potato strip by csmosis.

IIAFFA IZZAH Biotogy paper 3 ExceI Srore

ln 0.6 M sucrose solution.the final mass of the pcilaiostrip aftor being lmm6rsedis36g

The-ffnal.maes of poqto strip decrease Dscause thewater moteortes from tg oeti sap oiine-poiAo stripdiftuse out to the 0,6 M sucrqe sOuiion Uv osr[JJs.

ln 0.8 M sucrose solution,the final mass of lhe potatostrip after being immirsedis 32 g"

The-flnal.mass of poQto sbip decru*ee becauss theuater motecrutes fronr 1e f,ii l"p,;ane-ilLto sfiipdiftuse out to the 0.9 M sucrose soruiion Ov olrilGs.

osmoeb is the movernent of water mdecules ftorn distilred waterr o.2M ra.4M sucross#H::ji[ $:S]

sap or potato strrp n.ri-r,'i# pr"sr;;ild;; oi t*o ,o,o "nu

9p9rl" is the movemel{y3!"r moeues%m the cefl sap of potab strip into3;..K1;1$iucrose

sorution tt;;wh th;6,#'memn.anetii fifiIii& "no

[lAFfA lZZAll Biotogy prperJ Exceilscore

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CHAPTER 4 ,

44. :gg.rl"

effect of substrate concentration on the rate of enzyme

Percentage concentration bf_ albumen gusDension (o/o'l

rme taken (min)

10 7.0

15 10.0

12.5

SFS 1- Observ@ng or Making an inference

s.houf{ be aOte fo saG any tvrosv,s ru oHri any rwo ooseryauons correcily.:l{T!.,:l!{d be abte to srare

"ni t*o inr"i"n."J'*ni"n conespond to the

Albumen suspension wtrich is cloudy atconcentration 10 o/o furns clear after 7minutes.

Because albumen substrate has beenhydrolysed by pepsin enzyme within thetme reaction

Albumen suspension which is cloudy atconcentration 20 o/o tums clear afier 10minutes,

Because albumen substrate has beenhydrolysed by pepsin enzyme within thetime reaclion

Albumen suspension which is cloudy atconcentration 30 o/o turns clear after 12.Sminutes.

Albumen suspension at 1Oolo concentrationtake shorter time to turns clear cornpare to

Because albumen substrate has beenhydrolysed by pepsin enzyme within thetrme reaction

The time taken in albumenconcentration is faster because

HAFrA IZZAH Biotog], paperJ Excellscore

Students.nouta U

inferences

Sample answer:

Elame able to hydrolyse albumen suspension which is cloudy to tums clear and the rate ofenzyme reaction is affected by concentiation of atOumen suspension.

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.HAPTER z : study the content of oxygen and carbon dioxide in inharationair and exhalation air -

3- Measuring anAZ;frtorecordtneRna@

Length of air cotum@)

SPS 1- ObservingsPS4-tnferr@

(b) (i) Students(b) (ii) students shourd be abre to rr.t. ;;i t;;;;;;*. which correspond to theobservations correclly.

For activity type X, the length of aircotumn after treatment with KOH

The length of air column in J-tube decreaseiecause KoH solution absorb carbon Ji"rio"

"i"i

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HAIFA IZZAH Biology paper 3 Excrlt Score

For activity type Y, the lengith of aircolumn after treatment with KOHsolution is 6.0 cm.

The length of air column in J{ube decreasebecause KOH solution absorb carbon dioxide afterthe treatment.

Ob8ervation 3For activity type Z, the length of aircolumn after treatment wilh KOHsolution is 5.7

lnferonceThe length of air column in J-tube decreasebecause KOH solution absorb carbon dioxide afterthe treatment.

SPS 9 - Defining Qperationally

3 Studentsshouldbeabletodegcribothetermofexnaleoffiinferonces

Sample answer:

Exhaled air contain carbon dioxide gases that causes the length of air column in J-tubedecrease after it has being treated with KOH solution.

fft or.rlo,"CHAPTER 4 : CHEMICAL GOMPOSITTON OF THE CELL

48. Study the effect ofsubstrate concentration on the rate of enzymereaction

Score answerasuring and Using Numbers

3 (a) Students should be able to record the final reading by using thegiven:

apparatus

Concentration of starch

solution (%)

Time taken for iodine solution

remain unchanged

0.50 12s

1.00 16s

1.50 18s

2.OO 25s

SPS 1- Observing

SPS 4- lnfercing or Making an lnference3 (b) (i) Students should be able to state any two observations coneclly.

(b) (ii) Students should be able to state any two inferences which correspond to theobservations conectly.

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HAFFA IZZAI{ Biology l,aper 3 Exceil Score

0.5 o/o starch solution is hydrolysed fasterthan 1.007o starch solutioi., #or""-tir"nurnber of starch molecules in 0.50ol" staichsolution is lesser than in 1.00% starchsolution.

At.O. 507o /1 .00o/ol1.So/o /2.00 o/o starchsolution, the time taken for the colour ofiodine solution to remain unchanged is12116118n5 seconds.

Because starch substrate has beenhydrolysed by amylase enzyme within thetime reaction.

The time taken for the iodine solution inthe 0. 50% starch solution to remainunchanged is shorterthan 1.00% starchsolution.

thetermotenzymffi

Enzyme is a substance that hydrolyses the starch substrate to maintain the colour of iodinesolution and the rate of enzyme reaction arecte<j ov the concentration of the starch solution.

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CHAPTER 7 : Carry out an activity to ehow aerobic respiration.

$ Ps 3- u easuii{iiiE€ii|should be able to record thG readin g ry ustng-thEZppEEiG

Temoerature ocHeiqht. cm

20 2.630 3.940 4.O50 2.5

ng or Making an lnlerenceStudents snoutOstudents should be abre to state any tno inr"rencei nirri"h correspond to theobservations correctly.

1?

HAFFA IZZNI Biotogy paper 3 fxcelt Score

Sample answer:

should be able toobservation + inferencee

Sample answer:

Respiration in yeast is an activity of yeast which caused the height of coloured liquid in themanometgr increase and the rate of respiration is affected bv the temoerature

$PS I Observations SPS 4 lnferencesobsewataon tWhen the temperature of water bath is20oc , 30 "c I 4AoC t 50 oc

, the height ofcoloured liquid in the manometer is 2.6cm/3.9 cm/ 4.0 oml 2.5 cm.

lnference IThe height of coloured liquid in themanometer increase because yeast respireaerobically.

gbaeryation 2At 40'C the height of coloured liquid in themanometer incrsase more than theheight at 30"C.

lnference 2The rate of respiralion of yeast is higher at40"C than lhe rate of respiration of yeast at30"C because 40oC is a optimumtemperature for the respiration of Veast.

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CHAPTER 10 : study the effect of air movement on the rate of transpiration.

the term of respiration in yeast based on

Score anawetasPs 3- uring and Using Numbers

3 (a) should be able to record the final reading Oy uslng ihe apparatus

SPS 1- Observing

SPS 4- lnferring or Making an tnferenee3 (b) (i) students shoutd be able to state any two ob@

(b) (ii) students should be able to state any two inferences which coriespond to theobservations correc.ily.

Sample answer:

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HAFFA IZZNI Bioto$/ paper I Exceil Score

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utudents should be able to desCribelhEGrriiiinferences

Sample answer:

Transpiration is the process rosing water in form of water vapour from the barsam prantthroush reaves and is arrected ov-air.r"ni aii "Gj';il";;ilt "i;il U#-ili*""traveled by the air bubbte in the tapillary tr-u" iii ,iirt"r.

CHAPTER 6 : Determine the energy value in food sample

Students stroutC Oe aEtelo neEorO-IG reading by using tfie affiEiui

lnitial temperature = 2g-C._---i

Peanut 39.0

(o) (') t,uo"i(b) (ii) students,:::*::^::'" to ,tiG ;;i r,;; iiiJ,ln.u. which conespond to the

HAFFA IZZAH tliotogy pap€r J Ercelt Score

Sample answer:

Students should be able toinferences

Sample answer:

Energy value is quantity of heat / energy (B4J) released by ,l g of white bread when it wasburnt completely to increase the temperature of 20ml/ ZO ! witer by 5 "C.

the term of energy value based on the

3- Measuring

should be able to record the final reading Uy using the apparatus

White cloth Black cloth multicolouredoafterned cloth

Black 6 0 1

White 0 7 4

Yellow 2 2 3

Red 1 1 1

green 1 0 1

4- lnferrlng or an lnference

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CHAPTER 15 ; study the effect of colour camouflage in the survival of aspecies through analogy

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SPS t Obeervations SPS 4 lnferencesObgervatlon 1

The final temperatur€ of water after whitebread / peanut has been bumt is 34 oC /390C.

lnference IPeanut releases/produces a lot of energy/heat.

gbservafion 2The final temperature of water for peanutis higher than white bread.

lnference 2Peanut releases/produces more energy/heat compared lo white bread.

HATFA IZZAH Biotogy paper 3 Exceil Score

(b) (i) Studen,t(b) (ii) students shourd be abre to state;;; n;; iii"r"n"r* which correspond to theobservations correcily.

When the white cloth is used, thenumber of button taken are 0white,6 black, 2 yellow, 1 green

More buttons of a different colour are picked whenthe coJours between the buttons

""J tf.t-" tf"tn'"r"

very distinct.

When the black cloth is used, thenumber of button taken are 7white, 0 black, 2 yellow, 0 greenand 1 red.

More buttons of a different colour are picked whenthe colours between the buttons ""J

irr" tr"tn'"i"very distincl

When the multicoloured patternedcloth is used, the numbei of buttontaken are 4 white,l black, 3 yellow,

More buftons of a different colour are picked whenthe colours between the buttons ""J

tfr_.J tf"tn'"i_very distinct

When the white cloth is used, themost number of button taken are

The difference in colours between the wtrite clothand the black button are so obvious. .

sPs9- oetiningopix@urudents shoutd be aote to oeecliuElrreleriliiinferences

Sample answer;

|gx':|ilT:,i"?l"j:Tj::,T::l1li:Ily which buttons that represent organisms has the;:ffi"i;',.H#:ijE;,";",.:f:fi:tt, urat iepresenl;;j;#illiJffiH"','T5'p,:Jl&"$in"

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HAFFA IZZAH Biologli paper 3 Exc€ll Score

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CHAPTER 9 : Study the air pollution level from different environments

Score San answeiaSPS 3- Measuring and Using Numbers

3 (a) should be able to record the using the apparatus

SPS 1- Observing

SPS 4- lnferrlng or Making an lnference

3 (b) (i) Students should be able to state any two observations correc,tly.(b) (ii) Students should be able to state any two inferences which conespond to the

observations conectly.

Sample answer:

lThefinal timeforsampleof waterK/L/M lThis shows the presence and the level of I

I to complete decolourise the methylene I dissolved orygen in the waler sample. I

I blue solution is at 12.15 pn I 12.32 pm I I I

11520m I ItttlObservation2 llnferencez I

I Ttre finat time of sample water K to i tne Rnat time of sampte water K ic faster i

I complete decolourise the methylene blue I to complete decolourise the methylene due I

I solution is faster than the final time of I solution compare to sample water M I

I samplewater M. I because there is less amount of dissolved i

| | oxygen in water sample K than in M. I

SPS 9 - Defining Operationally

3 Students should be able to describe the term of BOD based on the observation +inferences

Sample answer:

BOD refer to high/ low concentration of dissolve oxygen in different water sample that takes alonger/shorter time to complete decolourise the methylene blue solutions.

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