law of conservation of reciprocal mass -...
TRANSCRIPT
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Reciprocal
Law of Conservation of
Mass
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Thank you for your purchase. I hope
you enjoy the Law of Conservation of
Mass Reciprocal Learning Activity! It
includes 6 student handouts and
teacher directions on how to
implement this teaching strategy into
your classroom. Please take the time
to look over my Copyright and Terms
of Use on the following page.
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DIRECTIONS FOR USE
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Elements # of atoms
in Reactants
# of atoms
in Products
Carbon (C) 12 2
Hydrogen
(H) 5 5
Oxygen (O) 4 4
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Law of Conservation of Mass wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww0 Player A Questions
1. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
P4 + 3O2 ⟶ 2P2O3
2. In the equation below, what is the mass of the
products?
2H2 + 2Cl2 ⟶ 2HCl
65 g + 35 g ⟶ _______ g
3. An incomplete chemical equation is given here.
__HCl + __Na2CO3 ⟶ __H2CO3 + __NaCl
Which set of numbers, placed in the blanks as the
coefficients, will balance the equation shown ?
A. 2, 2, 1, 1 C. 2, 1, 1, 2
B. 2, 1, 2, 1 D. 1, 2, 1, 2
4. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
2Al + 4HCl ⟶ 3H2 + 2AlCl3
5. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
2SnO2 + 4H2 ⟶ 2Sn + 4H2O
6. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
4Al + 3O2 ⟶ 2Al2O3
7. Which of the following equations is balanced
and following the law of conservation of mass?
A. 2HClO ⟶ 2H2O + 2Cl2O
B. CuO + 2HCl ⟶ 2CuCl2 + H2O C. MgCl2 + 2NaF ⟶ MgF2 + 2NaCl
D. 2C2H2 + 5O2 ⟶ 4CO2 + 2H2O
8. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
NH3+ 2O2 ⟶ NO + H2O
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Player B Answers
1.
This equation is following the Law of Conservation
of Mass because it has the same number of atoms of
each element on both the reactant side and product
side of the chemical equation.
2. A. N2 + 3H2 ⟶ 2NH3
A. both sides of the equation have 2 atoms of nitrogen (N) and 6 atoms of hydrogen (H)
B. The reactants have 2 atoms of hydrogen (H), but the product side has 4 atoms of hydrogen.
C. The reactants have 4 atoms of silver (Ag), but the product side has 2 atoms of silver.
D. The reactants have 2 atoms of nitrogen (N), but the product side has 1 atom of nitrogen.
3. 25 grams
The mass of the reactants must equal the mass of the
products. Set up an equation to solve for the missing
variable.
x + 15 = 40 and solve for x
25 + 15 = 40
4.
This equation is NOT following the Law of Conservation of Mass because it doesn’t have the same number of atoms of chlorine (Cl) on both sides of the chemical equation.
5.
This equation is NOT following the Law of
Conservation of Mass because it doesn’t have the
same number of atoms of chlorine (Cl) on both sides of
the chemical equation.
6. Location B. By adding a number 2 in location B, this will allow you to have 4 oxygens (O) on both the reactant and product side of the equation.
A. If you add a 2 in location A, you will have too many carbon (C) atoms on the reactant side of the equation. C. If you add a 2 in location C, you will have too many carbon (C) atoms on the product side of the equation. D. You cannot add or change subscripts in a chemical equation, so location D will not work. By doing this, you would completely change the substance.
7.
This equation is following the Law of Conservation
of Mass because it has the same number of atoms of
each element on both the reactant side and product
side of the chemical equation.
8. This equation is NOT following the Law of
Conservation of Mass because it doesn’t have the
same number of atoms of oxygen (O) on both sides of
the chemical equation.
Elements # of atoms in # of atoms in
Nitrogen (N) 2 2
Hydrogen (H) 6 6
Elements # of atoms in # of atoms in
Potassium (K) 2 2
Chlorine (Cl) 4 2
Elements # of atoms in
Reactants
# of atoms in
Products
Carbon (C) 12 12
Oxygen (O) 26 14
Hydrogen (H) 24 24
Elements # of atoms in
Reactants
# of atoms in
Products
Carbon (C) 2 2
Hydrogen (H) 6 6
Oxygen (O) 4 7
Elements # of atoms in # of atoms in
Nitrogen (N) 4 4
Oxygen (O) 2 2
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Law of Conservation of Mass wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww0
1. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
N2 + 3H2 ⟶ 2NH3
2. Which of the following equations is balanced
and following the law of conservation of mass?
A. N2 + 3H2 ⟶ 2NH3
B. H2 + O2 ⟶ 2H2O C. 2Ag2O ⟶ Ag2 + O2 D. N2 + H2 ⟶ NH3
3. According to the Law of Conservation of Mass,
how many grams of hydrogen are needed for this
reaction?
2H2 + O2 ⟶ 2H2O
____ g + 15 g ⟶ 40 g
4. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
2K + 2Cl2 ⟶ 2KCl
5. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
12CO2 + 12H2O ⟶ 2C6H12O6 + O2
6. An unbalanced equation is shown here. Below it is a diagram with four locations in the unbalanced equation labeled. The equation could be balanced by adding a number two (2) in which location? A, B, C, or D?
7. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
2H2 + 2O ⟶ 2H2O
8. Count the atoms on both sides of the equation
to determine if this chemical reaction is following
the Law of Conservation of Mass or not. Show all
work.
C2H6 + 2O2 ⟶ 3H2O + 2CO2
Player B Questions
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Player A Answers
1.
This equation is following the Law of Conservation
of Mass because it has the same number of atoms of
each element on both the reactant side and product
side of the chemical equation.
2. 100 grams
The mass of the reactants must equal the mass of the
products. Set up an equation to solve for the missing
variable.
65 + 35 = x and solve for x
65 + 35 = 100
3. C. 2, 1, 1, 2 By plugging these numbers into the blanks as coefficients, you will get the following atom counts:
4.
This equation is NOT following the Law of Conservation of Mass because it doesn’t have the same number of atoms of hydrogen (H) or chlorine (Cl) on both sides of the chemical equation.
5.
This equation is NOT following the Law of
Conservation of Mass because it doesn’t have the
same number of atoms of chlorine (Cl) on both sides of
the chemical equation.
6.
This equation is following the Law of Conservation
of Mass because it has the same number of atoms of
each element on both the reactant side and product
side of the chemical equation.
7. C. MgCl2 + 2NaF ⟶ MgF2 + 2NaCl
A. The reactants have 2 atoms of hydrogen (H), but the product side has 4 atoms of hydrogen.
B. The reactants have 1 atom of copper (Cu), but the product side has 2 atoms of copper.
C. both sides of the equation have 1 atom of magnesium (Mg), 2 atoms of chlorine (Cl), 2 atoms of sodium (Na), and 2 atoms of fluorine (F).
D. The reactants have 10 atoms of oxygen (O), but the product side has 8 atoms of oxygen.
8.
This equation is NOT following the Law of
Conservation of Mass because it doesn’t have the
same number of atoms of hydrogen (H) or oxygen (O)
on both sides of the chemical equation. Be careful on
the product side!! Oxygen is in 2 locations (on both
sides of the + sign) so you must add them together.
Elements # of atoms in
Reactants
# of atoms in
Products
Phosphorus (P) 4 4
Oxygen (O) 6 6
Elements # of atoms in
Reactants
# of atoms in
Products
Aluminum (Al) 2 2
Hydrogen (H) 4 6
Chlorine (Cl) 4 6
Elements # of atoms in
Reactants
# of atoms in
Products
Carbon (C) 12 12
Oxygen (O) 26 14
Hydrogen (H) 24 24
Elements # of atoms in
Reactants
# of atoms in
Products
Nitrogen (N) 1 1
Hydrogen (H) 3 2
Oxygen (O) 4 2
Elements # of atoms in
Reactants
# of atoms in
Products
Hydrogen (H) 2 2
Chlorine (Cl) 2 2
Sodium (Na) 2 2
Carbon (C) 1 1
Oxygen (O) 3 3
Elements # of atoms in
Reactants
# of atoms in
Products
Aluminum (Al) 4 6
Oxygen (O) 4 6
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A
C
E
G
B
D
F
H
Player A wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww0 Answer Sheet
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Player B wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww0 Answer Sheet
A
C
E
G
B
D
F
H
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