leakage impedance of transformer windings
DESCRIPTION
Leakage Impedance of Transformer Windings. Dept. Of Information Engineering – DEI University of Padova. Prof. Giorgio Spiazzi. Leakage Impedance of Transformer Windings. Ref.: - PowerPoint PPT PresentationTRANSCRIPT
Leakage Impedance of Leakage Impedance of Transformer WindingsTransformer Windings
Dept. Of Information Engineering – DEIDept. Of Information Engineering – DEI
University of PadovaUniversity of Padova
Prof. Giorgio SpiazziProf. Giorgio Spiazzi
Leakage Impedance of Leakage Impedance of Transformer WindingsTransformer Windings
• High Frequency induced effects on transformer High Frequency induced effects on transformer windingswindings
• Qualitative analysis of transformer winding Qualitative analysis of transformer winding leakage impedanceleakage impedance
• Quantitative analysis of transformer winding Quantitative analysis of transformer winding leakage impedanceleakage impedance
• Dowell curvesDowell curves• ExamplesExamples
Outline: Outline:
Ref.:Ref.:
P.L. Dowell, “Effects of Eddy Currents in Transformer Windings,” Proc. of IEE, Vol.13, No.8, August 1966, pp.1387-1394.
Simple Transformer Winding Simple Transformer Winding ArrangementArrangement
Secondary Secondary windingwinding
Primary Primary windingwinding
Isolation gapIsolation gap
Magneto-motive Force in the Magneto-motive Force in the Core WindowCore Window
m.m.f.m.m.f.(dc)(dc)
00
NIdH.f.m.mm
Magneto-motive Force in the Magneto-motive Force in the Core WindowCore Window
Secondary Secondary windingwinding
Primary Primary windingwinding
Isolation gapIsolation gap
m.m.f.m.m.f.(dc)(dc)
00
Leakage FluxLeakage Flux
The leakage flux in the core window causes The leakage flux in the core window causes eddy currents in the windingseddy currents in the windings
Leakage fluxLeakage flux
Power loss in the winding resistancePower loss in the winding resistance
Leakage fluxLeakage flux
Magnetic energy stored in the core window crossed Magnetic energy stored in the core window crossed by the leakage fluxby the leakage flux
Magnetic energy stored in the transformer leakage Magnetic energy stored in the transformer leakage inductanceinductance
Leakage FluxLeakage Flux
Skin EffectSkin Effect
High frequency currents in the conductor High frequency currents in the conductor generate a variable magnetic field that induces generate a variable magnetic field that induces
voltages and, consequently, currents. The voltages and, consequently, currents. The latter are directed in such a way to reinforce the latter are directed in such a way to reinforce the current flowing close to the conductor surfacecurrent flowing close to the conductor surface
DDPENPEN
JJREALREAL JJEQUIVALENTEQUIVALENT
DDWW
Current linesCurrent lines
DDPENPEN = skin depth = skin depth
Proximity EffectProximity Effect
• The current in a close path distributes The current in a close path distributes itself in such a way so as to minimize the itself in such a way so as to minimize the energy drawn from the source. energy drawn from the source.
PCBPCB
WW
++ ++ ++ ++ ++ ++ ++ ++ ++ ++
•• •• •• •• •• •• •• •• •• ••
Example: faced PCB tracksExample: faced PCB tracks
HF Current Distribution in HF Current Distribution in WindingsWindings
Inductor: single winding Inductor: single winding
........................
++++++
++++++
++++++
++++++
gg
FF FF
HF
Hg
g
F
H
The current concentrates The current concentrates on winding inner surfaceon winding inner surface
HF Current Distribution in HF Current Distribution in WindingsWindings
Transformer: single layerTransformer: single layerPrimary: 4 turns - 3A / Secondary: 1 turn - 12APrimary: 4 turns - 3A / Secondary: 1 turn - 12A
..
........
..............................
++++++
++++++
++++++
++++++
FF FF
++
..
++++++++++++++++++++++
....
..
The magnetic field is almost zero outside the The magnetic field is almost zero outside the two windings but is high between themtwo windings but is high between them
LF Current Distribution in LF Current Distribution in WindingsWindings
Transformer Transformer with multiple with multiple
layerslayers
PP11 PP22 SS33 SS22 SS11
Current Current homogeneously homogeneously
distributed inside distributed inside conductors conductors
W [J]W [J]
F=NIF=NI
Energy Energy densitydensity
[J/m][J/m]
LF Current Distribution in LF Current Distribution in WindingsWindings
Multiple winding transformer Multiple winding transformer with interleaved with interleaved
primary/secondary windingsprimary/secondary windings
PPaa PPbbSSbbSSaa
F=NIF=NI
Energy Energy densitydensity
[J/m][J/m] W [J]W [J]
Reduced leakage Reduced leakage inductance inductance
HF Current Distribution in HF Current Distribution in WindingsWindings
F=NIF=NI
PP22PP11SS33 SS22 SS11
Multiple winding transformer
Conductor thickness >> DConductor thickness >> DPENPEN
Magnetic field only between layers Magnetic field only between layers
HF Current Distribution in HF Current Distribution in WindingsWindings
F=NIF=NI
SS33 SS22 SS11
++.. .... ++++++
++
++
+1+1-1-1+2+2-2-2+3+3I=I=
Conductor thickness >> DConductor thickness >> DPENPEN
Secondary winding: 1ASecondary winding: 1A
Magnetic field only between layers : Magnetic field only between layers : different different currents induced on layer surfacescurrents induced on layer surfaces
Passive LayersPassive Layers
F=NIF=NI
SS33 SS22 SS11
++.. .... ++++++
++
++
+1+1-1-1+2+2-2-2+3+3I=I=
++++
++ ......-3-3+3+3
PP
Winding carrying zero current in a given Winding carrying zero current in a given instant instant
((e.g. one primary winding in a push-pull e.g. one primary winding in a push-pull transformer, one secondary winding in transformer transformer, one secondary winding in transformer
with center tapped secondary, EMI shieldwith center tapped secondary, EMI shield))
High losses! High losses!
Leakage ImpedanceLeakage Impedance
The leakage flux crossing a winding layer The leakage flux crossing a winding layer determines both its ac leakage resistance and determines both its ac leakage resistance and
inductanceinductance
When considering the leakage impedance due When considering the leakage impedance due to a particular layer, it is necessary to consider to a particular layer, it is necessary to consider the other layers of the windings insofar as they the other layers of the windings insofar as they
affect the flux in the layer being consideredaffect the flux in the layer being considered
Leakage ImpedanceLeakage Impedance
From the behavior of the From the behavior of the m.m.f. in a core window we m.m.f. in a core window we can say :can say :
The leakage flux distribution The leakage flux distribution across any layer depends only across any layer depends only on the current in that layer and on the current in that layer and the total current between the the total current between the layer and an adjacent position layer and an adjacent position of zero m.m.f.of zero m.m.f.
P1 P2 S3 S2 S1
m.m.f.m.m.f.(dc)(dc)
00
Winding portionsWinding portions
Leakage ImpedanceLeakage Impedance
For leakage impedance For leakage impedance calculation purposes we can calculation purposes we can consider the whole winding consider the whole winding subdivided in parts containing subdivided in parts containing each a position of zero m.m.f.. each a position of zero m.m.f.. Such parts will be termed Such parts will be termed “winding portions”.“winding portions”.
m.m.f.m.m.f.(dc)(dc)
00
Leakage ImpedanceLeakage Impedance
An intersection gap can be An intersection gap can be considered to be part of either considered to be part of either of the adjacent portions; thus, of the adjacent portions; thus, the leakage impedance due to the leakage impedance due to these gaps will be referred to these gaps will be referred to the primary if they are the primary if they are associated to a primary associated to a primary winding portion or to the winding portion or to the secondary if the gaps are secondary if the gaps are associated to a secondary associated to a secondary winding portion.winding portion.
m.m.f.m.m.f.(dc)(dc)
GapGap
00
Winding portionsWinding portions
Interleaved WindingsInterleaved Windings
A winding portion can contain a A winding portion can contain a half layer (if the corresponding half layer (if the corresponding winding section is composed by winding section is composed by an odd number of layers) an odd number of layers)
Pa PbSbSa
m.m.f.m.m.f.(dc)(dc)
00
Two cases: Two cases:
1)1) The winding portion contains The winding portion contains mm full layers full layers
2)2) The winding portion contains The winding portion contains mm full layers full layers ++ a a halfhalf layer layer
Frequency-Independent Components Frequency-Independent Components of Leakage Impedanceof Leakage Impedance
• Increasing the frequency Increasing the frequency will affect the current will affect the current distribution across each distribution across each conductor, but the total conductor, but the total net current will remain net current will remain unaltered. Consequently, unaltered. Consequently, the magnetic field H and the magnetic field H and its associated energy in its associated energy in the intersection gaps will the intersection gaps will be independent of the be independent of the frequency. frequency.
aa
uu gg
bb
00
Winding portionWinding portion
m.m.f.m.m.f.(dc)(dc)
Frequency-Independent Components Frequency-Independent Components of Leakage Impedanceof Leakage Impedance
• Hp:Hp:• Square section conductor having the Square section conductor having the
same section of circular onessame section of circular ones
• Average turn length Average turn length TT
• Uniform magnetic field in the core windowUniform magnetic field in the core window
22
a4
D
2
Da
DD aa
Leakage Inductance of Isolation Leakage Inductance of Isolation Gap g Gap g
aa
gg
bb
00
m.m.f.m.m.f.(dc)(dc)
Integer number Integer number mm of layers of layers
b
IN
b
ImNH 1p1
g
2
1gg
2
g0gIL
2
1VH
2
1W
NN = Number of turns per layer= Number of turns per layer
NNp p = Number of turns of the = Number of turns of the
whole winding portionwhole winding portion
gb
NL T
2p0
g
Tg bgV
Leakage Inductance of Isolation Leakage Inductance of Isolation Gap gGap g
aa
gg
bb
00
m.m.f.m.m.f.(dc)(dc)
Integer number Integer number mm of layers of layers ++ halfhalf layer layer
b
IN
2
1m
b
INH 1p1
g
2
1gg
2
g0gIL
2
1VH
2
1W
NNp p = Number of turns of the = Number of turns of the
whole winding portionwhole winding portion
gb
NL T
2p0
g
Tg bgV
Leakage Inductance of Gaps u Leakage Inductance of Gaps u Between LayersBetween Layers
aa
uu
bb
00
m.m.f.m.m.f.(dc)(dc)
Integer number Integer number mm of layers of layers
b
INpH 1
up
ppthth Gap Gap
ppthth Gap Gap
Tup buV
21upup
2up0up IL
2
1VH
2
1W
2T2
0up p
b
uNL
Leakage Inductance of Gaps u Leakage Inductance of Gaps u Between LayersBetween Layers
aa
uu
bb
00
m.m.f.m.m.f.(dc)(dc)
Overall inductance:Overall inductance:
1m
1p
2T2
0U p
b
uNL
1m1m26
mp
1m
1p
2
m2
11
b3
UNL T
2p0
U
u1mU (Total gap width)(Total gap width)
Leakage Inductance of Gaps u Leakage Inductance of Gaps u Between LayersBetween Layers
aa
bb
00
m.m.f.m.m.f.(dc)(dc)
Integer number Integer number mm of layers of layers ++ halfhalf layer layer
uu
2
1p
b
INH 1
up
ppthth Gap Gap
p = 1p = 1mm
Tup buV
21upup
2up0up IL
2
1VH
2
1W
2T
20
up 2
1p
b
uNL
Leakage Inductance of Gaps u Leakage Inductance of Gaps u Between LayersBetween Layers
aa
bb
00
m.m.f.m.m.f.(dc)(dc)
uu
m
1p
2T
20
U 2
1p
b
uNL
Overall inductance:Overall inductance:
1m21m212
m
2
1p
m
1p
2
1m2
1m2
b3
UNL T
2p0
U
muU (Total gap width)(Total gap width)
DC Winding InductanceDC Winding Inductance
Since the flux in the intersection gaps have Since the flux in the intersection gaps have already been taken into account, the energy already been taken into account, the energy associated to the flux crossing the conductor associated to the flux crossing the conductor layers of a given winding portion can be done layers of a given winding portion can be done considering the layers close to each other considering the layers close to each other without gaps. without gaps.
Being the current density constant at dc, the Being the current density constant at dc, the current and the associated magnetic field current and the associated magnetic field vary vary linearlylinearly with position x as indicated in the figure with position x as indicated in the figure (x=0 corresponds to the position of zero m.m.f.).(x=0 corresponds to the position of zero m.m.f.).
DC Winding InductanceDC Winding Inductance
a
h
b
HH
00 mhmh xx
dxdx
b
ImNH 1
max
xbh
INx
mh
HxH 1max
dvxH2
1dw 2
0
210w
21
32T
0
mh
0
T2
0
W
0
IL2
1
b3
hImN
2
1
bdxxH2
1dwW
Integer number Integer number mm of layers of layers
b3
hmNL
32T
00w
DC Winding InductanceDC Winding Inductance
Integer number Integer number mm of layers of layers ++ halfhalf layer layera
h
b
HH
00 xx
dxdx
2
1m
b
INH 1
max
(m+ )h(m+ )h1122
Same procedure, only Same procedure, only substitute m with m+1/2substitute m with m+1/2
32T
00w 2
1m
b3
hNL
DC Winding ResistanceDC Winding Resistance
a
h
b
Integer number Integer number mm of layers of layers
bh
mN
ah
mNR T
2T
0w
ab
NForm factor. It is equal to 1 Form factor. It is equal to 1 when the turns of the same when the turns of the same layer are close to each layer are close to each other.other.
DC Winding ResistanceDC Winding Resistance
The resistance of the The resistance of the winding portion is half of winding portion is half of the resistance of the the resistance of the winding section (made up winding section (made up by 2m+1 layers) having that by 2m+1 layers) having that portion as half sectionportion as half section
a
h
b
Integer number Integer number mm of layers of layers ++ halfhalf layer layer
2
1m
bh
N
ah
1m2N
2
1R T
2T
0w
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
• Only the flux crossing the winding layers is Only the flux crossing the winding layers is considered. considered.
• The current density inside each layer is calculated.The current density inside each layer is calculated.• The voltage developed across each layer is calculated The voltage developed across each layer is calculated
as the sum of a resistive component plus an induced as the sum of a resistive component plus an induced voltage due to the linked flux.voltage due to the linked flux.
• The total voltage across the winding portion is The total voltage across the winding portion is calculated summing the voltage across each layer.calculated summing the voltage across each layer.
• The leakage impedance of the winding portion is The leakage impedance of the winding portion is calculated whose real and imaginary parts represent calculated whose real and imaginary parts represent the leakage resistance and inductance, respectively.the leakage resistance and inductance, respectively.
ppthth layer layer
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
A generic layer A generic layer pp (p=1(p=1m) is m) is considered, and considered, and inside it, an inside it, an infinitesimal layer infinitesimal layer xx at position x (as at position x (as respect to the edge of respect to the edge of ppthth layer closer to the layer closer to the position at zero position at zero m.m.f.)m.m.f.)
a
h u g
b
x
0 x
0
m.m.f.m.m.f.(dc)(dc)
Integer number Integer number mm of layers of layers
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
Flux linking elementary Flux linking elementary layer layer x is x is bb++cc::
a
h u g
b
b c
pth layer
xdx
d cb
Bx T
x
0
dyybJ1pINb
1
b
iH
Magnetic field at position x:Magnetic field at position x:
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
a
h u g
b
b c
pth layer
NxjxJNV cbT
Voltage across pVoltage across pthth layer: layer:
VV is independent of x: is independent of x:
Ndx
dj
dx
dJN0
dx
dV cbT
dx
dj
dx
dJ cb
T
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
a
h u g
b
b c
pth layer
x
0
0 dyyJb
1pINj
dx
dJ
JJj
dx
Jd 202
2
j1D
j
PEN
0
xsinhQxcoshPJ Solution:Solution:
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
1pb
INQ
a
h u g
b
b c
pth layer
2
htanh1p
hsinh
1IN
bP
Coefficients:Coefficients:
Current Density DistributionCurrent Density Distribution
Current density inside pCurrent density inside pthth layer layer
xsinh1pxcosh2
htanh1p
hsinh
xcoshIN
bxJ
j1D
j
PEN
0
DDPENPEN = skin depth = skin depth
Normalized Current DensityNormalized Current Density
0
5
10
15
20
0 h
1°1° layer layer 2°2° layer layer 3°3° layer layer
ffss = 100kHz = 100kHz
JN(x) JN(x) JN(x)
ah
I
xJxJ
N
JN(x)30
10
20
00 h
Normalized Current DensityNormalized Current Density
3°3° layer layer
ffss = 10kHz = 10kHz
ffss = 50kHz = 50kHz
ffss = 100kHz = 100kHz
ffss = 500kHz = 500kHz
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
Voltage across pVoltage across pthth layer: layer:
NxjxJNdt
dNJNV
cbT
cbTp
VVpp is independent of x. is independent of x.
Thus, it is calculated at Thus, it is calculated at x = h:x = h:
NjJNdt
dNJNV chT
chTp
a
h u g
b
b c
pth layer
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
a
h u g
b
b c
pth layer
m
1pnnc
cc is the flux in all the is the flux in all the
winding layers beyond winding layers beyond the pthe pthth layer edge at layer edge at position x = h:position x = h:
x
0
0Tbcb dyyJ
b
1pIN
dx
d
dx
d
Let’s calculate the flux in Let’s calculate the flux in the generic pthe generic pthth layer: layer:
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
h
0
x
0
0T0T
h
0
x
0
0T
0
h
x
0
0T
0
bp
dxdyyJhb
1pIN
dxdyyJb
1pIN
dxdyyJb
1pINd
p
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
D2
1p
hb
IN20Tp
Total flux crossing Total flux crossing
ppthth layer: layer:
2
pmD
bh
IN
2
1nD
bh
IN
22
20T
m
1pn20T
m
1pnnc
Total flux linking pTotal flux linking pthth layer: layer:
2
htanhh2jDDD ir
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
2
Dpm1pM
bh
INVVV 22T
2
iprpp
Voltage across pVoltage across pthth layer: layer:
Current density at the edge of pCurrent density at the edge of pthth layer far from layer far from the position at zero m.m.f.:the position at zero m.m.f.:
D2
1pM
bh
INhJJh
hcothhjMMM ir
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
1mm3
DmM
bh
INVV 2T
2m
1pp
Total voltage across the winding Total voltage across the winding portion:portion:
Associated leakage impedance:Associated leakage impedance:
ww2T
2
w LjR1mm3
DmM
bh
N
I
VZ
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
R0w2r
r0ww FR1m3
DMRR
AC resistance:AC resistance:
L0w222
2ii
0ww FLhm
1mDM3LL
AC inductance:AC inductance:
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
m.m.f.
a
h u g
b
x
0 x
0
Layer (p+ )12
h/2
Layers 1 to m
Half layer
Integer number Integer number mm of of layers layers ++ halfhalf layer layer
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
• The overall leakage impedance associated to the integer The overall leakage impedance associated to the integer number m of layers is calculated.number m of layers is calculated.
• The leakage impedance of the half layer is calculated as The leakage impedance of the half layer is calculated as the ratio between its voltage Vthe ratio between its voltage V1/21/2 and current I. Being the and current I. Being the calculated impedances of each winding portion summed calculated impedances of each winding portion summed together, the contribution of the layer that is splitted into together, the contribution of the layer that is splitted into two parts (each half layer belonging to adjacent portions) two parts (each half layer belonging to adjacent portions) must be equally subdivided into the two portions.must be equally subdivided into the two portions.
• Consequently, the contribution of the half layer to the Consequently, the contribution of the half layer to the overall impedance of the winding portion is half the overall impedance of the winding portion is half the impedance of the full layer whose the considered half impedance of the full layer whose the considered half layer belongs to.layer belongs to.
Integer number Integer number mm of layers of layers ++ halfhalf layer layer
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
ww
22/1T
2
w
LjR
12
D1m6m4mmM12M6
bh
INZ
2
hcoth
2
h
2
hMjMMM i2/1r2/12/1
Integer number Integer number mm of layers of layers ++ halfhalf layer layer
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
AC resistance:AC resistance:
R0w
r2
rr2/10ww FR
6m12
D1m6m4mmM12M6RR
AC inductance:AC inductance:
L0w3
22
i2
ii2/10ww FL
2
1mh4
D1m6m4mmM12M6LL
AC Winding Leakage ImpedanceAC Winding Leakage Impedance
Such parameter represents the thickness of Such parameter represents the thickness of the winding layer, corrected by a form factor the winding layer, corrected by a form factor that depends on the turn separation in that that depends on the turn separation in that layer, normalized to the skin depthlayer, normalized to the skin depth
j1qj1D
hh
PEN
2
h
D
hq
PEN
hFF RR hFF LL
Normalized resistance and inductance:Normalized resistance and inductance:
Dowell CurvesDowell Curves
0.1 1 101
10
100
FR
q
1
1+1/2
2+1/2
3+1/2
4+1/2
2
3
4
Dowell CurvesDowell Curves
0.1 1 100.1
1
FL
q
1+1/2
1
Leakage Inductance CoefficientLeakage Inductance Coefficient
3
22
i2
ii2/1
222
2ii
L
2
1mh4
D1m6m4mmM12M6
hm
1mDM3
F
mm layers layers
mm ++ halfhalf layerslayers
22
iL
m h
DFLim
Example #1: Simple WindingExample #1: Simple Winding
Secondary Secondary windingwinding
b
DD11
uu1010 gg00
Primary Primary windingwinding
Example #1: Simple WindingExample #1: Simple Winding
• Primary conductor diameter AWG17: Primary conductor diameter AWG17: DD11 = 1.15mm = 1.15mm• Number of turns per primary layer:Number of turns per primary layer: NN11 = 12 = 12• Gap width between primary layers:Gap width between primary layers: uu1010= 0.2mm= 0.2mm• Gap width between prim. and sec.:Gap width between prim. and sec.: gg00 = 0.5mm = 0.5mm• Gap width between secondary layers:Gap width between secondary layers: uu22= 0.15mm= 0.15mm• Height of secondary turn:Height of secondary turn: aa22= 10mm= 10mm• Thickness of secondary layer:Thickness of secondary layer: hh22 = 0.6mm = 0.6mm• Core window height:Core window height: b = 14mmb = 14mm• Internal diameter of bobbin:Internal diameter of bobbin: DDcoil coil = 13.4mm= 13.4mm• Operating frequency:Operating frequency: ffss = 100kHz = 100kHz
Example #1: Simple WindingExample #1: Simple Winding
bb
aa11
aa22
hh11
uu11 gg hh22
uu22
Primary winding substituted by an equivalent squared Primary winding substituted by an equivalent squared cross section conductorcross section conductor
Example #1: Simple WindingExample #1: Simple Winding
aa11
aa22
hh11
uu11
gg hh22
uu22
2Da 11
= 1.019mm= 1.019mm
uu1 1 = u= u1010+D+D11-a-a11= 0.33mm= 0.33mm g = gg = g00+(D+(D11-a-a11)/2= 0.565mm)/2= 0.565mm
Example #1: Simple WindingExample #1: Simple Winding
• LLgg = 8.74 = 8.74HH• LLUU = 4.48 = 4.48HH• LLw0w0 = 21.01 = 21.01HH• FFLL = 0.26 = 0.26• LLww = 5.49 = 5.49HH• LLdd = L = Lgg+L+LUU+L+Lacac = 18.7 = 18.7HH• RRw0w0 = 80m = 80m • FFRR = 45.6 = 45.6• RRww = 3.63 = 3.63
PrimaryPrimary winding winding portion: portion:
• LLUU = 3.28nH = 3.28nH• LLw0w0 = 23.6nH = 23.6nH• FFLL = 0.65 = 0.65• LLww = 15.3nH = 15.3nH• LLdd = L = LUU+L+Lacac = 18.6nH = 18.6nH• RRw0w0 = 0.56m = 0.56m • FFRR = 11.7 = 11.7• RRww = 6.58m = 6.58m
SecondarySecondary winding winding portion: portion:
Example #2: Interleaved Example #2: Interleaved WindingsWindings
Secondary Secondary windingwinding
Primary Primary windingwinding
Example #2: Interleaved Example #2: Interleaved WindingsWindings
m.m.f.(dc)
0
P1 P2 P3 P4
Example #2: Interleaved Example #2: Interleaved WindingsWindings
• LLgg = 2.48 = 2.48HH
• LLUU = 0.36 = 0.36HH
• LLw0w0 = 2.98 = 2.98HH
• FFLL = 0.28 = 0.28
• LLww = 0.85 = 0.85HH
• LLdd = L = Lgg+L+LUU+L+Lacac = 3.69 = 3.69HH
• RRw0w0 = 45m = 45m
• FFRR = 12.3 = 12.3
• RRww = 0.553 = 0.553
PrimaryPrimary winding winding portion portion PP11: :
SecondarySecondary winding winding portion portion PP22::
• LLUU = 0.24nH = 0.24nH• LLw0w0 = 4.27nH = 4.27nH• FFLL = 0.68 = 0.68• LLww = 2.89nH = 2.89nH• LLdd = L = LUU+L+Lacac = 3.12nH = 3.12nH• RRw0w0 = 0.41m = 0.41m • FFRR = 3.53 = 3.53• RRww = 1.43m = 1.43m
Example #2: Interleaved Example #2: Interleaved WindingsWindings
• LLgg = 1.45 = 1.45HH
• LLUU = 0.22 = 0.22HH
• LLw0w0 = 1.74 = 1.74HH
• FFLL = 0.28 = 0.28
• LLww = 0.50 = 0.50HH
• LLdd = L = Lgg+L+LUU+L+Lacac = 2.16 = 2.16HH
• RRw0w0 = 26m = 26m
• FFRR = 12.3 = 12.3
• RRww = 0.324 = 0.324
PrimaryPrimary winding winding portion portion PP44::
SecondarySecondary winding winding portion portion PP33::
• LLUU = 0.22nH = 0.22nH• LLw0w0 = 3.87nH = 3.87nH• FFLL = 0.68 = 0.68• LLww = 2.62nH = 2.62nH• LLdd = L = LUU+L+Lacac = 2.83nH = 2.83nH• RRw0w0 = 0.37m = 0.37m • FFRR = 3.53 = 3.53• RRww = 1.3m = 1.3m
Example #2: Interleaved Example #2: Interleaved WindingsWindings
• LLgg = 3.93 = 3.93HH
• LLUU = 0.58 = 0.58HH
• LLw0w0 = 4.72 = 4.72HH
• LLww = 1.35 = 1.35HH
• LLdd = 5.85 = 5.85HH
• RRw0w0 = 71m = 71m
• RRww = 0.877 = 0.877
PrimaryPrimary winding: winding: Secondary Secondary winding: winding:
• LLUU = 0.46nH = 0.46nH• LLw0w0 = 8.14nH = 8.14nH• LLww = 5.51nH = 5.51nH• LLdd = 5.95nH = 5.95nH• RRw0w0 = 0.78m = 0.78m • RRww = 2.73m = 2.73m
Comparison between Simple and Comparison between Simple and Interleaved Windings Interleaved Windings
Interleaved windingInterleaved winding
• LLgg = 3.93 = 3.93HH
• LLUU = 0.58 = 0.58HH
• LLw0w0 = 4.72 = 4.72HH
• LLww = 1.35 = 1.35HH
• LLdd = 5.85 = 5.85HH
• RRw0w0 = 71m = 71m
• RRww = 0.877 = 0.877
Simple windingSimple winding
• LLgg = 8.74 = 8.74HH
• LLUU = 4.48 = 4.48HH
• LLw0w0 = 21.01 = 21.01HH
• LLww = 5.49 = 5.49HH
• LLdd = 18.7 = 18.7HH
• RRw0w0 = 80m = 80m
• RRww = 3.63 = 3.63
PrimaryPrimary winding: winding:
Comparison between Simple and Comparison between Simple and Interleaved WindingsInterleaved Windings
SecondarySecondary winding: winding:
Interleaved windingInterleaved winding• LLUU = 0.46nH = 0.46nH• LLw0w0 = 8.14nH = 8.14nH• LLww = 5.51nH = 5.51nH• LLdd = 5.95nH = 5.95nH• RRw0w0 = 0.78m = 0.78m • RRww = 2.73m = 2.73m
Simple windingSimple winding• LLUU = 3.28nH = 3.28nH• LLw0w0 = 23.6nH = 23.6nH• LLww = 15.3nH = 15.3nH• LLdd = 18.6nH = 18.6nH• RRw0w0 = 0.56m = 0.56m • RRww = 6.58m = 6.58m