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Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Lecture 1
Frequency Analysis ofDiscrete-time Signals
(4.2.1-4.2.3,4.2.5)
Dr D. Laurenson
27th May, 2013
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Course structure
Fourier transforms (3 lectures)
Correlation (2 lectures)
Linear systems (1 lecture)
Class test (1 class)
Random signals (2 lectures)
Digital ˛lters (2 lectures)
Power spectral estimation (2 lectures)
Multirate signal processing (1 lecture)
Analogue to digital converter (1 lecture)
Revision (1 lecture)
Matched ˛lters (2 lectures)
Wiener ˛lters (2 lectures)
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Outline
1 Introduction
2 Periodic signals
3 Power Density Spectra
4 Aperiodic Signals
5 Energy Density Spectrum
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Aperiodic, continuous time signals
Aperiodic in time implies continuous in frequency,thus the Fourier transform is used:
X(F ) =
Z 1`1
x(t)e`j2ıFtdt (4.1.30)
or, equivalently,
X(!) =
Z 1`1
x(t)e`j!tdt
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Aperiodic, continuous time signals
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Periodic, continuous time signals
Periodic in time implies sampled in frequency, thusthe Fourier Series is used. The sample spacing isF0 = 1
TPHz for a period TP s
ck =1
TP
ZTp
x(t)e`j2ıkF0tdt (4.1.9)
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Continuous time signals
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Discrete time periodic signals
Aperiodic in time ) Continuous in frequency
Periodic in time ) Sampled in frequency
By analogy, Sampled in time ) Periodic infrequency
Frequency domain is often normalised
Denote sampling frequency as 2ı
For a signal that is periodic in time, withperiod N, the sample spacing in frequency is ´t
2ı
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Discrete-time Fourier Series
The Discrete-time Fourier Series (DTFS) is de˛nedby
ck =1
N
N`1Xn=0
x(n)e`j2ıkn=N (4.2.8)
x(n) =
N`1Xk=0
ckej2ıkn=N (4.2.7)
Sometimes the normalisation of 1N
is performed inthe synthesis equation (4.2.7) instead of theanalysis (4.2.8)
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
DTFS example
x(n) = cos(ın=3) ) N = 6
) ck =1
N
N`1Xn=0
x(n)e`j2ıkn=N
=1
6
5Xn=0
cos(ın=3)e`j2ıkn=6
=1
6
5Xn=0
1
2
nejın=3 + e`jın=3
oe`j2ıkn=6
=1
12
5Xn=0
nej2ı(1`k)n=6 + e`j2ı(1+k)n=6
o
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
DTFS example
ck =1
12
8>>>>>>>>>>>>>>>>>>>>><>>>>>>>>>>>>>>>>>>>>>:
5Xn=0
ej2ı(1`k)n=6 +
5Xn=0
1
if k = `1
5Xn=0
1 +
5Xn=0
e`j2ı(1+k)n=6
if k = 1
5Xn=0
ej2ı(1`k)n=6 +
5Xn=0
e`j2ı(1+k)n=6
otherwise
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
DTFS example
N`1Xn=0
ej2ıkn=N =
N`1Xn=0
“ej2ık=N
”n
=1`
`ej2ık=N
´N1`
`ej2ık=N
´= 0 8k =2 (0;˚N;˚2N; : : :)
and 8k 2 (0;˚N;˚2N; : : :)
N`1Xn=0
ej2ıkn=N =
N`1Xn=0
1 = N
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
DTFS example
) ck =1
2
(1 ; k = `1 or k = 1
0 ; otherwise
Thus the DTFS of a sampled cosine is periodic,with period N, and consists of two non-zerofrequency components representing the twocomplex phasors that construct the cosine
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Power Density Spectra
DTFS is a transform
Relative delay is represented by the phasecomponent
Power Density Spectra represent the power ofthe constituent frequency components
The derivation of the PDS starts with thepower of a signal:
Px =1
N
N`1Xn=0
jx(n)j2 (4.2.10)
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Power Density Spectrum de˛nition
Expanding this, and representing x(n) by itsDTFS:
Px =1
N
N`1Xn=0
0@N`1Xk=0
ckej2ıkn=N
1Ax˜(n)
Switching the order of summation:
Px=
N`1Xk=0
ck
0@ 1
N
N`1Xn=0
x˜(n)ej2ıkn=N
1A=
N`1Xk=0
ckc˜k
jckj2 is the Power Density Spectrum
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
PDS example
x(n) =
(A ; 0 » n < L
0 ;L » n < N
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
PDS example
ck =1
N
N`1Xn=0
x(n)e`j2ıkn=N
=1
N
L`1Xn=0
A:“e`j2ık=N
”nM`1Xm=0
gn =1` gM
1` g
) ck =A
N
1` e`j2ıkL=N
1` e`j2ık=N
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
PDS example
jckj2 =A2
N2´ 1` e`j2ıkL=N
1` e`j2ık=N´ 1` ej2ıkL=N
1` ej2ık=N
=A2
N2´ 2` e`j2ıkL=N ` ej2ıkL=N
2` e`j2ık=N ` ej2ık=N
=A2
N2´``ej2ıkL=2N ` e`j2ıkL=2N
´2
``ej2ık=2N ` e`j2ık=2N
´2
=A2
N2´
sin2(ıkL=N)
sin2(ık=N)
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
PDS example
−1.5 −1 −0.5 0 0.5 1 1.50
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
Frequency (Cycles/Sampling interval)
N |
ck |
L = 5, N = 10
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
PDS example
−1.5 −1 −0.5 0 0.5 1 1.50
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
Frequency (Cycles/Sampling interval)
N |
ck |
L = 5, N = 40
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Power Density Spectrum properties
If a periodic sampled signal is real:
By de˛nition, x˜(n) = x(n)
c˜`k = ck, and c˜N`k = ck
jc`kj = jckj, and jcN`kj = jckj](c`k) = `](ck), and ](cN`k) = `](ck)
<(c`k) = <(ck) and =(c`k) = `=(ck)
<(cN`k) = <(ck) and =(cN`k) = `=(ck)
So for the PDS: jckj2 = jc`kj2 = jcN`kj2.
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Discrete-time Aperiodic Signals
Aperiodic signals have a continuous frequencytransform
Discrete-time (i.e. sampled) signals have aperiodic frequency transform
X(!) =
1Xn=`1
x(n)e`j!n (4.2.23)
This transform is also known as thediscrete-time Fourier transform (DTFT)
The period is fs = 1´t
, or !s = 2ı´t
The normalised frequency response is de˛nedby ´t = 1, giving rise to:
X(! + 2ık) = X(!) (4.2.24)
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Discrete-time Fourier TransformExample
Let the signal be an aperiodic rectangular pulse:
x(n) =
(A ; 0 » n < L
0 ;n < 0 or n – L
X(!) =
1Xn=`1
x(n)e`j!n
=
L`1Xn=0
Ae`j!n = A1` e`j!L
1` e`j!
= A ´ e`j!L=2
e`j!=2´ e
j!L=2 ` e`j!L=2
ej!=2 ` e`j!=2
= Ae`j!(L`1)=2 ´sin(!L=2)
sin(!=2)
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Discrete-time Fourier TransformExample
0
A
-3π -2π -π 0 π 2π 3π
Mag
nitu
de
Frequency (radians/sampling interval)
-π
0
π
-3π -2π -π 0 π 2π 3π
Pha
se
Frequency (radians/sampling interval)
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Discrete-time Aperiodic Signals
The reverse transform is given by
x(n) =1
2ı
Z ı
`ıX(!)ej!nd! (4.2.27)
This may be computed over any full period ofX(!), thus may also be written as:
x(n) =1
2ı
Z 2ı
0
X(!)ej!nd!
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Energy Density Spectrum
The energy density spectrum describes energy in asignal in terms of its frequency response:
Ex =
1Xn=`1
jx(n)j2 =1
2ı
Z ı
`ıjX(!)j2 d!
(4.2.41)The energy density spectrum is the integrand andde˛ned as:
Sxx(!) = jX(!)j2
For real valued signals,Sxx(`!) = Sxx(!) = Sxx(2ı ` !)
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Energy Density Spectrum Example
Let x(n) be de˛ned as:
x(n) =
(an ;n – 0
0 ;n < 0
where `1 < a < 1.
X(!) =
1Xn=`1
x(n)e`jn! =
1Xn=0
`ae`j!
´n
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Energy Density Spectrum Example
X(!) =1
1` ae`j!
) Sxx(!) =1
1` ae`j!1
1` aej!
=1
1 + a2 ` a (ej! + e`j!)
=1
1` 2a cos(!) + a2
The resulting spectrum depends upon theparameter a. For a = 0, which results in the inputbeing a single non-zero sample, the spectrum is‚at.
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Energy Density Spectrum Example
Lecture 1
Introduction
Periodicsignals
PowerDensitySpectra
AperiodicSignals
EnergyDensitySpectrum
Summary
1 Introduction
2 Periodic signals
3 Power Density Spectra
4 Aperiodic Signals
5 Energy Density Spectrum