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Hart Interactive – Honors Algebra 1 M4+ Lesson 3 HONORS ALGEBRA 1 Lesson 3: Operations with Complex Numbers Module 4+ Complex Numbers S.19 This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from ALG II-M1-TE-1.3.0-07.2015 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 3: Operations with Complex Numbers Opening Exercise Since complex numbers are built from real numbers, we should be able to add, subtract, multiply, and divide them. They should also satisfy the commutative, associative, and distributive properties, just as real numbers do. Let’s check how some of these operations work for complex numbers. Addition with Complex Numbers 1. Compute (3 + 4 ) + (7 20). Subtraction with Complex Numbers 2. Compute (3 + 4 ) (7 20). 3. In general terms, we can say ( + )+( + ) = (______ + ______) + (______ + ______) Multiplication with Complex Numbers 4. Compute (1 + 2 )(1 2). 5. In general terms, we can say ( + ) ( + ) = ______ + ______ + ______ + ______ = (______ ______) + (______ + ______) Addition of variable expressions is a matter of rearranging terms according to the properties of operations. Often, we call this combining like terms. These properties of operations apply to complex numbers. Multiplication is similar to polynomial multiplication, using the addition, subtraction, and multiplication operations and the fact that 2 = 1.

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Page 1: Lesson 3: Operations with Complex Numbersmrpunpanichgulmath.weebly.com/uploads/3/7/5/3/37534823/a1_m4_… · M HONORS ALGEBRA 1 Hart Interactive – Honors Algebra 1 Lesson 3 4+ Lesson

Hart Interactive – Honors Algebra 1 M4+ Lesson 3 HONORS ALGEBRA 1

Lesson 3: Operations with Complex Numbers

Module 4+ Complex Numbers

S.19

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org

This file derived from ALG II-M1-TE-1.3.0-07.2015

This work is licensed under a

Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Lesson 3: Operations with Complex Numbers

Opening Exercise

Since complex numbers are built from real numbers, we should be able to add, subtract, multiply, and divide

them. They should also satisfy the commutative, associative, and distributive properties, just as real numbers

do.

Let’s check how some of these operations work for complex numbers.

Addition with Complex Numbers

1. Compute (3 + 4𝑖𝑖) + (7 − 20𝑖𝑖).

Subtraction with Complex Numbers

2. Compute (3 + 4𝑖𝑖) − (7 − 20𝑖𝑖).

3. In general terms, we can say (𝑎𝑎 + 𝑏𝑏𝑖𝑖) + (𝑐𝑐 + 𝑑𝑑𝑖𝑖) = (______ + ______) + (______ + ______)𝑖𝑖

Multiplication with Complex Numbers

4. Compute (1 + 2𝑖𝑖)(1 − 2𝑖𝑖).

5. In general terms, we can say (𝑎𝑎 + 𝑏𝑏𝑖𝑖) ∙ (𝑐𝑐 + 𝑑𝑑𝑖𝑖) = ______ + ______ + ______ + ______

= (______ − ______) + (______ + ______)𝑖𝑖

Addition of variable expressions is a matter of

rearranging terms according to the properties

of operations. Often, we call this combining

like terms. These properties of operations

apply to complex numbers.

Multiplication is similar to polynomial

multiplication, using the addition,

subtraction, and multiplication

operations and the fact that 𝑖𝑖2 = −1.

Page 2: Lesson 3: Operations with Complex Numbersmrpunpanichgulmath.weebly.com/uploads/3/7/5/3/37534823/a1_m4_… · M HONORS ALGEBRA 1 Hart Interactive – Honors Algebra 1 Lesson 3 4+ Lesson

Hart Interactive – Honors Algebra 1 M4+ Lesson 3 HONORS ALGEBRA 1

Lesson 3: Operations with Complex Numbers

Module 4+ Complex Numbers

S.20

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org

This file derived from ALG II-M1-TE-1.3.0-07.2015

This work is licensed under a

Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Multiplication with Complex Numbers

6. Verify that −1 + 2𝑖𝑖 and −1 − 2𝑖𝑖 are solutions to 𝑥𝑥2 + 2𝑥𝑥 + 5 = 0.

7. Rewrite each expression as a polynomial in standard form.

A. (𝑥𝑥 + 𝑖𝑖)(𝑥𝑥 − 𝑖𝑖)

B. (𝑥𝑥 + 5𝑖𝑖)(𝑥𝑥 − 5𝑖𝑖)

C. �𝑥𝑥 − (2 + 𝑖𝑖)��𝑥𝑥 − (2 − 𝑖𝑖)�

Page 3: Lesson 3: Operations with Complex Numbersmrpunpanichgulmath.weebly.com/uploads/3/7/5/3/37534823/a1_m4_… · M HONORS ALGEBRA 1 Hart Interactive – Honors Algebra 1 Lesson 3 4+ Lesson

Hart Interactive – Honors Algebra 1 M4+ Lesson 3 HONORS ALGEBRA 1

Lesson 3: Operations with Complex Numbers

Module 4+ Complex Numbers

S.21

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org

This file derived from ALG II-M1-TE-1.3.0-07.2015

This work is licensed under a

Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Factor the following polynomial expressions into products of linear terms.

8. 𝑥𝑥2 + 9

9. 𝑥𝑥2 + 5

Reverse Your Thinking

Can we construct an equation if we know its solutions? When a polynomial equation is written in factored

form 𝑎𝑎(𝑥𝑥 − 𝑟𝑟1)(𝑥𝑥 − 𝑟𝑟2)⋯ (𝑥𝑥 − 𝑟𝑟𝑛𝑛) = 0, the solutions to the equation are 𝑟𝑟1, 𝑟𝑟2, … , 𝑟𝑟𝑛𝑛.

Write a polynomial 𝑃𝑃 with the lowest possible degree that has the given solutions. Explain how you

generated each answer. Write your answer in standard form. Be careful about which factors to multiply first

in Exercise 10!

10. −2, 3, −4𝑖𝑖, 4𝑖𝑖

11. 3 + 𝑖𝑖, 3 − 𝑖𝑖

Page 4: Lesson 3: Operations with Complex Numbersmrpunpanichgulmath.weebly.com/uploads/3/7/5/3/37534823/a1_m4_… · M HONORS ALGEBRA 1 Hart Interactive – Honors Algebra 1 Lesson 3 4+ Lesson

Hart Interactive – Honors Algebra 1 M4+ Lesson 3 HONORS ALGEBRA 1

Lesson 3: Operations with Complex Numbers

Module 4+ Complex Numbers

S.22

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org

This file derived from ALG II-M1-TE-1.3.0-07.2015

This work is licensed under a

Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Lesson Summary Adding two complex numbers is comparable to combining like terms in a polynomial expression.

Multiplying two complex numbers is like multiplying two binomials, except one can use 𝑖𝑖2 = −1 to

simplify more.

Complex numbers satisfy the associative, commutative, and distributive properties.

Page 5: Lesson 3: Operations with Complex Numbersmrpunpanichgulmath.weebly.com/uploads/3/7/5/3/37534823/a1_m4_… · M HONORS ALGEBRA 1 Hart Interactive – Honors Algebra 1 Lesson 3 4+ Lesson

Hart Interactive – Honors Algebra 1 M4+ Lesson 3 HONORS ALGEBRA 1

Lesson 3: Operations with Complex Numbers

Module 4+ Complex Numbers

S.23

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org

This file derived from ALG II-M1-TE-1.3.0-07.2015

This work is licensed under a

Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Homework Problem Set

1. Express each of the following in 𝑎𝑎 + 𝑏𝑏𝑖𝑖 form.

A. (2 + 5𝑖𝑖) + (4 + 3𝑖𝑖)

B. (−1 + 2𝑖𝑖) − (4 − 3𝑖𝑖) C. (4 + 𝑖𝑖) + (2 − 𝑖𝑖) − (1 − 𝑖𝑖) D. (5 + 3𝑖𝑖)(5 − 3𝑖𝑖) E. (2 − 𝑖𝑖)(2 + 𝑖𝑖) F. (1 + 𝑖𝑖)(2 − 3𝑖𝑖) + 3𝑖𝑖(1 − 𝑖𝑖) − 𝑖𝑖

2. Express each of the following in 𝑎𝑎 + 𝑏𝑏𝑖𝑖 form.

A. (1 + 𝑖𝑖)2 B. (1 + 𝑖𝑖)4 C. (1 + 𝑖𝑖)6

Page 6: Lesson 3: Operations with Complex Numbersmrpunpanichgulmath.weebly.com/uploads/3/7/5/3/37534823/a1_m4_… · M HONORS ALGEBRA 1 Hart Interactive – Honors Algebra 1 Lesson 3 4+ Lesson

Hart Interactive – Honors Algebra 1 M4+ Lesson 3 HONORS ALGEBRA 1

Lesson 3: Operations with Complex Numbers

Module 4+ Complex Numbers

S.24

This work is derived from Eureka Math ™ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org

This file derived from ALG II-M1-TE-1.3.0-07.2015

This work is licensed under a

Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

3. Evaluate 𝑥𝑥2 − 6𝑥𝑥 when 𝑥𝑥 = 3 − 𝑖𝑖.

4. Evaluate 4𝑥𝑥2 − 12𝑥𝑥 when 𝑥𝑥 = 32 −

𝑖𝑖2.

5. Show by substitution that 5−𝑖𝑖√55 is a solution to 5𝑥𝑥2 − 10𝑥𝑥 + 6 = 0.

6. Use the fact that 𝑥𝑥4 + 64 = (𝑥𝑥2 − 4𝑥𝑥 + 8)(𝑥𝑥2 + 4𝑥𝑥 + 8) to explain how you know that the graph of

𝑦𝑦 = 𝑥𝑥4 + 64 has no 𝑥𝑥-intercepts. You need not find the solutions.