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Link 1 ), ; , ( s r Let G be a digraph and (r,s) i s an arc is called a link.

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Link. Let G be a digraph and (r,s) is an arc. is called a link. positive link. is called a positive link. r. s. start. end. negative link. is called a negative link. s. r. start. end. link chain. : a sequece of links. is called a link chain. - PowerPoint PPT Presentation

TRANSCRIPT

Link

1),;,( sr

Let G be a digraph and (r,s) is an arc

is called a link.

positive link)1;,( sr is called a positive link

r s

start end

negative link)1;,( sr is called a negative link

rs

start end

link chain

),,( 1 is called a link chain

i j

eg. path : a sequence of arcs

a chain from i to j

: a sequece of links

simple chain

simple chain : chain with distinct starts for

not simple chain

closed chain : i=j, simple closed chain :cycle

it’s links

simple closed path = circuit

Singed length

linksnegativeoflinkspositiveofs ##:)(

,,1

length of

Let

inlinkof#:

is called siged length of

be a chain

chain product

1)(

kji

k

kkaA

,,1

with

Let ,,1;, kji kkkk

is called a chain product of A associated

be a chain

a cycle product.

If the chain is a cycle, we obtain

V1 V2 V3 Vk

D is called linearly k-partite

i=1,…,k-1

Vi Vi+1

cyclically m-partite

linearly m-partite

it consists of loopless isolated vertices

A digraph is linearly 1-partite

r-cyclic A square matrix A is r-cyclic if G(A) is

cyclically r-partite or equivalently

0

0

0

00

~

1

,1

23

12

r

rr

P

A

A

A

A

A

permutation similar

r-cyclic matrix in the superdiagonal block form

block-shift matrix

mkkMM ,1

1k

2m

whenever

A block-shift matrix is a square matrix

0kM

in block form with square diagonal blocks s.t.

00

0

00

,1

23

12

mmM

M

M

M

block-shift matrix

matrix iff it’s digraph is linearly partite.

A square matrix of size greater than one

is permutationally similar to a block-shift

Union of digraphs

21 GandG

),( 212121 EEVVGG

),( 222 EVG

In case

digraphs : 111 ,EVG

is called union of

and

21 VV

is called disjoint union

Remark 3.1The disjoint union of two cyclically m-partite

digraphs is cyclically m-partite

V1 V2 V3 Vk

U1 U2 U3 Uk

Remark 3.2

rm

A linearly r-partite digraph is cyclically

m-partite for any

Example for Remark 3.2

84

73

1062

951

VV

VV

VVV

VVV

A linearly 10-partite digraph is cyclically

4-partite

10=4x2+2

Lemma 3.3The disjoint union of a cyclically m-partite

digraph and a linearly s-partite digraph is

is a cyclically m-partite digraph.

.int

,1.3Re

.

,2.3Re

:1

partitemcyclicallyisuniondisjothe

markBy

partitemcyclicallyispartiteslinearlythe

markBy

msthatAssumCase

Case 2 s<m

m

ss

V

UV

UV

UV

22

11

Lemma 3.4

srtsr ,maxinteger t

The disjoint union of a linearly r-partite

is a linearly t-partite digraph for any positive

digraph and a linearly s-partite digraph is

partitesrlinearlyais

VVVUUUGG

digraphpartitekrlinearlyais

VVUVUVUU

GGskFor

digraphpartitesrrlinearlyais

VVUVUVUV

GG

UUUG

VVVVG

srassumemay

partiteslinearlyG

partiterlinearlyG

rs

rksskskk

rsss

s

rs

)(

:)3(

.

:,1,,1)2(

.,max

:

:

:

)1(

:

:

212121

1111

21

12211

21

212

211

2

1

Lemma 2.7.6

iV

mjiji ,1,

every chain from a vertex of

Given G linearly m-partite ( resp. cyclically

mVVV ,,, 21 Then

m-partite) with ordered partition

jVto a vertex

of

is of signed length j-i

(resp. j-i (mod m))

ijsandijthen

linknegativeaisIf

ijsandijthen

linkpositiveaisIf

When

Vinyvertex

atoVinxvertexafromchainabeLet

ionconsiderat

underchaintheoflengththeoninductionBy

j

i

1)(1

,

1)(1

,

,1

.

.

ijijssthen

ijshypotheseinductionby

andVxthenlinknegativeaisIf

ijijssthen

ijshypotheseinductionby

andVxthenlinkpositiveaisIf

andofstartthebex

Let

kConsider

jkk

jkk

kkk

k

111)ˆ()(

1)ˆ(

,

111)ˆ()(

1)ˆ(

,

,,,ˆ,

,,,,

2

1

1

121

21

Remark

Let G be a digraph and each of whose cycles

has zero signed length then every strongly

connected component of G is a single vertex

without loop.G is acyclic

0)(2

.2

.

,

ssoand

lengthofcircuitaistherethen

lengthof

walkclosedaisthereThen

verticesmoreortwo

withcomponentstrongahasG

notSuppose

Remark

00

*0

~ P

A

A is acyclic if and only if

Theorem 2.7.7 (i)

A digraph is linearly partite if and only if

each of cycles has zero signed length.

.

6.7.2,2:2

,1:1

""

lengthsignedzerohascycleeach

TheorembymIfCase

cycleemptyonlyhasGthenmIfCase

partitemlinearlybeGLet

ifonly

.

2

,,,

1

sin,

.

:

.

,

int""

2

221

1

11

21

graphundirected

connectedwithandpartitelinearlyisGthen

arcthisbeGletGinarcanbexxIf

partitelinearlyisGthen

xvertexglethebeGletVxGiven

graphundirected

connectedwithandpartitelinearlyiswhich

verticeskwithGofsubdigraphinducedvertexG

GGGGconstructtoGoing

connectedisdigraphgiventheofgraph

undirectedthethatassumemaywepartitelinearly

stillispartitelinearlyofuniondisjoSinceIf

k

n

p

k

pii

k

k

k

i

k

k

kp

k

VVupartition

orderedwithpartiteplinearlyisGClaim

iIfCase

VVuVV

partitionorderedwithpartiteplinearlyisGClaim

iIfCase

uGVbygenerated

subdigraphinducedvertexthebeGLet

kiandVvsomeforarcanisvu

tsGVVuassumemaywe

generalityloseWithoutGconstructtoNow

GofpartitionorderedthebeVVLet

GGGdconstructehavewethatSuppose

,,,

)1(:

1:2

,,,,,

:

1:1

)(

1),(

..)(\

,.

.,,

1

11

1

1

1

21

Theorem 2.7.7 (ii)

A digraph is cyclically m-partite but not

linearly partite if and only if each of its

cycles has signed length an integral

mutiple of m and it has at least one cycle

with nonzero signed length.

)(

)(mod0)(

6.7.2.,.

.

.

)(,

""

sm

ms

ThmByVxSayxtoxfromchaina

asconsideredbecaninxvertexanyTake

GincycleanyConsider

lengthsignednonzerowithcycleoneleast

athasGibypartitelinearlynotisGSince

ifOnly

j

1)()()(

)(),,,(

,

)1;,(

.),(

..1,,[

.,,

:

.,,)(

,,1

,,1)(mod)(

,,1),,(

,),,(

)(

.

,

int

1

1

11

1

1

1

ij

ji

ji

ji

ji

n

k

ikk

jji

ii

iik

sssBut

smsoandcycleaisthen

vtovfromchainaisthereSince

vvletandjithatassumeMay

Ginarcanisvv

tsijwithmjinotSuppose

VV

partionorderwithpartitemcyclicallyisGClaim

xxGV

withGofsubdigraphinducedvertexthebeGLet

kiforVsoandVxThen

kiformjsxVLet

kifor

andofendthebexLet

smlengthsignednonzerowithcycleaTake

connectedisGdigraphgiventheofgraphundirected

thethatassumemaywepartitemcyclically

stillispartitemcyclicallyofuniondisjoSince

Exercise

s1 (ii) G is linearly s-partite for a unique positive

Let G be linearly partite and

(i) Prove that if G is linearly s-partite then

= signed length of the longest chain

1s integers iff the undirected graph of G is

connected . Then

Corollary p.1

lengths of the cycles of G.

G is cyclically partite but not linearly partite

(2) G is cyclically m-partite iff m divides the

(1) The cyclic index of G = g.c.d of signed

cyclic index of G.

Corollary p.2

which G is d-cyclically partite is unique

ordered partition of vertex set of G w.r.t.

where d is the cyclic index of G.

(3) If the undirected graph of G is connected

then up to cyclic rearrangement, the

.

)(.)(7.7.2)(

.

..

,arg

.

)(7.7.2)(

Gofindexcyclicthedividesm

partitemcyclicallyisG

iCorandiiThmByii

Gofcyclestheof

lengthssignedofdcgisGofindexcyclicthe

msuchestltheisGofindexcyclictheSince

Gofcyclesthe

oflengthssignedofdivisorcommonaism

partitelinearlynotbutpartitemcyclicallyisG

iiThmByi

Theorem 2.7.10

g.c.d of signed lengths of closed chains

Let G be a digraph with connected undirected

of G. Then for vertex x

graph and k= g.c.d of signed lengths of cycles

containing x = k.

can not write cycles

Theorem 2.7.11

)()( BGAG and A, B have the

Let nMBA ,

same corresponding cycle products.

A and B are diagonally similar

1

1

1

1

1

1

1

1

1

1

)(

)(

,,1);,(,,,

)(

)()(

00

,1

sin""

kji

jik

ji

kjjii

kji

kkkk

ijij

jijiij

k

kk

k

kk

k

kk

k

kkkk

k

kk

ddB

ddb

dbdaA

kforjiwhere

AGofcycleaConsider

BGAG

bathen

njidbdathen

BDDAthatsuch

DmatrixdiagonalgularnonthatSuppose

)()(

1,

]

1,:2

1,:1

,,1[

,,1:

,,1

1

1

1

1

1111

1

11

1

11

11

1

11

1

1

BAhenceand

ddddclaimBy

ddddddthen

isandthenjsIfCase

ddddthen

jsandthenisIfCase

kfor

kforddddClaim

ssletand

kforofstartthebesLet

kss

kji

ssssji

kkkkk

ssji

kkkkk

ssji

kk

kk

k

kk

kkkk

k

kk

kk

k

kk

kk

k

kk

DgularnoneeryInductivel

Hinarcanisijifa

db

Hinarcanisjiifb

da

dLet

jidandkid

thatsuchichoosekjdIf

Hinarcanisiifa

b

Hinarcanisiifb

a

d

byivertextovertexfromcedis

ativertexfordeDeterdLettreeais

graphundirectedingcorrespondthethatsucharcs

nwithAGofHsubdigraphaTakeconnected

isAGofgraphundirectedthethatassumeMay

ji

iji

ij

iij

j

i

i

i

i

i

i

sinmindet

),(

),(

1),(),1(

,)1,(

)1,(

),1(

11tan

min.1.

1)(.

)(

1

1

1

1

1

jijiij

ijijij

ijijij

ij

ij

jijiij

dbda

bddathen

dAdaAaAand

BbBAsoandAGincycleais

thenandjiofncompositiothebeLet

Hinitojfromchainaistherethen

HinnotbutAGinarcanisjithatAssume

HinarcanisjioraifproblemNo

njifordbdaClaim

1

1

ˆ1

ˆ

ˆ

1

)()()(

)()()()(

,ˆ),(

ˆ

)(),(

.),(0,[

,1:

Theorem p.1

2,, mZmMA n Consider Let

AeA miD 2

~(b)

(a) A is m-cyclic

(c) All cycles of G(A) have signed lengths

an integral multiple of m.(d) All circuits of G(A) have lengths

an integral multiple of m.

Theorem p.2

Ae mi2

AeA mi2

~

(f)

(e)

)()( 2 tctcAe

Am

i

(g) A and

have the same peripheral spectrum.

Theorem p.3

When G(A) has at least one cycle with

Then

nonzero signed length, (a)-(c) are equivalent

)()()( cba

When A is irreducible, (a)-(d) are equivalent.

When A is nonnegative irreducible, then

(a)-(g) are equivalent.

)()(

)(1

)()()(

)()()(

~

)()(

)()(

)(2

)(2

211.7.2

2

AGincycleanyforsm

AGincycleanyfore

AGincycleanyforAeA

AGincycleanyforAeA

AeA

cb

knownba

mis

mis

miThmby

miD

equivalentaredaHence

d

AGof

lengthscircuitofdivisorcommonaism

AGoflengthscircuitofdcgm

AGofindexcyclicm

partitemcyclicallyisAGaThen

connectedstronglyisAGeirreduciblisAWhen

equivalentarecaHence

cbathatprovehaveWe

ac

iiThmbylengthsigned

nonzerowithcycleoneleastathasAGWhen

)()(

)(

)(

)(..

)(

)()(

.)(,

)()(

)()()(

)()(

)(7.7.2,

)(

.)()(

)()()()()(

int

int2

2

2

var)(

1,,1,0)(

:

)()(

)()()()()(

,

2

equivalentaregaHence

gfeba

cyclicmisAhm

egeranism

h

egeranis

h

m

mrotationaunder

iantinisAofspectrumperipheraltheg

hieA

Aofspectrumperipheralthe

ThmFrobeniusApply

AofityimprimitivofindexthehLet

agthatshowtoNow

gfebathatclearisit

eirreduciblenonnegativisAWhen

h

i

Spectral Index

nnnnn

A atatatattc

12

21

1)(

0ia

nMA and

Let

)(Aks

: = g.c.d of i at

The spectral index of A =

00:)( 21 ns aaaifAk

Combinatorial Spectral Theory of Nonnegative Matrices