martin-gay, beginning algebra, 5ed 22 33 44 55

12

Upload: lorraine-brianna-warner

Post on 11-Jan-2016

219 views

Category:

Documents


4 download

TRANSCRIPT

Page 1: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55
Page 2: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 22

Page 3: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 33

Page 4: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 44

Page 5: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 55

Page 6: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 66

Page 7: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 77

Page 8: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 88

Page 9: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 99

Page 10: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 1010

Example

For each pair of polynomials, find the least common multiple.a) 16a and 24bb) 24x4y4 and 6x6y2

c) x2 4 and x2 2x 8

Solution

a) 16a = 2 2 2 2 a 24b = 2 2 2 3 b

The LCM = 2 2 2 2 a 3 b

The LCM is 24 3 a b, or 48ab

16a is a factor of the LCM

24b is a factor of the LCM

Page 11: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 1111

Example continued

b) 24x4y4 = 2 2 2 3 x x x x y y y y

6x6y2 = 2 3 x x x x x x y y

LCM = 2 2 2 3 x x x x y y y y x x

Note that we used the highest power of each factor. The LCM is 24x6y4

c) x2 4 = (x 2)(x + 2)

x2 2x 8 = (x + 2)(x 4)

LCM = (x 2)(x + 2)(x 4)

x2 4 is a factor of the LCM

x2 2x 8 is a factor of the LCM

Page 12: Martin-Gay, Beginning Algebra, 5ed 22 33 44 55

Martin-Gay, Beginning Algebra, 5ed 1212

a)

b)

c)

d)

e)