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Page 1: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5
Page 2: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

Martin-Gay, Beginning Algebra, 5ed 22

Location of Newport D1

Location of Gatlinburg C2

Location of Robbinsville A5

Page 3: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

Martin-Gay, Beginning Algebra, 5ed 33

Page 4: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

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Page 5: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

Martin-Gay, Beginning Algebra, 5ed 55

Page 6: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

Martin-Gay, Beginning Algebra, 5ed 66

Page 7: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

Martin-Gay, Beginning Algebra, 5ed 77

Page 8: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

Martin-Gay, Beginning Algebra, 5ed 88

Page 9: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

Martin-Gay, Beginning Algebra, 5ed 99

Determine whether (3, – 2) is a solution of 2x + 5y = – 4.Let x = 3 and y = – 2 in the equation.

2x + 5y = – 4

2(3) + 5(–2) = – 4 Replace x with 3 and y with –2.

6 + (–10) = – 4 Simplify.

– 4 = – 4 True

So (3, –2) is a solution of 2x + 5y = – 4

Example:

Page 10: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

Martin-Gay, Beginning Algebra, 5ed 1010

Determine whether (– 1, 6) is a solution of 3x – y = 5.Let x = – 1 and y = 6 in the equation.

3x – y = 5 3(– 1) – 6 = 5 Replace x with – 1 and y with 6.

– 3 – 6 = 5 Simplify.

– 9 = 5 False

So (– 1, 6) is not a solution of 3x – y = 5

Example:

Page 11: Martin-Gay, Beginning Algebra, 5ed 22 Location of NewportD1 Location of GatlinburgC2 Location of RobbinsvilleA5

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